3.164 \(\int \frac{\text{csch}^5(x)}{a+a \cosh (x)} \, dx\)

Optimal. Leaf size=78 \[ \frac{a^2}{24 (a \cosh (x)+a)^3}-\frac{a}{32 (a-a \cosh (x))^2}+\frac{3 a}{32 (a \cosh (x)+a)^2}-\frac{1}{8 (a-a \cosh (x))}+\frac{3}{16 (a \cosh (x)+a)}-\frac{5 \tanh ^{-1}(\cosh (x))}{16 a} \]

[Out]

(-5*ArcTanh[Cosh[x]])/(16*a) - a/(32*(a - a*Cosh[x])^2) - 1/(8*(a - a*Cosh[x])) + a^2/(24*(a + a*Cosh[x])^3) +
 (3*a)/(32*(a + a*Cosh[x])^2) + 3/(16*(a + a*Cosh[x]))

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Rubi [A]  time = 0.106355, antiderivative size = 78, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {2667, 44, 206} \[ \frac{a^2}{24 (a \cosh (x)+a)^3}-\frac{a}{32 (a-a \cosh (x))^2}+\frac{3 a}{32 (a \cosh (x)+a)^2}-\frac{1}{8 (a-a \cosh (x))}+\frac{3}{16 (a \cosh (x)+a)}-\frac{5 \tanh ^{-1}(\cosh (x))}{16 a} \]

Antiderivative was successfully verified.

[In]

Int[Csch[x]^5/(a + a*Cosh[x]),x]

[Out]

(-5*ArcTanh[Cosh[x]])/(16*a) - a/(32*(a - a*Cosh[x])^2) - 1/(8*(a - a*Cosh[x])) + a^2/(24*(a + a*Cosh[x])^3) +
 (3*a)/(32*(a + a*Cosh[x])^2) + 3/(16*(a + a*Cosh[x]))

Rule 2667

Int[cos[(e_.) + (f_.)*(x_)]^(p_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.), x_Symbol] :> Dist[1/(b^p*f), S
ubst[Int[(a + x)^(m + (p - 1)/2)*(a - x)^((p - 1)/2), x], x, b*Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, m}, x]
&& IntegerQ[(p - 1)/2] && EqQ[a^2 - b^2, 0] && (GeQ[p, -1] ||  !IntegerQ[m + 1/2])

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
 /; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{\text{csch}^5(x)}{a+a \cosh (x)} \, dx &=-\left (a^5 \operatorname{Subst}\left (\int \frac{1}{(a-x)^3 (a+x)^4} \, dx,x,a \cosh (x)\right )\right )\\ &=-\left (a^5 \operatorname{Subst}\left (\int \left (\frac{1}{16 a^4 (a-x)^3}+\frac{1}{8 a^5 (a-x)^2}+\frac{1}{8 a^3 (a+x)^4}+\frac{3}{16 a^4 (a+x)^3}+\frac{3}{16 a^5 (a+x)^2}+\frac{5}{16 a^5 \left (a^2-x^2\right )}\right ) \, dx,x,a \cosh (x)\right )\right )\\ &=-\frac{a}{32 (a-a \cosh (x))^2}-\frac{1}{8 (a-a \cosh (x))}+\frac{a^2}{24 (a+a \cosh (x))^3}+\frac{3 a}{32 (a+a \cosh (x))^2}+\frac{3}{16 (a+a \cosh (x))}-\frac{5}{16} \operatorname{Subst}\left (\int \frac{1}{a^2-x^2} \, dx,x,a \cosh (x)\right )\\ &=-\frac{5 \tanh ^{-1}(\cosh (x))}{16 a}-\frac{a}{32 (a-a \cosh (x))^2}-\frac{1}{8 (a-a \cosh (x))}+\frac{a^2}{24 (a+a \cosh (x))^3}+\frac{3 a}{32 (a+a \cosh (x))^2}+\frac{3}{16 (a+a \cosh (x))}\\ \end{align*}

Mathematica [A]  time = 0.256084, size = 89, normalized size = 1.14 \[ \frac{\cosh ^2\left (\frac{x}{2}\right ) \left (-3 \text{csch}^4\left (\frac{x}{2}\right )+24 \text{csch}^2\left (\frac{x}{2}\right )+2 \text{sech}^6\left (\frac{x}{2}\right )+9 \text{sech}^4\left (\frac{x}{2}\right )+36 \text{sech}^2\left (\frac{x}{2}\right )+120 \log \left (\sinh \left (\frac{x}{2}\right )\right )-120 \log \left (\cosh \left (\frac{x}{2}\right )\right )\right )}{192 (a \cosh (x)+a)} \]

Antiderivative was successfully verified.

