Optimal. Leaf size=94 \[ -\frac{2 i \text{PolyLog}\left (2,-i e^{i \sec ^{-1}(a+b x)}\right )}{b}+\frac{2 i \text{PolyLog}\left (2,i e^{i \sec ^{-1}(a+b x)}\right )}{b}+\frac{(a+b x) \sec ^{-1}(a+b x)^2}{b}+\frac{4 i \sec ^{-1}(a+b x) \tan ^{-1}\left (e^{i \sec ^{-1}(a+b x)}\right )}{b} \]
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Rubi [A] time = 0.0627073, antiderivative size = 94, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 8, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.75, Rules used = {5252, 5216, 3757, 4181, 2279, 2391} \[ -\frac{2 i \text{PolyLog}\left (2,-i e^{i \sec ^{-1}(a+b x)}\right )}{b}+\frac{2 i \text{PolyLog}\left (2,i e^{i \sec ^{-1}(a+b x)}\right )}{b}+\frac{(a+b x) \sec ^{-1}(a+b x)^2}{b}+\frac{4 i \sec ^{-1}(a+b x) \tan ^{-1}\left (e^{i \sec ^{-1}(a+b x)}\right )}{b} \]
Antiderivative was successfully verified.
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Rule 5252
Rule 5216
Rule 3757
Rule 4181
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \sec ^{-1}(a+b x)^2 \, dx &=\frac{\operatorname{Subst}\left (\int \sec ^{-1}(x)^2 \, dx,x,a+b x\right )}{b}\\ &=\frac{\operatorname{Subst}\left (\int x^2 \sec (x) \tan (x) \, dx,x,\sec ^{-1}(a+b x)\right )}{b}\\ &=\frac{(a+b x) \sec ^{-1}(a+b x)^2}{b}-\frac{2 \operatorname{Subst}\left (\int x \sec (x) \, dx,x,\sec ^{-1}(a+b x)\right )}{b}\\ &=\frac{(a+b x) \sec ^{-1}(a+b x)^2}{b}+\frac{4 i \sec ^{-1}(a+b x) \tan ^{-1}\left (e^{i \sec ^{-1}(a+b x)}\right )}{b}+\frac{2 \operatorname{Subst}\left (\int \log \left (1-i e^{i x}\right ) \, dx,x,\sec ^{-1}(a+b x)\right )}{b}-\frac{2 \operatorname{Subst}\left (\int \log \left (1+i e^{i x}\right ) \, dx,x,\sec ^{-1}(a+b x)\right )}{b}\\ &=\frac{(a+b x) \sec ^{-1}(a+b x)^2}{b}+\frac{4 i \sec ^{-1}(a+b x) \tan ^{-1}\left (e^{i \sec ^{-1}(a+b x)}\right )}{b}-\frac{(2 i) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{i \sec ^{-1}(a+b x)}\right )}{b}+\frac{(2 i) \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{i \sec ^{-1}(a+b x)}\right )}{b}\\ &=\frac{(a+b x) \sec ^{-1}(a+b x)^2}{b}+\frac{4 i \sec ^{-1}(a+b x) \tan ^{-1}\left (e^{i \sec ^{-1}(a+b x)}\right )}{b}-\frac{2 i \text{Li}_2\left (-i e^{i \sec ^{-1}(a+b x)}\right )}{b}+\frac{2 i \text{Li}_2\left (i e^{i \sec ^{-1}(a+b x)}\right )}{b}\\ \end{align*}
Mathematica [A] time = 0.108282, size = 111, normalized size = 1.18 \[ \frac{-2 i \text{PolyLog}\left (2,-i e^{i \sec ^{-1}(a+b x)}\right )+2 i \text{PolyLog}\left (2,i e^{i \sec ^{-1}(a+b x)}\right )+\sec ^{-1}(a+b x) \left ((a+b x) \sec ^{-1}(a+b x)-2 \log \left (1-i e^{i \sec ^{-1}(a+b x)}\right )+2 \log \left (1+i e^{i \sec ^{-1}(a+b x)}\right )\right )}{b} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.325, size = 179, normalized size = 1.9 \begin{align*} x \left ({\rm arcsec} \left (bx+a\right ) \right ) ^{2}+{\frac{ \left ({\rm arcsec} \left (bx+a\right ) \right ) ^{2}a}{b}}-2\,{\frac{{\rm arcsec} \left (bx+a\right )}{b}\ln \left ( 1-i \left ( \left ( bx+a \right ) ^{-1}+i\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) \right ) }+2\,{\frac{{\rm arcsec} \left (bx+a\right )}{b}\ln \left ( 1+i \left ( \left ( bx+a \right ) ^{-1}+i\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) \right ) }-{\frac{2\,i}{b}{\it dilog} \left ( 1+i \left ( \left ( bx+a \right ) ^{-1}+i\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) \right ) }+{\frac{2\,i}{b}{\it dilog} \left ( 1-i \left ( \left ( bx+a \right ) ^{-1}+i\sqrt{1- \left ( bx+a \right ) ^{-2}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} x \arctan \left (\sqrt{b x + a + 1} \sqrt{b x + a - 1}\right )^{2} - \frac{1}{4} \, x \log \left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )^{2} - \int \frac{2 \, \sqrt{b x + a + 1} \sqrt{b x + a - 1} b x \arctan \left (\sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) +{\left (b^{3} x^{3} + 3 \, a b^{2} x^{2} + a^{3} +{\left (3 \, a^{2} - 1\right )} b x - a\right )} \log \left (b x + a\right )^{2} -{\left (b^{3} x^{3} + 2 \, a b^{2} x^{2} +{\left (a^{2} - 1\right )} b x +{\left (b^{3} x^{3} + 3 \, a b^{2} x^{2} + a^{3} +{\left (3 \, a^{2} - 1\right )} b x - a\right )} \log \left (b x + a\right )\right )} \log \left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}{b^{3} x^{3} + 3 \, a b^{2} x^{2} + a^{3} +{\left (3 \, a^{2} - 1\right )} b x - a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\operatorname{arcsec}\left (b x + a\right )^{2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \operatorname{asec}^{2}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \operatorname{arcsec}\left (b x + a\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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