Optimal. Leaf size=161 \[ \frac{\text{PolyLog}\left (2,-\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}\right )}{b d^2}+\frac{\text{PolyLog}\left (2,-\frac{b e^{c+d x}}{\sqrt{a^2-b^2}+a}\right )}{b d^2}+\frac{x \log \left (\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}+1\right )}{b d}+\frac{x \log \left (\frac{b e^{c+d x}}{\sqrt{a^2-b^2}+a}+1\right )}{b d}-\frac{x^2}{2 b} \]
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Rubi [A] time = 0.24167, antiderivative size = 161, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {5562, 2190, 2279, 2391} \[ \frac{\text{PolyLog}\left (2,-\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}\right )}{b d^2}+\frac{\text{PolyLog}\left (2,-\frac{b e^{c+d x}}{\sqrt{a^2-b^2}+a}\right )}{b d^2}+\frac{x \log \left (\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}+1\right )}{b d}+\frac{x \log \left (\frac{b e^{c+d x}}{\sqrt{a^2-b^2}+a}+1\right )}{b d}-\frac{x^2}{2 b} \]
Antiderivative was successfully verified.
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Rule 5562
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{x \sinh (c+d x)}{a+b \cosh (c+d x)} \, dx &=-\frac{x^2}{2 b}+\int \frac{e^{c+d x} x}{a-\sqrt{a^2-b^2}+b e^{c+d x}} \, dx+\int \frac{e^{c+d x} x}{a+\sqrt{a^2-b^2}+b e^{c+d x}} \, dx\\ &=-\frac{x^2}{2 b}+\frac{x \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}\right )}{b d}+\frac{x \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2-b^2}}\right )}{b d}-\frac{\int \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}\right ) \, dx}{b d}-\frac{\int \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2-b^2}}\right ) \, dx}{b d}\\ &=-\frac{x^2}{2 b}+\frac{x \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}\right )}{b d}+\frac{x \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2-b^2}}\right )}{b d}-\frac{\operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{a-\sqrt{a^2-b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{b d^2}-\frac{\operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{a+\sqrt{a^2-b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{b d^2}\\ &=-\frac{x^2}{2 b}+\frac{x \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}\right )}{b d}+\frac{x \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2-b^2}}\right )}{b d}+\frac{\text{Li}_2\left (-\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}\right )}{b d^2}+\frac{\text{Li}_2\left (-\frac{b e^{c+d x}}{a+\sqrt{a^2-b^2}}\right )}{b d^2}\\ \end{align*}
Mathematica [A] time = 0.0121135, size = 160, normalized size = 0.99 \[ \frac{\text{PolyLog}\left (2,\frac{b e^{c+d x}}{\sqrt{a^2-b^2}-a}\right )}{b d^2}+\frac{\text{PolyLog}\left (2,-\frac{b e^{c+d x}}{\sqrt{a^2-b^2}+a}\right )}{b d^2}+\frac{x \log \left (\frac{b e^{c+d x}}{a-\sqrt{a^2-b^2}}+1\right )}{b d}+\frac{x \log \left (\frac{b e^{c+d x}}{\sqrt{a^2-b^2}+a}+1\right )}{b d}-\frac{x^2}{2 b} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.047, size = 368, normalized size = 2.3 \begin{align*} -{\frac{{x}^{2}}{2\,b}}-2\,{\frac{cx}{bd}}-{\frac{{c}^{2}}{{d}^{2}b}}+{\frac{x}{bd}\ln \left ({ \left ( -b{{\rm e}^{dx+c}}+\sqrt{{a}^{2}-{b}^{2}}-a \right ) \left ( -a+\sqrt{{a}^{2}-{b}^{2}} \right ) ^{-1}} \right ) }+{\frac{c}{{d}^{2}b}\ln \left ({ \left ( -b{{\rm e}^{dx+c}}+\sqrt{{a}^{2}-{b}^{2}}-a \right ) \left ( -a+\sqrt{{a}^{2}-{b}^{2}} \right ) ^{-1}} \right ) }+{\frac{x}{bd}\ln \left ({ \left ( b{{\rm e}^{dx+c}}+\sqrt{{a}^{2}-{b}^{2}}+a \right ) \left ( a+\sqrt{{a}^{2}-{b}^{2}} \right ) ^{-1}} \right ) }+{\frac{c}{{d}^{2}b}\ln \left ({ \left ( b{{\rm e}^{dx+c}}+\sqrt{{a}^{2}-{b}^{2}}+a \right ) \left ( a+\sqrt{{a}^{2}-{b}^{2}} \right ) ^{-1}} \right ) }+{\frac{1}{{d}^{2}b}{\it dilog} \left ({ \left ( -b{{\rm e}^{dx+c}}+\sqrt{{a}^{2}-{b}^{2}}-a \right ) \left ( -a+\sqrt{{a}^{2}-{b}^{2}} \right ) ^{-1}} \right ) }+{\frac{1}{{d}^{2}b}{\it dilog} \left ({ \left ( b{{\rm e}^{dx+c}}+\sqrt{{a}^{2}-{b}^{2}}+a \right ) \left ( a+\sqrt{{a}^{2}-{b}^{2}} \right ) ^{-1}} \right ) }+2\,{\frac{c\ln \left ({{\rm e}^{dx+c}} \right ) }{{d}^{2}b}}-{\frac{c\ln \left ( b{{\rm e}^{2\,dx+2\,c}}+2\,a{{\rm e}^{dx+c}}+b \right ) }{{d}^{2}b}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{x^{2}}{2 \, b} - \frac{1}{2} \, \int \frac{4 \,{\left (a x e^{\left (d x + c\right )} + b x\right )}}{b^{2} e^{\left (2 \, d x + 2 \, c\right )} + 2 \, a b e^{\left (d x + c\right )} + b^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.97892, size = 902, normalized size = 5.6 \begin{align*} -\frac{d^{2} x^{2} + 2 \, c \log \left (2 \, b \cosh \left (d x + c\right ) + 2 \, b \sinh \left (d x + c\right ) + 2 \, b \sqrt{\frac{a^{2} - b^{2}}{b^{2}}} + 2 \, a\right ) + 2 \, c \log \left (2 \, b \cosh \left (d x + c\right ) + 2 \, b \sinh \left (d x + c\right ) - 2 \, b \sqrt{\frac{a^{2} - b^{2}}{b^{2}}} + 2 \, a\right ) - 2 \,{\left (d x + c\right )} \log \left (\frac{a \cosh \left (d x + c\right ) + a \sinh \left (d x + c\right ) +{\left (b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )\right )} \sqrt{\frac{a^{2} - b^{2}}{b^{2}}} + b}{b}\right ) - 2 \,{\left (d x + c\right )} \log \left (\frac{a \cosh \left (d x + c\right ) + a \sinh \left (d x + c\right ) -{\left (b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )\right )} \sqrt{\frac{a^{2} - b^{2}}{b^{2}}} + b}{b}\right ) - 2 \,{\rm Li}_2\left (-\frac{a \cosh \left (d x + c\right ) + a \sinh \left (d x + c\right ) +{\left (b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )\right )} \sqrt{\frac{a^{2} - b^{2}}{b^{2}}} + b}{b} + 1\right ) - 2 \,{\rm Li}_2\left (-\frac{a \cosh \left (d x + c\right ) + a \sinh \left (d x + c\right ) -{\left (b \cosh \left (d x + c\right ) + b \sinh \left (d x + c\right )\right )} \sqrt{\frac{a^{2} - b^{2}}{b^{2}}} + b}{b} + 1\right )}{2 \, b d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x \sinh{\left (c + d x \right )}}{a + b \cosh{\left (c + d x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x \sinh \left (d x + c\right )}{b \cosh \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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