Optimal. Leaf size=206 \[ \frac{5 e^{-2 a} x \left (c x^n\right )^{-4/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{4 \left (e^{-2 a} \left (c x^n\right )^{-4/n}+1\right )^2}-\frac{1}{4} x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )+\frac{5 x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{12 \left (e^{-2 a} \left (c x^n\right )^{-4/n}+1\right )}-\frac{5 e^{-3 a} x \left (c x^n\right )^{-6/n} \text{csch}^{-1}\left (e^a \left (c x^n\right )^{2/n}\right ) \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{4 \left (e^{-2 a} \left (c x^n\right )^{-4/n}+1\right )^{5/2}} \]
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Rubi [A] time = 0.153696, antiderivative size = 206, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.444, Rules used = {5526, 5534, 353, 349, 345, 242, 277, 215} \[ \frac{5 e^{-2 a} x \left (c x^n\right )^{-4/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{4 \left (e^{-2 a} \left (c x^n\right )^{-4/n}+1\right )^2}-\frac{1}{4} x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )+\frac{5 x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{12 \left (e^{-2 a} \left (c x^n\right )^{-4/n}+1\right )}-\frac{5 e^{-3 a} x \left (c x^n\right )^{-6/n} \text{csch}^{-1}\left (e^a \left (c x^n\right )^{2/n}\right ) \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{4 \left (e^{-2 a} \left (c x^n\right )^{-4/n}+1\right )^{5/2}} \]
Antiderivative was successfully verified.
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Rule 5526
Rule 5534
Rule 353
Rule 349
Rule 345
Rule 242
Rule 277
Rule 215
Rubi steps
\begin{align*} \int \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right ) \, dx &=\frac{\left (x \left (c x^n\right )^{-1/n}\right ) \operatorname{Subst}\left (\int x^{-1+\frac{1}{n}} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log (x)}{n}\right ) \, dx,x,c x^n\right )}{n}\\ &=\frac{\left (x \left (c x^n\right )^{-6/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )\right ) \operatorname{Subst}\left (\int x^{-1+\frac{6}{n}} \left (1+e^{-2 a} x^{-4/n}\right )^{5/2} \, dx,x,c x^n\right )}{n \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )^{5/2}}\\ &=-\frac{1}{4} x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )+\frac{\left (5 x \left (c x^n\right )^{-6/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )\right ) \operatorname{Subst}\left (\int x^{-1+\frac{6}{n}} \left (1+e^{-2 a} x^{-4/n}\right )^{3/2} \, dx,x,c x^n\right )}{2 n \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )^{5/2}}\\ &=-\frac{1}{4} x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )+\frac{5 x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{12 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )}+\frac{\left (5 e^{-2 a} x \left (c x^n\right )^{-6/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )\right ) \operatorname{Subst}\left (\int x^{-1+\frac{2}{n}} \sqrt{1+e^{-2 a} x^{-4/n}} \, dx,x,c x^n\right )}{2 n \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )^{5/2}}\\ &=-\frac{1}{4} x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )+\frac{5 x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{12 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )}+\frac{\left (5 e^{-2 a} x \left (c x^n\right )^{-6/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )\right ) \operatorname{Subst}\left (\int \sqrt{1+\frac{e^{-2 a}}{x^2}} \, dx,x,\left (c x^n\right )^{2/n}\right )}{4 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )^{5/2}}\\ &=-\frac{1}{4} x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )+\frac{5 x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{12 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )}-\frac{\left (5 e^{-2 a} x \left (c x^n\right )^{-6/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1+e^{-2 a} x^2}}{x^2} \, dx,x,\left (c x^n\right )^{-2/n}\right )}{4 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )^{5/2}}\\ &=-\frac{1}{4} x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )+\frac{5 e^{-2 a} x \left (c x^n\right )^{-4/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{4 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )^2}+\frac{5 x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{12 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )}-\frac{\left (5 e^{-4 a} x \left (c x^n\right )^{-6/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+e^{-2 a} x^2}} \, dx,x,\left (c x^n\right )^{-2/n}\right )}{4 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )^{5/2}}\\ &=-\frac{1}{4} x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )+\frac{5 e^{-2 a} x \left (c x^n\right )^{-4/n} \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{4 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )^2}+\frac{5 x \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{12 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )}-\frac{5 e^{-3 a} x \left (c x^n\right )^{-6/n} \sinh ^{-1}\left (e^{-a} \left (c x^n\right )^{-2/n}\right ) \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right )}{4 \left (1+e^{-2 a} \left (c x^n\right )^{-4/n}\right )^{5/2}}\\ \end{align*}
Mathematica [C] time = 0.459269, size = 85, normalized size = 0.41 \[ \frac{1}{14} e^{2 a} x \left (c x^n\right )^{4/n} \left (e^{2 a} \left (c x^n\right )^{4/n}+1\right ) \, _2F_1\left (2,\frac{7}{2};\frac{9}{2};e^{2 a} \left (c x^n\right )^{4/n}+1\right ) \cosh ^{\frac{5}{2}}\left (a+\frac{2 \log \left (c x^n\right )}{n}\right ) \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.334, size = 0, normalized size = 0. \begin{align*} \int \left ( \cosh \left ( a+2\,{\frac{\ln \left ( c{x}^{n} \right ) }{n}} \right ) \right ) ^{{\frac{5}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \cosh \left (a + \frac{2 \, \log \left (c x^{n}\right )}{n}\right )^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.86262, size = 475, normalized size = 2.31 \begin{align*} \frac{{\left (15 \, \sqrt{2} x^{3} e^{\left (\frac{3 \,{\left (a n + 2 \, \log \left (c\right )\right )}}{2 \, n}\right )} \log \left (\frac{x^{4} e^{\left (\frac{2 \,{\left (a n + 2 \, \log \left (c\right )\right )}}{n}\right )} - 2 \, \sqrt{2} \sqrt{\frac{1}{2}} x \sqrt{\frac{x^{4} e^{\left (\frac{2 \,{\left (a n + 2 \, \log \left (c\right )\right )}}{n}\right )} + 1}{x^{2}}} + 2}{x^{4}}\right ) + 4 \, \sqrt{\frac{1}{2}}{\left (2 \, x^{8} e^{\left (\frac{4 \,{\left (a n + 2 \, \log \left (c\right )\right )}}{n}\right )} + 14 \, x^{4} e^{\left (\frac{2 \,{\left (a n + 2 \, \log \left (c\right )\right )}}{n}\right )} - 3\right )} \sqrt{\frac{x^{4} e^{\left (\frac{2 \,{\left (a n + 2 \, \log \left (c\right )\right )}}{n}\right )} + 1}{x^{2}}} e^{\left (-\frac{a n + 2 \, \log \left (c\right )}{2 \, n}\right )}\right )} e^{\left (-\frac{2 \,{\left (a n + 2 \, \log \left (c\right )\right )}}{n}\right )}}{192 \, x^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \cosh \left (a + \frac{2 \, \log \left (c x^{n}\right )}{n}\right )^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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