Optimal. Leaf size=116 \[ e^x+\frac{\log \left (-\sqrt{2} e^x+e^{2 x}+1\right )}{4 \sqrt{2}}-\frac{\log \left (\sqrt{2} e^x+e^{2 x}+1\right )}{4 \sqrt{2}}-\frac{1}{2} \tan ^{-1}\left (e^x\right )+\frac{\tan ^{-1}\left (1-\sqrt{2} e^x\right )}{2 \sqrt{2}}-\frac{\tan ^{-1}\left (\sqrt{2} e^x+1\right )}{2 \sqrt{2}}-\frac{1}{2} \tanh ^{-1}\left (e^x\right ) \]
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Rubi [A] time = 0.0777028, antiderivative size = 116, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 12, integrand size = 8, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 1.5, Rules used = {2282, 388, 214, 212, 206, 203, 211, 1165, 628, 1162, 617, 204} \[ e^x+\frac{\log \left (-\sqrt{2} e^x+e^{2 x}+1\right )}{4 \sqrt{2}}-\frac{\log \left (\sqrt{2} e^x+e^{2 x}+1\right )}{4 \sqrt{2}}-\frac{1}{2} \tan ^{-1}\left (e^x\right )+\frac{\tan ^{-1}\left (1-\sqrt{2} e^x\right )}{2 \sqrt{2}}-\frac{\tan ^{-1}\left (\sqrt{2} e^x+1\right )}{2 \sqrt{2}}-\frac{1}{2} \tanh ^{-1}\left (e^x\right ) \]
Antiderivative was successfully verified.
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Rule 2282
Rule 388
Rule 214
Rule 212
Rule 206
Rule 203
Rule 211
Rule 1165
Rule 628
Rule 1162
Rule 617
Rule 204
Rubi steps
\begin{align*} \int e^x \coth (4 x) \, dx &=\operatorname{Subst}\left (\int \frac{-1-x^8}{1-x^8} \, dx,x,e^x\right )\\ &=e^x-2 \operatorname{Subst}\left (\int \frac{1}{1-x^8} \, dx,x,e^x\right )\\ &=e^x-\operatorname{Subst}\left (\int \frac{1}{1-x^4} \, dx,x,e^x\right )-\operatorname{Subst}\left (\int \frac{1}{1+x^4} \, dx,x,e^x\right )\\ &=e^x-\frac{1}{2} \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,e^x\right )-\frac{1}{2} \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,e^x\right )-\frac{1}{2} \operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,e^x\right )-\frac{1}{2} \operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,e^x\right )\\ &=e^x-\frac{1}{2} \tan ^{-1}\left (e^x\right )-\frac{1}{2} \tanh ^{-1}\left (e^x\right )-\frac{1}{4} \operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,e^x\right )-\frac{1}{4} \operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,e^x\right )+\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,e^x\right )}{4 \sqrt{2}}+\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,e^x\right )}{4 \sqrt{2}}\\ &=e^x-\frac{1}{2} \tan ^{-1}\left (e^x\right )-\frac{1}{2} \tanh ^{-1}\left (e^x\right )+\frac{\log \left (1-\sqrt{2} e^x+e^{2 x}\right )}{4 \sqrt{2}}-\frac{\log \left (1+\sqrt{2} e^x+e^{2 x}\right )}{4 \sqrt{2}}-\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\sqrt{2} e^x\right )}{2 \sqrt{2}}+\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\sqrt{2} e^x\right )}{2 \sqrt{2}}\\ &=e^x-\frac{1}{2} \tan ^{-1}\left (e^x\right )+\frac{\tan ^{-1}\left (1-\sqrt{2} e^x\right )}{2 \sqrt{2}}-\frac{\tan ^{-1}\left (1+\sqrt{2} e^x\right )}{2 \sqrt{2}}-\frac{1}{2} \tanh ^{-1}\left (e^x\right )+\frac{\log \left (1-\sqrt{2} e^x+e^{2 x}\right )}{4 \sqrt{2}}-\frac{\log \left (1+\sqrt{2} e^x+e^{2 x}\right )}{4 \sqrt{2}}\\ \end{align*}
Mathematica [C] time = 0.0164104, size = 22, normalized size = 0.19 \[ e^x-2 e^x \, _2F_1\left (\frac{1}{8},1;\frac{9}{8};e^{8 x}\right ) \]
Antiderivative was successfully verified.
