Optimal. Leaf size=43 \[ \frac{5 x}{2}-\frac{5 \coth ^3(x)}{6}+\coth ^2(x)-\frac{5 \coth (x)}{2}-2 \log (\sinh (x))+\frac{\coth ^3(x)}{2 (\tanh (x)+1)} \]
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Rubi [A] time = 0.10075, antiderivative size = 43, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 11, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.364, Rules used = {3552, 3529, 3531, 3475} \[ \frac{5 x}{2}-\frac{5 \coth ^3(x)}{6}+\coth ^2(x)-\frac{5 \coth (x)}{2}-2 \log (\sinh (x))+\frac{\coth ^3(x)}{2 (\tanh (x)+1)} \]
Antiderivative was successfully verified.
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Rule 3552
Rule 3529
Rule 3531
Rule 3475
Rubi steps
\begin{align*} \int \frac{\coth ^4(x)}{1+\tanh (x)} \, dx &=\frac{\coth ^3(x)}{2 (1+\tanh (x))}-\frac{1}{2} \int \coth ^4(x) (-5+4 \tanh (x)) \, dx\\ &=-\frac{5}{6} \coth ^3(x)+\frac{\coth ^3(x)}{2 (1+\tanh (x))}-\frac{1}{2} i \int \coth ^3(x) (-4 i+5 i \tanh (x)) \, dx\\ &=\coth ^2(x)-\frac{5 \coth ^3(x)}{6}+\frac{\coth ^3(x)}{2 (1+\tanh (x))}+\frac{1}{2} \int \coth ^2(x) (5-4 \tanh (x)) \, dx\\ &=-\frac{5 \coth (x)}{2}+\coth ^2(x)-\frac{5 \coth ^3(x)}{6}+\frac{\coth ^3(x)}{2 (1+\tanh (x))}+\frac{1}{2} i \int \coth (x) (4 i-5 i \tanh (x)) \, dx\\ &=\frac{5 x}{2}-\frac{5 \coth (x)}{2}+\coth ^2(x)-\frac{5 \coth ^3(x)}{6}+\frac{\coth ^3(x)}{2 (1+\tanh (x))}-2 \int \coth (x) \, dx\\ &=\frac{5 x}{2}-\frac{5 \coth (x)}{2}+\coth ^2(x)-\frac{5 \coth ^3(x)}{6}-2 \log (\sinh (x))+\frac{\coth ^3(x)}{2 (1+\tanh (x))}\\ \end{align*}
Mathematica [A] time = 0.127994, size = 42, normalized size = 0.98 \[ \frac{1}{12} \left (-3 \cosh (2 x)-4 \coth (x) \left (\text{csch}^2(x)+7\right )+3 \left (10 x+\sinh (2 x)+2 \text{csch}^2(x)-8 \log (\sinh (x))\right )\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.036, size = 91, normalized size = 2.1 \begin{align*} -{\frac{1}{24} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{3}}+{\frac{1}{8} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{2}}-{\frac{9}{8}\tanh \left ({\frac{x}{2}} \right ) }- \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-2}+ \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-1}+{\frac{9}{2}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) }-{\frac{1}{24} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-3}}+{\frac{1}{8} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-2}}-{\frac{9}{8} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-1}}-2\,\ln \left ( \tanh \left ( x/2 \right ) \right ) -{\frac{1}{2}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.14226, size = 86, normalized size = 2. \begin{align*} \frac{1}{2} \, x - \frac{2 \,{\left (15 \, e^{\left (-2 \, x\right )} - 12 \, e^{\left (-4 \, x\right )} - 7\right )}}{3 \,{\left (3 \, e^{\left (-2 \, x\right )} - 3 \, e^{\left (-4 \, x\right )} + e^{\left (-6 \, x\right )} - 1\right )}} - \frac{1}{4} \, e^{\left (-2 \, x\right )} - 2 \, \log \left (e^{\left (-x\right )} + 1\right ) - 2 \, \log \left (e^{\left (-x\right )} - 1\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.21132, size = 1897, normalized size = 44.12 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\coth ^{4}{\left (x \right )}}{\tanh{\left (x \right )} + 1}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.27094, size = 65, normalized size = 1.51 \begin{align*} \frac{9}{2} \, x - \frac{{\left (51 \, e^{\left (6 \, x\right )} - 81 \, e^{\left (4 \, x\right )} + 65 \, e^{\left (2 \, x\right )} - 3\right )} e^{\left (-2 \, x\right )}}{12 \,{\left (e^{\left (2 \, x\right )} - 1\right )}^{3}} - 2 \, \log \left ({\left | e^{\left (2 \, x\right )} - 1 \right |}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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