3.101 \(\int \frac{\text{sech}^5(x)}{a+b \text{csch}(x)} \, dx\)

Optimal. Leaf size=149 \[ -\frac{a^4 b \log (a \sinh (x)+b)}{\left (a^2+b^2\right )^3}-\frac{\text{sech}^4(x) (b-a \sinh (x))}{4 \left (a^2+b^2\right )}-\frac{\text{sech}^2(x) \left (4 a^2 b-a \left (3 a^2-b^2\right ) \sinh (x)\right )}{8 \left (a^2+b^2\right )^2}-\frac{a (b+3 i a) \log (-\sinh (x)+i)}{16 (a-i b)^3}+\frac{a (3 a+i b) \log (\sinh (x)+i)}{16 (-b+i a)^3} \]

[Out]

-(a*((3*I)*a + b)*Log[I - Sinh[x]])/(16*(a - I*b)^3) + (a*(3*a + I*b)*Log[I + Sinh[x]])/(16*(I*a - b)^3) - (a^
4*b*Log[b + a*Sinh[x]])/(a^2 + b^2)^3 - (Sech[x]^4*(b - a*Sinh[x]))/(4*(a^2 + b^2)) - (Sech[x]^2*(4*a^2*b - a*
(3*a^2 - b^2)*Sinh[x]))/(8*(a^2 + b^2)^2)

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Rubi [A]  time = 0.340972, antiderivative size = 149, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.385, Rules used = {3872, 2837, 12, 823, 801} \[ -\frac{a^4 b \log (a \sinh (x)+b)}{\left (a^2+b^2\right )^3}-\frac{\text{sech}^4(x) (b-a \sinh (x))}{4 \left (a^2+b^2\right )}-\frac{\text{sech}^2(x) \left (4 a^2 b-a \left (3 a^2-b^2\right ) \sinh (x)\right )}{8 \left (a^2+b^2\right )^2}-\frac{a (b+3 i a) \log (-\sinh (x)+i)}{16 (a-i b)^3}+\frac{a (3 a+i b) \log (\sinh (x)+i)}{16 (-b+i a)^3} \]

Antiderivative was successfully verified.

[In]

Int[Sech[x]^5/(a + b*Csch[x]),x]

[Out]

-(a*((3*I)*a + b)*Log[I - Sinh[x]])/(16*(a - I*b)^3) + (a*(3*a + I*b)*Log[I + Sinh[x]])/(16*(I*a - b)^3) - (a^
4*b*Log[b + a*Sinh[x]])/(a^2 + b^2)^3 - (Sech[x]^4*(b - a*Sinh[x]))/(4*(a^2 + b^2)) - (Sech[x]^2*(4*a^2*b - a*
(3*a^2 - b^2)*Sinh[x]))/(8*(a^2 + b^2)^2)

Rule 3872

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_.)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_.), x_Symbol] :> Int[((g*C
os[e + f*x])^p*(b + a*Sin[e + f*x])^m)/Sin[e + f*x]^m, x] /; FreeQ[{a, b, e, f, g, p}, x] && IntegerQ[m]

Rule 2837

Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)
*(x_)])^(n_.), x_Symbol] :> Dist[1/(b^p*f), Subst[Int[(a + x)^m*(c + (d*x)/b)^n*(b^2 - x^2)^((p - 1)/2), x], x
, b*Sin[e + f*x]], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IntegerQ[(p - 1)/2] && NeQ[a^2 - b^2, 0]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 823

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> -Simp[((d + e*x)^(
m + 1)*(f*a*c*e - a*g*c*d + c*(c*d*f + a*e*g)*x)*(a + c*x^2)^(p + 1))/(2*a*c*(p + 1)*(c*d^2 + a*e^2)), x] + Di
st[1/(2*a*c*(p + 1)*(c*d^2 + a*e^2)), Int[(d + e*x)^m*(a + c*x^2)^(p + 1)*Simp[f*(c^2*d^2*(2*p + 3) + a*c*e^2*
(m + 2*p + 3)) - a*c*d*e*g*m + c*e*(c*d*f + a*e*g)*(m + 2*p + 4)*x, x], x], x] /; FreeQ[{a, c, d, e, f, g}, x]
&& NeQ[c*d^2 + a*e^2, 0] && LtQ[p, -1] && (IntegerQ[m] || IntegerQ[p] || IntegersQ[2*m, 2*p])

