Optimal. Leaf size=264 \[ \frac{6 i a \csc ^{-1}(a+b x) \text{PolyLog}\left (2,-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{6 i a \csc ^{-1}(a+b x) \text{PolyLog}\left (2,e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{3 i \text{PolyLog}\left (2,e^{2 i \csc ^{-1}(a+b x)}\right )}{2 b^2}-\frac{6 a \text{PolyLog}\left (3,-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{6 a \text{PolyLog}\left (3,e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac{3 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}+\frac{3 i \csc ^{-1}(a+b x)^2}{2 b^2}-\frac{3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3 \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.255632, antiderivative size = 264, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 12, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 1.2, Rules used = {5259, 4427, 4190, 4183, 2531, 2282, 6589, 4184, 3717, 2190, 2279, 2391} \[ \frac{6 i a \csc ^{-1}(a+b x) \text{PolyLog}\left (2,-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{6 i a \csc ^{-1}(a+b x) \text{PolyLog}\left (2,e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{3 i \text{PolyLog}\left (2,e^{2 i \csc ^{-1}(a+b x)}\right )}{2 b^2}-\frac{6 a \text{PolyLog}\left (3,-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{6 a \text{PolyLog}\left (3,e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac{3 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}+\frac{3 i \csc ^{-1}(a+b x)^2}{2 b^2}-\frac{3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3 \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 5259
Rule 4427
Rule 4190
Rule 4183
Rule 2531
Rule 2282
Rule 6589
Rule 4184
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int x \csc ^{-1}(a+b x)^3 \, dx &=-\frac{\operatorname{Subst}\left (\int x^3 \cot (x) \csc (x) (-a+\csc (x)) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}\\ &=\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac{3 \operatorname{Subst}\left (\int x^2 (-a+\csc (x))^2 \, dx,x,\csc ^{-1}(a+b x)\right )}{2 b^2}\\ &=\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac{3 \operatorname{Subst}\left (\int \left (a^2 x^2-2 a x^2 \csc (x)+x^2 \csc ^2(x)\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{2 b^2}\\ &=-\frac{a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac{3 \operatorname{Subst}\left (\int x^2 \csc ^2(x) \, dx,x,\csc ^{-1}(a+b x)\right )}{2 b^2}+\frac{(3 a) \operatorname{Subst}\left (\int x^2 \csc (x) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}\\ &=\frac{3 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac{a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac{6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{3 \operatorname{Subst}\left (\int x \cot (x) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}-\frac{(6 a) \operatorname{Subst}\left (\int x \log \left (1-e^{i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}+\frac{(6 a) \operatorname{Subst}\left (\int x \log \left (1+e^{i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}\\ &=\frac{3 i \csc ^{-1}(a+b x)^2}{2 b^2}+\frac{3 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac{a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac{6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{6 i a \csc ^{-1}(a+b x) \text{Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{6 i a \csc ^{-1}(a+b x) \text{Li}_2\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{(6 i) \operatorname{Subst}\left (\int \frac{e^{2 i x} x}{1-e^{2 i x}} \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}-\frac{(6 i a) \operatorname{Subst}\left (\int \text{Li}_2\left (-e^{i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}+\frac{(6 i a) \operatorname{Subst}\left (\int \text{Li}_2\left (e^{i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}\\ &=\frac{3 i \csc ^{-1}(a+b x)^2}{2 b^2}+\frac{3 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac{a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac{6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{6 i a \csc ^{-1}(a+b x) \text{Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{6 i a \csc ^{-1}(a+b x) \text{Li}_2\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{3 \operatorname{Subst}\left (\int \log \left (1-e^{2 i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}-\frac{(6 a) \operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{(6 a) \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )}{b^2}\\ &=\frac{3 i \csc ^{-1}(a+b x)^2}{2 b^2}+\frac{3 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac{a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac{6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{6 i a \csc ^{-1}(a+b x) \text{Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{6 i a \csc ^{-1}(a+b x) \text{Li}_2\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{6 a \text{Li}_3\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{6 a \text{Li}_3\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{(3 i) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i \csc ^{-1}(a+b x)}\right )}{2 b^2}\\ &=\frac{3 i \csc ^{-1}(a+b x)^2}{2 b^2}+\frac{3 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac{a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac{6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{6 i a \csc ^{-1}(a+b x) \text{Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac{6 i a \csc ^{-1}(a+b x) \text{Li}_2\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{3 i \text{Li}_2\left (e^{2 i \csc ^{-1}(a+b x)}\right )}{2 b^2}-\frac{6 a \text{Li}_3\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac{6 a \text{Li}_3\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}\\ \end{align*}
