Optimal. Leaf size=144 \[ \frac{5 d^3 \sqrt{-e} \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )}{96 e^{7/2}}+\frac{5 d^2 x \sqrt{d+e x^2}}{96 (-e)^{5/2}}+\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{-e}}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 (-e)^{3/2}}+\frac{1}{6} x^6 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right ) \]
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Rubi [A] time = 0.0801685, antiderivative size = 144, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.16, Rules used = {5151, 321, 217, 206} \[ \frac{5 d^3 \sqrt{-e} \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )}{96 e^{7/2}}+\frac{5 d^2 x \sqrt{d+e x^2}}{96 (-e)^{5/2}}+\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{-e}}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 (-e)^{3/2}}+\frac{1}{6} x^6 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right ) \]
Antiderivative was successfully verified.
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Rule 5151
Rule 321
Rule 217
Rule 206
Rubi steps
\begin{align*} \int x^5 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right ) \, dx &=\frac{1}{6} x^6 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )-\frac{1}{6} \sqrt{-e} \int \frac{x^6}{\sqrt{d+e x^2}} \, dx\\ &=\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{-e}}+\frac{1}{6} x^6 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )-\frac{(5 d) \int \frac{x^4}{\sqrt{d+e x^2}} \, dx}{36 \sqrt{-e}}\\ &=\frac{5 d x^3 \sqrt{d+e x^2}}{144 (-e)^{3/2}}+\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{-e}}+\frac{1}{6} x^6 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )-\frac{\left (5 d^2\right ) \int \frac{x^2}{\sqrt{d+e x^2}} \, dx}{48 (-e)^{3/2}}\\ &=\frac{5 d^2 x \sqrt{d+e x^2}}{96 (-e)^{5/2}}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 (-e)^{3/2}}+\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{-e}}+\frac{1}{6} x^6 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )-\frac{\left (5 d^3\right ) \int \frac{1}{\sqrt{d+e x^2}} \, dx}{96 (-e)^{5/2}}\\ &=\frac{5 d^2 x \sqrt{d+e x^2}}{96 (-e)^{5/2}}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 (-e)^{3/2}}+\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{-e}}+\frac{1}{6} x^6 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )-\frac{\left (5 d^3\right ) \operatorname{Subst}\left (\int \frac{1}{1-e x^2} \, dx,x,\frac{x}{\sqrt{d+e x^2}}\right )}{96 (-e)^{5/2}}\\ &=\frac{5 d^2 x \sqrt{d+e x^2}}{96 (-e)^{5/2}}+\frac{5 d x^3 \sqrt{d+e x^2}}{144 (-e)^{3/2}}+\frac{x^5 \sqrt{d+e x^2}}{36 \sqrt{-e}}+\frac{1}{6} x^6 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )-\frac{5 d^3 \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{d+e x^2}}\right )}{96 (-e)^{5/2} \sqrt{e}}\\ \end{align*}
Mathematica [A] time = 0.0754222, size = 86, normalized size = 0.6 \[ \frac{\sqrt{-e} x \sqrt{d+e x^2} \left (-15 d^2+10 d e x^2-8 e^2 x^4\right )+3 \left (5 d^3+16 e^3 x^6\right ) \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{288 e^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.043, size = 211, normalized size = 1.5 \begin{align*}{\frac{{x}^{6}}{6}\arctan \left ({x\sqrt{-e}{\frac{1}{\sqrt{e{x}^{2}+d}}}} \right ) }+{\frac{{x}^{7}}{48\,d}\sqrt{-e}\sqrt{e{x}^{2}+d}}-{\frac{7\,{x}^{5}}{288\,e}\sqrt{-e}\sqrt{e{x}^{2}+d}}+{\frac{35\,d{x}^{3}}{1152\,{e}^{2}}\sqrt{-e}\sqrt{e{x}^{2}+d}}-{\frac{5\,{d}^{2}x}{128\,{e}^{3}}\sqrt{-e}\sqrt{e{x}^{2}+d}}+{\frac{5\,{d}^{3}}{96}\sqrt{-e}\ln \left ( x\sqrt{e}+\sqrt{e{x}^{2}+d} \right ){e}^{-{\frac{7}{2}}}}-{\frac{{x}^{5}}{48\,de}\sqrt{-e} \left ( e{x}^{2}+d \right ) ^{{\frac{3}{2}}}}+{\frac{5\,{x}^{3}}{288\,{e}^{2}}\sqrt{-e} \left ( e{x}^{2}+d \right ) ^{{\frac{3}{2}}}}-{\frac{5\,dx}{384\,{e}^{3}}\sqrt{-e} \left ( e{x}^{2}+d \right ) ^{{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{6} \, x^{6} \arctan \left (\sqrt{-e} x, \sqrt{e x^{2} + d}\right ) - d \sqrt{-e} \int -\frac{\sqrt{e x^{2} + d} x^{6}}{6 \,{\left (e^{2} x^{4} + d e x^{2} -{\left (e x^{2} + d\right )}^{2}\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.2305, size = 182, normalized size = 1.26 \begin{align*} -\frac{{\left (8 \, e^{2} x^{5} - 10 \, d e x^{3} + 15 \, d^{2} x\right )} \sqrt{e x^{2} + d} \sqrt{-e} - 3 \,{\left (16 \, e^{3} x^{6} + 5 \, d^{3}\right )} \arctan \left (\frac{\sqrt{-e} x}{\sqrt{e x^{2} + d}}\right )}{288 \, e^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 8.85741, size = 129, normalized size = 0.9 \begin{align*} \begin{cases} \frac{5 i d^{3} \operatorname{atanh}{\left (\frac{\sqrt{e} x}{\sqrt{d + e x^{2}}} \right )}}{96 e^{3}} - \frac{5 i d^{2} x \sqrt{d + e x^{2}}}{96 e^{\frac{5}{2}}} + \frac{5 i d x^{3} \sqrt{d + e x^{2}}}{144 e^{\frac{3}{2}}} + \frac{i x^{6} \operatorname{atanh}{\left (\frac{\sqrt{e} x}{\sqrt{d + e x^{2}}} \right )}}{6} - \frac{i x^{5} \sqrt{d + e x^{2}}}{36 \sqrt{e}} & \text{for}\: e \neq 0 \\0 & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.21964, size = 119, normalized size = 0.83 \begin{align*} \frac{1}{6} \, x^{6} \arctan \left (\frac{x \sqrt{-e}}{\sqrt{x^{2} e + d}}\right ) - \frac{5}{96} \, d^{3} \arcsin \left (\frac{x e}{\sqrt{-d e}}\right ) e^{\left (-3\right )} - \frac{1}{288} \,{\left (2 \,{\left (4 \, x^{2} e^{\left (-1\right )} - 5 \, d e^{\left (-2\right )}\right )} x^{2} + 15 \, d^{2} e^{\left (-3\right )}\right )} \sqrt{-x^{2} e^{2} - d e} x \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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