Rule 801

Int[(((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_)))/((a_) + (c_.)*(x_)^2), x_Symbol] :> Int[ExpandIntegrand[(
(d + e*x)^m*(f + g*x))/(a + c*x^2), x], x] /; FreeQ[{a, c, d, e, f, g}, x] && NeQ[c*d^2 + a*e^2, 0] && Integer
Q[m]

Rubi steps

\begin{align*} \int \frac{\text{sech}^5(x)}{a+b \text{csch}(x)} \, dx &=i \int \frac{\text{sech}^4(x) \tanh (x)}{i b+i a \sinh (x)} \, dx\\ &=-\left (\left (i a^5\right ) \operatorname{Subst}\left (\int \frac{x}{a (i b+x) \left (a^2-x^2\right )^3} \, dx,x,i a \sinh (x)\right )\right )\\ &=-\left (\left (i a^4\right ) \operatorname{Subst}\left (\int \frac{x}{(i b+x) \left (a^2-x^2\right )^3} \, dx,x,i a \sinh (x)\right )\right )\\ &=-\frac{\text{sech}^4(x) (b-a \sinh (x))}{4 \left (a^2+b^2\right )}-\frac{\left (i a^2\right ) \operatorname{Subst}\left (\int \frac{-i a^2 b+3 a^2 x}{(i b+x) \left (a^2-x^2\right )^2} \, dx,x,i a \sinh (x)\right )}{4 \left (a^2+b^2\right )}\\ &=-\frac{\text{sech}^4(x) (b-a \sinh (x))}{4 \left (a^2+b^2\right )}-\frac{\text{sech}^2(x) \left (4 a^2 b-a \left (3 a^2-b^2\right ) \sinh (x)\right )}{8 \left (a^2+b^2\right )^2}-\frac{i \operatorname{Subst}\left (\int \frac{-i a^2 b \left (5 a^2+b^2\right )+a^2 \left (3 a^2-b^2\right ) x}{(i b+x) \left (a^2-x^2\right )} \, dx,x,i a \sinh (x)\right )}{8 \left (a^2+b^2\right )^2}\\ &=-\frac{\text{sech}^4(x) (b-a \sinh (x))}{4 \left (a^2+b^2\right )}-\frac{\text{sech}^2(x) \left (4 a^2 b-a \left (3 a^2-b^2\right ) \sinh (x)\right )}{8 \left (a^2+b^2\right )^2}-\frac{i \operatorname{Subst}\left (\int \left (\frac{a (a-i b)^2 (3 a+i b)}{2 (a+i b) (a-x)}-\frac{8 a^4 b}{\left (a^2+b^2\right ) (b-i x)}+\frac{a (3 a-i b) (a+i b)^2}{2 (a-i b) (a+x)}\right ) \, dx,x,i a \sinh (x)\right )}{8 \left (a^2+b^2\right )^2}\\ &=-\frac{a (3 i a+b) \log (i-\sinh (x))}{16 (a-i b)^3}+\frac{a (3 a+i b) \log (i+\sinh (x))}{16 (i a-b)^3}-\frac{a^4 b \log (b+a \sinh (x))}{\left (a^2+b^2\right )^3}-\frac{\text{sech}^4(x) (b-a \sinh (x))}{4 \left (a^2+b^2\right )}-\frac{\text{sech}^2(x) \left (4 a^2 b-a \left (3 a^2-b^2\right ) \sinh (x)\right )}{8 \left (a^2+b^2\right )^2}\\ \end{align*}

Mathematica [A]  time = 0.274322, size = 138, normalized size = 0.93 \[ \frac{-4 a^2 b \left (a^2+b^2\right ) \text{sech}^2(x)-2 b \left (a^2+b^2\right )^2 \text{sech}^4(x)+2 a \left (-6 a^2 b^2+3 a^4-b^4\right ) \tan ^{-1}\left (\tanh \left (\frac{x}{2}\right )\right )+2 a \left (a^2+b^2\right )^2 \tanh (x) \text{sech}^3(x)+a \left (2 a^2 b^2+3 a^4-b^4\right ) \tanh (x) \text{sech}(x)+8 a^4 b (\log (\cosh (x))-\log (a \sinh (x)+b))}{8 \left (a^2+b^2\right )^3} \]

Antiderivative was successfully verified.

