3.210 \(\int \frac{x}{a+b \cosh ^2(x)} \, dx\)

Optimal. Leaf size=191 \[ \frac{\text{PolyLog}\left (2,-\frac{b e^{2 x}}{-2 \sqrt{a} \sqrt{a+b}+2 a+b}\right )}{4 \sqrt{a} \sqrt{a+b}}-\frac{\text{PolyLog}\left (2,-\frac{b e^{2 x}}{2 \sqrt{a} \sqrt{a+b}+2 a+b}\right )}{4 \sqrt{a} \sqrt{a+b}}+\frac{x \log \left (\frac{b e^{2 x}}{-2 \sqrt{a} \sqrt{a+b}+2 a+b}+1\right )}{2 \sqrt{a} \sqrt{a+b}}-\frac{x \log \left (\frac{b e^{2 x}}{2 \sqrt{a} \sqrt{a+b}+2 a+b}+1\right )}{2 \sqrt{a} \sqrt{a+b}} \]

[Out]

(x*Log[1 + (b*E^(2*x))/(2*a + b - 2*Sqrt[a]*Sqrt[a + b])])/(2*Sqrt[a]*Sqrt[a + b]) - (x*Log[1 + (b*E^(2*x))/(2
*a + b + 2*Sqrt[a]*Sqrt[a + b])])/(2*Sqrt[a]*Sqrt[a + b]) + PolyLog[2, -((b*E^(2*x))/(2*a + b - 2*Sqrt[a]*Sqrt
[a + b]))]/(4*Sqrt[a]*Sqrt[a + b]) - PolyLog[2, -((b*E^(2*x))/(2*a + b + 2*Sqrt[a]*Sqrt[a + b]))]/(4*Sqrt[a]*S
qrt[a + b])

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Rubi [A]  time = 0.376604, antiderivative size = 191, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 6, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {5630, 3320, 2264, 2190, 2279, 2391} \[ \frac{\text{PolyLog}\left (2,-\frac{b e^{2 x}}{-2 \sqrt{a} \sqrt{a+b}+2 a+b}\right )}{4 \sqrt{a} \sqrt{a+b}}-\frac{\text{PolyLog}\left (2,-\frac{b e^{2 x}}{2 \sqrt{a} \sqrt{a+b}+2 a+b}\right )}{4 \sqrt{a} \sqrt{a+b}}+\frac{x \log \left (\frac{b e^{2 x}}{-2 \sqrt{a} \sqrt{a+b}+2 a+b}+1\right )}{2 \sqrt{a} \sqrt{a+b}}-\frac{x \log \left (\frac{b e^{2 x}}{2 \sqrt{a} \sqrt{a+b}+2 a+b}+1\right )}{2 \sqrt{a} \sqrt{a+b}} \]

Antiderivative was successfully verified.

[In]

Int[x/(a + b*Cosh[x]^2),x]

[Out]

(x*Log[1 + (b*E^(2*x))/(2*a + b - 2*Sqrt[a]*Sqrt[a + b])])/(2*Sqrt[a]*Sqrt[a + b]) - (x*Log[1 + (b*E^(2*x))/(2
*a + b + 2*Sqrt[a]*Sqrt[a + b])])/(2*Sqrt[a]*Sqrt[a + b]) + PolyLog[2, -((b*E^(2*x))/(2*a + b - 2*Sqrt[a]*Sqrt
[a + b]))]/(4*Sqrt[a]*Sqrt[a + b]) - PolyLog[2, -((b*E^(2*x))/(2*a + b + 2*Sqrt[a]*Sqrt[a + b]))]/(4*Sqrt[a]*S
qrt[a + b])

Rule 5630

Int[(Cosh[(c_.) + (d_.)*(x_)]^2*(b_.) + (a_))^(n_)*(x_)^(m_.), x_Symbol] :> Dist[1/2^n, Int[x^m*(2*a + b + b*C
osh[2*c + 2*d*x])^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a - b, 0] && IGtQ[m, 0] && ILtQ[n, 0] && (EqQ[n,
-1] || (EqQ[m, 1] && EqQ[n, -2]))