Mathematica [A] time = 0.805551, size = 314, normalized size = 1.19 \[ \frac{12 i a \csc ^{-1}(a+b x) \text{PolyLog}\left (2,-e^{i \csc ^{-1}(a+b x)}\right )-12 i a \csc ^{-1}(a+b x) \text{PolyLog}\left (2,e^{i \csc ^{-1}(a+b x)}\right )+3 i \text{PolyLog}\left (2,e^{2 i \csc ^{-1}(a+b x)}\right )-12 a \text{PolyLog}\left (3,-e^{i \csc ^{-1}(a+b x)}\right )+12 a \text{PolyLog}\left (3,e^{i \csc ^{-1}(a+b x)}\right )+3 a \sqrt{\frac{a^2+2 a b x+b^2 x^2-1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2+3 b x \sqrt{\frac{a^2+2 a b x+b^2 x^2-1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2-a^2 \csc ^{-1}(a+b x)^3+b^2 x^2 \csc ^{-1}(a+b x)^3+3 i \csc ^{-1}(a+b x)^2+6 a \csc ^{-1}(a+b x)^2 \log \left (1-e^{i \csc ^{-1}(a+b x)}\right )-6 a \csc ^{-1}(a+b x)^2 \log \left (1+e^{i \csc ^{-1}(a+b x)}\right )-6 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{2 b^2} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 0.425, size = 481, normalized size = 1.8 \begin{align*}{\frac{{x}^{2} \left ({\rm arccsc} \left (bx+a\right ) \right ) ^{3}}{2}}-{\frac{{a}^{2} \left ({\rm arccsc} \left (bx+a\right ) \right ) ^{3}}{2\,{b}^{2}}}+{\frac{3\,x \left ({\rm arccsc} \left (bx+a\right ) \right ) ^{2}}{2\,b}\sqrt{{\frac{-1+ \left ( bx+a \right ) ^{2}}{ \left ( bx+a \right ) ^{2}}}}}+{\frac{3\, \left ({\rm arccsc} \left (bx+a\right ) \right ) ^{2}a}{2\,{b}^{2}}\sqrt{{\frac{-1+ \left ( bx+a \right ) ^{2}}{ \left ( bx+a \right ) ^{2}}}}}+{\frac{{\frac{3\,i}{2}} \left ({\rm arccsc} \left (bx+a\right ) \right ) ^{2}}{{b}^{2}}}+3\,{\frac{ \left ({\rm arccsc} \left (bx+a\right ) \right ) ^{2}a}{{b}^{2}}\ln \left ( 1-{\frac{i}{bx+a}}-\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) }-3\,{\frac{ \left ({\rm arccsc} \left (bx+a\right ) \right ) ^{2}a}{{b}^{2}}\ln \left ( 1+{\frac{i}{bx+a}}+\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) }-3\,{\frac{{\rm arccsc} \left (bx+a\right )}{{b}^{2}}\ln \left ( 1-{\frac{i}{bx+a}}-\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) }+6\,{\frac{a}{{b}^{2}}{\it polylog} \left ( 3,{\frac{i}{bx+a}}+\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) }-3\,{\frac{{\rm arccsc} \left (bx+a\right )}{{b}^{2}}\ln \left ( 1+{\frac{i}{bx+a}}+\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) }-6\,{\frac{a}{{b}^{2}}{\it polylog} \left ( 3,{\frac{-i}{bx+a}}-\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) }-{\frac{6\,ia{\rm arccsc} \left (bx+a\right )}{{b}^{2}}{\it polylog} \left ( 2,{\frac{i}{bx+a}}+\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) }+{\frac{6\,ia{\rm arccsc} \left (bx+a\right )}{{b}^{2}}{\it polylog} \left ( 2,{\frac{-i}{bx+a}}-\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) }+{\frac{3\,i}{{b}^{2}}{\it polylog} \left ( 2,{\frac{i}{bx+a}}+\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) }+{\frac{3\,i}{{b}^{2}}{\it polylog} \left ( 2,{\frac{-i}{bx+a}}-\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{2} \, x^{2} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right )^{3} - \frac{3}{8} \, x^{2} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) \log \left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )^{2} - \int \frac{3 \,{\left (8 \,{\left (b^{3} x^{4} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) + 3 \, a b^{2} x^{3} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) +{\left (3 \, a^{2} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) - \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right )\right )} b x^{2} +{\left (a^{3} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) - a \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right )\right )} x\right )} \log \left (b x + a\right )^{2} -{\left (4 \, b x^{2} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right )^{2} - b x^{2} \log \left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )^{2}\right )} \sqrt{b x + a + 1} \sqrt{b x + a - 1} - 4 \,{\left (b^{3} x^{4} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) + 2 \, a b^{2} x^{3} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) +{\left (a^{2} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) - \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right )\right )} b x^{2} + 2 \,{\left (b^{3} x^{4} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) + 3 \, a b^{2} x^{3} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) +{\left (3 \, a^{2} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) - \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right )\right )} b x^{2} +{\left (a^{3} \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) - a \arctan \left (1, \sqrt{b x + a + 1} \sqrt{b x + a - 1}\right )\right )} x\right )} \log \left (b x + a\right )\right )} \log \left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )\right )}}{8 \,{\left (b^{3} x^{3} + 3 \, a b^{2} x^{2} + a^{3} +{\left (3 \, a^{2} - 1\right )} b x - a\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (x \operatorname{arccsc}\left (b x + a\right )^{3}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \operatorname{acsc}^{3}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \operatorname{arccsc}\left (b x + a\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]