[In]

Integrate[Sech[x]^5/(a + b*Csch[x]),x]

[Out]

(2*a*(3*a^4 - 6*a^2*b^2 - b^4)*ArcTan[Tanh[x/2]] + 8*a^4*b*(Log[Cosh[x]] - Log[b + a*Sinh[x]]) - 4*a^2*b*(a^2
+ b^2)*Sech[x]^2 - 2*b*(a^2 + b^2)^2*Sech[x]^4 + a*(3*a^4 + 2*a^2*b^2 - b^4)*Sech[x]*Tanh[x] + 2*a*(a^2 + b^2)
^2*Sech[x]^3*Tanh[x])/(8*(a^2 + b^2)^3)

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Maple [B]  time = 0.046, size = 1168, normalized size = 7.8 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sech(x)^5/(a+b*csch(x)),x)

[Out]

-3/2/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^7*a^3*b^2+6/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(
tanh(1/2*x)^2+1)^4*tanh(1/2*x)^2*a^2*b^3+3/2/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)*a^3
*b^2-1/4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^7*a*b^4+4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)
/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^6*a^4*b+4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^4*a^2
*b^3-5/2/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^3*a^3*b^2-7/4/(a^4+2*a^2*b^2+b^4)/(a^2+
b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^3*a*b^4+4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^2
*a^4*b+1/4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)*a*b^4+6/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)
/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^6*a^2*b^3+5/2/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^5
*a^3*b^2+7/4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^5*a*b^4+4/(a^4+2*a^2*b^2+b^4)/(a^2+
b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^4*a^4*b+3/4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)*arctan(tanh(1/2*x))*a^5+2/(a^4+
2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^6*b^5-a^4*b/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)*ln(tanh(1/2
*x)^2*b-2*a*tanh(1/2*x)-b)-1/4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)*arctan(tanh(1/2*x))*a*b^4+1/(a^4+2*a^2*b^2+b^4)/(
a^2+b^2)*ln(tanh(1/2*x)^2+1)*a^4*b+3/4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^5*a^5-3/4
/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^3*a^5+2/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2
*x)^2+1)^4*tanh(1/2*x)^2*b^5-5/4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tanh(1/2*x)^7*a^5-3/2/(a^4+
2*a^2*b^2+b^4)/(a^2+b^2)*arctan(tanh(1/2*x))*a^3*b^2+5/4/(a^4+2*a^2*b^2+b^4)/(a^2+b^2)/(tanh(1/2*x)^2+1)^4*tan
h(1/2*x)*a^5

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Maxima [B]  time = 1.58297, size = 470, normalized size = 3.15 \begin{align*} -\frac{a^{4} b \log \left (-2 \, b e^{\left (-x\right )} + a e^{\left (-2 \, x\right )} - a\right )}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} + \frac{a^{4} b \log \left (e^{\left (-2 \, x\right )} + 1\right )}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} - \frac{{\left (3 \, a^{5} - 6 \, a^{3} b^{2} - a b^{4}\right )} \arctan \left (e^{\left (-x\right )}\right )}{4 \,{\left (a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}\right )}} - \frac{8 \, a^{2} b e^{\left (-2 \, x\right )} + 8 \, a^{2} b e^{\left (-6 \, x\right )} -{\left (3 \, a^{3} - a b^{2}\right )} e^{\left (-x\right )} -{\left (11 \, a^{3} + 7 \, a b^{2}\right )} e^{\left (-3 \, x\right )} + 16 \,{\left (2 \, a^{2} b + b^{3}\right )} e^{\left (-4 \, x\right )} +{\left (11 \, a^{3} + 7 \, a b^{2}\right )} e^{\left (-5 \, x\right )} +{\left (3 \, a^{3} - a b^{2}\right )} e^{\left (-7 \, x\right )}}{4 \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4} + 4 \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )} e^{\left (-2 \, x\right )} + 6 \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )} e^{\left (-4 \, x\right )} + 4 \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )} e^{\left (-6 \, x\right )} +{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )} e^{\left (-8 \, x\right )}\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(x)^5/(a+b*csch(x)),x, algorithm="maxima")

[Out]

