Optimal. Leaf size=254 \[ -\frac{2 b \text{PolyLog}\left (2,-\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{2 b \text{PolyLog}\left (2,-\frac{i a e^{i \csc ^{-1}(a+b x)}}{\sqrt{1-a^2}+1}\right )}{a \sqrt{1-a^2}}-\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{\sqrt{1-a^2}+1}\right )}{a \sqrt{1-a^2}}-\frac{b \csc ^{-1}(a+b x)^2}{a}-\frac{\csc ^{-1}(a+b x)^2}{x} \]
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Rubi [A] time = 0.415623, antiderivative size = 254, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 8, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.667, Rules used = {5259, 4427, 4191, 3323, 2264, 2190, 2279, 2391} \[ -\frac{2 b \text{PolyLog}\left (2,-\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{2 b \text{PolyLog}\left (2,-\frac{i a e^{i \csc ^{-1}(a+b x)}}{\sqrt{1-a^2}+1}\right )}{a \sqrt{1-a^2}}-\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{\sqrt{1-a^2}+1}\right )}{a \sqrt{1-a^2}}-\frac{b \csc ^{-1}(a+b x)^2}{a}-\frac{\csc ^{-1}(a+b x)^2}{x} \]
Antiderivative was successfully verified.
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Rule 5259
Rule 4427
Rule 4191
Rule 3323
Rule 2264
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\csc ^{-1}(a+b x)^2}{x^2} \, dx &=-\left (b \operatorname{Subst}\left (\int \frac{x^2 \cot (x) \csc (x)}{(-a+\csc (x))^2} \, dx,x,\csc ^{-1}(a+b x)\right )\right )\\ &=-\frac{\csc ^{-1}(a+b x)^2}{x}+(2 b) \operatorname{Subst}\left (\int \frac{x}{-a+\csc (x)} \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=-\frac{\csc ^{-1}(a+b x)^2}{x}+(2 b) \operatorname{Subst}\left (\int \left (-\frac{x}{a}+\frac{x}{a (1-a \sin (x))}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=-\frac{b \csc ^{-1}(a+b x)^2}{a}-\frac{\csc ^{-1}(a+b x)^2}{x}+\frac{(2 b) \operatorname{Subst}\left (\int \frac{x}{1-a \sin (x)} \, dx,x,\csc ^{-1}(a+b x)\right )}{a}\\ &=-\frac{b \csc ^{-1}(a+b x)^2}{a}-\frac{\csc ^{-1}(a+b x)^2}{x}+\frac{(4 b) \operatorname{Subst}\left (\int \frac{e^{i x} x}{-i a+2 e^{i x}+i a e^{2 i x}} \, dx,x,\csc ^{-1}(a+b x)\right )}{a}\\ &=-\frac{b \csc ^{-1}(a+b x)^2}{a}-\frac{\csc ^{-1}(a+b x)^2}{x}+\frac{(4 i b) \operatorname{Subst}\left (\int \frac{e^{i x} x}{2-2 \sqrt{1-a^2}+2 i a e^{i x}} \, dx,x,\csc ^{-1}(a+b x)\right )}{\sqrt{1-a^2}}-\frac{(4 i b) \operatorname{Subst}\left (\int \frac{e^{i x} x}{2+2 \sqrt{1-a^2}+2 i a e^{i x}} \, dx,x,\csc ^{-1}(a+b x)\right )}{\sqrt{1-a^2}}\\ &=-\frac{b \csc ^{-1}(a+b x)^2}{a}-\frac{\csc ^{-1}(a+b x)^2}{x}-\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{(2 i b) \operatorname{Subst}\left (\int \log \left (1+\frac{2 i a e^{i x}}{2-2 \sqrt{1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{a \sqrt{1-a^2}}-\frac{(2 i b) \operatorname{Subst}\left (\int \log \left (1+\frac{2 i a e^{i x}}{2+2 \sqrt{1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{a \sqrt{1-a^2}}\\ &=-\frac{b \csc ^{-1}(a+b x)^2}{a}-\frac{\csc ^{-1}(a+b x)^2}{x}-\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{(2 b) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 i a x}{2-2 \sqrt{1-a^2}}\right )}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )}{a \sqrt{1-a^2}}-\frac{(2 b) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 i a x}{2+2 \sqrt{1-a^2}}\right )}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )}{a \sqrt{1-a^2}}\\ &=-\frac{b \csc ^{-1}(a+b x)^2}{a}-\frac{\csc ^{-1}(a+b x)^2}{x}-\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{2 i b \csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}-\frac{2 b \text{Li}_2\left (-\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}+\frac{2 b \text{Li}_2\left (-\frac{i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt{1-a^2}}\right )}{a \sqrt{1-a^2}}\\ \end{align*}
