3.1 \(\int \tanh ^6(a+b x) \, dx\)

Optimal. Leaf size=43 \[ -\frac{\tanh ^5(a+b x)}{5 b}-\frac{\tanh ^3(a+b x)}{3 b}-\frac{\tanh (a+b x)}{b}+x \]

[Out]

x - Tanh[a + b*x]/b - Tanh[a + b*x]^3/(3*b) - Tanh[a + b*x]^5/(5*b)

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Rubi [A]  time = 0.0239146, antiderivative size = 43, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 2, integrand size = 8, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {3473, 8} \[ -\frac{\tanh ^5(a+b x)}{5 b}-\frac{\tanh ^3(a+b x)}{3 b}-\frac{\tanh (a+b x)}{b}+x \]

Antiderivative was successfully verified.

[In]

Int[Tanh[a + b*x]^6,x]

[Out]

x - Tanh[a + b*x]/b - Tanh[a + b*x]^3/(3*b) - Tanh[a + b*x]^5/(5*b)

Rule 3473

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*(b*Tan[c + d*x])^(n - 1))/(d*(n - 1)), x] - Dis
t[b^2, Int[(b*Tan[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1]

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rubi steps

\begin{align*} \int \tanh ^6(a+b x) \, dx &=-\frac{\tanh ^5(a+b x)}{5 b}+\int \tanh ^4(a+b x) \, dx\\ &=-\frac{\tanh ^3(a+b x)}{3 b}-\frac{\tanh ^5(a+b x)}{5 b}+\int \tanh ^2(a+b x) \, dx\\ &=-\frac{\tanh (a+b x)}{b}-\frac{\tanh ^3(a+b x)}{3 b}-\frac{\tanh ^5(a+b x)}{5 b}+\int 1 \, dx\\ &=x-\frac{\tanh (a+b x)}{b}-\frac{\tanh ^3(a+b x)}{3 b}-\frac{\tanh ^5(a+b x)}{5 b}\\ \end{align*}

Mathematica [A]  time = 0.0188822, size = 53, normalized size = 1.23 \[ -\frac{\tanh ^5(a+b x)}{5 b}-\frac{\tanh ^3(a+b x)}{3 b}+\frac{\tanh ^{-1}(\tanh (a+b x))}{b}-\frac{\tanh (a+b x)}{b} \]

Antiderivative was successfully verified.

[In]

Integrate[Tanh[a + b*x]^6,x]

[Out]

ArcTanh[Tanh[a + b*x]]/b - Tanh[a + b*x]/b - Tanh[a + b*x]^3/(3*b) - Tanh[a + b*x]^5/(5*b)

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Maple [A]  time = 0.005, size = 67, normalized size = 1.6 \begin{align*} -{\frac{ \left ( \tanh \left ( bx+a \right ) \right ) ^{5}}{5\,b}}-{\frac{ \left ( \tanh \left ( bx+a \right ) \right ) ^{3}}{3\,b}}-{\frac{\tanh \left ( bx+a \right ) }{b}}-{\frac{\ln \left ( -1+\tanh \left ( bx+a \right ) \right ) }{2\,b}}+{\frac{\ln \left ( 1+\tanh \left ( bx+a \right ) \right ) }{2\,b}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tanh(b*x+a)^6,x)

[Out]

-1/5*tanh(b*x+a)^5/b-1/3*tanh(b*x+a)^3/b-tanh(b*x+a)/b-1/2/b*ln(-1+tanh(b*x+a))+1/2*ln(1+tanh(b*x+a))/b

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Maxima [B]  time = 1.04313, size = 155, normalized size = 3.6 \begin{align*} x + \frac{a}{b} - \frac{2 \,{\left (70 \, e^{\left (-2 \, b x - 2 \, a\right )} + 140 \, e^{\left (-4 \, b x - 4 \, a\right )} + 90 \, e^{\left (-6 \, b x - 6 \, a\right )} + 45 \, e^{\left (-8 \, b x - 8 \, a\right )} + 23\right )}}{15 \, b{\left (5 \, e^{\left (-2 \, b x - 2 \, a\right )} + 10 \, e^{\left (-4 \, b x - 4 \, a\right )} + 10 \, e^{\left (-6 \, b x - 6 \, a\right )} + 5 \, e^{\left (-8 \, b x - 8 \, a\right )} + e^{\left (-10 \, b x - 10 \, a\right )} + 1\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(b*x+a)^6,x, algorithm="maxima")