-a^4*b*log(-2*b*e^(-x) + a*e^(-2*x) - a)/(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6) + a^4*b*log(e^(-2*x) + 1)/(a^6 +
3*a^4*b^2 + 3*a^2*b^4 + b^6) - 1/4*(3*a^5 - 6*a^3*b^2 - a*b^4)*arctan(e^(-x))/(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b
^6) - 1/4*(8*a^2*b*e^(-2*x) + 8*a^2*b*e^(-6*x) - (3*a^3 - a*b^2)*e^(-x) - (11*a^3 + 7*a*b^2)*e^(-3*x) + 16*(2*
a^2*b + b^3)*e^(-4*x) + (11*a^3 + 7*a*b^2)*e^(-5*x) + (3*a^3 - a*b^2)*e^(-7*x))/(a^4 + 2*a^2*b^2 + b^4 + 4*(a^
4 + 2*a^2*b^2 + b^4)*e^(-2*x) + 6*(a^4 + 2*a^2*b^2 + b^4)*e^(-4*x) + 4*(a^4 + 2*a^2*b^2 + b^4)*e^(-6*x) + (a^4
+ 2*a^2*b^2 + b^4)*e^(-8*x))

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Fricas [B]  time = 2.28082, size = 6677, normalized size = 44.81 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(x)^5/(a+b*csch(x)),x, algorithm="fricas")

[Out]

