Optimal. Leaf size=83 \[ \frac{e^{c (a+b x)} \tanh (a c+b c x) \sqrt{\coth ^2(a c+b c x)}}{b c}-\frac{2 \tanh ^{-1}\left (e^{c (a+b x)}\right ) \tanh (a c+b c x) \sqrt{\coth ^2(a c+b c x)}}{b c} \]
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Rubi [A] time = 0.143621, antiderivative size = 83, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.16, Rules used = {6720, 2282, 388, 206} \[ \frac{e^{c (a+b x)} \tanh (a c+b c x) \sqrt{\coth ^2(a c+b c x)}}{b c}-\frac{2 \tanh ^{-1}\left (e^{c (a+b x)}\right ) \tanh (a c+b c x) \sqrt{\coth ^2(a c+b c x)}}{b c} \]
Antiderivative was successfully verified.
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Rule 6720
Rule 2282
Rule 388
Rule 206
Rubi steps
\begin{align*} \int e^{c (a+b x)} \sqrt{\coth ^2(a c+b c x)} \, dx &=\left (\sqrt{\coth ^2(a c+b c x)} \tanh (a c+b c x)\right ) \int e^{c (a+b x)} \coth (a c+b c x) \, dx\\ &=\frac{\left (\sqrt{\coth ^2(a c+b c x)} \tanh (a c+b c x)\right ) \operatorname{Subst}\left (\int \frac{-1-x^2}{1-x^2} \, dx,x,e^{c (a+b x)}\right )}{b c}\\ &=\frac{e^{c (a+b x)} \sqrt{\coth ^2(a c+b c x)} \tanh (a c+b c x)}{b c}-\frac{\left (2 \sqrt{\coth ^2(a c+b c x)} \tanh (a c+b c x)\right ) \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,e^{c (a+b x)}\right )}{b c}\\ &=\frac{e^{c (a+b x)} \sqrt{\coth ^2(a c+b c x)} \tanh (a c+b c x)}{b c}-\frac{2 \tanh ^{-1}\left (e^{c (a+b x)}\right ) \sqrt{\coth ^2(a c+b c x)} \tanh (a c+b c x)}{b c}\\ \end{align*}
Mathematica [A] time = 0.0577475, size = 51, normalized size = 0.61 \[ \frac{\left (e^{c (a+b x)}-2 \tanh ^{-1}\left (e^{c (a+b x)}\right )\right ) \tanh (c (a+b x)) \sqrt{\coth ^2(c (a+b x))}}{b c} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.238, size = 213, normalized size = 2.6 \begin{align*}{\frac{ \left ({{\rm e}^{2\,c \left ( bx+a \right ) }}-1 \right ){{\rm e}^{c \left ( bx+a \right ) }}}{ \left ( 1+{{\rm e}^{2\,c \left ( bx+a \right ) }} \right ) cb}\sqrt{{\frac{ \left ( 1+{{\rm e}^{2\,c \left ( bx+a \right ) }} \right ) ^{2}}{ \left ({{\rm e}^{2\,c \left ( bx+a \right ) }}-1 \right ) ^{2}}}}}+{\frac{ \left ({{\rm e}^{2\,c \left ( bx+a \right ) }}-1 \right ) \ln \left ({{\rm e}^{c \left ( bx+a \right ) }}-1 \right ) }{ \left ( 1+{{\rm e}^{2\,c \left ( bx+a \right ) }} \right ) cb}\sqrt{{\frac{ \left ( 1+{{\rm e}^{2\,c \left ( bx+a \right ) }} \right ) ^{2}}{ \left ({{\rm e}^{2\,c \left ( bx+a \right ) }}-1 \right ) ^{2}}}}}-{\frac{ \left ({{\rm e}^{2\,c \left ( bx+a \right ) }}-1 \right ) \ln \left ({{\rm e}^{c \left ( bx+a \right ) }}+1 \right ) }{ \left ( 1+{{\rm e}^{2\,c \left ( bx+a \right ) }} \right ) cb}\sqrt{{\frac{ \left ( 1+{{\rm e}^{2\,c \left ( bx+a \right ) }} \right ) ^{2}}{ \left ({{\rm e}^{2\,c \left ( bx+a \right ) }}-1 \right ) ^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.70541, size = 76, normalized size = 0.92 \begin{align*} \frac{e^{\left (b c x + a c\right )}}{b c} - \frac{\log \left (e^{\left (b c x + a c\right )} + 1\right )}{b c} + \frac{\log \left (e^{\left (b c x + a c\right )} - 1\right )}{b c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.37335, size = 196, normalized size = 2.36 \begin{align*} \frac{\cosh \left (b c x + a c\right ) - \log \left (\cosh \left (b c x + a c\right ) + \sinh \left (b c x + a c\right ) + 1\right ) + \log \left (\cosh \left (b c x + a c\right ) + \sinh \left (b c x + a c\right ) - 1\right ) + \sinh \left (b c x + a c\right )}{b c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.1916, size = 127, normalized size = 1.53 \begin{align*} \frac{\frac{e^{\left (b c x + a c\right )}}{\mathrm{sgn}\left (e^{\left (2 \, b c x + 2 \, a c\right )} - 1\right )} - \frac{\log \left (e^{\left (b c x + a c\right )} + 1\right )}{\mathrm{sgn}\left (e^{\left (2 \, b c x + 2 \, a c\right )} - 1\right )} + \frac{\log \left ({\left | e^{\left (b c x + a c\right )} - 1 \right |}\right )}{\mathrm{sgn}\left (e^{\left (2 \, b c x + 2 \, a c\right )} - 1\right )}}{b c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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