Optimal. Leaf size=155 \[ -\frac{\left (17 a^2+2\right ) (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^4}-\frac{a^4 \sec ^{-1}(a+b x)}{4 b^4}+\frac{\left (2 a^2+1\right ) a \tanh ^{-1}\left (\sqrt{1-\frac{1}{(a+b x)^2}}\right )}{2 b^4}-\frac{x^2 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^2}+\frac{a (a+b x)^2 \sqrt{1-\frac{1}{(a+b x)^2}}}{3 b^4}+\frac{1}{4} x^4 \sec ^{-1}(a+b x) \]
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Rubi [A] time = 0.139038, antiderivative size = 155, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.7, Rules used = {5258, 4426, 3782, 4048, 3770, 3767, 8} \[ -\frac{\left (17 a^2+2\right ) (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^4}-\frac{a^4 \sec ^{-1}(a+b x)}{4 b^4}+\frac{\left (2 a^2+1\right ) a \tanh ^{-1}\left (\sqrt{1-\frac{1}{(a+b x)^2}}\right )}{2 b^4}-\frac{x^2 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^2}+\frac{a (a+b x)^2 \sqrt{1-\frac{1}{(a+b x)^2}}}{3 b^4}+\frac{1}{4} x^4 \sec ^{-1}(a+b x) \]
Antiderivative was successfully verified.
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Rule 5258
Rule 4426
Rule 3782
Rule 4048
Rule 3770
Rule 3767
Rule 8
Rubi steps
\begin{align*} \int x^3 \sec ^{-1}(a+b x) \, dx &=\frac{\operatorname{Subst}\left (\int x \sec (x) (-a+\sec (x))^3 \tan (x) \, dx,x,\sec ^{-1}(a+b x)\right )}{b^4}\\ &=\frac{1}{4} x^4 \sec ^{-1}(a+b x)-\frac{\operatorname{Subst}\left (\int (-a+\sec (x))^4 \, dx,x,\sec ^{-1}(a+b x)\right )}{4 b^4}\\ &=-\frac{x^2 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^2}+\frac{1}{4} x^4 \sec ^{-1}(a+b x)-\frac{\operatorname{Subst}\left (\int (-a+\sec (x)) \left (-3 a^3+\left (2+9 a^2\right ) \sec (x)-8 a \sec ^2(x)\right ) \, dx,x,\sec ^{-1}(a+b x)\right )}{12 b^4}\\ &=-\frac{x^2 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^2}+\frac{a (a+b x)^2 \sqrt{1-\frac{1}{(a+b x)^2}}}{3 b^4}+\frac{1}{4} x^4 \sec ^{-1}(a+b x)-\frac{\operatorname{Subst}\left (\int \left (6 a^4-12 a \left (1+2 a^2\right ) \sec (x)+2 \left (2+17 a^2\right ) \sec ^2(x)\right ) \, dx,x,\sec ^{-1}(a+b x)\right )}{24 b^4}\\ &=-\frac{x^2 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^2}+\frac{a (a+b x)^2 \sqrt{1-\frac{1}{(a+b x)^2}}}{3 b^4}-\frac{a^4 \sec ^{-1}(a+b x)}{4 b^4}+\frac{1}{4} x^4 \sec ^{-1}(a+b x)+\frac{\left (a \left (1+2 a^2\right )\right ) \operatorname{Subst}\left (\int \sec (x) \, dx,x,\sec ^{-1}(a+b x)\right )}{2 b^4}-\frac{\left (2+17 a^2\right ) \operatorname{Subst}\left (\int \sec ^2(x) \, dx,x,\sec ^{-1}(a+b x)\right )}{12 b^4}\\ &=-\frac{x^2 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^2}+\frac{a (a+b x)^2 \sqrt{1-\frac{1}{(a+b x)^2}}}{3 b^4}-\frac{a^4 \sec ^{-1}(a+b x)}{4 b^4}+\frac{1}{4} x^4 \sec ^{-1}(a+b x)+\frac{a \left (1+2 a^2\right ) \tanh ^{-1}\left (\sqrt{1-\frac{1}{(a+b x)^2}}\right )}{2 b^4}+\frac{\left (2+17 a^2\right ) \operatorname{Subst}\left (\int 1 \, dx,x,-(a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}\right )}{12 b^4}\\ &=-\frac{\left (2+17 a^2\right ) (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^4}-\frac{x^2 (a+b x) \sqrt{1-\frac{1}{(a+b x)^2}}}{12 b^2}+\frac{a (a+b x)^2 \sqrt{1-\frac{1}{(a+b x)^2}}}{3 b^4}-\frac{a^4 \sec ^{-1}(a+b x)}{4 b^4}+\frac{1}{4} x^4 \sec ^{-1}(a+b x)+\frac{a \left (1+2 a^2\right ) \tanh ^{-1}\left (\sqrt{1-\frac{1}{(a+b x)^2}}\right )}{2 b^4}\\ \end{align*}
