3.123 \(\int \frac{\coth ^6(x)}{a+b \text{csch}(x)} \, dx\)

Optimal. Leaf size=183 \[ \frac{2 \left (a^2+b^2\right )^{5/2} \tanh ^{-1}\left (\frac{a-b \tanh \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2}}\right )}{a b^5}+\frac{a \left (a^2+3 b^2\right ) \coth (x)}{b^4}+\frac{\left (a^2+3 b^2\right ) \tanh ^{-1}(\cosh (x))}{2 b^3}-\frac{\left (3 a^2 b^2+a^4+3 b^4\right ) \tanh ^{-1}(\cosh (x))}{b^5}-\frac{\left (a^2+3 b^2\right ) \coth (x) \text{csch}(x)}{2 b^3}+\frac{a \coth ^3(x)}{3 b^2}-\frac{a \coth (x)}{b^2}+\frac{x}{a}-\frac{3 \tanh ^{-1}(\cosh (x))}{8 b}-\frac{\coth (x) \text{csch}^3(x)}{4 b}+\frac{3 \coth (x) \text{csch}(x)}{8 b} \]

[Out]

x/a - (3*ArcTanh[Cosh[x]])/(8*b) + ((a^2 + 3*b^2)*ArcTanh[Cosh[x]])/(2*b^3) - ((a^4 + 3*a^2*b^2 + 3*b^4)*ArcTa
nh[Cosh[x]])/b^5 + (2*(a^2 + b^2)^(5/2)*ArcTanh[(a - b*Tanh[x/2])/Sqrt[a^2 + b^2]])/(a*b^5) - (a*Coth[x])/b^2
+ (a*(a^2 + 3*b^2)*Coth[x])/b^4 + (a*Coth[x]^3)/(3*b^2) + (3*Coth[x]*Csch[x])/(8*b) - ((a^2 + 3*b^2)*Coth[x]*C
sch[x])/(2*b^3) - (Coth[x]*Csch[x]^3)/(4*b)

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Rubi [A]  time = 0.336513, antiderivative size = 183, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 9, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.692, Rules used = {3898, 2897, 3770, 3767, 8, 3768, 2660, 618, 204} \[ \frac{2 \left (a^2+b^2\right )^{5/2} \tanh ^{-1}\left (\frac{a-b \tanh \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2}}\right )}{a b^5}+\frac{a \left (a^2+3 b^2\right ) \coth (x)}{b^4}+\frac{\left (a^2+3 b^2\right ) \tanh ^{-1}(\cosh (x))}{2 b^3}-\frac{\left (3 a^2 b^2+a^4+3 b^4\right ) \tanh ^{-1}(\cosh (x))}{b^5}-\frac{\left (a^2+3 b^2\right ) \coth (x) \text{csch}(x)}{2 b^3}+\frac{a \coth ^3(x)}{3 b^2}-\frac{a \coth (x)}{b^2}+\frac{x}{a}-\frac{3 \tanh ^{-1}(\cosh (x))}{8 b}-\frac{\coth (x) \text{csch}^3(x)}{4 b}+\frac{3 \coth (x) \text{csch}(x)}{8 b} \]

Antiderivative was successfully verified.

[In]

Int[Coth[x]^6/(a + b*Csch[x]),x]

[Out]

x/a - (3*ArcTanh[Cosh[x]])/(8*b) + ((a^2 + 3*b^2)*ArcTanh[Cosh[x]])/(2*b^3) - ((a^4 + 3*a^2*b^2 + 3*b^4)*ArcTa
nh[Cosh[x]])/b^5 + (2*(a^2 + b^2)^(5/2)*ArcTanh[(a - b*Tanh[x/2])/Sqrt[a^2 + b^2]])/(a*b^5) - (a*Coth[x])/b^2
+ (a*(a^2 + 3*b^2)*Coth[x])/b^4 + (a*Coth[x]^3)/(3*b^2) + (3*Coth[x]*Csch[x])/(8*b) - ((a^2 + 3*b^2)*Coth[x]*C
sch[x])/(2*b^3) - (Coth[x]*Csch[x]^3)/(4*b)

