Optimal. Leaf size=216 \[ -\frac{30 \sqrt{-e} e^{11/4} \left (\sqrt{d}+\sqrt{e} x\right ) \sqrt{\frac{d+e x^2}{\left (\sqrt{d}+\sqrt{e} x\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{e} \sqrt{x}}{\sqrt [4]{d}}\right ),\frac{1}{2}\right )}{1001 d^{13/4} \sqrt{d+e x^2}}-\frac{60 (-e)^{5/2} \sqrt{d+e x^2}}{1001 d^3 x^{3/2}}-\frac{36 (-e)^{3/2} \sqrt{d+e x^2}}{1001 d^2 x^{7/2}}-\frac{4 \sqrt{-e} \sqrt{d+e x^2}}{143 d x^{11/2}}-\frac{2 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{13 x^{13/2}} \]
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Rubi [A] time = 0.108009, antiderivative size = 216, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.148, Rules used = {5151, 325, 329, 220} \[ -\frac{30 \sqrt{-e} e^{11/4} \left (\sqrt{d}+\sqrt{e} x\right ) \sqrt{\frac{d+e x^2}{\left (\sqrt{d}+\sqrt{e} x\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{e} \sqrt{x}}{\sqrt [4]{d}}\right ),\frac{1}{2}\right )}{1001 d^{13/4} \sqrt{d+e x^2}}-\frac{60 (-e)^{5/2} \sqrt{d+e x^2}}{1001 d^3 x^{3/2}}-\frac{36 (-e)^{3/2} \sqrt{d+e x^2}}{1001 d^2 x^{7/2}}-\frac{4 \sqrt{-e} \sqrt{d+e x^2}}{143 d x^{11/2}}-\frac{2 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{13 x^{13/2}} \]
Antiderivative was successfully verified.
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Rule 5151
Rule 325
Rule 329
Rule 220
Rubi steps
\begin{align*} \int \frac{\tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{x^{15/2}} \, dx &=-\frac{2 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{13 x^{13/2}}+\frac{1}{13} \left (2 \sqrt{-e}\right ) \int \frac{1}{x^{13/2} \sqrt{d+e x^2}} \, dx\\ &=-\frac{4 \sqrt{-e} \sqrt{d+e x^2}}{143 d x^{11/2}}-\frac{2 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{13 x^{13/2}}+\frac{\left (18 (-e)^{3/2}\right ) \int \frac{1}{x^{9/2} \sqrt{d+e x^2}} \, dx}{143 d}\\ &=-\frac{4 \sqrt{-e} \sqrt{d+e x^2}}{143 d x^{11/2}}-\frac{36 (-e)^{3/2} \sqrt{d+e x^2}}{1001 d^2 x^{7/2}}-\frac{2 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{13 x^{13/2}}+\frac{\left (90 (-e)^{5/2}\right ) \int \frac{1}{x^{5/2} \sqrt{d+e x^2}} \, dx}{1001 d^2}\\ &=-\frac{4 \sqrt{-e} \sqrt{d+e x^2}}{143 d x^{11/2}}-\frac{36 (-e)^{3/2} \sqrt{d+e x^2}}{1001 d^2 x^{7/2}}-\frac{60 (-e)^{5/2} \sqrt{d+e x^2}}{1001 d^3 x^{3/2}}-\frac{2 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{13 x^{13/2}}+\frac{\left (30 (-e)^{7/2}\right ) \int \frac{1}{\sqrt{x} \sqrt{d+e x^2}} \, dx}{1001 d^3}\\ &=-\frac{4 \sqrt{-e} \sqrt{d+e x^2}}{143 d x^{11/2}}-\frac{36 (-e)^{3/2} \sqrt{d+e x^2}}{1001 d^2 x^{7/2}}-\frac{60 (-e)^{5/2} \sqrt{d+e x^2}}{1001 d^3 x^{3/2}}-\frac{2 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{13 x^{13/2}}+\frac{\left (60 (-e)^{7/2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{d+e x^4}} \, dx,x,\sqrt{x}\right )}{1001 d^3}\\ &=-\frac{4 \sqrt{-e} \sqrt{d+e x^2}}{143 d x^{11/2}}-\frac{36 (-e)^{3/2} \sqrt{d+e x^2}}{1001 d^2 x^{7/2}}-\frac{60 (-e)^{5/2} \sqrt{d+e x^2}}{1001 d^3 x^{3/2}}-\frac{2 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )}{13 x^{13/2}}+\frac{30 (-e)^{7/2} \left (\sqrt{d}+\sqrt{e} x\right ) \sqrt{\frac{d+e x^2}{\left (\sqrt{d}+\sqrt{e} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{e} \sqrt{x}}{\sqrt [4]{d}}\right )|\frac{1}{2}\right )}{1001 d^{13/4} \sqrt [4]{e} \sqrt{d+e x^2}}\\ \end{align*}
Mathematica [C] time = 0.577851, size = 171, normalized size = 0.79 \[ \frac{2 \left (\frac{30 i (-e)^{7/2} x^{15/2} \sqrt{\frac{d}{e x^2}+1} \text{EllipticF}\left (i \sinh ^{-1}\left (\frac{\sqrt{\frac{i \sqrt{d}}{\sqrt{e}}}}{\sqrt{x}}\right ),-1\right )}{d^3 \sqrt{\frac{i \sqrt{d}}{\sqrt{e}}} \sqrt{d+e x^2}}-\frac{2 \sqrt{-e} \sqrt{d+e x^2} \left (7 d^2 x-9 d e x^3+15 e^2 x^5\right )}{d^3}-77 \tan ^{-1}\left (\frac{\sqrt{-e} x}{\sqrt{d+e x^2}}\right )\right )}{1001 x^{13/2}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.285, size = 0, normalized size = 0. \begin{align*} \int{\arctan \left ({x\sqrt{-e}{\frac{1}{\sqrt{e{x}^{2}+d}}}} \right ){x}^{-{\frac{15}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{2 \,{\left (-d \sqrt{-e} x^{\frac{13}{2}} \int -\frac{\sqrt{e x^{2} + d} x}{{\left (e x^{2} + d\right )}^{2} x^{\frac{15}{2}} -{\left (e^{2} x^{4} + d e x^{2}\right )} x^{\frac{15}{2}}}\,{d x} - \arctan \left (\sqrt{-e} x, \sqrt{e x^{2} + d}\right )\right )}}{13 \, x^{\frac{13}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\arctan \left (\frac{\sqrt{-e} x}{\sqrt{e x^{2} + d}}\right )}{x^{\frac{15}{2}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\arctan \left (\frac{\sqrt{-e} x}{\sqrt{e x^{2} + d}}\right )}{x^{\frac{15}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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