[In]

Integrate[Csch[x]^5/(a + a*Cosh[x]),x]

[Out]

(Cosh[x/2]^2*(24*Csch[x/2]^2 - 3*Csch[x/2]^4 - 120*Log[Cosh[x/2]] + 120*Log[Sinh[x/2]] + 36*Sech[x/2]^2 + 9*Se
ch[x/2]^4 + 2*Sech[x/2]^6))/(192*(a + a*Cosh[x]))

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Maple [A]  time = 0.022, size = 67, normalized size = 0.9 \begin{align*} -{\frac{1}{192\,a} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{6}}+{\frac{5}{128\,a} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{4}}-{\frac{5}{32\,a} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{2}}-{\frac{1}{128\,a} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-4}}+{\frac{5}{16\,a}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) }+{\frac{5}{64\,a} \left ( \tanh \left ({\frac{x}{2}} \right ) \right ) ^{-2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csch(x)^5/(a+a*cosh(x)),x)

[Out]

-1/192/a*tanh(1/2*x)^6+5/128/a*tanh(1/2*x)^4-5/32/a*tanh(1/2*x)^2-1/128/a/tanh(1/2*x)^4+5/16/a*ln(tanh(1/2*x))
+5/64/a/tanh(1/2*x)^2

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Maxima [B]  time = 1.02713, size = 209, normalized size = 2.68 \begin{align*} \frac{15 \, e^{\left (-x\right )} + 30 \, e^{\left (-2 \, x\right )} - 40 \, e^{\left (-3 \, x\right )} - 110 \, e^{\left (-4 \, x\right )} + 18 \, e^{\left (-5 \, x\right )} - 110 \, e^{\left (-6 \, x\right )} - 40 \, e^{\left (-7 \, x\right )} + 30 \, e^{\left (-8 \, x\right )} + 15 \, e^{\left (-9 \, x\right )}}{24 \,{\left (2 \, a e^{\left (-x\right )} - 3 \, a e^{\left (-2 \, x\right )} - 8 \, a e^{\left (-3 \, x\right )} + 2 \, a e^{\left (-4 \, x\right )} + 12 \, a e^{\left (-5 \, x\right )} + 2 \, a e^{\left (-6 \, x\right )} - 8 \, a e^{\left (-7 \, x\right )} - 3 \, a e^{\left (-8 \, x\right )} + 2 \, a e^{\left (-9 \, x\right )} + a e^{\left (-10 \, x\right )} + a\right )}} - \frac{5 \, \log \left (e^{\left (-x\right )} + 1\right )}{16 \, a} + \frac{5 \, \log \left (e^{\left (-x\right )} - 1\right )}{16 \, a} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(x)^5/(a+a*cosh(x)),x, algorithm="maxima")

[Out]

1/24*(15*e^(-x) + 30*e^(-2*x) - 40*e^(-3*x) - 110*e^(-4*x) + 18*e^(-5*x) - 110*e^(-6*x) - 40*e^(-7*x) + 30*e^(
-8*x) + 15*e^(-9*x))/(2*a*e^(-x) - 3*a*e^(-2*x) - 8*a*e^(-3*x) + 2*a*e^(-4*x) + 12*a*e^(-5*x) + 2*a*e^(-6*x) -
 8*a*e^(-7*x) - 3*a*e^(-8*x) + 2*a*e^(-9*x) + a*e^(-10*x) + a) - 5/16*log(e^(-x) + 1)/a + 5/16*log(e^(-x) - 1)
/a

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Fricas [B]  time = 2.08501, size = 5257, normalized size = 67.4 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(x)^5/(a+a*cosh(x)),x, algorithm="fricas")

[Out]