Rule 3320

Int[((c_.) + (d_.)*(x_))^(m_.)/((a_) + (b_.)*sin[(e_.) + Pi*(k_.) + (Complex[0, fz_])*(f_.)*(x_)]), x_Symbol]
:> Dist[2, Int[((c + d*x)^m*E^(-(I*e) + f*fz*x))/(E^(I*Pi*(k - 1/2))*(b + (2*a*E^(-(I*e) + f*fz*x))/E^(I*Pi*(k
- 1/2)) - (b*E^(2*(-(I*e) + f*fz*x)))/E^(2*I*k*Pi))), x], x] /; FreeQ[{a, b, c, d, e, f, fz}, x] && IntegerQ[
2*k] && NeQ[a^2 - b^2, 0] && IGtQ[m, 0]

Rule 2264

Int[((F_)^(u_)*((f_.) + (g_.)*(x_))^(m_.))/((a_.) + (b_.)*(F_)^(u_) + (c_.)*(F_)^(v_)), x_Symbol] :> With[{q =
Rt[b^2 - 4*a*c, 2]}, Dist[(2*c)/q, Int[((f + g*x)^m*F^u)/(b - q + 2*c*F^u), x], x] - Dist[(2*c)/q, Int[((f +
g*x)^m*F^u)/(b + q + 2*c*F^u), x], x]] /; FreeQ[{F, a, b, c, f, g}, x] && EqQ[v, 2*u] && LinearQ[u, x] && NeQ[
b^2 - 4*a*c, 0] && IGtQ[m, 0]

Rule 2190

Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/((a_) + (b_.)*((F_)^((g_.)*((e_.) +
(f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[((c + d*x)^m*Log[1 + (b*(F^(g*(e + f*x)))^n)/a])/(b*f*g*n*Log[F]), x]
- Dist[(d*m)/(b*f*g*n*Log[F]), Int[(c + d*x)^(m - 1)*Log[1 + (b*(F^(g*(e + f*x)))^n)/a], x], x] /; FreeQ[{F,
a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]

Rule 2279

Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Dist[1/(d*e*n*Log[F]), Subst[Int
[Log[a + b*x]/x, x], x, (F^(e*(c + d*x)))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rubi steps

\begin{align*} \int \frac{x}{a+b \cosh ^2(x)} \, dx &=2 \int \frac{x}{2 a+b+b \cosh (2 x)} \, dx\\ &=4 \int \frac{e^{2 x} x}{b+2 (2 a+b) e^{2 x}+b e^{4 x}} \, dx\\ &=\frac{(2 b) \int \frac{e^{2 x} x}{-4 \sqrt{a} \sqrt{a+b}+2 (2 a+b)+2 b e^{2 x}} \, dx}{\sqrt{a} \sqrt{a+b}}-\frac{(2 b) \int \frac{e^{2 x} x}{4 \sqrt{a} \sqrt{a+b}+2 (2 a+b)+2 b e^{2 x}} \, dx}{\sqrt{a} \sqrt{a+b}}\\ &=\frac{x \log \left (1+\frac{b e^{2 x}}{2 a+b-2 \sqrt{a} \sqrt{a+b}}\right )}{2 \sqrt{a} \sqrt{a+b}}-\frac{x \log \left (1+\frac{b e^{2 x}}{2 a+b+2 \sqrt{a} \sqrt{a+b}}\right )}{2 \sqrt{a} \sqrt{a+b}}-\frac{\int \log \left (1+\frac{2 b e^{2 x}}{-4 \sqrt{a} \sqrt{a+b}+2 (2 a+b)}\right ) \, dx}{2 \sqrt{a} \sqrt{a+b}}+\frac{\int \log \left (1+\frac{2 b e^{2 x}}{4 \sqrt{a} \sqrt{a+b}+2 (2 a+b)}\right ) \, dx}{2 \sqrt{a} \sqrt{a+b}}\\ &=\frac{x \log \left (1+\frac{b e^{2 x}}{2 a+b-2 \sqrt{a} \sqrt{a+b}}\right )}{2 \sqrt{a} \sqrt{a+b}}-\frac{x \log \left (1+\frac{b e^{2 x}}{2 a+b+2 \sqrt{a} \sqrt{a+b}}\right )}{2 \sqrt{a} \sqrt{a+b}}-\frac{\operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 b x}{-4 \sqrt{a} \sqrt{a+b}+2 (2 a+b)}\right )}{x} \, dx,x,e^{2 x}\right )}{4 \sqrt{a} \sqrt{a+b}}+\frac{\operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 b x}{4 \sqrt{a} \sqrt{a+b}+2 (2 a+b)}\right )}{x} \, dx,x,e^{2 x}\right )}{4 \sqrt{a} \sqrt{a+b}}\\ &=\frac{x \log \left (1+\frac{b e^{2 x}}{2 a+b-2 \sqrt{a} \sqrt{a+b}}\right )}{2 \sqrt{a} \sqrt{a+b}}-\frac{x \log \left (1+\frac{b e^{2 x}}{2 a+b+2 \sqrt{a} \sqrt{a+b}}\right )}{2 \sqrt{a} \sqrt{a+b}}+\frac{\text{Li}_2\left (-\frac{b e^{2 x}}{2 a+b-2 \sqrt{a} \sqrt{a+b}}\right )}{4 \sqrt{a} \sqrt{a+b}}-\frac{\text{Li}_2\left (-\frac{b e^{2 x}}{2 a+b+2 \sqrt{a} \sqrt{a+b}}\right )}{4 \sqrt{a} \sqrt{a+b}}\\ \end{align*}

