Optimal. Leaf size=210 \[ -i \text{PolyLog}\left (2,-\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )-i \text{PolyLog}\left (2,-\frac{i a e^{i \csc ^{-1}(a+b x)}}{\sqrt{1-a^2}+1}\right )+\frac{1}{2} i \text{PolyLog}\left (2,e^{2 i \csc ^{-1}(a+b x)}\right )+\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )+\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{\sqrt{1-a^2}+1}\right )-\csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right ) \]
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Rubi [A] time = 0.30023, antiderivative size = 210, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 8, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.8, Rules used = {5259, 4552, 4529, 3717, 2190, 2279, 2391, 4519} \[ -i \text{PolyLog}\left (2,-\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )-i \text{PolyLog}\left (2,-\frac{i a e^{i \csc ^{-1}(a+b x)}}{\sqrt{1-a^2}+1}\right )+\frac{1}{2} i \text{PolyLog}\left (2,e^{2 i \csc ^{-1}(a+b x)}\right )+\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )+\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{\sqrt{1-a^2}+1}\right )-\csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right ) \]
Antiderivative was successfully verified.
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Rule 5259
Rule 4552
Rule 4529
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rule 4519
Rubi steps
\begin{align*} \int \frac{\csc ^{-1}(a+b x)}{x} \, dx &=-\operatorname{Subst}\left (\int \frac{x \cot (x) \csc (x)}{-a+\csc (x)} \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=-\operatorname{Subst}\left (\int \frac{x \cot (x)}{1-a \sin (x)} \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=-\left (a \operatorname{Subst}\left (\int \frac{x \cos (x)}{1-a \sin (x)} \, dx,x,\csc ^{-1}(a+b x)\right )\right )-\operatorname{Subst}\left (\int x \cot (x) \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=2 i \operatorname{Subst}\left (\int \frac{e^{2 i x} x}{1-e^{2 i x}} \, dx,x,\csc ^{-1}(a+b x)\right )-a \operatorname{Subst}\left (\int \frac{e^{i x} x}{1-\sqrt{1-a^2}+i a e^{i x}} \, dx,x,\csc ^{-1}(a+b x)\right )-a \operatorname{Subst}\left (\int \frac{e^{i x} x}{1+\sqrt{1-a^2}+i a e^{i x}} \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )+\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt{1-a^2}}\right )-\csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )-\operatorname{Subst}\left (\int \log \left (1+\frac{i a e^{i x}}{1-\sqrt{1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )-\operatorname{Subst}\left (\int \log \left (1+\frac{i a e^{i x}}{1+\sqrt{1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )+\operatorname{Subst}\left (\int \log \left (1-e^{2 i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )+\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt{1-a^2}}\right )-\csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )-\frac{1}{2} i \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i \csc ^{-1}(a+b x)}\right )+i \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{i a x}{1-\sqrt{1-a^2}}\right )}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )+i \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{i a x}{1+\sqrt{1-a^2}}\right )}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )\\ &=\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )+\csc ^{-1}(a+b x) \log \left (1+\frac{i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt{1-a^2}}\right )-\csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )-i \text{Li}_2\left (-\frac{i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt{1-a^2}}\right )-i \text{Li}_2\left (-\frac{i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt{1-a^2}}\right )+\frac{1}{2} i \text{Li}_2\left (e^{2 i \csc ^{-1}(a+b x)}\right )\\ \end{align*}
Mathematica [A] time = 0.411638, size = 375, normalized size = 1.79 \[ \frac{1}{8} \left (8 i \left (\text{PolyLog}\left (2,-\frac{i \left (\sqrt{1-a^2}-1\right ) e^{-i \csc ^{-1}(a+b x)}}{a}\right )+\text{PolyLog}\left (2,\frac{i \left (\sqrt{1-a^2}+1\right ) e^{-i \csc ^{-1}(a+b x)}}{a}\right )\right )+4 i \left (\csc ^{-1}(a+b x)^2+\text{PolyLog}\left (2,e^{2 i \csc ^{-1}(a+b x)}\right )\right )-4 \log \left (1+\frac{i \left (\sqrt{1-a^2}-1\right ) e^{-i \csc ^{-1}(a+b x)}}{a}\right ) \left (-2 \csc ^{-1}(a+b x)+4 \sin ^{-1}\left (\frac{\sqrt{\frac{a-1}{a}}}{\sqrt{2}}\right )+\pi \right )-4 \log \left (1-\frac{i \left (\sqrt{1-a^2}+1\right ) e^{-i \csc ^{-1}(a+b x)}}{a}\right ) \left (-2 \csc ^{-1}(a+b x)-4 \sin ^{-1}\left (\frac{\sqrt{\frac{a-1}{a}}}{\sqrt{2}}\right )+\pi \right )-32 i \sin ^{-1}\left (\frac{\sqrt{\frac{a-1}{a}}}{\sqrt{2}}\right ) \tan ^{-1}\left (\frac{(a+1) \cot \left (\frac{1}{4} \left (2 \csc ^{-1}(a+b x)+\pi \right )\right )}{\sqrt{1-a^2}}\right )+i \left (\pi -2 \csc ^{-1}(a+b x)\right )^2+4 \log \left (\frac{b x}{a+b x}\right ) \left (\pi -2 \csc ^{-1}(a+b x)\right )-8 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )+8 \log \left (\frac{b x}{a+b x}\right ) \csc ^{-1}(a+b x)\right ) \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.439, size = 607, normalized size = 2.9 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arccsc}\left (b x + a\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{arccsc}\left (b x + a\right )}{x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{acsc}{\left (a + b x \right )}}{x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{arccsc}\left (b x + a\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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