1/4*((3*a^5 + 2*a^3*b^2 - a*b^4)*cosh(x)^7 + (3*a^5 + 2*a^3*b^2 - a*b^4)*sinh(x)^7 - 8*(a^4*b + a^2*b^3)*cosh(
x)^6 - (8*a^4*b + 8*a^2*b^3 - 7*(3*a^5 + 2*a^3*b^2 - a*b^4)*cosh(x))*sinh(x)^6 + (11*a^5 + 18*a^3*b^2 + 7*a*b^
4)*cosh(x)^5 + (11*a^5 + 18*a^3*b^2 + 7*a*b^4 + 21*(3*a^5 + 2*a^3*b^2 - a*b^4)*cosh(x)^2 - 48*(a^4*b + a^2*b^3
)*cosh(x))*sinh(x)^5 - 16*(2*a^4*b + 3*a^2*b^3 + b^5)*cosh(x)^4 - (32*a^4*b + 48*a^2*b^3 + 16*b^5 - 35*(3*a^5
+ 2*a^3*b^2 - a*b^4)*cosh(x)^3 + 120*(a^4*b + a^2*b^3)*cosh(x)^2 - 5*(11*a^5 + 18*a^3*b^2 + 7*a*b^4)*cosh(x))*
sinh(x)^4 - (11*a^5 + 18*a^3*b^2 + 7*a*b^4)*cosh(x)^3 - (11*a^5 + 18*a^3*b^2 + 7*a*b^4 - 35*(3*a^5 + 2*a^3*b^2
- a*b^4)*cosh(x)^4 + 160*(a^4*b + a^2*b^3)*cosh(x)^3 - 10*(11*a^5 + 18*a^3*b^2 + 7*a*b^4)*cosh(x)^2 + 64*(2*a
^4*b + 3*a^2*b^3 + b^5)*cosh(x))*sinh(x)^3 - 8*(a^4*b + a^2*b^3)*cosh(x)^2 + (21*(3*a^5 + 2*a^3*b^2 - a*b^4)*c
osh(x)^5 - 8*a^4*b - 8*a^2*b^3 - 120*(a^4*b + a^2*b^3)*cosh(x)^4 + 10*(11*a^5 + 18*a^3*b^2 + 7*a*b^4)*cosh(x)^
3 - 96*(2*a^4*b + 3*a^2*b^3 + b^5)*cosh(x)^2 - 3*(11*a^5 + 18*a^3*b^2 + 7*a*b^4)*cosh(x))*sinh(x)^2 + ((3*a^5
- 6*a^3*b^2 - a*b^4)*cosh(x)^8 + 8*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)*sinh(x)^7 + (3*a^5 - 6*a^3*b^2 - a*b^4)
*sinh(x)^8 + 4*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^6 + 4*(3*a^5 - 6*a^3*b^2 - a*b^4 + 7*(3*a^5 - 6*a^3*b^2 - a
*b^4)*cosh(x)^2)*sinh(x)^6 + 8*(7*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^3 + 3*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x
))*sinh(x)^5 + 3*a^5 - 6*a^3*b^2 - a*b^4 + 6*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^4 + 2*(9*a^5 - 18*a^3*b^2 - 3
*a*b^4 + 35*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^4 + 30*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^2)*sinh(x)^4 + 8*(7
*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^5 + 10*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^3 + 3*(3*a^5 - 6*a^3*b^2 - a*b
^4)*cosh(x))*sinh(x)^3 + 4*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^2 + 4*(7*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^6
+ 3*a^5 - 6*a^3*b^2 - a*b^4 + 15*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^4 + 9*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)
^2)*sinh(x)^2 + 8*((3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^7 + 3*(3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x)^5 + 3*(3*a^5
- 6*a^3*b^2 - a*b^4)*cosh(x)^3 + (3*a^5 - 6*a^3*b^2 - a*b^4)*cosh(x))*sinh(x))*arctan(cosh(x) + sinh(x)) - (3*
a^5 + 2*a^3*b^2 - a*b^4)*cosh(x) - 4*(a^4*b*cosh(x)^8 + 8*a^4*b*cosh(x)*sinh(x)^7 + a^4*b*sinh(x)^8 + 4*a^4*b*
cosh(x)^6 + 6*a^4*b*cosh(x)^4 + 4*a^4*b*cosh(x)^2 + 4*(7*a^4*b*cosh(x)^2 + a^4*b)*sinh(x)^6 + 8*(7*a^4*b*cosh(
x)^3 + 3*a^4*b*cosh(x))*sinh(x)^5 + a^4*b + 2*(35*a^4*b*cosh(x)^4 + 30*a^4*b*cosh(x)^2 + 3*a^4*b)*sinh(x)^4 +
8*(7*a^4*b*cosh(x)^5 + 10*a^4*b*cosh(x)^3 + 3*a^4*b*cosh(x))*sinh(x)^3 + 4*(7*a^4*b*cosh(x)^6 + 15*a^4*b*cosh(
x)^4 + 9*a^4*b*cosh(x)^2 + a^4*b)*sinh(x)^2 + 8*(a^4*b*cosh(x)^7 + 3*a^4*b*cosh(x)^5 + 3*a^4*b*cosh(x)^3 + a^4
*b*cosh(x))*sinh(x))*log(2*(a*sinh(x) + b)/(cosh(x) - sinh(x))) + 4*(a^4*b*cosh(x)^8 + 8*a^4*b*cosh(x)*sinh(x)
^7 + a^4*b*sinh(x)^8 + 4*a^4*b*cosh(x)^6 + 6*a^4*b*cosh(x)^4 + 4*a^4*b*cosh(x)^2 + 4*(7*a^4*b*cosh(x)^2 + a^4*
b)*sinh(x)^6 + 8*(7*a^4*b*cosh(x)^3 + 3*a^4*b*cosh(x))*sinh(x)^5 + a^4*b + 2*(35*a^4*b*cosh(x)^4 + 30*a^4*b*co
sh(x)^2 + 3*a^4*b)*sinh(x)^4 + 8*(7*a^4*b*cosh(x)^5 + 10*a^4*b*cosh(x)^3 + 3*a^4*b*cosh(x))*sinh(x)^3 + 4*(7*a
^4*b*cosh(x)^6 + 15*a^4*b*cosh(x)^4 + 9*a^4*b*cosh(x)^2 + a^4*b)*sinh(x)^2 + 8*(a^4*b*cosh(x)^7 + 3*a^4*b*cosh
(x)^5 + 3*a^4*b*cosh(x)^3 + a^4*b*cosh(x))*sinh(x))*log(2*cosh(x)/(cosh(x) - sinh(x))) + (7*(3*a^5 + 2*a^3*b^2
- a*b^4)*cosh(x)^6 - 48*(a^4*b + a^2*b^3)*cosh(x)^5 - 3*a^5 - 2*a^3*b^2 + a*b^4 + 5*(11*a^5 + 18*a^3*b^2 + 7*
a*b^4)*cosh(x)^4 - 64*(2*a^4*b + 3*a^2*b^3 + b^5)*cosh(x)^3 - 3*(11*a^5 + 18*a^3*b^2 + 7*a*b^4)*cosh(x)^2 - 16
*(a^4*b + a^2*b^3)*cosh(x))*sinh(x))/((a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^8 + 8*(a^6 + 3*a^4*b^2 + 3*a
^2*b^4 + b^6)*cosh(x)*sinh(x)^7 + (a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*sinh(x)^8 + 4*(a^6 + 3*a^4*b^2 + 3*a^2*b
^4 + b^6)*cosh(x)^6 + 4*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6 + 7*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^2)*
sinh(x)^6 + a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6 + 8*(7*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^3 + 3*(a^6 +
3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x))*sinh(x)^5 + 6*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^4 + 2*(3*a^6 +
9*a^4*b^2 + 9*a^2*b^4 + 3*b^6 + 35*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^4 + 30*(a^6 + 3*a^4*b^2 + 3*a^
2*b^4 + b^6)*cosh(x)^2)*sinh(x)^4 + 8*(7*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^5 + 10*(a^6 + 3*a^4*b^2 +
3*a^2*b^4 + b^6)*cosh(x)^3 + 3*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x))*sinh(x)^3 + 4*(a^6 + 3*a^4*b^2 +
3*a^2*b^4 + b^6)*cosh(x)^2 + 4*(7*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^6 + a^6 + 3*a^4*b^2 + 3*a^2*b^4
+ b^6 + 15*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^4 + 9*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^2)*si
nh(x)^2 + 8*((a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^7 + 3*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^5 +
3*(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x)^3 + (a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6)*cosh(x))*sinh(x))