Rule 3898

Int[cot[(c_.) + (d_.)*(x_)]^(m_.)*(csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_))^(n_), x_Symbol] :> Int[(Cos[c + d*x]^
m*(b + a*Sin[c + d*x])^n)/Sin[c + d*x]^(m + n), x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && IntegerQ[
n] && IntegerQ[m] && (IntegerQ[m/2] || LeQ[m, 1])

Rule 2897

Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(
m_), x_Symbol] :> Int[ExpandTrig[(d*sin[e + f*x])^n*(a + b*sin[e + f*x])^m*(1 - sin[e + f*x]^2)^(p/2), x], x]
/; FreeQ[{a, b, d, e, f}, x] && NeQ[a^2 - b^2, 0] && IntegersQ[m, 2*n, p/2] && (LtQ[m, -1] || (EqQ[m, -1] && G
tQ[p, 0]))

Rule 3770

Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]

Rule 3767

Int[csc[(c_.) + (d_.)*(x_)]^(n_), x_Symbol] :> -Dist[d^(-1), Subst[Int[ExpandIntegrand[(1 + x^2)^(n/2 - 1), x]
, x], x, Cot[c + d*x]], x] /; FreeQ[{c, d}, x] && IGtQ[n/2, 0]

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 3768

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> -Simp[(b*Cos[c + d*x]*(b*Csc[c + d*x])^(n - 1))/(d*(n -
 1)), x] + Dist[(b^2*(n - 2))/(n - 1), Int[(b*Csc[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1
] && IntegerQ[2*n]

Rule 2660

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{e = FreeFactors[Tan[(c + d*x)/2], x]}, Dis
t[(2*e)/d, Subst[Int[1/(a + 2*b*e*x + a*e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}, x] &&
 NeQ[a^2 - b^2, 0]

