Optimal. Leaf size=104 \[ -\frac{a x \left (2 a^2-3 b^2\right )}{2 b^4}+\frac{\sinh (x) \left (2 \left (a^2-b^2\right )-a b \cosh (x)\right )}{2 b^3}+\frac{2 (a-b)^{3/2} (a+b)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{a-b} \tanh \left (\frac{x}{2}\right )}{\sqrt{a+b}}\right )}{b^4}+\frac{\sinh ^3(x)}{3 b} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.240763, antiderivative size = 104, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.385, Rules used = {2695, 2865, 2735, 2659, 208} \[ -\frac{a x \left (2 a^2-3 b^2\right )}{2 b^4}+\frac{\sinh (x) \left (2 \left (a^2-b^2\right )-a b \cosh (x)\right )}{2 b^3}+\frac{2 (a-b)^{3/2} (a+b)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{a-b} \tanh \left (\frac{x}{2}\right )}{\sqrt{a+b}}\right )}{b^4}+\frac{\sinh ^3(x)}{3 b} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 2695
Rule 2865
Rule 2735
Rule 2659
Rule 208
Rubi steps
\begin{align*} \int \frac{\sinh ^4(x)}{a+b \cosh (x)} \, dx &=\frac{\sinh ^3(x)}{3 b}+\frac{\int \frac{(-b-a \cosh (x)) \sinh ^2(x)}{a+b \cosh (x)} \, dx}{b}\\ &=\frac{\left (2 \left (a^2-b^2\right )-a b \cosh (x)\right ) \sinh (x)}{2 b^3}+\frac{\sinh ^3(x)}{3 b}-\frac{\int \frac{b \left (a^2-2 b^2\right )+a \left (2 a^2-3 b^2\right ) \cosh (x)}{a+b \cosh (x)} \, dx}{2 b^3}\\ &=-\frac{a \left (2 a^2-3 b^2\right ) x}{2 b^4}+\frac{\left (2 \left (a^2-b^2\right )-a b \cosh (x)\right ) \sinh (x)}{2 b^3}+\frac{\sinh ^3(x)}{3 b}+\frac{\left (a^2-b^2\right )^2 \int \frac{1}{a+b \cosh (x)} \, dx}{b^4}\\ &=-\frac{a \left (2 a^2-3 b^2\right ) x}{2 b^4}+\frac{\left (2 \left (a^2-b^2\right )-a b \cosh (x)\right ) \sinh (x)}{2 b^3}+\frac{\sinh ^3(x)}{3 b}+\frac{\left (2 \left (a^2-b^2\right )^2\right ) \operatorname{Subst}\left (\int \frac{1}{a+b-(a-b) x^2} \, dx,x,\tanh \left (\frac{x}{2}\right )\right )}{b^4}\\ &=-\frac{a \left (2 a^2-3 b^2\right ) x}{2 b^4}+\frac{2 (a-b)^{3/2} (a+b)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{a-b} \tanh \left (\frac{x}{2}\right )}{\sqrt{a+b}}\right )}{b^4}+\frac{\left (2 \left (a^2-b^2\right )-a b \cosh (x)\right ) \sinh (x)}{2 b^3}+\frac{\sinh ^3(x)}{3 b}\\ \end{align*}
Mathematica [A] time = 0.179862, size = 95, normalized size = 0.91 \[ \frac{-24 \left (b^2-a^2\right )^{3/2} \tan ^{-1}\left (\frac{(a-b) \tanh \left (\frac{x}{2}\right )}{\sqrt{b^2-a^2}}\right )+12 a^2 b \sinh (x)-12 a^3 x+18 a b^2 x-3 a b^2 \sinh (2 x)-15 b^3 \sinh (x)+b^3 \sinh (3 x)}{12 b^4} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.021, size = 338, normalized size = 3.3 \begin{align*} 2\,{\frac{{a}^{4}}{{b}^{4}\sqrt{ \left ( a+b \right ) \left ( a-b \right ) }}{\it Artanh} \left ({\frac{ \left ( a-b \right ) \tanh \left ( x/2 \right ) }{\sqrt{ \left ( a+b \right ) \left ( a-b \right ) }}} \right ) }-4\,{\frac{{a}^{2}}{{b}^{2}\sqrt{ \left ( a+b \right ) \left ( a-b \right ) }}{\it Artanh} \left ({\frac{ \left ( a-b \right ) \tanh \left ( x/2 \right ) }{\sqrt{ \left ( a+b \right ) \left ( a-b \right ) }}} \right ) }+2\,{\frac{1}{\sqrt{ \left ( a+b \right ) \left ( a-b \right ) }}{\it Artanh} \left ({\frac{ \left ( a-b \right ) \tanh \left ( x/2 \right ) }{\sqrt{ \left ( a+b \right ) \left ( a-b \right ) }}} \right ) }-{\frac{1}{3\,b} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-3}}+{\frac{a}{2\,{b}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-2}}+{\frac{1}{2\,b} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-2}}-{\frac{{a}^{2}}{{b}^{3}} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-1}}-{\frac{a}{2\,{b}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-1}}+{\frac{1}{b} \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) ^{-1}}-{\frac{{a}^{3}}{{b}^{4}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) }+{\frac{3\,a}{2\,{b}^{2}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) }-{\frac{1}{3\,b} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-3}}-{\frac{a}{2\,{b}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-2}}-{\frac{1}{2\,b} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-2}}-{\frac{{a}^{2}}{{b}^{3}} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-1}}-{\frac{a}{2\,{b}^{2}} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-1}}+{\frac{1}{b} \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) ^{-1}}+{\frac{{a}^{3}}{{b}^{4}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) }-{\frac{3\,a}{2\,{b}^{2}}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [B] time = 2.08383, size = 2843, normalized size = 27.34 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A] time = 1.1654, size = 197, normalized size = 1.89 \begin{align*} \frac{b^{2} e^{\left (3 \, x\right )} - 3 \, a b e^{\left (2 \, x\right )} + 12 \, a^{2} e^{x} - 15 \, b^{2} e^{x}}{24 \, b^{3}} - \frac{{\left (2 \, a^{3} - 3 \, a b^{2}\right )} x}{2 \, b^{4}} + \frac{{\left (3 \, a b^{2} e^{x} - b^{3} - 3 \,{\left (4 \, a^{2} b - 5 \, b^{3}\right )} e^{\left (2 \, x\right )}\right )} e^{\left (-3 \, x\right )}}{24 \, b^{4}} + \frac{2 \,{\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} \arctan \left (\frac{b e^{x} + a}{\sqrt{-a^{2} + b^{2}}}\right )}{\sqrt{-a^{2} + b^{2}} b^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]