3.36 \(\int \frac{1}{(b \sinh (c+d x))^{4/3}} \, dx\)

Optimal. Leaf size=58 \[ -\frac{3 \cosh (c+d x) \, _2F_1\left (-\frac{1}{6},\frac{1}{2};\frac{5}{6};-\sinh ^2(c+d x)\right )}{b d \sqrt{\cosh ^2(c+d x)} \sqrt [3]{b \sinh (c+d x)}} \]

[Out]

(-3*Cosh[c + d*x]*Hypergeometric2F1[-1/6, 1/2, 5/6, -Sinh[c + d*x]^2])/(b*d*Sqrt[Cosh[c + d*x]^2]*(b*Sinh[c +
d*x])^(1/3))

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Rubi [A]  time = 0.0154207, antiderivative size = 58, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.083, Rules used = {2643} \[ -\frac{3 \cosh (c+d x) \, _2F_1\left (-\frac{1}{6},\frac{1}{2};\frac{5}{6};-\sinh ^2(c+d x)\right )}{b d \sqrt{\cosh ^2(c+d x)} \sqrt [3]{b \sinh (c+d x)}} \]

Antiderivative was successfully verified.

[In]

Int[(b*Sinh[c + d*x])^(-4/3),x]

[Out]

(-3*Cosh[c + d*x]*Hypergeometric2F1[-1/6, 1/2, 5/6, -Sinh[c + d*x]^2])/(b*d*Sqrt[Cosh[c + d*x]^2]*(b*Sinh[c +
d*x])^(1/3))

Rule 2643

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(Cos[c + d*x]*(b*Sin[c + d*x])^(n + 1)*Hypergeomet
ric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2])/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]), x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rubi steps

\begin{align*} \int \frac{1}{(b \sinh (c+d x))^{4/3}} \, dx &=-\frac{3 \cosh (c+d x) \, _2F_1\left (-\frac{1}{6},\frac{1}{2};\frac{5}{6};-\sinh ^2(c+d x)\right )}{b d \sqrt{\cosh ^2(c+d x)} \sqrt [3]{b \sinh (c+d x)}}\\ \end{align*}

Mathematica [A]  time = 0.0372699, size = 55, normalized size = 0.95 \[ -\frac{3 \sqrt{\cosh ^2(c+d x)} \tanh (c+d x) \, _2F_1\left (-\frac{1}{6},\frac{1}{2};\frac{5}{6};-\sinh ^2(c+d x)\right )}{d (b \sinh (c+d x))^{4/3}} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*Sinh[c + d*x])^(-4/3),x]

[Out]

(-3*Sqrt[Cosh[c + d*x]^2]*Hypergeometric2F1[-1/6, 1/2, 5/6, -Sinh[c + d*x]^2]*Tanh[c + d*x])/(d*(b*Sinh[c + d*
x])^(4/3))

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Maple [F]  time = 0.023, size = 0, normalized size = 0. \begin{align*} \int \left ( b\sinh \left ( dx+c \right ) \right ) ^{-{\frac{4}{3}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*sinh(d*x+c))^(4/3),x)

[Out]

int(1/(b*sinh(d*x+c))^(4/3),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (b \sinh \left (d x + c\right )\right )^{\frac{4}{3}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*sinh(d*x+c))^(4/3),x, algorithm="maxima")

[Out]

integrate((b*sinh(d*x + c))^(-4/3), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\left (b \sinh \left (d x + c\right )\right )^{\frac{2}{3}}}{b^{2} \sinh \left (d x + c\right )^{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*sinh(d*x+c))^(4/3),x, algorithm="fricas")

[Out]

integral((b*sinh(d*x + c))^(2/3)/(b^2*sinh(d*x + c)^2), x)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (b \sinh{\left (c + d x \right )}\right )^{\frac{4}{3}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*sinh(d*x+c))**(4/3),x)

[Out]

Integral((b*sinh(c + d*x))**(-4/3), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (b \sinh \left (d x + c\right )\right )^{\frac{4}{3}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*sinh(d*x+c))^(4/3),x, algorithm="giac")

[Out]

integrate((b*sinh(d*x + c))^(-4/3), x)