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Maple [C] time = 0.07, size = 56, normalized size = 0.5 \begin{align*}{{\rm e}^{x}}-{\frac{\ln \left ({{\rm e}^{x}}+1 \right ) }{4}}+{\frac{\ln \left ({{\rm e}^{x}}-1 \right ) }{4}}+{\frac{i}{4}}\ln \left ({{\rm e}^{x}}-i \right ) -{\frac{i}{4}}\ln \left ({{\rm e}^{x}}+i \right ) +\sum _{{\it \_R}={\it RootOf} \left ( 256\,{{\it \_Z}}^{4}+1 \right ) }{\it \_R}\,\ln \left ({{\rm e}^{x}}-4\,{\it \_R} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.69206, size = 131, normalized size = 1.13 \begin{align*} -\frac{1}{4} \, \sqrt{2} \arctan \left (\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} + 2 \, e^{x}\right )}\right ) - \frac{1}{4} \, \sqrt{2} \arctan \left (-\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} - 2 \, e^{x}\right )}\right ) - \frac{1}{8} \, \sqrt{2} \log \left (\sqrt{2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) + \frac{1}{8} \, \sqrt{2} \log \left (-\sqrt{2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) - \frac{1}{2} \, \arctan \left (e^{x}\right ) + e^{x} - \frac{1}{4} \, \log \left (e^{x} + 1\right ) + \frac{1}{4} \, \log \left (e^{x} - 1\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.10871, size = 447, normalized size = 3.85 \begin{align*} \frac{1}{2} \, \sqrt{2} \arctan \left (-\sqrt{2} e^{x} + \sqrt{2} \sqrt{\sqrt{2} e^{x} + e^{\left (2 \, x\right )} + 1} - 1\right ) + \frac{1}{2} \, \sqrt{2} \arctan \left (-\sqrt{2} e^{x} + \frac{1}{2} \, \sqrt{2} \sqrt{-4 \, \sqrt{2} e^{x} + 4 \, e^{\left (2 \, x\right )} + 4} + 1\right ) - \frac{1}{8} \, \sqrt{2} \log \left (4 \, \sqrt{2} e^{x} + 4 \, e^{\left (2 \, x\right )} + 4\right ) + \frac{1}{8} \, \sqrt{2} \log \left (-4 \, \sqrt{2} e^{x} + 4 \, e^{\left (2 \, x\right )} + 4\right ) - \frac{1}{2} \, \arctan \left (e^{x}\right ) + e^{x} - \frac{1}{4} \, \log \left (e^{x} + 1\right ) + \frac{1}{4} \, \log \left (e^{x} - 1\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int e^{x} \coth{\left (4 x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.3042, size = 132, normalized size = 1.14 \begin{align*} -\frac{1}{4} \, \sqrt{2} \arctan \left (\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} + 2 \, e^{x}\right )}\right ) - \frac{1}{4} \, \sqrt{2} \arctan \left (-\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} - 2 \, e^{x}\right )}\right ) - \frac{1}{8} \, \sqrt{2} \log \left (\sqrt{2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) + \frac{1}{8} \, \sqrt{2} \log \left (-\sqrt{2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) - \frac{1}{2} \, \arctan \left (e^{x}\right ) + e^{x} - \frac{1}{4} \, \log \left (e^{x} + 1\right ) + \frac{1}{4} \, \log \left ({\left | e^{x} - 1 \right |}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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