Rule 618

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{\coth ^6(x)}{a+b \text{csch}(x)} \, dx &=i \int \frac{\cosh (x) \coth ^5(x)}{i b+i a \sinh (x)} \, dx\\ &=-\int \left (-\frac{1}{a}-\frac{\left (a^4+3 a^2 b^2+3 b^4\right ) \text{csch}(x)}{b^5}-\frac{a \left (-a^2-3 b^2\right ) \text{csch}^2(x)}{b^4}-\frac{\left (a^2+3 b^2\right ) \text{csch}^3(x)}{b^3}+\frac{a \text{csch}^4(x)}{b^2}-\frac{\text{csch}^5(x)}{b}+\frac{i \left (a^2+b^2\right )^3}{a b^5 (i b+i a \sinh (x))}\right ) \, dx\\ &=\frac{x}{a}-\frac{a \int \text{csch}^4(x) \, dx}{b^2}+\frac{\int \text{csch}^5(x) \, dx}{b}-\frac{\left (i \left (a^2+b^2\right )^3\right ) \int \frac{1}{i b+i a \sinh (x)} \, dx}{a b^5}-\frac{\left (a \left (a^2+3 b^2\right )\right ) \int \text{csch}^2(x) \, dx}{b^4}+\frac{\left (a^2+3 b^2\right ) \int \text{csch}^3(x) \, dx}{b^3}+\frac{\left (a^4+3 a^2 b^2+3 b^4\right ) \int \text{csch}(x) \, dx}{b^5}\\ &=\frac{x}{a}-\frac{\left (a^4+3 a^2 b^2+3 b^4\right ) \tanh ^{-1}(\cosh (x))}{b^5}-\frac{\left (a^2+3 b^2\right ) \coth (x) \text{csch}(x)}{2 b^3}-\frac{\coth (x) \text{csch}^3(x)}{4 b}-\frac{(i a) \operatorname{Subst}\left (\int \left (1+x^2\right ) \, dx,x,-i \coth (x)\right )}{b^2}-\frac{3 \int \text{csch}^3(x) \, dx}{4 b}-\frac{\left (2 i \left (a^2+b^2\right )^3\right ) \operatorname{Subst}\left (\int \frac{1}{i b+2 i a x-i b x^2} \, dx,x,\tanh \left (\frac{x}{2}\right )\right )}{a b^5}+\frac{\left (i a \left (a^2+3 b^2\right )\right ) \operatorname{Subst}(\int 1 \, dx,x,-i \coth (x))}{b^4}-\frac{\left (a^2+3 b^2\right ) \int \text{csch}(x) \, dx}{2 b^3}\\ &=\frac{x}{a}+\frac{\left (a^2+3 b^2\right ) \tanh ^{-1}(\cosh (x))}{2 b^3}-\frac{\left (a^4+3 a^2 b^2+3 b^4\right ) \tanh ^{-1}(\cosh (x))}{b^5}-\frac{a \coth (x)}{b^2}+\frac{a \left (a^2+3 b^2\right ) \coth (x)}{b^4}+\frac{a \coth ^3(x)}{3 b^2}+\frac{3 \coth (x) \text{csch}(x)}{8 b}-\frac{\left (a^2+3 b^2\right ) \coth (x) \text{csch}(x)}{2 b^3}-\frac{\coth (x) \text{csch}^3(x)}{4 b}+\frac{3 \int \text{csch}(x) \, dx}{8 b}+\frac{\left (4 i \left (a^2+b^2\right )^3\right ) \operatorname{Subst}\left (\int \frac{1}{-4 \left (a^2+b^2\right )-x^2} \, dx,x,2 i a-2 i b \tanh \left (\frac{x}{2}\right )\right )}{a b^5}\\ &=\frac{x}{a}-\frac{3 \tanh ^{-1}(\cosh (x))}{8 b}+\frac{\left (a^2+3 b^2\right ) \tanh ^{-1}(\cosh (x))}{2 b^3}-\frac{\left (a^4+3 a^2 b^2+3 b^4\right ) \tanh ^{-1}(\cosh (x))}{b^5}+\frac{2 \left (a^2+b^2\right )^{5/2} \tanh ^{-1}\left (\frac{a-b \tanh \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2}}\right )}{a b^5}-\frac{a \coth (x)}{b^2}+\frac{a \left (a^2+3 b^2\right ) \coth (x)}{b^4}+\frac{a \coth ^3(x)}{3 b^2}+\frac{3 \coth (x) \text{csch}(x)}{8 b}-\frac{\left (a^2+3 b^2\right ) \coth (x) \text{csch}(x)}{2 b^3}-\frac{\coth (x) \text{csch}^3(x)}{4 b}\\ \end{align*}

Mathematica [A]  time = 1.56235, size = 269, normalized size = 1.47 \[ \frac{\text{csch}(x) (a \sinh (x)+b) \left (32 a^2 b \left (3 a^2+7 b^2\right ) \tanh \left (\frac{x}{2}\right )+32 a^2 b \left (3 a^2+7 b^2\right ) \coth \left (\frac{x}{2}\right )-6 a b^2 \left (4 a^2+9 b^2\right ) \text{csch}^2\left (\frac{x}{2}\right )-6 a b^2 \left (4 a^2+9 b^2\right ) \text{sech}^2\left (\frac{x}{2}\right )+24 a \left (20 a^2 b^2+8 a^4+15 b^4\right ) \log \left (\tanh \left (\frac{x}{2}\right )\right )+384 \left (-a^2-b^2\right )^{5/2} \tan ^{-1}\left (\frac{a-b \tanh \left (\frac{x}{2}\right )}{\sqrt{-a^2-b^2}}\right )-64 a^2 b^3 \sinh ^4\left (\frac{x}{2}\right ) \text{csch}^3(x)+4 a^2 b^3 \sinh (x) \text{csch}^4\left (\frac{x}{2}\right )-3 a b^4 \text{csch}^4\left (\frac{x}{2}\right )+3 a b^4 \text{sech}^4\left (\frac{x}{2}\right )+192 b^5 x\right )}{192 a b^5 (a+b \text{csch}(x))} \]

Antiderivative was successfully verified.

