Optimal. Leaf size=98 \[ \frac{2 a^{5/2} \tanh ^{-1}\left (\frac{\sqrt{a} \tanh (c+d x)}{\sqrt{a \text{sech}(c+d x)+a}}\right )}{d}+\frac{14 a^3 \tanh (c+d x)}{3 d \sqrt{a \text{sech}(c+d x)+a}}+\frac{2 a^2 \tanh (c+d x) \sqrt{a \text{sech}(c+d x)+a}}{3 d} \]
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Rubi [A] time = 0.120318, antiderivative size = 98, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.357, Rules used = {3775, 3915, 3774, 203, 3792} \[ \frac{2 a^{5/2} \tanh ^{-1}\left (\frac{\sqrt{a} \tanh (c+d x)}{\sqrt{a \text{sech}(c+d x)+a}}\right )}{d}+\frac{14 a^3 \tanh (c+d x)}{3 d \sqrt{a \text{sech}(c+d x)+a}}+\frac{2 a^2 \tanh (c+d x) \sqrt{a \text{sech}(c+d x)+a}}{3 d} \]
Antiderivative was successfully verified.
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Rule 3775
Rule 3915
Rule 3774
Rule 203
Rule 3792
Rubi steps
\begin{align*} \int (a+a \text{sech}(c+d x))^{5/2} \, dx &=\frac{2 a^2 \sqrt{a+a \text{sech}(c+d x)} \tanh (c+d x)}{3 d}+\frac{1}{3} (2 a) \int \sqrt{a+a \text{sech}(c+d x)} \left (\frac{3 a}{2}+\frac{7}{2} a \text{sech}(c+d x)\right ) \, dx\\ &=\frac{2 a^2 \sqrt{a+a \text{sech}(c+d x)} \tanh (c+d x)}{3 d}+a^2 \int \sqrt{a+a \text{sech}(c+d x)} \, dx+\frac{1}{3} \left (7 a^2\right ) \int \text{sech}(c+d x) \sqrt{a+a \text{sech}(c+d x)} \, dx\\ &=\frac{14 a^3 \tanh (c+d x)}{3 d \sqrt{a+a \text{sech}(c+d x)}}+\frac{2 a^2 \sqrt{a+a \text{sech}(c+d x)} \tanh (c+d x)}{3 d}+\frac{\left (2 i a^3\right ) \operatorname{Subst}\left (\int \frac{1}{a+x^2} \, dx,x,-\frac{i a \tanh (c+d x)}{\sqrt{a+a \text{sech}(c+d x)}}\right )}{d}\\ &=\frac{2 a^{5/2} \tanh ^{-1}\left (\frac{\sqrt{a} \tanh (c+d x)}{\sqrt{a+a \text{sech}(c+d x)}}\right )}{d}+\frac{14 a^3 \tanh (c+d x)}{3 d \sqrt{a+a \text{sech}(c+d x)}}+\frac{2 a^2 \sqrt{a+a \text{sech}(c+d x)} \tanh (c+d x)}{3 d}\\ \end{align*}
Mathematica [A] time = 0.327859, size = 99, normalized size = 1.01 \[ \frac{a^2 \text{sech}\left (\frac{1}{2} (c+d x)\right ) \text{sech}(c+d x) \sqrt{a (\text{sech}(c+d x)+1)} \left (-6 \sinh \left (\frac{1}{2} (c+d x)\right )+8 \sinh \left (\frac{3}{2} (c+d x)\right )+3 \sqrt{2} \sinh ^{-1}\left (\sqrt{2} \sinh \left (\frac{1}{2} (c+d x)\right )\right ) \cosh ^{\frac{3}{2}}(c+d x)\right )}{3 d} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.178, size = 0, normalized size = 0. \begin{align*} \int \left ( a+a{\rm sech} \left (dx+c\right ) \right ) ^{{\frac{5}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a \operatorname{sech}\left (d x + c\right ) + a\right )}^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.77612, size = 2558, normalized size = 26.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.36297, size = 216, normalized size = 2.2 \begin{align*} \frac{\frac{48 \, a^{3} \arctan \left (-\frac{\sqrt{a} e^{\left (d x + c\right )} - \sqrt{a e^{\left (2 \, d x + 2 \, c\right )} + a}}{\sqrt{-a}}\right )}{\sqrt{-a}} + \frac{4 \,{\left ({\left ({\left (\frac{4 \, e^{\left (d x - 3 \, c\right )}}{a^{2}} - \frac{3 \, e^{\left (-4 \, c\right )}}{a^{2}}\right )} e^{\left (d x\right )} + \frac{3 \, e^{\left (-5 \, c\right )}}{a^{2}}\right )} e^{\left (d x\right )} - \frac{4 \, e^{\left (-6 \, c\right )}}{a^{2}}\right )}}{{\left (a e^{\left (2 \, d x + 2 \, c\right )} + a\right )}^{\frac{3}{2}}} - \frac{3 \, e^{\left (-6 \, c\right )} \log \left ({\left | -\sqrt{a} e^{\left (d x + c\right )} + \sqrt{a e^{\left (2 \, d x + 2 \, c\right )} + a} \right |}\right )}{a^{\frac{7}{2}}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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