Optimal. Leaf size=60 \[ \frac{2 B \left (a^2-b^2\right ) \tanh ^{-1}\left (\frac{b-a \tanh \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2}}\right )}{a b \sqrt{a^2+b^2}}+\frac{B x}{b} \]
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Rubi [A] time = 0.0837459, antiderivative size = 60, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {2735, 2660, 618, 206} \[ \frac{2 B \left (a^2-b^2\right ) \tanh ^{-1}\left (\frac{b-a \tanh \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2}}\right )}{a b \sqrt{a^2+b^2}}+\frac{B x}{b} \]
Antiderivative was successfully verified.
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Rule 2735
Rule 2660
Rule 618
Rule 206
Rubi steps
\begin{align*} \int \frac{\frac{b B}{a}+B \sinh (x)}{a+b \sinh (x)} \, dx &=\frac{B x}{b}-\frac{\left (i \left (-i a B+\frac{i b^2 B}{a}\right )\right ) \int \frac{1}{a+b \sinh (x)} \, dx}{b}\\ &=\frac{B x}{b}-\frac{\left (2 i \left (-i a B+\frac{i b^2 B}{a}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a+2 b x-a x^2} \, dx,x,\tanh \left (\frac{x}{2}\right )\right )}{b}\\ &=\frac{B x}{b}+\frac{\left (4 i \left (-i a B+\frac{i b^2 B}{a}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 \left (a^2+b^2\right )-x^2} \, dx,x,2 b-2 a \tanh \left (\frac{x}{2}\right )\right )}{b}\\ &=\frac{B x}{b}+\frac{2 \left (a^2-b^2\right ) B \tanh ^{-1}\left (\frac{b-a \tanh \left (\frac{x}{2}\right )}{\sqrt{a^2+b^2}}\right )}{a b \sqrt{a^2+b^2}}\\ \end{align*}
Mathematica [A] time = 0.0692626, size = 66, normalized size = 1.1 \[ \frac{B \left (a x-\frac{2 \left (a^2-b^2\right ) \tan ^{-1}\left (\frac{b-a \tanh \left (\frac{x}{2}\right )}{\sqrt{-a^2-b^2}}\right )}{\sqrt{-a^2-b^2}}\right )}{a b} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.02, size = 105, normalized size = 1.8 \begin{align*}{\frac{B}{b}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) +1 \right ) }-{\frac{B}{b}\ln \left ( \tanh \left ({\frac{x}{2}} \right ) -1 \right ) }-2\,{\frac{aB}{b\sqrt{{a}^{2}+{b}^{2}}}{\it Artanh} \left ( 1/2\,{\frac{2\,a\tanh \left ( x/2 \right ) -2\,b}{\sqrt{{a}^{2}+{b}^{2}}}} \right ) }+2\,{\frac{bB}{a\sqrt{{a}^{2}+{b}^{2}}}{\it Artanh} \left ( 1/2\,{\frac{2\,a\tanh \left ( x/2 \right ) -2\,b}{\sqrt{{a}^{2}+{b}^{2}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.78377, size = 398, normalized size = 6.63 \begin{align*} -\frac{{\left (B a^{2} - B b^{2}\right )} \sqrt{a^{2} + b^{2}} \log \left (\frac{b^{2} \cosh \left (x\right )^{2} + b^{2} \sinh \left (x\right )^{2} + 2 \, a b \cosh \left (x\right ) + 2 \, a^{2} + b^{2} + 2 \,{\left (b^{2} \cosh \left (x\right ) + a b\right )} \sinh \left (x\right ) - 2 \, \sqrt{a^{2} + b^{2}}{\left (b \cosh \left (x\right ) + b \sinh \left (x\right ) + a\right )}}{b \cosh \left (x\right )^{2} + b \sinh \left (x\right )^{2} + 2 \, a \cosh \left (x\right ) + 2 \,{\left (b \cosh \left (x\right ) + a\right )} \sinh \left (x\right ) - b}\right ) -{\left (B a^{3} + B a b^{2}\right )} x}{a^{3} b + a b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 103.155, size = 350, normalized size = 5.83 \begin{align*} \begin{cases} \text{NaN} & \text{for}\: a = 0 \wedge b = 0 \\\frac{B \cosh{\left (x \right )}}{a} & \text{for}\: b = 0 \\\frac{B b x}{b^{2} + i b \sqrt{b^{2}} \tanh{\left (\frac{x}{2} \right )}} - \frac{4 B b \tanh{\left (\frac{x}{2} \right )}}{b^{2} + i b \sqrt{b^{2}} \tanh{\left (\frac{x}{2} \right )}} + \frac{i B x \sqrt{b^{2}} \tanh{\left (\frac{x}{2} \right )}}{b^{2} + i b \sqrt{b^{2}} \tanh{\left (\frac{x}{2} \right )}} & \text{for}\: a = - \sqrt{- b^{2}} \\- \frac{B b x}{- b^{2} + i b \sqrt{b^{2}} \tanh{\left (\frac{x}{2} \right )}} + \frac{4 B b \tanh{\left (\frac{x}{2} \right )}}{- b^{2} + i b \sqrt{b^{2}} \tanh{\left (\frac{x}{2} \right )}} + \frac{i B x \sqrt{b^{2}} \tanh{\left (\frac{x}{2} \right )}}{- b^{2} + i b \sqrt{b^{2}} \tanh{\left (\frac{x}{2} \right )}} & \text{for}\: a = \sqrt{- b^{2}} \\\frac{B a \log{\left (\tanh{\left (\frac{x}{2} \right )} - \frac{b}{a} - \frac{\sqrt{a^{2} + b^{2}}}{a} \right )}}{b \sqrt{a^{2} + b^{2}}} - \frac{B a \log{\left (\tanh{\left (\frac{x}{2} \right )} - \frac{b}{a} + \frac{\sqrt{a^{2} + b^{2}}}{a} \right )}}{b \sqrt{a^{2} + b^{2}}} + \frac{B x}{b} - \frac{B b \log{\left (\tanh{\left (\frac{x}{2} \right )} - \frac{b}{a} - \frac{\sqrt{a^{2} + b^{2}}}{a} \right )}}{a \sqrt{a^{2} + b^{2}}} + \frac{B b \log{\left (\tanh{\left (\frac{x}{2} \right )} - \frac{b}{a} + \frac{\sqrt{a^{2} + b^{2}}}{a} \right )}}{a \sqrt{a^{2} + b^{2}}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.26471, size = 111, normalized size = 1.85 \begin{align*} \frac{B x}{b} - \frac{{\left (B a^{2} - B b^{2}\right )} \log \left (\frac{{\left | 2 \, b e^{x} + 2 \, a - 2 \, \sqrt{a^{2} + b^{2}} \right |}}{{\left | 2 \, b e^{x} + 2 \, a + 2 \, \sqrt{a^{2} + b^{2}} \right |}}\right )}{\sqrt{a^{2} + b^{2}} a b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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