1/48*(30*cosh(x)^9 + 30*(9*cosh(x) + 2)*sinh(x)^8 + 30*sinh(x)^9 + 60*cosh(x)^8 + 40*(27*cosh(x)^2 + 12*cosh(x
) - 2)*sinh(x)^7 - 80*cosh(x)^7 + 20*(126*cosh(x)^3 + 84*cosh(x)^2 - 28*cosh(x) - 11)*sinh(x)^6 - 220*cosh(x)^
6 + 12*(315*cosh(x)^4 + 280*cosh(x)^3 - 140*cosh(x)^2 - 110*cosh(x) + 3)*sinh(x)^5 + 36*cosh(x)^5 + 20*(189*co
sh(x)^5 + 210*cosh(x)^4 - 140*cosh(x)^3 - 165*cosh(x)^2 + 9*cosh(x) - 11)*sinh(x)^4 - 220*cosh(x)^4 + 40*(63*c
osh(x)^6 + 84*cosh(x)^5 - 70*cosh(x)^4 - 110*cosh(x)^3 + 9*cosh(x)^2 - 22*cosh(x) - 2)*sinh(x)^3 - 80*cosh(x)^
3 + 60*(18*cosh(x)^7 + 28*cosh(x)^6 - 28*cosh(x)^5 - 55*cosh(x)^4 + 6*cosh(x)^3 - 22*cosh(x)^2 - 4*cosh(x) + 1
)*sinh(x)^2 + 60*cosh(x)^2 - 15*(cosh(x)^10 + 2*(5*cosh(x) + 1)*sinh(x)^9 + sinh(x)^10 + 2*cosh(x)^9 + 3*(15*c
osh(x)^2 + 6*cosh(x) - 1)*sinh(x)^8 - 3*cosh(x)^8 + 8*(15*cosh(x)^3 + 9*cosh(x)^2 - 3*cosh(x) - 1)*sinh(x)^7 -
 8*cosh(x)^7 + 2*(105*cosh(x)^4 + 84*cosh(x)^3 - 42*cosh(x)^2 - 28*cosh(x) + 1)*sinh(x)^6 + 2*cosh(x)^6 + 12*(
21*cosh(x)^5 + 21*cosh(x)^4 - 14*cosh(x)^3 - 14*cosh(x)^2 + cosh(x) + 1)*sinh(x)^5 + 12*cosh(x)^5 + 2*(105*cos
h(x)^6 + 126*cosh(x)^5 - 105*cosh(x)^4 - 140*cosh(x)^3 + 15*cosh(x)^2 + 30*cosh(x) + 1)*sinh(x)^4 + 2*cosh(x)^
4 + 8*(15*cosh(x)^7 + 21*cosh(x)^6 - 21*cosh(x)^5 - 35*cosh(x)^4 + 5*cosh(x)^3 + 15*cosh(x)^2 + cosh(x) - 1)*s
inh(x)^3 - 8*cosh(x)^3 + 3*(15*cosh(x)^8 + 24*cosh(x)^7 - 28*cosh(x)^6 - 56*cosh(x)^5 + 10*cosh(x)^4 + 40*cosh
(x)^3 + 4*cosh(x)^2 - 8*cosh(x) - 1)*sinh(x)^2 - 3*cosh(x)^2 + 2*(5*cosh(x)^9 + 9*cosh(x)^8 - 12*cosh(x)^7 - 2
8*cosh(x)^6 + 6*cosh(x)^5 + 30*cosh(x)^4 + 4*cosh(x)^3 - 12*cosh(x)^2 - 3*cosh(x) + 1)*sinh(x) + 2*cosh(x) + 1
)*log(cosh(x) + sinh(x) + 1) + 15*(cosh(x)^10 + 2*(5*cosh(x) + 1)*sinh(x)^9 + sinh(x)^10 + 2*cosh(x)^9 + 3*(15
*cosh(x)^2 + 6*cosh(x) - 1)*sinh(x)^8 - 3*cosh(x)^8 + 8*(15*cosh(x)^3 + 9*cosh(x)^2 - 3*cosh(x) - 1)*sinh(x)^7
 - 8*cosh(x)^7 + 2*(105*cosh(x)^4 + 84*cosh(x)^3 - 42*cosh(x)^2 - 28*cosh(x) + 1)*sinh(x)^6 + 2*cosh(x)^6 + 12
*(21*cosh(x)^5 + 21*cosh(x)^4 - 14*cosh(x)^3 - 14*cosh(x)^2 + cosh(x) + 1)*sinh(x)^5 + 12*cosh(x)^5 + 2*(105*c
osh(x)^6 + 126*cosh(x)^5 - 105*cosh(x)^4 - 140*cosh(x)^3 + 15*cosh(x)^2 + 30*cosh(x) + 1)*sinh(x)^4 + 2*cosh(x
)^4 + 8*(15*cosh(x)^7 + 21*cosh(x)^6 - 21*cosh(x)^5 - 35*cosh(x)^4 + 5*cosh(x)^3 + 15*cosh(x)^2 + cosh(x) - 1)
*sinh(x)^3 - 8*cosh(x)^3 + 3*(15*cosh(x)^8 + 24*cosh(x)^7 - 28*cosh(x)^6 - 56*cosh(x)^5 + 10*cosh(x)^4 + 40*co
sh(x)^3 + 4*cosh(x)^2 - 8*cosh(x) - 1)*sinh(x)^2 - 3*cosh(x)^2 + 2*(5*cosh(x)^9 + 9*cosh(x)^8 - 12*cosh(x)^7 -
 28*cosh(x)^6 + 6*cosh(x)^5 + 30*cosh(x)^4 + 4*cosh(x)^3 - 12*cosh(x)^2 - 3*cosh(x) + 1)*sinh(x) + 2*cosh(x) +
 1)*log(cosh(x) + sinh(x) - 1) + 10*(27*cosh(x)^8 + 48*cosh(x)^7 - 56*cosh(x)^6 - 132*cosh(x)^5 + 18*cosh(x)^4
 - 88*cosh(x)^3 - 24*cosh(x)^2 + 12*cosh(x) + 3)*sinh(x) + 30*cosh(x))/(a*cosh(x)^10 + a*sinh(x)^10 + 2*a*cosh
(x)^9 + 2*(5*a*cosh(x) + a)*sinh(x)^9 - 3*a*cosh(x)^8 + 3*(15*a*cosh(x)^2 + 6*a*cosh(x) - a)*sinh(x)^8 - 8*a*c
osh(x)^7 + 8*(15*a*cosh(x)^3 + 9*a*cosh(x)^2 - 3*a*cosh(x) - a)*sinh(x)^7 + 2*a*cosh(x)^6 + 2*(105*a*cosh(x)^4
 + 84*a*cosh(x)^3 - 42*a*cosh(x)^2 - 28*a*cosh(x) + a)*sinh(x)^6 + 12*a*cosh(x)^5 + 12*(21*a*cosh(x)^5 + 21*a*
cosh(x)^4 - 14*a*cosh(x)^3 - 14*a*cosh(x)^2 + a*cosh(x) + a)*sinh(x)^5 + 2*a*cosh(x)^4 + 2*(105*a*cosh(x)^6 +
126*a*cosh(x)^5 - 105*a*cosh(x)^4 - 140*a*cosh(x)^3 + 15*a*cosh(x)^2 + 30*a*cosh(x) + a)*sinh(x)^4 - 8*a*cosh(
x)^3 + 8*(15*a*cosh(x)^7 + 21*a*cosh(x)^6 - 21*a*cosh(x)^5 - 35*a*cosh(x)^4 + 5*a*cosh(x)^3 + 15*a*cosh(x)^2 +
 a*cosh(x) - a)*sinh(x)^3 - 3*a*cosh(x)^2 + 3*(15*a*cosh(x)^8 + 24*a*cosh(x)^7 - 28*a*cosh(x)^6 - 56*a*cosh(x)
^5 + 10*a*cosh(x)^4 + 40*a*cosh(x)^3 + 4*a*cosh(x)^2 - 8*a*cosh(x) - a)*sinh(x)^2 + 2*a*cosh(x) + 2*(5*a*cosh(
x)^9 + 9*a*cosh(x)^8 - 12*a*cosh(x)^7 - 28*a*cosh(x)^6 + 6*a*cosh(x)^5 + 30*a*cosh(x)^4 + 4*a*cosh(x)^3 - 12*a
*cosh(x)^2 - 3*a*cosh(x) + a)*sinh(x) + a)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(x)**5/(a+a*cosh(x)),x)