[In]

Integrate[Coth[x]^6/(a + b*Csch[x]),x]

[Out]

(Csch[x]*(b + a*Sinh[x])*(192*b^5*x + 384*(-a^2 - b^2)^(5/2)*ArcTan[(a - b*Tanh[x/2])/Sqrt[-a^2 - b^2]] + 32*a
^2*b*(3*a^2 + 7*b^2)*Coth[x/2] - 6*a*b^2*(4*a^2 + 9*b^2)*Csch[x/2]^2 - 3*a*b^4*Csch[x/2]^4 + 24*a*(8*a^4 + 20*
a^2*b^2 + 15*b^4)*Log[Tanh[x/2]] - 6*a*b^2*(4*a^2 + 9*b^2)*Sech[x/2]^2 + 3*a*b^4*Sech[x/2]^4 - 64*a^2*b^3*Csch
[x]^3*Sinh[x/2]^4 + 4*a^2*b^3*Csch[x/2]^4*Sinh[x] + 32*a^2*b*(3*a^2 + 7*b^2)*Tanh[x/2]))/(192*a*b^5*(a + b*Csc
h[x]))

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Maple [B]  time = 0.043, size = 360, normalized size = 2. \begin{align*}{\frac{1}{64\,b} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{4}}+{\frac{a}{24\,{b}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{3}}+{\frac{{a}^{2}}{8\,{b}^{3}} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{2}}+{\frac{1}{4\,b} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{2}}+{\frac{{a}^{3}}{2\,{b}^{4}}\tanh \left ({\frac{x}{2}} \right ) }+{\frac{9\,a}{8\,{b}^{2}}\tanh \left ({\frac{x}{2}} \right ) }+{\frac{1}{a}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) }-2\,{\frac{{a}^{5}}{{b}^{5}\sqrt{{a}^{2}+{b}^{2}}}{\it Artanh} \left ( 1/2\,{\frac{2\,\tanh \left ( x/2 \right ) b-2\,a}{\sqrt{{a}^{2}+{b}^{2}}}} \right ) }-6\,{\frac{{a}^{3}}{{b}^{3}\sqrt{{a}^{2}+{b}^{2}}}{\it Artanh} \left ( 1/2\,{\frac{2\,\tanh \left ( x/2 \right ) b-2\,a}{\sqrt{{a}^{2}+{b}^{2}}}} \right ) }-6\,{\frac{a}{b\sqrt{{a}^{2}+{b}^{2}}}{\it Artanh} \left ( 1/2\,{\frac{2\,\tanh \left ( x/2 \right ) b-2\,a}{\sqrt{{a}^{2}+{b}^{2}}}} \right ) }-2\,{\frac{b}{a\sqrt{{a}^{2}+{b}^{2}}}{\it Artanh} \left ( 1/2\,{\frac{2\,\tanh \left ( x/2 \right ) b-2\,a}{\sqrt{{a}^{2}+{b}^{2}}}} \right ) }-{\frac{1}{64\,b} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-4}}-{\frac{{a}^{2}}{8\,{b}^{3}} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-2}}-{\frac{1}{4\,b} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-2}}+{\frac{{a}^{4}}{{b}^{5}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) }+{\frac{5\,{a}^{2}}{2\,{b}^{3}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) }+{\frac{15}{8\,b}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) }+{\frac{a}{24\,{b}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-3}}+{\frac{{a}^{3}}{2\,{b}^{4}} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-1}}+{\frac{9\,a}{8\,{b}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-1}}-{\frac{1}{a}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(coth(x)^6/(a+b*csch(x)),x)

[Out]