[Out]

x + a/b - 2/15*(70*e^(-2*b*x - 2*a) + 140*e^(-4*b*x - 4*a) + 90*e^(-6*b*x - 6*a) + 45*e^(-8*b*x - 8*a) + 23)/(
b*(5*e^(-2*b*x - 2*a) + 10*e^(-4*b*x - 4*a) + 10*e^(-6*b*x - 6*a) + 5*e^(-8*b*x - 8*a) + e^(-10*b*x - 10*a) +
1))

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Fricas [B]  time = 2.36573, size = 717, normalized size = 16.67 \begin{align*} \frac{{\left (15 \, b x + 23\right )} \cosh \left (b x + a\right )^{5} + 5 \,{\left (15 \, b x + 23\right )} \cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{4} - 23 \, \sinh \left (b x + a\right )^{5} + 5 \,{\left (15 \, b x + 23\right )} \cosh \left (b x + a\right )^{3} - 5 \,{\left (46 \, \cosh \left (b x + a\right )^{2} + 5\right )} \sinh \left (b x + a\right )^{3} + 5 \,{\left (2 \,{\left (15 \, b x + 23\right )} \cosh \left (b x + a\right )^{3} + 3 \,{\left (15 \, b x + 23\right )} \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right )^{2} + 10 \,{\left (15 \, b x + 23\right )} \cosh \left (b x + a\right ) - 5 \,{\left (23 \, \cosh \left (b x + a\right )^{4} + 15 \, \cosh \left (b x + a\right )^{2} + 10\right )} \sinh \left (b x + a\right )}{15 \,{\left (b \cosh \left (b x + a\right )^{5} + 5 \, b \cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{4} + 5 \, b \cosh \left (b x + a\right )^{3} + 5 \,{\left (2 \, b \cosh \left (b x + a\right )^{3} + 3 \, b \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right )^{2} + 10 \, b \cosh \left (b x + a\right )\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(b*x+a)^6,x, algorithm="fricas")

[Out]

1/15*((15*b*x + 23)*cosh(b*x + a)^5 + 5*(15*b*x + 23)*cosh(b*x + a)*sinh(b*x + a)^4 - 23*sinh(b*x + a)^5 + 5*(
15*b*x + 23)*cosh(b*x + a)^3 - 5*(46*cosh(b*x + a)^2 + 5)*sinh(b*x + a)^3 + 5*(2*(15*b*x + 23)*cosh(b*x + a)^3
+ 3*(15*b*x + 23)*cosh(b*x + a))*sinh(b*x + a)^2 + 10*(15*b*x + 23)*cosh(b*x + a) - 5*(23*cosh(b*x + a)^4 + 1
5*cosh(b*x + a)^2 + 10)*sinh(b*x + a))/(b*cosh(b*x + a)^5 + 5*b*cosh(b*x + a)*sinh(b*x + a)^4 + 5*b*cosh(b*x +
a)^3 + 5*(2*b*cosh(b*x + a)^3 + 3*b*cosh(b*x + a))*sinh(b*x + a)^2 + 10*b*cosh(b*x + a))

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Sympy [A]  time = 0.653121, size = 39, normalized size = 0.91 \begin{align*} \begin{cases} x - \frac{\tanh ^{5}{\left (a + b x \right )}}{5 b} - \frac{\tanh ^{3}{\left (a + b x \right )}}{3 b} - \frac{\tanh{\left (a + b x \right )}}{b} & \text{for}\: b \neq 0 \\x \tanh ^{6}{\left (a \right )} & \text{otherwise} \end{cases} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(b*x+a)**6,x)

[Out]

Piecewise((x - tanh(a + b*x)**5/(5*b) - tanh(a + b*x)**3/(3*b) - tanh(a + b*x)/b, Ne(b, 0)), (x*tanh(a)**6, Tr
ue))

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Giac [A]  time = 1.19926, size = 100, normalized size = 2.33 \begin{align*} \frac{b x + a}{b} + \frac{2 \,{\left (45 \, e^{\left (8 \, b x + 8 \, a\right )} + 90 \, e^{\left (6 \, b x + 6 \, a\right )} + 140 \, e^{\left (4 \, b x + 4 \, a\right )} + 70 \, e^{\left (2 \, b x + 2 \, a\right )} + 23\right )}}{15 \, b{\left (e^{\left (2 \, b x + 2 \, a\right )} + 1\right )}^{5}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(b*x+a)^6,x, algorithm="giac")

[Out]

(b*x + a)/b + 2/15*(45*e^(8*b*x + 8*a) + 90*e^(6*b*x + 6*a) + 140*e^(4*b*x + 4*a) + 70*e^(2*b*x + 2*a) + 23)/(
b*(e^(2*b*x + 2*a) + 1)^5)