[Out]

Timed out

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Giac [A]  time = 1.16065, size = 157, normalized size = 2.01 \begin{align*} -\frac{5 \, \log \left (e^{\left (-x\right )} + e^{x} + 2\right )}{32 \, a} + \frac{5 \, \log \left (e^{\left (-x\right )} + e^{x} - 2\right )}{32 \, a} - \frac{15 \,{\left (e^{\left (-x\right )} + e^{x}\right )}^{2} - 76 \, e^{\left (-x\right )} - 76 \, e^{x} + 100}{64 \, a{\left (e^{\left (-x\right )} + e^{x} - 2\right )}^{2}} + \frac{55 \,{\left (e^{\left (-x\right )} + e^{x}\right )}^{3} + 402 \,{\left (e^{\left (-x\right )} + e^{x}\right )}^{2} + 1020 \, e^{\left (-x\right )} + 1020 \, e^{x} + 936}{192 \, a{\left (e^{\left (-x\right )} + e^{x} + 2\right )}^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(x)^5/(a+a*cosh(x)),x, algorithm="giac")

[Out]

-5/32*log(e^(-x) + e^x + 2)/a + 5/32*log(e^(-x) + e^x - 2)/a - 1/64*(15*(e^(-x) + e^x)^2 - 76*e^(-x) - 76*e^x
+ 100)/(a*(e^(-x) + e^x - 2)^2) + 1/192*(55*(e^(-x) + e^x)^3 + 402*(e^(-x) + e^x)^2 + 1020*e^(-x) + 1020*e^x +
 936)/(a*(e^(-x) + e^x + 2)^3)