Mathematica [C]  time = 0.562128, size = 536, normalized size = 2.81 \[ -\frac{i \left (\text{PolyLog}\left (2,\frac{\left (-2 i \sqrt{-a (a+b)}+2 a+b\right ) \left (-i \sqrt{-a (a+b)} \tanh (x)+a+b\right )}{b \left (i \sqrt{-a (a+b)} \tanh (x)+a+b\right )}\right )-\text{PolyLog}\left (2,\frac{\left (2 i \sqrt{-a (a+b)}+2 a+b\right ) \left (-i \sqrt{-a (a+b)} \tanh (x)+a+b\right )}{b \left (i \sqrt{-a (a+b)} \tanh (x)+a+b\right )}\right )\right )+4 x \tan ^{-1}\left (\frac{(a+b) \coth (x)}{\sqrt{-a (a+b)}}\right )+2 i \cos ^{-1}\left (-\frac{2 a}{b}-1\right ) \tan ^{-1}\left (\frac{a \tanh (x)}{\sqrt{-a (a+b)}}\right )-\log \left (\frac{2 (a+b) \left (a+i \sqrt{-a (a+b)}\right ) (\tanh (x)-1)}{b \left (i \sqrt{-a (a+b)} \tanh (x)+a+b\right )}\right ) \left (\cos ^{-1}\left (-\frac{2 a}{b}-1\right )-2 \tan ^{-1}\left (\frac{a \tanh (x)}{\sqrt{-a (a+b)}}\right )\right )-\log \left (\frac{2 i (a+b) \left (\sqrt{-a (a+b)}+i a\right ) (\tanh (x)+1)}{b \left (i \sqrt{-a (a+b)} \tanh (x)+a+b\right )}\right ) \left (2 \tan ^{-1}\left (\frac{a \tanh (x)}{\sqrt{-a (a+b)}}\right )+\cos ^{-1}\left (-\frac{2 a}{b}-1\right )\right )+\log \left (\frac{\sqrt{2} e^{-x} \sqrt{-a (a+b)}}{\sqrt{b} \sqrt{2 a+b \cosh (2 x)+b}}\right ) \left (-2 \tan ^{-1}\left (\frac{a \tanh (x)}{\sqrt{-a (a+b)}}\right )+2 \tan ^{-1}\left (\frac{(a+b) \coth (x)}{\sqrt{-a (a+b)}}\right )+\cos ^{-1}\left (-\frac{2 a}{b}-1\right )\right )+\log \left (\frac{\sqrt{2} e^x \sqrt{-a (a+b)}}{\sqrt{b} \sqrt{2 a+b \cosh (2 x)+b}}\right ) \left (2 \tan ^{-1}\left (\frac{a \tanh (x)}{\sqrt{-a (a+b)}}\right )-2 \tan ^{-1}\left (\frac{(a+b) \coth (x)}{\sqrt{-a (a+b)}}\right )+\cos ^{-1}\left (-\frac{2 a}{b}-1\right )\right )}{4 \sqrt{-a (a+b)}} \]

Antiderivative was successfully verified.

[In]

Integrate[x/(a + b*Cosh[x]^2),x]

[Out]