Mathematica [B] time = 3.09822, size = 802, normalized size = 3.16 \[ -\frac{b \left (\frac{(a+b x) \csc ^{-1}(a+b x)^2}{b x}+\frac{2 \pi \tan ^{-1}\left (\frac{a-\tan \left (\frac{1}{2} \csc ^{-1}(a+b x)\right )}{\sqrt{1-a^2}}\right )}{\sqrt{1-a^2}}+\frac{2 \left (-2 \cos ^{-1}\left (\frac{1}{a}\right ) \tanh ^{-1}\left (\frac{(a+1) \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )}{\sqrt{a^2-1}}\right )+\left (\pi -2 \csc ^{-1}(a+b x)\right ) \tanh ^{-1}\left (\frac{(a-1) \tan \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )}{\sqrt{a^2-1}}\right )+\left (\cos ^{-1}\left (\frac{1}{a}\right )+2 i \left (\tanh ^{-1}\left (\frac{(a-1) \tan \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )}{\sqrt{a^2-1}}\right )-\tanh ^{-1}\left (\frac{(a+1) \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )}{\sqrt{a^2-1}}\right )\right )\right ) \log \left (\frac{\left (\frac{1}{2}+\frac{i}{2}\right ) \sqrt{a^2-1} e^{-\frac{1}{2} i \csc ^{-1}(a+b x)}}{\sqrt{a} \sqrt{-\frac{b x}{a+b x}}}\right )+\left (\cos ^{-1}\left (\frac{1}{a}\right )+2 i \tanh ^{-1}\left (\frac{(a+1) \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )}{\sqrt{a^2-1}}\right )-2 i \tanh ^{-1}\left (\frac{(a-1) \tan \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )}{\sqrt{a^2-1}}\right )\right ) \log \left (\frac{\left (\frac{1}{2}-\frac{i}{2}\right ) \sqrt{a^2-1} e^{\frac{1}{2} i \csc ^{-1}(a+b x)}}{\sqrt{a} \sqrt{-\frac{b x}{a+b x}}}\right )-\left (\cos ^{-1}\left (\frac{1}{a}\right )-2 i \tanh ^{-1}\left (\frac{(a+1) \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )}{\sqrt{a^2-1}}\right )\right ) \log \left (\frac{(a-1) \left (i a+\sqrt{a^2-1}+i\right ) \left (\cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )-i\right )}{a \left (a+\sqrt{a^2-1} \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )-1\right )}\right )-\left (\cos ^{-1}\left (\frac{1}{a}\right )+2 i \tanh ^{-1}\left (\frac{(a+1) \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )}{\sqrt{a^2-1}}\right )\right ) \log \left (\frac{(a-1) \left (-i a+\sqrt{a^2-1}-i\right ) \left (\cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )+i\right )}{a \left (a+\sqrt{a^2-1} \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )-1\right )}\right )+i \left (\text{PolyLog}\left (2,\frac{\left (i \sqrt{a^2-1}+1\right ) \left (-a+\sqrt{a^2-1} \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )+1\right )}{a \left (a+\sqrt{a^2-1} \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )-1\right )}\right )-\text{PolyLog}\left (2,\frac{\left (1-i \sqrt{a^2-1}\right ) \left (-a+\sqrt{a^2-1} \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )+1\right )}{a \left (a+\sqrt{a^2-1} \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )-1\right )}\right )\right )\right )}{\sqrt{a^2-1}}\right )}{a} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.493, size = 307, normalized size = 1.2 \begin{align*} -{\frac{b \left ({\rm arccsc} \left (bx+a\right ) \right ) ^{2}}{a}}-{\frac{ \left ({\rm arccsc} \left (bx+a\right ) \right ) ^{2}}{x}}+2\,{\frac{b{\rm arccsc} \left (bx+a\right )}{a\sqrt{{a}^{2}-1}}\ln \left ({\frac{1}{i-\sqrt{{a}^{2}-1}} \left ( -a \left ({\frac{i}{bx+a}}+\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) +i-\sqrt{{a}^{2}-1} \right ) } \right ) }-2\,{\frac{b{\rm arccsc} \left (bx+a\right )}{a\sqrt{{a}^{2}-1}}\ln \left ({\frac{1}{i+\sqrt{{a}^{2}-1}} \left ( -a \left ({\frac{i}{bx+a}}+\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) +\sqrt{{a}^{2}-1}+i \right ) } \right ) }+{\frac{2\,ib}{a}{\it dilog} \left ({ \left ( -a \left ({\frac{i}{bx+a}}+\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) +\sqrt{{a}^{2}-1}+i \right ) \left ( i+\sqrt{{a}^{2}-1} \right ) ^{-1}} \right ){\frac{1}{\sqrt{{a}^{2}-1}}}}-{\frac{2\,ib}{a}{\it dilog} \left ({ \left ( -a \left ({\frac{i}{bx+a}}+\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) +i-\sqrt{{a}^{2}-1} \right ) \left ( i-\sqrt{{a}^{2}-1} \right ) ^{-1}} \right ){\frac{1}{\sqrt{{a}^{2}-1}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{arccsc}\left (b x + a\right )^{2}}{x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{acsc}^{2}{\left (a + b x \right )}}{x^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arccsc}\left (b x + a\right )^{2}}{x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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