Mathematica [A] time = 0.279875, size = 150, normalized size = 0.97 \[ \frac{-\sqrt{\frac{a^2+2 a b x+b^2 x^2-1}{(a+b x)^2}} \left (9 a^2 b x+13 a^3-3 a b^2 x^2+2 a+b^3 x^3+2 b x\right )+6 \left (2 a^2+1\right ) a \log \left ((a+b x) \left (\sqrt{\frac{a^2+2 a b x+b^2 x^2-1}{(a+b x)^2}}+1\right )\right )+3 a^4 \sin ^{-1}\left (\frac{1}{a+b x}\right )+3 b^4 x^4 \sec ^{-1}(a+b x)}{12 b^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.217, size = 359, normalized size = 2.3 \begin{align*}{\frac{{x}^{4}{\rm arcsec} \left (bx+a\right )}{4}}-{\frac{ \left ( -1+ \left ( bx+a \right ) ^{2} \right ){x}^{2}}{12\,{b}^{2} \left ( bx+a \right ) }{\frac{1}{\sqrt{{\frac{-1+ \left ( bx+a \right ) ^{2}}{ \left ( bx+a \right ) ^{2}}}}}}}+{\frac{{a}^{4}}{4\,{b}^{4} \left ( bx+a \right ) }\sqrt{-1+ \left ( bx+a \right ) ^{2}}\arctan \left ({\frac{1}{\sqrt{-1+ \left ( bx+a \right ) ^{2}}}} \right ){\frac{1}{\sqrt{{\frac{-1+ \left ( bx+a \right ) ^{2}}{ \left ( bx+a \right ) ^{2}}}}}}}+{\frac{ \left ( -1+ \left ( bx+a \right ) ^{2} \right ) xa}{3\,{b}^{3} \left ( bx+a \right ) }{\frac{1}{\sqrt{{\frac{-1+ \left ( bx+a \right ) ^{2}}{ \left ( bx+a \right ) ^{2}}}}}}}+{\frac{{a}^{3}}{{b}^{4} \left ( bx+a \right ) }\sqrt{-1+ \left ( bx+a \right ) ^{2}}\ln \left ( bx+a+\sqrt{-1+ \left ( bx+a \right ) ^{2}} \right ){\frac{1}{\sqrt{{\frac{-1+ \left ( bx+a \right ) ^{2}}{ \left ( bx+a \right ) ^{2}}}}}}}-{\frac{ \left ( -13+13\, \left ( bx+a \right ) ^{2} \right ){a}^{2}}{12\,{b}^{4} \left ( bx+a \right ) }{\frac{1}{\sqrt{{\frac{-1+ \left ( bx+a \right ) ^{2}}{ \left ( bx+a \right ) ^{2}}}}}}}+{\frac{a}{2\,{b}^{4} \left ( bx+a \right ) }\sqrt{-1+ \left ( bx+a \right ) ^{2}}\ln \left ( bx+a+\sqrt{-1+ \left ( bx+a \right ) ^{2}} \right ){\frac{1}{\sqrt{{\frac{-1+ \left ( bx+a \right ) ^{2}}{ \left ( bx+a \right ) ^{2}}}}}}}-{\frac{-1+ \left ( bx+a \right ) ^{2}}{6\,{b}^{4} \left ( bx+a \right ) }{\frac{1}{\sqrt{{\frac{-1+ \left ( bx+a \right ) ^{2}}{ \left ( bx+a \right ) ^{2}}}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{4} \, x^{4} \arctan \left (\sqrt{b x + a + 1} \sqrt{b x + a - 1}\right ) - \int \frac{{\left (b^{2} x^{5} + a b x^{4}\right )} e^{\left (\frac{1}{2} \, \log \left (b x + a + 1\right ) + \frac{1}{2} \, \log \left (b x + a - 1\right )\right )}}{4 \,{\left (b^{2} x^{2} + 2 \, a b x + a^{2} +{\left (b^{2} x^{2} + 2 \, a b x + a^{2} - 1\right )} e^{\left (\log \left (b x + a + 1\right ) + \log \left (b x + a - 1\right )\right )} - 1\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.60988, size = 316, normalized size = 2.04 \begin{align*} \frac{3 \, b^{4} x^{4} \operatorname{arcsec}\left (b x + a\right ) - 6 \, a^{4} \arctan \left (-b x - a + \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} - 1}\right ) - 6 \,{\left (2 \, a^{3} + a\right )} \log \left (-b x - a + \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} - 1}\right ) - \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} - 1}{\left (b^{2} x^{2} - 4 \, a b x + 13 \, a^{2} + 2\right )}}{12 \, b^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{3} \operatorname{asec}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{3} \operatorname{arcsec}\left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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