1/64/b*tanh(1/2*x)^4+1/24/b^2*a*tanh(1/2*x)^3+1/8/b^3*a^2*tanh(1/2*x)^2+1/4/b*tanh(1/2*x)^2+1/2/b^4*a^3*tanh(1
/2*x)+9/8/b^2*a*tanh(1/2*x)+1/a*ln(tanh(1/2*x)+1)-2*a^5/b^5/(a^2+b^2)^(1/2)*arctanh(1/2*(2*tanh(1/2*x)*b-2*a)/
(a^2+b^2)^(1/2))-6*a^3/b^3/(a^2+b^2)^(1/2)*arctanh(1/2*(2*tanh(1/2*x)*b-2*a)/(a^2+b^2)^(1/2))-6*a/b/(a^2+b^2)^
(1/2)*arctanh(1/2*(2*tanh(1/2*x)*b-2*a)/(a^2+b^2)^(1/2))-2/a*b/(a^2+b^2)^(1/2)*arctanh(1/2*(2*tanh(1/2*x)*b-2*
a)/(a^2+b^2)^(1/2))-1/64/b/tanh(1/2*x)^4-1/8/b^3/tanh(1/2*x)^2*a^2-1/4/b/tanh(1/2*x)^2+1/b^5*ln(tanh(1/2*x))*a
^4+5/2/b^3*ln(tanh(1/2*x))*a^2+15/8/b*ln(tanh(1/2*x))+1/24*a/b^2/tanh(1/2*x)^3+1/2*a^3/b^4/tanh(1/2*x)+9/8*a/b
^2/tanh(1/2*x)-1/a*ln(tanh(1/2*x)-1)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(coth(x)^6/(a+b*csch(x)),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [B]  time = 3.25833, size = 7830, normalized size = 42.79 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(coth(x)^6/(a+b*csch(x)),x, algorithm="fricas")

[Out]

