Optimal. Leaf size=112 \[ -\frac{b x \left (a^2+2 b^2\right )}{2 a^4}+\frac{\left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^3}+\frac{2 b^4 \tan ^{-1}\left (\frac{\sqrt{a-b} \tanh \left (\frac{x}{2}\right )}{\sqrt{a+b}}\right )}{a^4 \sqrt{a-b} \sqrt{a+b}}-\frac{b \sinh (x) \cosh (x)}{2 a^2}+\frac{\sinh (x) \cosh ^2(x)}{3 a} \]
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Rubi [A] time = 0.423414, antiderivative size = 112, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.462, Rules used = {3853, 4104, 3919, 3831, 2659, 205} \[ -\frac{b x \left (a^2+2 b^2\right )}{2 a^4}+\frac{\left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^3}+\frac{2 b^4 \tan ^{-1}\left (\frac{\sqrt{a-b} \tanh \left (\frac{x}{2}\right )}{\sqrt{a+b}}\right )}{a^4 \sqrt{a-b} \sqrt{a+b}}-\frac{b \sinh (x) \cosh (x)}{2 a^2}+\frac{\sinh (x) \cosh ^2(x)}{3 a} \]
Antiderivative was successfully verified.
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Rule 3853
Rule 4104
Rule 3919
Rule 3831
Rule 2659
Rule 205
Rubi steps
\begin{align*} \int \frac{\cosh ^3(x)}{a+b \text{sech}(x)} \, dx &=\frac{\cosh ^2(x) \sinh (x)}{3 a}+\frac{\int \frac{\cosh ^2(x) \left (-3 b+2 a \text{sech}(x)+2 b \text{sech}^2(x)\right )}{a+b \text{sech}(x)} \, dx}{3 a}\\ &=-\frac{b \cosh (x) \sinh (x)}{2 a^2}+\frac{\cosh ^2(x) \sinh (x)}{3 a}-\frac{\int \frac{\cosh (x) \left (-2 \left (2 a^2+3 b^2\right )-a b \text{sech}(x)+3 b^2 \text{sech}^2(x)\right )}{a+b \text{sech}(x)} \, dx}{6 a^2}\\ &=\frac{\left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^3}-\frac{b \cosh (x) \sinh (x)}{2 a^2}+\frac{\cosh ^2(x) \sinh (x)}{3 a}+\frac{\int \frac{-3 b \left (a^2+2 b^2\right )-3 a b^2 \text{sech}(x)}{a+b \text{sech}(x)} \, dx}{6 a^3}\\ &=-\frac{b \left (a^2+2 b^2\right ) x}{2 a^4}+\frac{\left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^3}-\frac{b \cosh (x) \sinh (x)}{2 a^2}+\frac{\cosh ^2(x) \sinh (x)}{3 a}+\frac{b^4 \int \frac{\text{sech}(x)}{a+b \text{sech}(x)} \, dx}{a^4}\\ &=-\frac{b \left (a^2+2 b^2\right ) x}{2 a^4}+\frac{\left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^3}-\frac{b \cosh (x) \sinh (x)}{2 a^2}+\frac{\cosh ^2(x) \sinh (x)}{3 a}+\frac{b^3 \int \frac{1}{1+\frac{a \cosh (x)}{b}} \, dx}{a^4}\\ &=-\frac{b \left (a^2+2 b^2\right ) x}{2 a^4}+\frac{\left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^3}-\frac{b \cosh (x) \sinh (x)}{2 a^2}+\frac{\cosh ^2(x) \sinh (x)}{3 a}+\frac{\left (2 b^3\right ) \operatorname{Subst}\left (\int \frac{1}{1+\frac{a}{b}-\left (1-\frac{a}{b}\right ) x^2} \, dx,x,\tanh \left (\frac{x}{2}\right )\right )}{a^4}\\ &=-\frac{b \left (a^2+2 b^2\right ) x}{2 a^4}+\frac{2 b^4 \tan ^{-1}\left (\frac{\sqrt{a-b} \tanh \left (\frac{x}{2}\right )}{\sqrt{a+b}}\right )}{a^4 \sqrt{a-b} \sqrt{a+b}}+\frac{\left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^3}-\frac{b \cosh (x) \sinh (x)}{2 a^2}+\frac{\cosh ^2(x) \sinh (x)}{3 a}\\ \end{align*}
Mathematica [A] time = 0.159893, size = 99, normalized size = 0.88 \[ \frac{-6 b x \left (a^2+2 b^2\right )+3 a \left (3 a^2+4 b^2\right ) \sinh (x)-\frac{24 b^4 \tan ^{-1}\left (\frac{(b-a) \tanh \left (\frac{x}{2}\right )}{\sqrt{a^2-b^2}}\right )}{\sqrt{a^2-b^2}}-3 a^2 b \sinh (2 x)+a^3 \sinh (3 x)}{12 a^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.036, size = 264, normalized size = 2.4 \begin{align*} -{\frac{1}{3\,a} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-3}}+{\frac{1}{2\,a} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-2}}+{\frac{b}{2\,{a}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-2}}-{\frac{1}{a} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-1}}-{\frac{b}{2\,{a}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-1}}-{\frac{{b}^{2}}{{a}^{3}} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-1}}-{\frac{b}{2\,{a}^{2}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) }-{\frac{{b}^{3}}{{a}^{4}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) }-{\frac{1}{3\,a} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-3}}-{\frac{1}{2\,a} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-2}}-{\frac{b}{2\,{a}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-2}}-{\frac{1}{a} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-1}}-{\frac{b}{2\,{a}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-1}}-{\frac{{b}^{2}}{{a}^{3}} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-1}}+{\frac{b}{2\,{a}^{2}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) }+{\frac{{b}^{3}}{{a}^{4}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) }+2\,{\frac{{b}^{4}}{{a}^{4}\sqrt{ \left ( a+b \right ) \left ( a-b \right ) }}\arctan \left ({\frac{ \left ( a-b \right ) \tanh \left ( x/2 \right ) }{\sqrt{ \left ( a+b \right ) \left ( a-b \right ) }}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.69503, size = 3675, normalized size = 32.81 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cosh ^{3}{\left (x \right )}}{a + b \operatorname{sech}{\left (x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.14753, size = 180, normalized size = 1.61 \begin{align*} \frac{2 \, b^{4} \arctan \left (\frac{a e^{x} + b}{\sqrt{a^{2} - b^{2}}}\right )}{\sqrt{a^{2} - b^{2}} a^{4}} + \frac{a^{2} e^{\left (3 \, x\right )} - 3 \, a b e^{\left (2 \, x\right )} + 9 \, a^{2} e^{x} + 12 \, b^{2} e^{x}}{24 \, a^{3}} - \frac{{\left (a^{2} b + 2 \, b^{3}\right )} x}{2 \, a^{4}} + \frac{{\left (3 \, a^{2} b e^{x} - a^{3} - 3 \,{\left (3 \, a^{3} + 4 \, a b^{2}\right )} e^{\left (2 \, x\right )}\right )} e^{\left (-3 \, x\right )}}{24 \, a^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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