-(4*x*ArcTan[((a + b)*Coth[x])/Sqrt[-(a*(a + b))]] + (2*I)*ArcCos[-1 - (2*a)/b]*ArcTan[(a*Tanh[x])/Sqrt[-(a*(a
+ b))]] + (ArcCos[-1 - (2*a)/b] + 2*ArcTan[((a + b)*Coth[x])/Sqrt[-(a*(a + b))]] - 2*ArcTan[(a*Tanh[x])/Sqrt[
-(a*(a + b))]])*Log[(Sqrt[2]*Sqrt[-(a*(a + b))])/(Sqrt[b]*E^x*Sqrt[2*a + b + b*Cosh[2*x]])] + (ArcCos[-1 - (2*
a)/b] - 2*ArcTan[((a + b)*Coth[x])/Sqrt[-(a*(a + b))]] + 2*ArcTan[(a*Tanh[x])/Sqrt[-(a*(a + b))]])*Log[(Sqrt[2
]*Sqrt[-(a*(a + b))]*E^x)/(Sqrt[b]*Sqrt[2*a + b + b*Cosh[2*x]])] - (ArcCos[-1 - (2*a)/b] - 2*ArcTan[(a*Tanh[x]
)/Sqrt[-(a*(a + b))]])*Log[(2*(a + b)*(a + I*Sqrt[-(a*(a + b))])*(-1 + Tanh[x]))/(b*(a + b + I*Sqrt[-(a*(a + b
))]*Tanh[x]))] - (ArcCos[-1 - (2*a)/b] + 2*ArcTan[(a*Tanh[x])/Sqrt[-(a*(a + b))]])*Log[((2*I)*(a + b)*(I*a + S
qrt[-(a*(a + b))])*(1 + Tanh[x]))/(b*(a + b + I*Sqrt[-(a*(a + b))]*Tanh[x]))] + I*(PolyLog[2, ((2*a + b - (2*I
)*Sqrt[-(a*(a + b))])*(a + b - I*Sqrt[-(a*(a + b))]*Tanh[x]))/(b*(a + b + I*Sqrt[-(a*(a + b))]*Tanh[x]))] - Po
lyLog[2, ((2*a + b + (2*I)*Sqrt[-(a*(a + b))])*(a + b - I*Sqrt[-(a*(a + b))]*Tanh[x]))/(b*(a + b + I*Sqrt[-(a*
(a + b))]*Tanh[x]))]))/(4*Sqrt[-(a*(a + b))])

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Maple [B]  time = 0.046, size = 487, normalized size = 2.6 \begin{align*}{\frac{x}{2}\ln \left ( 1-{b{{\rm e}^{2\,x}} \left ( 2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}}-{\frac{{x}^{2}}{2}{\frac{1}{\sqrt{a \left ( a+b \right ) }}}}+{\frac{1}{4}{\it polylog} \left ( 2,{b{{\rm e}^{2\,x}} \left ( 2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}}+{x\ln \left ( 1-{b{{\rm e}^{2\,x}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}} \right ) \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}}+{ax\ln \left ( 1-{b{{\rm e}^{2\,x}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}}+{\frac{bx}{2}\ln \left ( 1-{b{{\rm e}^{2\,x}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}}-{{x}^{2} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}}-{a{x}^{2}{\frac{1}{\sqrt{a \left ( a+b \right ) }}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}}-{\frac{b{x}^{2}}{2}{\frac{1}{\sqrt{a \left ( a+b \right ) }}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}}+{\frac{1}{2}{\it polylog} \left ( 2,{b{{\rm e}^{2\,x}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}} \right ) \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}}+{\frac{a}{2}{\it polylog} \left ( 2,{b{{\rm e}^{2\,x}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}}+{\frac{b}{4}{\it polylog} \left ( 2,{b{{\rm e}^{2\,x}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}} \left ( -2\,\sqrt{a \left ( a+b \right ) }-2\,a-b \right ) ^{-1}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(a+b*cosh(x)^2),x)

[Out]

1/2/(a*(a+b))^(1/2)*x*ln(1-b*exp(2*x)/(2*(a*(a+b))^(1/2)-2*a-b))-1/2/(a*(a+b))^(1/2)*x^2+1/4/(a*(a+b))^(1/2)*p
olylog(2,b*exp(2*x)/(2*(a*(a+b))^(1/2)-2*a-b))+1/(-2*(a*(a+b))^(1/2)-2*a-b)*ln(1-b*exp(2*x)/(-2*(a*(a+b))^(1/2
)-2*a-b))*x+1/(a*(a+b))^(1/2)/(-2*(a*(a+b))^(1/2)-2*a-b)*ln(1-b*exp(2*x)/(-2*(a*(a+b))^(1/2)-2*a-b))*a*x+1/2/(
a*(a+b))^(1/2)/(-2*(a*(a+b))^(1/2)-2*a-b)*ln(1-b*exp(2*x)/(-2*(a*(a+b))^(1/2)-2*a-b))*b*x-1/(-2*(a*(a+b))^(1/2
)-2*a-b)*x^2-1/(a*(a+b))^(1/2)/(-2*(a*(a+b))^(1/2)-2*a-b)*a*x^2-1/2/(a*(a+b))^(1/2)/(-2*(a*(a+b))^(1/2)-2*a-b)
*b*x^2+1/2/(-2*(a*(a+b))^(1/2)-2*a-b)*polylog(2,b*exp(2*x)/(-2*(a*(a+b))^(1/2)-2*a-b))+1/2/(a*(a+b))^(1/2)/(-2
*(a*(a+b))^(1/2)-2*a-b)*polylog(2,b*exp(2*x)/(-2*(a*(a+b))^(1/2)-2*a-b))*a+1/4/(a*(a+b))^(1/2)/(-2*(a*(a+b))^(
1/2)-2*a-b)*polylog(2,b*exp(2*x)/(-2*(a*(a+b))^(1/2)-2*a-b))*b

