Optimal. Leaf size=431 \[ \frac{3 b^2 \text{PolyLog}\left (3,1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )}{2 c}-\frac{3 b^2 \text{PolyLog}\left (3,-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )}{2 c}+\frac{3 i b \text{PolyLog}\left (2,1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )^2}{2 c}-\frac{3 i b \text{PolyLog}\left (2,-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )^2}{2 c}-\frac{3 i b^3 \text{PolyLog}\left (4,1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right )}{4 c}+\frac{3 i b^3 \text{PolyLog}\left (4,-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right )}{4 c}-\frac{2 \tanh ^{-1}\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )^3}{c} \]
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Rubi [A] time = 0.484625, antiderivative size = 431, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.175, Rules used = {6681, 4850, 4988, 4884, 4994, 4998, 6610} \[ \frac{3 b^2 \text{PolyLog}\left (3,1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )}{2 c}-\frac{3 b^2 \text{PolyLog}\left (3,-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )}{2 c}+\frac{3 i b \text{PolyLog}\left (2,1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )^2}{2 c}-\frac{3 i b \text{PolyLog}\left (2,-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )^2}{2 c}-\frac{3 i b^3 \text{PolyLog}\left (4,1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right )}{4 c}+\frac{3 i b^3 \text{PolyLog}\left (4,-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right )}{4 c}-\frac{2 \tanh ^{-1}\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{c x+1}}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )^3}{c} \]
Antiderivative was successfully verified.
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Rule 6681
Rule 4850
Rule 4988
Rule 4884
Rule 4994
Rule 4998
Rule 6610
Rubi steps
\begin{align*} \int \frac{\left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^3}{1-c^2 x^2} \, dx &=-\frac{\operatorname{Subst}\left (\int \frac{\left (a+b \tan ^{-1}(x)\right )^3}{x} \, dx,x,\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )}{c}\\ &=-\frac{2 \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^3 \tanh ^{-1}\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{c}+\frac{(6 b) \operatorname{Subst}\left (\int \frac{\left (a+b \tan ^{-1}(x)\right )^2 \tanh ^{-1}\left (1-\frac{2}{1+i x}\right )}{1+x^2} \, dx,x,\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )}{c}\\ &=-\frac{2 \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^3 \tanh ^{-1}\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{c}+\frac{(3 b) \operatorname{Subst}\left (\int \frac{\left (a+b \tan ^{-1}(x)\right )^2 \log \left (2-\frac{2}{1+i x}\right )}{1+x^2} \, dx,x,\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )}{c}-\frac{(3 b) \operatorname{Subst}\left (\int \frac{\left (a+b \tan ^{-1}(x)\right )^2 \log \left (\frac{2}{1+i x}\right )}{1+x^2} \, dx,x,\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )}{c}\\ &=-\frac{2 \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^3 \tanh ^{-1}\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{c}+\frac{3 i b \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^2 \text{Li}_2\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}-\frac{3 i b \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^2 \text{Li}_2\left (-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}-\frac{\left (3 i b^2\right ) \operatorname{Subst}\left (\int \frac{\left (a+b \tan ^{-1}(x)\right ) \text{Li}_2\left (1-\frac{2}{1+i x}\right )}{1+x^2} \, dx,x,\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )}{c}+\frac{\left (3 i b^2\right ) \operatorname{Subst}\left (\int \frac{\left (a+b \tan ^{-1}(x)\right ) \text{Li}_2\left (-1+\frac{2}{1+i x}\right )}{1+x^2} \, dx,x,\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )}{c}\\ &=-\frac{2 \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^3 \tanh ^{-1}\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{c}+\frac{3 i b \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^2 \text{Li}_2\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}-\frac{3 i b \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^2 \text{Li}_2\left (-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}+\frac{3 b^2 \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right ) \text{Li}_3\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}-\frac{3 b^2 \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right ) \text{Li}_3\left (-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}-\frac{\left (3 b^3\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3\left (1-\frac{2}{1+i x}\right )}{1+x^2} \, dx,x,\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )}{2 c}+\frac{\left (3 b^3\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3\left (-1+\frac{2}{1+i x}\right )}{1+x^2} \, dx,x,\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )}{2 c}\\ &=-\frac{2 \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^3 \tanh ^{-1}\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{c}+\frac{3 i b \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^2 \text{Li}_2\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}-\frac{3 i b \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right )^2 \text{Li}_2\left (-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}+\frac{3 b^2 \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right ) \text{Li}_3\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}-\frac{3 b^2 \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{1+c x}}\right )\right ) \text{Li}_3\left (-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{2 c}-\frac{3 i b^3 \text{Li}_4\left (1-\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{4 c}+\frac{3 i b^3 \text{Li}_4\left (-1+\frac{2}{1+\frac{i \sqrt{1-c x}}{\sqrt{1+c x}}}\right )}{4 c}\\ \end{align*}
Mathematica [A] time = 0.176544, size = 530, normalized size = 1.23 \[ -\frac{6 b^2 \text{PolyLog}\left (3,-\frac{\sqrt{1-c x}+i \sqrt{c x+1}}{\sqrt{1-c x}-i \sqrt{c x+1}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )-6 b^2 \text{PolyLog}\left (3,\frac{\sqrt{1-c x}+i \sqrt{c x+1}}{\sqrt{1-c x}-i \sqrt{c x+1}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )+6 i b \text{PolyLog}\left (2,-\frac{\sqrt{1-c x}+i \sqrt{c x+1}}{\sqrt{1-c x}-i \sqrt{c x+1}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )^2-6 i b \text{PolyLog}\left (2,\frac{\sqrt{1-c x}+i \sqrt{c x+1}}{\sqrt{1-c x}-i \sqrt{c x+1}}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )^2-3 i b^3 \text{PolyLog}\left (4,-\frac{\sqrt{1-c x}+i \sqrt{c x+1}}{\sqrt{1-c x}-i \sqrt{c x+1}}\right )+3 i b^3 \text{PolyLog}\left (4,\frac{\sqrt{1-c x}+i \sqrt{c x+1}}{\sqrt{1-c x}-i \sqrt{c x+1}}\right )+8 \tanh ^{-1}\left (1-\frac{2 i}{-\frac{\sqrt{1-c x}}{\sqrt{c x+1}}+i}\right ) \left (a+b \tan ^{-1}\left (\frac{\sqrt{1-c x}}{\sqrt{c x+1}}\right )\right )^3}{4 c} \]
Antiderivative was successfully verified.
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Maple [B] time = 2.559, size = 1745, normalized size = 4.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{2} \, a^{3}{\left (\frac{\log \left (c x + 1\right )}{c} - \frac{\log \left (c x - 1\right )}{c}\right )} + \frac{\frac{15}{2} \,{\left (b^{3} \log \left (c x + 1\right ) - b^{3} \log \left (-c x + 1\right )\right )} \arctan \left (\sqrt{-c x + 1}, \sqrt{c x + 1}\right )^{3} - \frac{45}{8} \,{\left (b^{3} \log \left (2\right )^{2} \log \left (c x + 1\right ) - b^{3} \log \left (2\right )^{2} \log \left (-c x + 1\right )\right )} \arctan \left (\sqrt{-c x + 1}, \sqrt{c x + 1}\right ) - \frac{1}{2} \, c \int \frac{784 \, b^{3} \arctan \left (\sqrt{-c x + 1}, \sqrt{c x + 1}\right )^{3} + 3072 \, a b^{2} \arctan \left (\sqrt{-c x + 1}, \sqrt{c x + 1}\right )^{2} - 45 \,{\left (b^{3} \log \left (2\right )^{2} \log \left (c x + 1\right ) - b^{3} \log \left (2\right )^{2} \log \left (-c x + 1\right ) - 4 \,{\left (b^{3} \log \left (c x + 1\right ) - b^{3} \log \left (-c x + 1\right )\right )} \arctan \left (\sqrt{-c x + 1}, \sqrt{c x + 1}\right )^{2}\right )} \sqrt{c x + 1} \sqrt{-c x + 1} + 12 \,{\left (15 \, b^{3} \log \left (2\right )^{2} + 256 \, a^{2} b\right )} \arctan \left (\sqrt{-c x + 1}, \sqrt{c x + 1}\right )}{8 \,{\left (c^{2} x^{2} - 1\right )}}\,{d x}}{64 \, c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{b^{3} \arctan \left (\frac{\sqrt{-c x + 1}}{\sqrt{c x + 1}}\right )^{3} + 3 \, a b^{2} \arctan \left (\frac{\sqrt{-c x + 1}}{\sqrt{c x + 1}}\right )^{2} + 3 \, a^{2} b \arctan \left (\frac{\sqrt{-c x + 1}}{\sqrt{c x + 1}}\right ) + a^{3}}{c^{2} x^{2} - 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{{\left (b \arctan \left (\frac{\sqrt{-c x + 1}}{\sqrt{c x + 1}}\right ) + a\right )}^{3}}{c^{2} x^{2} - 1}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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