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{sech}^{5}{\left (x \right )}}{a + b \operatorname{csch}{\left (x \right )}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(x)**5/(a+b*csch(x)),x)

[Out]

Integral(sech(x)**5/(a + b*csch(x)), x)

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Giac [B]  time = 1.1783, size = 505, normalized size = 3.39 \begin{align*} -\frac{a^{5} b \log \left ({\left | -a{\left (e^{\left (-x\right )} - e^{x}\right )} + 2 \, b \right |}\right )}{a^{7} + 3 \, a^{5} b^{2} + 3 \, a^{3} b^{4} + a b^{6}} + \frac{a^{4} b \log \left ({\left (e^{\left (-x\right )} - e^{x}\right )}^{2} + 4\right )}{2 \,{\left (a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}\right )}} + \frac{{\left (\pi + 2 \, \arctan \left (\frac{1}{2} \,{\left (e^{\left (2 \, x\right )} - 1\right )} e^{\left (-x\right )}\right )\right )}{\left (3 \, a^{5} - 6 \, a^{3} b^{2} - a b^{4}\right )}}{16 \,{\left (a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}\right )}} - \frac{3 \, a^{4} b{\left (e^{\left (-x\right )} - e^{x}\right )}^{4} + 3 \, a^{5}{\left (e^{\left (-x\right )} - e^{x}\right )}^{3} + 2 \, a^{3} b^{2}{\left (e^{\left (-x\right )} - e^{x}\right )}^{3} - a b^{4}{\left (e^{\left (-x\right )} - e^{x}\right )}^{3} + 32 \, a^{4} b{\left (e^{\left (-x\right )} - e^{x}\right )}^{2} + 8 \, a^{2} b^{3}{\left (e^{\left (-x\right )} - e^{x}\right )}^{2} + 20 \, a^{5}{\left (e^{\left (-x\right )} - e^{x}\right )} + 24 \, a^{3} b^{2}{\left (e^{\left (-x\right )} - e^{x}\right )} + 4 \, a b^{4}{\left (e^{\left (-x\right )} - e^{x}\right )} + 96 \, a^{4} b + 64 \, a^{2} b^{3} + 16 \, b^{5}}{4 \,{\left (a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}\right )}{\left ({\left (e^{\left (-x\right )} - e^{x}\right )}^{2} + 4\right )}^{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(x)^5/(a+b*csch(x)),x, algorithm="giac")

[Out]

-a^5*b*log(abs(-a*(e^(-x) - e^x) + 2*b))/(a^7 + 3*a^5*b^2 + 3*a^3*b^4 + a*b^6) + 1/2*a^4*b*log((e^(-x) - e^x)^
2 + 4)/(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6) + 1/16*(pi + 2*arctan(1/2*(e^(2*x) - 1)*e^(-x)))*(3*a^5 - 6*a^3*b^2
- a*b^4)/(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6) - 1/4*(3*a^4*b*(e^(-x) - e^x)^4 + 3*a^5*(e^(-x) - e^x)^3 + 2*a^3
*b^2*(e^(-x) - e^x)^3 - a*b^4*(e^(-x) - e^x)^3 + 32*a^4*b*(e^(-x) - e^x)^2 + 8*a^2*b^3*(e^(-x) - e^x)^2 + 20*a
^5*(e^(-x) - e^x) + 24*a^3*b^2*(e^(-x) - e^x) + 4*a*b^4*(e^(-x) - e^x) + 96*a^4*b + 64*a^2*b^3 + 16*b^5)/((a^6
+ 3*a^4*b^2 + 3*a^2*b^4 + b^6)*((e^(-x) - e^x)^2 + 4)^2)