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{b \cosh \left (x\right )^{2} + a}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(a+b*cosh(x)^2),x, algorithm="maxima")

[Out]

integrate(x/(b*cosh(x)^2 + a), x)

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Fricas [B]  time = 1.95436, size = 1968, normalized size = 10.3 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(a+b*cosh(x)^2),x, algorithm="fricas")

[Out]

-1/2*(b*x*sqrt((a^2 + a*b)/b^2)*log((((2*a + b)*cosh(x) + (2*a + b)*sinh(x) - 2*(b*cosh(x) + b*sinh(x))*sqrt((
a^2 + a*b)/b^2))*sqrt(-(2*b*sqrt((a^2 + a*b)/b^2) + 2*a + b)/b) + b)/b) + b*x*sqrt((a^2 + a*b)/b^2)*log(-(((2*
a + b)*cosh(x) + (2*a + b)*sinh(x) - 2*(b*cosh(x) + b*sinh(x))*sqrt((a^2 + a*b)/b^2))*sqrt(-(2*b*sqrt((a^2 + a
*b)/b^2) + 2*a + b)/b) - b)/b) - b*x*sqrt((a^2 + a*b)/b^2)*log((((2*a + b)*cosh(x) + (2*a + b)*sinh(x) + 2*(b*
cosh(x) + b*sinh(x))*sqrt((a^2 + a*b)/b^2))*sqrt((2*b*sqrt((a^2 + a*b)/b^2) - 2*a - b)/b) + b)/b) - b*x*sqrt((
a^2 + a*b)/b^2)*log(-(((2*a + b)*cosh(x) + (2*a + b)*sinh(x) + 2*(b*cosh(x) + b*sinh(x))*sqrt((a^2 + a*b)/b^2)
)*sqrt((2*b*sqrt((a^2 + a*b)/b^2) - 2*a - b)/b) - b)/b) + b*sqrt((a^2 + a*b)/b^2)*dilog(-(((2*a + b)*cosh(x) +
(2*a + b)*sinh(x) - 2*(b*cosh(x) + b*sinh(x))*sqrt((a^2 + a*b)/b^2))*sqrt(-(2*b*sqrt((a^2 + a*b)/b^2) + 2*a +
b)/b) + b)/b + 1) + b*sqrt((a^2 + a*b)/b^2)*dilog((((2*a + b)*cosh(x) + (2*a + b)*sinh(x) - 2*(b*cosh(x) + b*
sinh(x))*sqrt((a^2 + a*b)/b^2))*sqrt(-(2*b*sqrt((a^2 + a*b)/b^2) + 2*a + b)/b) - b)/b + 1) - b*sqrt((a^2 + a*b
)/b^2)*dilog(-(((2*a + b)*cosh(x) + (2*a + b)*sinh(x) + 2*(b*cosh(x) + b*sinh(x))*sqrt((a^2 + a*b)/b^2))*sqrt(
(2*b*sqrt((a^2 + a*b)/b^2) - 2*a - b)/b) + b)/b + 1) - b*sqrt((a^2 + a*b)/b^2)*dilog((((2*a + b)*cosh(x) + (2*
a + b)*sinh(x) + 2*(b*cosh(x) + b*sinh(x))*sqrt((a^2 + a*b)/b^2))*sqrt((2*b*sqrt((a^2 + a*b)/b^2) - 2*a - b)/b
) - b)/b + 1))/(a^2 + a*b)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(a+b*cosh(x)**2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{b \cosh \left (x\right )^{2} + a}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(a+b*cosh(x)^2),x, algorithm="giac")

[Out]

integrate(x/(b*cosh(x)^2 + a), x)