3.194 \(\int \frac{\tanh ^{\frac{5}{2}}(a+b \log (c x^n))}{x} \, dx\)

Optimal. Leaf size=73 \[ -\frac{2 \tanh ^{\frac{3}{2}}\left (a+b \log \left (c x^n\right )\right )}{3 b n}+\frac{\tanh ^{-1}\left (\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{b n}-\frac{\tan ^{-1}\left (\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{b n} \]

[Out]

-(ArcTan[Sqrt[Tanh[a + b*Log[c*x^n]]]]/(b*n)) + ArcTanh[Sqrt[Tanh[a + b*Log[c*x^n]]]]/(b*n) - (2*Tanh[a + b*Lo
g[c*x^n]]^(3/2))/(3*b*n)

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Rubi [A]  time = 0.0527211, antiderivative size = 73, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.316, Rules used = {3473, 3476, 329, 298, 203, 206} \[ -\frac{2 \tanh ^{\frac{3}{2}}\left (a+b \log \left (c x^n\right )\right )}{3 b n}+\frac{\tanh ^{-1}\left (\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{b n}-\frac{\tan ^{-1}\left (\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{b n} \]

Antiderivative was successfully verified.

[In]

Int[Tanh[a + b*Log[c*x^n]]^(5/2)/x,x]

[Out]

-(ArcTan[Sqrt[Tanh[a + b*Log[c*x^n]]]]/(b*n)) + ArcTanh[Sqrt[Tanh[a + b*Log[c*x^n]]]]/(b*n) - (2*Tanh[a + b*Lo
g[c*x^n]]^(3/2))/(3*b*n)

Rule 3473

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*(b*Tan[c + d*x])^(n - 1))/(d*(n - 1)), x] - Dis
t[b^2, Int[(b*Tan[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1]

Rule 3476

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Dist[b/d, Subst[Int[x^n/(b^2 + x^2), x], x, b*Tan[c + d
*x]], x] /; FreeQ[{b, c, d, n}, x] &&  !IntegerQ[n]

Rule 329

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + (b*x^(k*n))/c^n)^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 298

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-(a/b), 2]], s = Denominator[Rt[-(a/b),
2]]}, Dist[s/(2*b), Int[1/(r + s*x^2), x], x] - Dist[s/(2*b), Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &
&  !GtQ[a/b, 0]

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{\tanh ^{\frac{5}{2}}\left (a+b \log \left (c x^n\right )\right )}{x} \, dx &=\frac{\operatorname{Subst}\left (\int \tanh ^{\frac{5}{2}}(a+b x) \, dx,x,\log \left (c x^n\right )\right )}{n}\\ &=-\frac{2 \tanh ^{\frac{3}{2}}\left (a+b \log \left (c x^n\right )\right )}{3 b n}+\frac{\operatorname{Subst}\left (\int \sqrt{\tanh (a+b x)} \, dx,x,\log \left (c x^n\right )\right )}{n}\\ &=-\frac{2 \tanh ^{\frac{3}{2}}\left (a+b \log \left (c x^n\right )\right )}{3 b n}-\frac{\operatorname{Subst}\left (\int \frac{\sqrt{x}}{-1+x^2} \, dx,x,\tanh \left (a+b \log \left (c x^n\right )\right )\right )}{b n}\\ &=-\frac{2 \tanh ^{\frac{3}{2}}\left (a+b \log \left (c x^n\right )\right )}{3 b n}-\frac{2 \operatorname{Subst}\left (\int \frac{x^2}{-1+x^4} \, dx,x,\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{b n}\\ &=-\frac{2 \tanh ^{\frac{3}{2}}\left (a+b \log \left (c x^n\right )\right )}{3 b n}+\frac{\operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{b n}-\frac{\operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{b n}\\ &=-\frac{\tan ^{-1}\left (\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{b n}+\frac{\tanh ^{-1}\left (\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{b n}-\frac{2 \tanh ^{\frac{3}{2}}\left (a+b \log \left (c x^n\right )\right )}{3 b n}\\ \end{align*}

Mathematica [A]  time = 0.285213, size = 64, normalized size = 0.88 \[ -\frac{2 \tanh ^{\frac{3}{2}}\left (a+b \log \left (c x^n\right )\right )-3 \tanh ^{-1}\left (\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )+3 \tan ^{-1}\left (\sqrt{\tanh \left (a+b \log \left (c x^n\right )\right )}\right )}{3 b n} \]

Antiderivative was successfully verified.

