3.8 \(\int \cosh ^{\frac{5}{2}}(a+b x) \, dx\)

Optimal. Leaf size=46 \[ \frac{2 \sinh (a+b x) \cosh ^{\frac{3}{2}}(a+b x)}{5 b}-\frac{6 i E\left (\left .\frac{1}{2} i (a+b x)\right |2\right )}{5 b} \]

[Out]

(((-6*I)/5)*EllipticE[(I/2)*(a + b*x), 2])/b + (2*Cosh[a + b*x]^(3/2)*Sinh[a + b*x])/(5*b)

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Rubi [A]  time = 0.0196099, antiderivative size = 46, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {2635, 2639} \[ \frac{2 \sinh (a+b x) \cosh ^{\frac{3}{2}}(a+b x)}{5 b}-\frac{6 i E\left (\left .\frac{1}{2} i (a+b x)\right |2\right )}{5 b} \]

Antiderivative was successfully verified.

[In]

Int[Cosh[a + b*x]^(5/2),x]

[Out]

(((-6*I)/5)*EllipticE[(I/2)*(a + b*x), 2])/b + (2*Cosh[a + b*x]^(3/2)*Sinh[a + b*x])/(5*b)

Rule 2635

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> -Simp[(b*Cos[c + d*x]*(b*Sin[c + d*x])^(n - 1))/(d*n),
x] + Dist[(b^2*(n - 1))/n, Int[(b*Sin[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && Integer
Q[2*n]

Rule 2639

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticE[(1*(c - Pi/2 + d*x))/2, 2])/d, x] /; FreeQ[{
c, d}, x]

Rubi steps

\begin{align*} \int \cosh ^{\frac{5}{2}}(a+b x) \, dx &=\frac{2 \cosh ^{\frac{3}{2}}(a+b x) \sinh (a+b x)}{5 b}+\frac{3}{5} \int \sqrt{\cosh (a+b x)} \, dx\\ &=-\frac{6 i E\left (\left .\frac{1}{2} i (a+b x)\right |2\right )}{5 b}+\frac{2 \cosh ^{\frac{3}{2}}(a+b x) \sinh (a+b x)}{5 b}\\ \end{align*}

Mathematica [A]  time = 0.050679, size = 44, normalized size = 0.96 \[ \frac{\sinh (2 (a+b x)) \sqrt{\cosh (a+b x)}-6 i E\left (\left .\frac{1}{2} i (a+b x)\right |2\right )}{5 b} \]

Antiderivative was successfully verified.

[In]

Integrate[Cosh[a + b*x]^(5/2),x]

[Out]

((-6*I)*EllipticE[(I/2)*(a + b*x), 2] + Sqrt[Cosh[a + b*x]]*Sinh[2*(a + b*x)])/(5*b)

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Maple [B]  time = 0.037, size = 188, normalized size = 4.1 \begin{align*}{\frac{2}{5\,b}\sqrt{ \left ( 2\, \left ( \cosh \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1 \right ) \left ( \sinh \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{2}} \left ( 8\, \left ( \cosh \left ( 1/2\,bx+a/2 \right ) \right ) ^{7}-16\, \left ( \cosh \left ( 1/2\,bx+a/2 \right ) \right ) ^{5}+10\, \left ( \cosh \left ( 1/2\,bx+a/2 \right ) \right ) ^{3}-3\,\sqrt{- \left ( \sinh \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}}\sqrt{-2\, \left ( \cosh \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}+1}{\it EllipticE} \left ( \cosh \left ( 1/2\,bx+a/2 \right ) ,\sqrt{2} \right ) -2\,\cosh \left ( 1/2\,bx+a/2 \right ) \right ){\frac{1}{\sqrt{2\, \left ( \sinh \left ( 1/2\,bx+a/2 \right ) \right ) ^{4}+ \left ( \sinh \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{2}}}} \left ( \sinh \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{-1}{\frac{1}{\sqrt{2\, \left ( \cosh \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cosh(b*x+a)^(5/2),x)

[Out]

2/5*((2*cosh(1/2*b*x+1/2*a)^2-1)*sinh(1/2*b*x+1/2*a)^2)^(1/2)*(8*cosh(1/2*b*x+1/2*a)^7-16*cosh(1/2*b*x+1/2*a)^
5+10*cosh(1/2*b*x+1/2*a)^3-3*(-sinh(1/2*b*x+1/2*a)^2)^(1/2)*(-2*cosh(1/2*b*x+1/2*a)^2+1)^(1/2)*EllipticE(cosh(
1/2*b*x+1/2*a),2^(1/2))-2*cosh(1/2*b*x+1/2*a))/(2*sinh(1/2*b*x+1/2*a)^4+sinh(1/2*b*x+1/2*a)^2)^(1/2)/sinh(1/2*
b*x+1/2*a)/(2*cosh(1/2*b*x+1/2*a)^2-1)^(1/2)/b

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \cosh \left (b x + a\right )^{\frac{5}{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)^(5/2),x, algorithm="maxima")

[Out]

integrate(cosh(b*x + a)^(5/2), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\cosh \left (b x + a\right )^{\frac{5}{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)^(5/2),x, algorithm="fricas")

[Out]

integral(cosh(b*x + a)^(5/2), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)**(5/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \cosh \left (b x + a\right )^{\frac{5}{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)^(5/2),x, algorithm="giac")

[Out]

integrate(cosh(b*x + a)^(5/2), x)