Optimal. Leaf size=316 \[ -\frac{2 b^4}{a d \left (a^2-b^2\right )^2 \sqrt{a+b \text{sech}(c+d x)}}+\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a}}\right )}{a^{3/2} d}-\frac{\sqrt{a+b \text{sech}(c+d x)}}{4 d (a+b)^2 (1-\text{sech}(c+d x))}-\frac{\sqrt{a+b \text{sech}(c+d x)}}{4 d (a-b)^2 (\text{sech}(c+d x)+1)}+\frac{b \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a-b}}\right )}{4 d (a-b)^{5/2}}-\frac{b \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a+b}}\right )}{4 d (a+b)^{5/2}}-\frac{(2 a-3 b) \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a-b}}\right )}{2 d (a-b)^{5/2}}-\frac{(2 a+3 b) \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a+b}}\right )}{2 d (a+b)^{5/2}} \]
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Rubi [A] time = 0.426842, antiderivative size = 316, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 5, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.217, Rules used = {3885, 898, 1335, 206, 199} \[ -\frac{2 b^4}{a d \left (a^2-b^2\right )^2 \sqrt{a+b \text{sech}(c+d x)}}+\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a}}\right )}{a^{3/2} d}-\frac{\sqrt{a+b \text{sech}(c+d x)}}{4 d (a+b)^2 (1-\text{sech}(c+d x))}-\frac{\sqrt{a+b \text{sech}(c+d x)}}{4 d (a-b)^2 (\text{sech}(c+d x)+1)}+\frac{b \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a-b}}\right )}{4 d (a-b)^{5/2}}-\frac{b \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a+b}}\right )}{4 d (a+b)^{5/2}}-\frac{(2 a-3 b) \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a-b}}\right )}{2 d (a-b)^{5/2}}-\frac{(2 a+3 b) \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a+b}}\right )}{2 d (a+b)^{5/2}} \]
Antiderivative was successfully verified.
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Rule 3885
Rule 898
Rule 1335
Rule 206
Rule 199
Rubi steps
\begin{align*} \int \frac{\coth ^3(c+d x)}{(a+b \text{sech}(c+d x))^{3/2}} \, dx &=-\frac{b^4 \operatorname{Subst}\left (\int \frac{1}{x (a+x)^{3/2} \left (b^2-x^2\right )^2} \, dx,x,b \text{sech}(c+d x)\right )}{d}\\ &=-\frac{\left (2 b^4\right ) \operatorname{Subst}\left (\int \frac{1}{x^2 \left (-a+x^2\right ) \left (-a^2+b^2+2 a x^2-x^4\right )^2} \, dx,x,\sqrt{a+b \text{sech}(c+d x)}\right )}{d}\\ &=-\frac{\left (2 b^4\right ) \operatorname{Subst}\left (\int \left (-\frac{1}{a (a-b)^2 (a+b)^2 x^2}-\frac{1}{a b^4 \left (a-x^2\right )}-\frac{1}{4 (a-b) b^3 \left (a-b-x^2\right )^2}+\frac{2 a-3 b}{4 (a-b)^2 b^4 \left (a-b-x^2\right )}+\frac{1}{4 b^3 (a+b) \left (a+b-x^2\right )^2}+\frac{2 a+3 b}{4 b^4 (a+b)^2 \left (a+b-x^2\right )}\right ) \, dx,x,\sqrt{a+b \text{sech}(c+d x)}\right )}{d}\\ &=-\frac{2 b^4}{a \left (a^2-b^2\right )^2 d \sqrt{a+b \text{sech}(c+d x)}}+\frac{2 \operatorname{Subst}\left (\int \frac{1}{a-x^2} \, dx,x,\sqrt{a+b \text{sech}(c+d x)}\right )}{a d}-\frac{(2 a-3 b) \operatorname{Subst}\left (\int \frac{1}{a-b-x^2} \, dx,x,\sqrt{a+b \text{sech}(c+d x)}\right )}{2 (a-b)^2 d}+\frac{b \operatorname{Subst}\left (\int \frac{1}{\left (a-b-x^2\right )^2} \, dx,x,\sqrt{a+b \text{sech}(c+d x)}\right )}{2 (a-b) d}-\frac{b \operatorname{Subst}\left (\int \frac{1}{\left (a+b-x^2\right )^2} \, dx,x,\sqrt{a+b \text{sech}(c+d x)}\right )}{2 (a+b) d}-\frac{(2 a+3 b) \operatorname{Subst}\left (\int \frac{1}{a+b-x^2} \, dx,x,\sqrt{a+b \text{sech}(c+d x)}\right )}{2 (a+b)^2 d}\\ &=\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a}}\right )}{a^{3/2} d}-\frac{(2 a-3 b) \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a-b}}\right )}{2 (a-b)^{5/2} d}-\frac{(2 a+3 b) \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a+b}}\right )}{2 (a+b)^{5/2} d}-\frac{2 b^4}{a \left (a^2-b^2\right )^2 d \sqrt{a+b \text{sech}(c+d x)}}-\frac{\sqrt{a+b \text{sech}(c+d x)}}{4 (a+b)^2 d (1-\text{sech}(c+d x))}-\frac{\sqrt{a+b \text{sech}(c+d x)}}{4 (a-b)^2 d (1+\text{sech}(c+d