Optimal. Leaf size=208 \[ -\frac{\left (15 a^4 c^2-20 a^2 c d+8 d^2\right ) \tanh ^{-1}\left (\frac{a \sqrt{c+d x^2}}{\sqrt{a^2 c-d}}\right )}{15 c^3 \left (a^2 c-d\right )^{5/2}}+\frac{a \left (7 a^2 c-4 d\right )}{15 c^2 \left (a^2 c-d\right )^2 \sqrt{c+d x^2}}+\frac{a}{15 c \left (a^2 c-d\right ) \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}} \]
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Rubi [A] time = 0.934717, antiderivative size = 208, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 9, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.562, Rules used = {192, 191, 4913, 6688, 12, 6715, 897, 1261, 208} \[ -\frac{\left (15 a^4 c^2-20 a^2 c d+8 d^2\right ) \tanh ^{-1}\left (\frac{a \sqrt{c+d x^2}}{\sqrt{a^2 c-d}}\right )}{15 c^3 \left (a^2 c-d\right )^{5/2}}+\frac{a \left (7 a^2 c-4 d\right )}{15 c^2 \left (a^2 c-d\right )^2 \sqrt{c+d x^2}}+\frac{a}{15 c \left (a^2 c-d\right ) \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}} \]
Antiderivative was successfully verified.
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Rule 192
Rule 191
Rule 4913
Rule 6688
Rule 12
Rule 6715
Rule 897
Rule 1261
Rule 208
Rubi steps
\begin{align*} \int \frac{\cot ^{-1}(a x)}{\left (c+d x^2\right )^{7/2}} \, dx &=\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}+a \int \frac{\frac{x}{5 c \left (c+d x^2\right )^{5/2}}+\frac{4 x}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{8 x}{15 c^3 \sqrt{c+d x^2}}}{1+a^2 x^2} \, dx\\ &=\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}+a \int \frac{x \left (15 c^2+20 c d x^2+8 d^2 x^4\right )}{15 c^3 \left (1+a^2 x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx\\ &=\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}+\frac{a \int \frac{x \left (15 c^2+20 c d x^2+8 d^2 x^4\right )}{\left (1+a^2 x^2\right ) \left (c+d x^2\right )^{5/2}} \, dx}{15 c^3}\\ &=\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}+\frac{a \operatorname{Subst}\left (\int \frac{15 c^2+20 c d x+8 d^2 x^2}{\left (1+a^2 x\right ) (c+d x)^{5/2}} \, dx,x,x^2\right )}{30 c^3}\\ &=\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}+\frac{a \operatorname{Subst}\left (\int \frac{3 c^2+4 c x^2+8 x^4}{x^4 \left (\frac{-a^2 c+d}{d}+\frac{a^2 x^2}{d}\right )} \, dx,x,\sqrt{c+d x^2}\right )}{15 c^3 d}\\ &=\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}+\frac{a \operatorname{Subst}\left (\int \left (\frac{3 c^2 d}{\left (-a^2 c+d\right ) x^4}-\frac{c \left (7 a^2 c-4 d\right ) d}{\left (-a^2 c+d\right )^2 x^2}+\frac{d \left (15 a^4 c^2-20 a^2 c d+8 d^2\right )}{\left (-a^2 c+d\right )^2 \left (-a^2 c+d+a^2 x^2\right )}\right ) \, dx,x,\sqrt{c+d x^2}\right )}{15 c^3 d}\\ &=\frac{a}{15 c \left (a^2 c-d\right ) \left (c+d x^2\right )^{3/2}}+\frac{a \left (7 a^2 c-4 d\right )}{15 c^2 \left (a^2 c-d\right )^2 \sqrt{c+d x^2}}+\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}+\frac{\left (a \left (15 a^4 c^2-20 a^2 c d+8 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-a^2 c+d+a^2 x^2} \, dx,x,\sqrt{c+d x^2}\right )}{15 c^3 \left (a^2 c-d\right )^2}\\ &=\frac{a}{15 c \left (a^2 c-d\right ) \left (c+d x^2\right )^{3/2}}+\frac{a \left (7 a^2 c-4 d\right )}{15 c^2 \left (a^2 c-d\right )^2 \sqrt{c+d x^2}}+\frac{x \cot ^{-1}(a x)}{5 c \left (c+d x^2\right )^{5/2}}+\frac{4 x \cot ^{-1}(a x)}{15 c^2 \left (c+d x^2\right )^{3/2}}+\frac{8 x \cot ^{-1}(a x)}{15 c^3 \sqrt{c+d x^2}}-\frac{\left (15 a^4 c^2-20 a^2 c d+8 d^2\right ) \tanh ^{-1}\left (\frac{a \sqrt{c+d x^2}}{\sqrt{a^2 c-d}}\right )}{15 c^3 \left (a^2 c-d\right )^{5/2}}\\ \end{align*}
Mathematica [C] time = 0.938296, size = 345, normalized size = 1.66 \[ -\frac{\frac{\left (15 a^4 c^2-20 a^2 c d+8 d^2\right ) \log \left (\frac{60 a c^3 \left (a^2 c-d\right )^{3/2} \left (\sqrt{a^2 c-d} \sqrt{c+d x^2}+a c-i d x\right )}{(a x+i) \left (15 a^4 c^2-20 a^2 c d+8 d^2\right )}\right )}{\left (a^2 c-d\right )^{5/2}}+\frac{\left (15 a^4 c^2-20 a^2 c d+8 d^2\right ) \log \left (\frac{60 a c^3 \left (a^2 c-d\right )^{3/2} \left (\sqrt{a^2 c-d} \sqrt{c+d x^2}+a c+i d x\right )}{(a x-i) \left (15 a^4 c^2-20 a^2 c d+8 d^2\right )}\right )}{\left (a^2 c-d\right )^{5/2}}-\frac{2 a c \left (a^2 c \left (8 c+7 d x^2\right )-d \left (5 c+4 d x^2\right )\right )}{\left (d-a^2 c\right )^2 \left (c+d x^2\right )^{3/2}}-\frac{2 x \cot ^{-1}(a x) \left (15 c^2+20 c d x^2+8 d^2 x^4\right )}{\left (c+d x^2\right )^{5/2}}}{30 c^3} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.891, size = 0, normalized size = 0. \begin{align*} \int{{\rm arccot} \left (ax\right ) \left ( d{x}^{2}+c \right ) ^{-{\frac{7}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 3.58127, size = 2569, normalized size = 12.35 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.21745, size = 281, normalized size = 1.35 \begin{align*} \frac{1}{15} \, a{\left (\frac{{\left (15 \, a^{4} c^{2} - 20 \, a^{2} c d + 8 \, d^{2}\right )} \arctan \left (\frac{\sqrt{d x^{2} + c} a}{\sqrt{-a^{2} c + d}}\right )}{{\left (a^{4} c^{5} - 2 \, a^{2} c^{4} d + c^{3} d^{2}\right )} \sqrt{-a^{2} c + d} a} + \frac{7 \,{\left (d x^{2} + c\right )} a^{2} c + a^{2} c^{2} - 4 \,{\left (d x^{2} + c\right )} d - c d}{{\left (a^{4} c^{4} - 2 \, a^{2} c^{3} d + c^{2} d^{2}\right )}{\left (d x^{2} + c\right )}^{\frac{3}{2}}}\right )} + \frac{{\left (4 \, x^{2}{\left (\frac{2 \, d^{2} x^{2}}{c^{3}} + \frac{5 \, d}{c^{2}}\right )} + \frac{15}{c}\right )} x \arctan \left (\frac{1}{a x}\right )}{15 \,{\left (d x^{2} + c\right )}^{\frac{5}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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