[In]

Integrate[Tanh[a + b*Log[c*x^n]]^(5/2)/x,x]

[Out]

-(3*ArcTan[Sqrt[Tanh[a + b*Log[c*x^n]]]] - 3*ArcTanh[Sqrt[Tanh[a + b*Log[c*x^n]]]] + 2*Tanh[a + b*Log[c*x^n]]^
(3/2))/(3*b*n)

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Maple [A]  time = 0.023, size = 93, normalized size = 1.3 \begin{align*} -{\frac{2}{3\,bn} \left ( \tanh \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) \right ) ^{{\frac{3}{2}}}}-{\frac{1}{2\,bn}\ln \left ( \sqrt{\tanh \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) }-1 \right ) }+{\frac{1}{2\,bn}\ln \left ( \sqrt{\tanh \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) }+1 \right ) }-{\frac{1}{bn}\arctan \left ( \sqrt{\tanh \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) } \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tanh(a+b*ln(c*x^n))^(5/2)/x,x)

[Out]

-2/3*tanh(a+b*ln(c*x^n))^(3/2)/b/n-1/2/b/n*ln(tanh(a+b*ln(c*x^n))^(1/2)-1)+1/2/b/n*ln(tanh(a+b*ln(c*x^n))^(1/2
)+1)-arctan(tanh(a+b*ln(c*x^n))^(1/2))/b/n

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\tanh \left (b \log \left (c x^{n}\right ) + a\right )^{\frac{5}{2}}}{x}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(a+b*log(c*x^n))^(5/2)/x,x, algorithm="maxima")

[Out]

integrate(tanh(b*log(c*x^n) + a)^(5/2)/x, x)

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Fricas [B]  time = 2.23465, size = 2091, normalized size = 28.64 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(a+b*log(c*x^n))^(5/2)/x,x, algorithm="fricas")

[Out]

-1/6*(6*(cosh(b*n*log(x) + b*log(c) + a)^2 + 2*cosh(b*n*log(x) + b*log(c) + a)*sinh(b*n*log(x) + b*log(c) + a)
+ sinh(b*n*log(x) + b*log(c) + a)^2 + 1)*arctan(-cosh(b*n*log(x) + b*log(c) + a)^2 - 2*cosh(b*n*log(x) + b*lo
g(c) + a)*sinh(b*n*log(x) + b*log(c) + a) - sinh(b*n*log(x) + b*log(c) + a)^2 + (cosh(b*n*log(x) + b*log(c) +
a)^2 + 2*cosh(b*n*log(x) + b*log(c) + a)*sinh(b*n*log(x) + b*log(c) + a) + sinh(b*n*log(x) + b*log(c) + a)^2 +
1)*sqrt(sinh(b*n*log(x) + b*log(c) + a)/cosh(b*n*log(x) + b*log(c) + a))) + 4*cosh(b*n*log(x) + b*log(c) + a)
^2 + 3*(cosh(b*n*log(x) + b*log(c) + a)^2 + 2*cosh(b*n*log(x) + b*log(c) + a)*sinh(b*n*log(x) + b*log(c) + a)
+ sinh(b*n*log(x) + b*log(c) + a)^2 + 1)*log(-cosh(b*n*log(x) + b*log(c) + a)^2 - 2*cosh(b*n*log(x) + b*log(c)
+ a)*sinh(b*n*log(x) + b*log(c) + a) - sinh(b*n*log(x) + b*log(c) + a)^2 + (cosh(b*n*log(x) + b*log(c) + a)^2
+ 2*cosh(b*n*log(x) + b*log(c) + a)*sinh(b*n*log(x) + b*log(c) + a) + sinh(b*n*log(x) + b*log(c) + a)^2 + 1)*
sqrt(sinh(b*n*log(x) + b*log(c) + a)/cosh(b*n*log(x) + b*log(c) + a))) + 8*cosh(b*n*log(x) + b*log(c) + a)*sin
h(b*n*log(x) + b*log(c) + a) + 4*sinh(b*n*log(x) + b*log(c) + a)^2 + 4*(cosh(b*n*log(x) + b*log(c) + a)^2 + 2*
cosh(b*n*log(x) + b*log(c) + a)*sinh(b*n*log(x) + b*log(c) + a) + sinh(b*n*log(x) + b*log(c) + a)^2 - 1)*sqrt(
sinh(b*n*log(x) + b*log(c) + a)/cosh(b*n*log(x) + b*log(c) + a)) + 4)/(b*n*cosh(b*n*log(x) + b*log(c) + a)^2 +
2*b*n*cosh(b*n*log(x) + b*log(c) + a)*sinh(b*n*log(x) + b*log(c) + a) + b*n*sinh(b*n*log(x) + b*log(c) + a)^2
+ b*n)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(a+b*ln(c*x**n))**(5/2)/x,x)

[Out]

Timed out

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Giac [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(a+b*log(c*x^n))^(5/2)/x,x, algorithm="giac")

[Out]

Timed out