Optimal. Leaf size=307 \[ -\frac{(e x)^{m+1} \left (2 b^2 d^2 n^2+m^2+2 m+1\right ) \, _2F_1\left (1,\frac{m+1}{2 b d n};\frac{m+1}{2 b d n}+1;-e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{b^2 d^2 e (m+1) n^2}+\frac{e^{-2 a d} (e x)^{m+1} \left (\frac{e^{2 a d} (-2 b d n+m+1)}{n}-\frac{e^{4 a d} (2 b d n+m+1) \left (c x^n\right )^{2 b d}}{n}\right )}{2 b^2 d^2 e n \left (e^{2 a d} \left (c x^n\right )^{2 b d}+1\right )}-\frac{(e x)^{m+1} \left (1-e^{2 a d} \left (c x^n\right )^{2 b d}\right )^2}{2 b d e n \left (e^{2 a d} \left (c x^n\right )^{2 b d}+1\right )^2}+\frac{(e x)^{m+1} (b d n+m+1) (2 b d n+m+1)}{2 b^2 d^2 e (m+1) n^2} \]
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Rubi [F] time = 0.071333, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int (e x)^m \tanh ^3\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin{align*} \int (e x)^m \tanh ^3\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx &=\int (e x)^m \tanh ^3\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx\\ \end{align*}
Mathematica [A] time = 16.7604, size = 606, normalized size = 1.97 \[ \frac{x^{-m} (e x)^m \left (2 b^2 d^2 n^2+m^2+2 m+1\right ) \text{sech}\left (d \left (a+b \left (\log \left (c x^n\right )-n \log (x)\right )\right )\right ) \left (\frac{x^{m+1} \sinh (b d n \log (x)) \text{sech}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{m+1}-\frac{\cosh \left (d \left (a+b \left (\log \left (c x^n\right )-n \log (x)\right )\right )\right ) \exp \left (-\frac{(2 m+1) \left (a+b \left (\log \left (c x^n\right )-n \log (x)\right )\right )}{b n}\right ) \left ((2 b d n+m+1) \exp \left (\frac{2 a m+a+b (2 m+1) \left (\log \left (c x^n\right )-n \log (x)\right )+b (m+1) n \log (x)}{b n}\right ) \, _2F_1\left (1,\frac{m+1}{2 b d n};\frac{m+1}{2 b d n}+1;-e^{2 d \left (a+b \log \left (c x^n\right )\right )}\right )-(m+1) \exp \left (\frac{a (2 b d n+2 m+1)}{b n}+\frac{(2 b d n+2 m+1) \left (\log \left (c x^n\right )-n \log (x)\right )}{n}+\log (x) (2 b d n+m+1)\right ) \, _2F_1\left (1,\frac{m+2 b d n+1}{2 b d n};\frac{m+4 b d n+1}{2 b d n};-e^{2 d \left (a+b \log \left (c x^n\right )\right )}\right )+(2 b d n+m+1) \tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right ) \exp \left (\frac{2 a m+a+b (2 m+1) \left (\log \left (c x^n\right )-n \log (x)\right )+b (m+1) n \log (x)}{b n}\right )\right )}{(m+1) (2 b d n+m+1)}\right )}{2 b^2 d^2 n^2}-\frac{(m+1) x (e x)^m \sinh (b d n \log (x)) \text{sech}\left (d \left (a+b \left (\log \left (c x^n\right )-n \log (x)\right )\right )\right ) \text{sech}\left (d \left (a+b \left (\log \left (c x^n\right )-n \log (x)\right )\right )+b d n \log (x)\right )}{2 b^2 d^2 n^2}+\frac{x (e x)^m \tanh \left (d \left (a+b \left (\log \left (c x^n\right )-n \log (x)\right )\right )\right )}{m+1}+\frac{x (e x)^m \text{sech}^2\left (d \left (a+b \left (\log \left (c x^n\right )-n \log (x)\right )\right )+b d n \log (x)\right )}{2 b d n} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.218, size = 0, normalized size = 0. \begin{align*} \int \left ( ex \right ) ^{m} \left ( \tanh \left ( d \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) \right ) \right ) ^{3}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -{\left (2 \, b^{2} d^{2} e^{m} n^{2} +{\left (m^{2} + 2 \, m + 1\right )} e^{m}\right )} \int \frac{x^{m}}{b^{2} c^{2 \, b d} d^{2} n^{2} e^{\left (2 \, b d \log \left (x^{n}\right ) + 2 \, a d\right )} + b^{2} d^{2} n^{2}}\,{d x} + \frac{b^{2} c^{4 \, b d} d^{2} e^{m} n^{2} x e^{\left (4 \, b d \log \left (x^{n}\right ) + 4 \, a d + m \log \left (x\right )\right )} +{\left (b^{2} d^{2} e^{m} n^{2} +{\left (m^{2} + 2 \, m + 1\right )} e^{m}\right )} x x^{m} +{\left (2 \, b^{2} c^{2 \, b d} d^{2} e^{m} n^{2} e^{\left (2 \, a d\right )} + 2 \,{\left (m n + n\right )} b c^{2 \, b d} d e^{m} e^{\left (2 \, a d\right )} +{\left (m^{2} + 2 \, m + 1\right )} c^{2 \, b d} e^{m} e^{\left (2 \, a d\right )}\right )} x e^{\left (2 \, b d \log \left (x^{n}\right ) + m \log \left (x\right )\right )}}{{\left (m n^{2} + n^{2}\right )} b^{2} c^{4 \, b d} d^{2} e^{\left (4 \, b d \log \left (x^{n}\right ) + 4 \, a d\right )} + 2 \,{\left (m n^{2} + n^{2}\right )} b^{2} c^{2 \, b d} d^{2} e^{\left (2 \, b d \log \left (x^{n}\right ) + 2 \, a d\right )} +{\left (m n^{2} + n^{2}\right )} b^{2} d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\left (e x\right )^{m} \tanh \left (b d \log \left (c x^{n}\right ) + a d\right )^{3}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (e x\right )^{m} \tanh \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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