1/24*(24*b^5*x*cosh(x)^8 + 24*b^5*x*sinh(x)^8 - 6*(4*a^3*b^2 + 9*a*b^4)*cosh(x)^7 + 6*(32*b^5*x*cosh(x) - 4*a^
3*b^2 - 9*a*b^4)*sinh(x)^7 - 48*(2*b^5*x - a^4*b - 3*a^2*b^3)*cosh(x)^6 + 6*(112*b^5*x*cosh(x)^2 - 16*b^5*x +
8*a^4*b + 24*a^2*b^3 - 7*(4*a^3*b^2 + 9*a*b^4)*cosh(x))*sinh(x)^6 + 24*b^5*x + 6*(4*a^3*b^2 + a*b^4)*cosh(x)^5
 + 6*(224*b^5*x*cosh(x)^3 + 4*a^3*b^2 + a*b^4 - 21*(4*a^3*b^2 + 9*a*b^4)*cosh(x)^2 - 48*(2*b^5*x - a^4*b - 3*a
^2*b^3)*cosh(x))*sinh(x)^5 - 48*a^4*b - 112*a^2*b^3 + 48*(3*b^5*x - 3*a^4*b - 7*a^2*b^3)*cosh(x)^4 + 6*(280*b^
5*x*cosh(x)^4 + 24*b^5*x - 24*a^4*b - 56*a^2*b^3 - 35*(4*a^3*b^2 + 9*a*b^4)*cosh(x)^3 - 120*(2*b^5*x - a^4*b -
 3*a^2*b^3)*cosh(x)^2 + 5*(4*a^3*b^2 + a*b^4)*cosh(x))*sinh(x)^4 + 6*(4*a^3*b^2 + a*b^4)*cosh(x)^3 + 6*(224*b^
5*x*cosh(x)^5 + 4*a^3*b^2 + a*b^4 - 35*(4*a^3*b^2 + 9*a*b^4)*cosh(x)^4 - 160*(2*b^5*x - a^4*b - 3*a^2*b^3)*cos
h(x)^3 + 10*(4*a^3*b^2 + a*b^4)*cosh(x)^2 + 32*(3*b^5*x - 3*a^4*b - 7*a^2*b^3)*cosh(x))*sinh(x)^3 - 16*(6*b^5*
x - 9*a^4*b - 19*a^2*b^3)*cosh(x)^2 + 2*(336*b^5*x*cosh(x)^6 - 48*b^5*x - 63*(4*a^3*b^2 + 9*a*b^4)*cosh(x)^5 +
 72*a^4*b + 152*a^2*b^3 - 360*(2*b^5*x - a^4*b - 3*a^2*b^3)*cosh(x)^4 + 30*(4*a^3*b^2 + a*b^4)*cosh(x)^3 + 144
*(3*b^5*x - 3*a^4*b - 7*a^2*b^3)*cosh(x)^2 + 9*(4*a^3*b^2 + a*b^4)*cosh(x))*sinh(x)^2 + 24*((a^4 + 2*a^2*b^2 +
 b^4)*cosh(x)^8 + 8*(a^4 + 2*a^2*b^2 + b^4)*cosh(x)*sinh(x)^7 + (a^4 + 2*a^2*b^2 + b^4)*sinh(x)^8 - 4*(a^4 + 2
*a^2*b^2 + b^4)*cosh(x)^6 - 4*(a^4 + 2*a^2*b^2 + b^4 - 7*(a^4 + 2*a^2*b^2 + b^4)*cosh(x)^2)*sinh(x)^6 + 8*(7*(
a^4 + 2*a^2*b^2 + b^4)*cosh(x)^3 - 3*(a^4 + 2*a^2*b^2 + b^4)*cosh(x))*sinh(x)^5 + 6*(a^4 + 2*a^2*b^2 + b^4)*co
sh(x)^4 + 2*(35*(a^4 + 2*a^2*b^2 + b^4)*cosh(x)^4 + 3*a^4 + 6*a^2*b^2 + 3*b^4 - 30*(a^4 + 2*a^2*b^2 + b^4)*cos
h(x)^2)*sinh(x)^4 + a^4 + 2*a^2*b^2 + b^4 + 8*(7*(a^4 + 2*a^2*b^2 + b^4)*cosh(x)^5 - 10*(a^4 + 2*a^2*b^2 + b^4
)*cosh(x)^3 + 3*(a^4 + 2*a^2*b^2 + b^4)*cosh(x))*sinh(x)^3 - 4*(a^4 + 2*a^2*b^2 + b^4)*cosh(x)^2 + 4*(7*(a^4 +
 2*a^2*b^2 + b^4)*cosh(x)^6 - 15*(a^4 + 2*a^2*b^2 + b^4)*cosh(x)^4 - a^4 - 2*a^2*b^2 - b^4 + 9*(a^4 + 2*a^2*b^
2 + b^4)*cosh(x)^2)*sinh(x)^2 + 8*((a^4 + 2*a^2*b^2 + b^4)*cosh(x)^7 - 3*(a^4 + 2*a^2*b^2 + b^4)*cosh(x)^5 + 3
*(a^4 + 2*a^2*b^2 + b^4)*cosh(x)^3 - (a^4 + 2*a^2*b^2 + b^4)*cosh(x))*sinh(x))*sqrt(a^2 + b^2)*log((a^2*cosh(x
)^2 + a^2*sinh(x)^2 + 2*a*b*cosh(x) + a^2 + 2*b^2 + 2*(a^2*cosh(x) + a*b)*sinh(x) + 2*sqrt(a^2 + b^2)*(a*cosh(
x) + a*sinh(x) + b))/(a*cosh(x)^2 + a*sinh(x)^2 + 2*b*cosh(x) + 2*(a*cosh(x) + b)*sinh(x) - a)) - 6*(4*a^3*b^2
 + 9*a*b^4)*cosh(x) - 3*((8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^8 + 8*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)
*sinh(x)^7 + (8*a^5 + 20*a^3*b^2 + 15*a*b^4)*sinh(x)^8 - 4*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^6 - 4*(8*a^
5 + 20*a^3*b^2 + 15*a*b^4 - 7*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^2)*sinh(x)^6 + 8*(7*(8*a^5 + 20*a^3*b^2
+ 15*a*b^4)*cosh(x)^3 - 3*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x))*sinh(x)^5 + 8*a^5 + 20*a^3*b^2 + 15*a*b^4 +
 6*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^4 + 2*(24*a^5 + 60*a^3*b^2 + 45*a*b^4 + 35*(8*a^5 + 20*a^3*b^2 + 15