x))}+\frac{b \operatorname{Subst}\left (\int \frac{1}{a-b-x^2} \, dx,x,\sqrt{a+b \text{sech}(c+d x)}\right )}{4 (a-b)^2 d}-\frac{b \operatorname{Subst}\left (\int \frac{1}{a+b-x^2} \, dx,x,\sqrt{a+b \text{sech}(c+d x)}\right )}{4 (a+b)^2 d}\\ &=\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a}}\right )}{a^{3/2} d}-\frac{(2 a-3 b) \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a-b}}\right )}{2 (a-b)^{5/2} d}+\frac{b \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a-b}}\right )}{4 (a-b)^{5/2} d}-\frac{b \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a+b}}\right )}{4 (a+b)^{5/2} d}-\frac{(2 a+3 b) \tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}(c+d x)}}{\sqrt{a+b}}\right )}{2 (a+b)^{5/2} d}-\frac{2 b^4}{a \left (a^2-b^2\right )^2 d \sqrt{a+b \text{sech}(c+d x)}}-\frac{\sqrt{a+b \text{sech}(c+d x)}}{4 (a+b)^2 d (1-\text{sech}(c+d x))}-\frac{\sqrt{a+b \text{sech}(c+d x)}}{4 (a-b)^2 d (1+\text{sech}(c+d x))}\\ \end{align*}
Mathematica [B] time = 7.52323, size = 996, normalized size = 3.15 \[ \frac{(b+a \cosh (c+d x))^2 \left (\frac{2 b^5}{a^2 \left (a^2-b^2\right )^2 (b+a \cosh (c+d x))}+\frac{\left (-a^2+2 b \cosh (c+d x) a-b^2\right ) \text{csch}^2(c+d x)}{2 \left (b^2-a^2\right )^2}-\frac{a^4+b^2 a^2+4 b^4}{2 a^2 \left (b^2-a^2\right )^2}\right ) \text{sech}^2(c+d x)}{d (a+b \text{sech}(c+d x))^{3/2}}+\frac{(b+a \cosh (c+d x))^{3/2} \left (\frac{\left (2 a^4-4 b^2 a^2+2 b^4\right ) \left (\sqrt{a} \left (\sqrt{a+b} \tan ^{-1}\left (\frac{\sqrt{a} \sqrt{b+a \cosh (c+d x)}}{\sqrt{a-b} \sqrt{-a \cosh (c+d x)}}\right )+\sqrt{a-b} \tan ^{-1}\left (\frac{\sqrt{a} \sqrt{b+a \cosh (c+d x)}}{\sqrt{a+b} \sqrt{-a \cosh (c+d x)}}\right )\right )-4 \sqrt{a-b} \sqrt{a+b} \tan ^{-1}\left (\frac{\sqrt{b+a \cosh (c+d x)}}{\sqrt{-a \cosh (c+d x)}}\right )\right ) \sqrt{-a \cosh (c+d x)} \sqrt{\frac{a \cosh (c+d x)-a}{\cosh (c+d x) a+a}} \cosh (2 (c+d x)) \sqrt{\text{sech}(c+d x)} (\cosh (c+d x) a+a)}{\sqrt{a-b} \sqrt{a+b} \sqrt{\cosh (c+d x)-1} \sqrt{\cosh (c+d x)+1} \left (a^2-2 b^2-2 (b+a \cosh (c+d x))^2+4 b (b+a \cosh (c+d x))\right )}-\frac{\left (2 a^4-6 b^2 a^2-2 b^4\right ) \left (\sqrt{a+b} \tanh ^{-1}\left (\frac{\sqrt{a} \sqrt{b+a \cosh (c+d x)}}{\sqrt{a-b} \sqrt{a \cosh (c+d x)}}\right )+\sqrt{a-b} \tanh ^{-1}\left (\frac{\sqrt{a} \sqrt{b+a \cosh (c+d x)}}{\sqrt{a+b} \sqrt{a \cosh (c+d x)}}\right )\right ) \sqrt{a \cosh (c+d x)} \sqrt{\frac{a \cosh (c+d x)-a}{\cosh (c+d x) a+a}} \sqrt{\text{sech}(c+d x)} (\cosh (c+d x) a+a)}{a^{3/2} \sqrt{a-b} \sqrt{a+b} \sqrt{\cosh (c+d x)-1} \sqrt{\cosh (c+d x)+1}}+\frac{\left (7 a b^3-a^3 b\right ) \left (\sqrt{a-b} \tan ^{-1}\left (\frac{\sqrt{a} \sqrt{b+a \cosh (c+d x)}}{\sqrt{-a-b} \sqrt{a \cosh (c+d x)}}\right )+\sqrt{-a-b} \tanh ^{-1}\left (\frac{\sqrt{a} \sqrt{b+a \cosh (c+d x)}}{\sqrt{a-b} \sqrt{a \cosh (c+d x)}}\right )\right ) \sqrt{\frac{a \cosh (c+d x)-a}{\cosh (c+d x) a+a}} (\cosh (c+d x) a+a)}{\sqrt{a} \sqrt{-a-b} \sqrt{a-b} \sqrt{\cosh (c+d x)-1} \sqrt{a \cosh (c+d x)} \sqrt{\cosh (c+d x)+1} \sqrt{\text{sech}(c+d x)}}\right ) \text{sech}^{\frac{3}{2}}(c+d x)}{4 a (a-b)^2 (a+b)^2 d (a+b \text{sech}(c+d x))^{3/2}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.167, size = 0, normalized size = 0. \begin{align*} \int{ \left ({\rm coth} \left (dx+c\right ) \right ) ^{3} \left ( a+b{\rm sech} \left (dx+c\right ) \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\coth \left (d x + c\right )^{3}}{{\left (b \operatorname{sech}\left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\coth ^{3}{\left (c + d x \right )}}{\left (a + b \operatorname{sech}{\left (c + d x \right )}\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\coth \left (d x + c\right )^{3}}{{\left (b \operatorname{sech}\left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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