3.41 \(\int x^{-1+n} \sec ^{-1}(a+b x^n) \, dx\)

Optimal. Leaf size=49 \[ \frac{\left (a+b x^n\right ) \sec ^{-1}\left (a+b x^n\right )}{b n}-\frac{\tanh ^{-1}\left (\sqrt{1-\frac{1}{\left (a+b x^n\right )^2}}\right )}{b n} \]

[Out]

((a + b*x^n)*ArcSec[a + b*x^n])/(b*n) - ArcTanh[Sqrt[1 - (a + b*x^n)^(-2)]]/(b*n)

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Rubi [A]  time = 0.0716714, antiderivative size = 49, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.429, Rules used = {6715, 5250, 372, 266, 63, 206} \[ \frac{\left (a+b x^n\right ) \sec ^{-1}\left (a+b x^n\right )}{b n}-\frac{\tanh ^{-1}\left (\sqrt{1-\frac{1}{\left (a+b x^n\right )^2}}\right )}{b n} \]

Antiderivative was successfully verified.

[In]

Int[x^(-1 + n)*ArcSec[a + b*x^n],x]

[Out]

((a + b*x^n)*ArcSec[a + b*x^n])/(b*n) - ArcTanh[Sqrt[1 - (a + b*x^n)^(-2)]]/(b*n)

Rule 6715

Int[(u_)*(x_)^(m_.), x_Symbol] :> Dist[1/(m + 1), Subst[Int[SubstFor[x^(m + 1), u, x], x], x, x^(m + 1)], x] /
; FreeQ[m, x] && NeQ[m, -1] && FunctionOfQ[x^(m + 1), u, x]

Rule 5250

Int[ArcSec[(c_) + (d_.)*(x_)], x_Symbol] :> Simp[((c + d*x)*ArcSec[c + d*x])/d, x] - Int[1/((c + d*x)*Sqrt[1 -
1/(c + d*x)^2]), x] /; FreeQ[{c, d}, x]

Rule 372

Int[(u_)^(m_.)*((a_) + (b_.)*(v_)^(n_))^(p_.), x_Symbol] :> Dist[u^m/(Coefficient[v, x, 1]*v^m), Subst[Int[x^m
*(a + b*x^n)^p, x], x, v], x] /; FreeQ[{a, b, m, n, p}, x] && LinearPairQ[u, v, x]

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int x^{-1+n} \sec ^{-1}\left (a+b x^n\right ) \, dx &=\frac{\operatorname{Subst}\left (\int \sec ^{-1}(a+b x) \, dx,x,x^n\right )}{n}\\ &=\frac{\left (a+b x^n\right ) \sec ^{-1}\left (a+b x^n\right )}{b n}-\frac{\operatorname{Subst}\left (\int \frac{1}{(a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}} \, dx,x,x^n\right )}{n}\\ &=\frac{\left (a+b x^n\right ) \sec ^{-1}\left (a+b x^n\right )}{b n}-\frac{\operatorname{Subst}\left (\int \frac{1}{\sqrt{1-\frac{1}{x^2}} x} \, dx,x,a+b x^n\right )}{b n}\\ &=\frac{\left (a+b x^n\right ) \sec ^{-1}\left (a+b x^n\right )}{b n}+\frac{\operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} x} \, dx,x,\frac{1}{\left (a+b x^n\right )^2}\right )}{2 b n}\\ &=\frac{\left (a+b x^n\right ) \sec ^{-1}\left (a+b x^n\right )}{b n}-\frac{\operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sqrt{1-\frac{1}{\left (a+b x^n\right )^2}}\right )}{b n}\\ &=\frac{\left (a+b x^n\right ) \sec ^{-1}\left (a+b x^n\right )}{b n}-\frac{\tanh ^{-1}\left (\sqrt{1-\frac{1}{\left (a+b x^n\right )^2}}\right )}{b n}\\ \end{align*}

Mathematica [B]  time = 0.334603, size = 130, normalized size = 2.65 \[ \frac{\left (a+b x^n\right ) \sec ^{-1}\left (a+b x^n\right )}{b n}-\frac{\sqrt{\left (a+b x^n\right )^2-1} \left (\log \left (\frac{a+b x^n}{\sqrt{\left (a+b x^n\right )^2-1}}+1\right )-\log \left (1-\frac{a+b x^n}{\sqrt{\left (a+b x^n\right )^2-1}}\right )\right )}{2 b n \left (a+b x^n\right ) \sqrt{1-\frac{1}{\left (a+b x^n\right )^2}}} \]

Antiderivative was successfully verified.

[In]

Integrate[x^(-1 + n)*ArcSec[a + b*x^n],x]

[Out]

((a + b*x^n)*ArcSec[a + b*x^n])/(b*n) - (Sqrt[-1 + (a + b*x^n)^2]*(-Log[1 - (a + b*x^n)/Sqrt[-1 + (a + b*x^n)^
2]] + Log[1 + (a + b*x^n)/Sqrt[-1 + (a + b*x^n)^2]]))/(2*b*n*(a + b*x^n)*Sqrt[1 - (a + b*x^n)^(-2)])

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Maple [F]  time = 0.35, size = 0, normalized size = 0. \begin{align*} \int{x}^{n-1}{\rm arcsec} \left (a+b{x}^{n}\right )\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(n-1)*arcsec(a+b*x^n),x)

[Out]

int(x^(n-1)*arcsec(a+b*x^n),x)

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Maxima [A]  time = 0.950173, size = 89, normalized size = 1.82 \begin{align*} \frac{2 \,{\left (b x^{n} + a\right )} \operatorname{arcsec}\left (b x^{n} + a\right ) - \log \left (\sqrt{-\frac{1}{{\left (b x^{n} + a\right )}^{2}} + 1} + 1\right ) + \log \left (-\sqrt{-\frac{1}{{\left (b x^{n} + a\right )}^{2}} + 1} + 1\right )}{2 \, b n} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(-1+n)*arcsec(a+b*x^n),x, algorithm="maxima")

[Out]

1/2*(2*(b*x^n + a)*arcsec(b*x^n + a) - log(sqrt(-1/(b*x^n + a)^2 + 1) + 1) + log(-sqrt(-1/(b*x^n + a)^2 + 1) +
1))/(b*n)

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Fricas [A]  time = 2.59592, size = 216, normalized size = 4.41 \begin{align*} \frac{b x^{n} \operatorname{arcsec}\left (b x^{n} + a\right ) + 2 \, a \arctan \left (-b x^{n} - a + \sqrt{b^{2} x^{2 \, n} + 2 \, a b x^{n} + a^{2} - 1}\right ) + \log \left (-b x^{n} - a + \sqrt{b^{2} x^{2 \, n} + 2 \, a b x^{n} + a^{2} - 1}\right )}{b n} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(-1+n)*arcsec(a+b*x^n),x, algorithm="fricas")

[Out]

(b*x^n*arcsec(b*x^n + a) + 2*a*arctan(-b*x^n - a + sqrt(b^2*x^(2*n) + 2*a*b*x^n + a^2 - 1)) + log(-b*x^n - a +
sqrt(b^2*x^(2*n) + 2*a*b*x^n + a^2 - 1)))/(b*n)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(-1+n)*asec(a+b*x**n),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{n - 1} \operatorname{arcsec}\left (b x^{n} + a\right )\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(-1+n)*arcsec(a+b*x^n),x, algorithm="giac")

[Out]

integrate(x^(n - 1)*arcsec(b*x^n + a), x)