*a*b^4)*cosh(x)^4 - 30*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^2)*sinh(x)^4 + 8*(7*(8*a^5 + 20*a^3*b^2 + 15*a*
b^4)*cosh(x)^5 - 10*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^3 + 3*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x))*sin
h(x)^3 - 4*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^2 + 4*(7*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^6 - 8*a^5
- 20*a^3*b^2 - 15*a*b^4 - 15*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^4 + 9*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cos
h(x)^2)*sinh(x)^2 + 8*((8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^7 - 3*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^5
 + 3*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^3 - (8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x))*sinh(x))*log(cosh(x)
 + sinh(x) + 1) + 3*((8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^8 + 8*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)*sin
h(x)^7 + (8*a^5 + 20*a^3*b^2 + 15*a*b^4)*sinh(x)^8 - 4*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^6 - 4*(8*a^5 +
20*a^3*b^2 + 15*a*b^4 - 7*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^2)*sinh(x)^6 + 8*(7*(8*a^5 + 20*a^3*b^2 + 15
*a*b^4)*cosh(x)^3 - 3*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x))*sinh(x)^5 + 8*a^5 + 20*a^3*b^2 + 15*a*b^4 + 6*(
8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^4 + 2*(24*a^5 + 60*a^3*b^2 + 45*a*b^4 + 35*(8*a^5 + 20*a^3*b^2 + 15*a*b
^4)*cosh(x)^4 - 30*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^2)*sinh(x)^4 + 8*(7*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)
*cosh(x)^5 - 10*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^3 + 3*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x))*sinh(x)
^3 - 4*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^2 + 4*(7*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^6 - 8*a^5 - 20
*a^3*b^2 - 15*a*b^4 - 15*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^4 + 9*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)
^2)*sinh(x)^2 + 8*((8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^7 - 3*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^5 + 3
*(8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x)^3 - (8*a^5 + 20*a^3*b^2 + 15*a*b^4)*cosh(x))*sinh(x))*log(cosh(x) + s
inh(x) - 1) + 2*(96*b^5*x*cosh(x)^7 - 21*(4*a^3*b^2 + 9*a*b^4)*cosh(x)^6 - 144*(2*b^5*x - a^4*b - 3*a^2*b^3)*c
osh(x)^5 - 12*a^3*b^2 - 27*a*b^4 + 15*(4*a^3*b^2 + a*b^4)*cosh(x)^4 + 96*(3*b^5*x - 3*a^4*b - 7*a^2*b^3)*cosh(
x)^3 + 9*(4*a^3*b^2 + a*b^4)*cosh(x)^2 - 16*(6*b^5*x - 9*a^4*b - 19*a^2*b^3)*cosh(x))*sinh(x))/(a*b^5*cosh(x)^
8 + 8*a*b^5*cosh(x)*sinh(x)^7 + a*b^5*sinh(x)^8 - 4*a*b^5*cosh(x)^6 + 6*a*b^5*cosh(x)^4 - 4*a*b^5*cosh(x)^2 +
4*(7*a*b^5*cosh(x)^2 - a*b^5)*sinh(x)^6 + a*b^5 + 8*(7*a*b^5*cosh(x)^3 - 3*a*b^5*cosh(x))*sinh(x)^5 + 2*(35*a*
b^5*cosh(x)^4 - 30*a*b^5*cosh(x)^2 + 3*a*b^5)*sinh(x)^4 + 8*(7*a*b^5*cosh(x)^5 - 10*a*b^5*cosh(x)^3 + 3*a*b^5*
cosh(x))*sinh(x)^3 + 4*(7*a*b^5*cosh(x)^6 - 15*a*b^5*cosh(x)^4 + 9*a*b^5*cosh(x)^2 - a*b^5)*sinh(x)^2 + 8*(a*b
^5*cosh(x)^7 - 3*a*b^5*cosh(x)^5 + 3*a*b^5*cosh(x)^3 - a*b^5*cosh(x))*sinh(x))

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\coth ^{6}{\left (x \right )}}{a + b \operatorname{csch}{\left (x \right )}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(coth(x)**6/(a+b*csch(x)),x)

[Out]

Integral(coth(x)**6/(a + b*csch(x)), x)

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Giac [A]  time = 1.16333, size = 412, normalized size = 2.25 \begin{align*} \frac{x}{a} - \frac{{\left (8 \, a^{4} + 20 \, a^{2} b^{2} + 15 \, b^{4}\right )} \log \left (e^{x} + 1\right )}{8 \, b^{5}} + \frac{{\left (8 \, a^{4} + 20 \, a^{2} b^{2} + 15 \, b^{4}\right )} \log \left ({\left | e^{x} - 1 \right |}\right )}{8 \, b^{5}} - \frac{{\left (a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}\right )} \log \left (\frac{{\left | 2 \, a e^{x} + 2 \, b - 2 \, \sqrt{a^{2} + b^{2}} \right |}}{{\left | 2 \, a e^{x} + 2 \, b + 2 \, \sqrt{a^{2} + b^{2}} \right |}}\right )}{\sqrt{a^{2} + b^{2}} a b^{5}} - \frac{12 \, a^{2} b e^{\left (7 \, x\right )} + 27 \, b^{3} e^{\left (7 \, x\right )} - 24 \, a^{3} e^{\left (6 \, x\right )} - 72 \, a b^{2} e^{\left (6 \, x\right )} - 12 \, a^{2} b e^{\left (5 \, x\right )} - 3 \, b^{3} e^{\left (5 \, x\right )} + 72 \, a^{3} e^{\left (4 \, x\right )} + 168 \, a b^{2} e^{\left (4 \, x\right )} - 12 \, a^{2} b e^{\left (3 \, x\right )} - 3 \, b^{3} e^{\left (3 \, x\right )} - 72 \, a^{3} e^{\left (2 \, x\right )} - 152 \, a b^{2} e^{\left (2 \, x\right )} + 12 \, a^{2} b e^{x} + 27 \, b^{3} e^{x} + 24 \, a^{3} + 56 \, a b^{2}}{12 \, b^{4}{\left (e^{\left (2 \, x\right )} - 1\right )}^{4}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(coth(x)^6/(a+b*csch(x)),x, algorithm="giac")

[Out]

x/a - 1/8*(8*a^4 + 20*a^2*b^2 + 15*b^4)*log(e^x + 1)/b^5 + 1/8*(8*a^4 + 20*a^2*b^2 + 15*b^4)*log(abs(e^x - 1))
/b^5 - (a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*log(abs(2*a*e^x + 2*b - 2*sqrt(a^2 + b^2))/abs(2*a*e^x + 2*b + 2*sq
rt(a^2 + b^2)))/(sqrt(a^2 + b^2)*a*b^5) - 1/12*(12*a^2*b*e^(7*x) + 27*b^3*e^(7*x) - 24*a^3*e^(6*x) - 72*a*b^2*
e^(6*x) - 12*a^2*b*e^(5*x) - 3*b^3*e^(5*x) + 72*a^3*e^(4*x) + 168*a*b^2*e^(4*x) - 12*a^2*b*e^(3*x) - 3*b^3*e^(
3*x) - 72*a^3*e^(2*x) - 152*a*b^2*e^(2*x) + 12*a^2*b*e^x + 27*b^3*e^x + 24*a^3 + 56*a*b^2)/(b^4*(e^(2*x) - 1)^
4)