Optimal. Leaf size=180 \[ -\frac{\log \left (e^{2 c (a+b x)}-\sqrt{2} e^{a c+b c x}+1\right )}{2 \sqrt{2} b c}+\frac{\log \left (e^{2 c (a+b x)}+\sqrt{2} e^{a c+b c x}+1\right )}{2 \sqrt{2} b c}+\frac{\tan ^{-1}\left (1-\sqrt{2} e^{a c+b c x}\right )}{\sqrt{2} b c}-\frac{\tan ^{-1}\left (\sqrt{2} e^{a c+b c x}+1\right )}{\sqrt{2} b c}+\frac{e^{a c+b c x} \tan ^{-1}(\tanh (c (a+b x)))}{b c} \]
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Rubi [A] time = 0.181831, antiderivative size = 180, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 10, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {2194, 5207, 12, 2249, 297, 1162, 617, 204, 1165, 628} \[ -\frac{\log \left (e^{2 c (a+b x)}-\sqrt{2} e^{a c+b c x}+1\right )}{2 \sqrt{2} b c}+\frac{\log \left (e^{2 c (a+b x)}+\sqrt{2} e^{a c+b c x}+1\right )}{2 \sqrt{2} b c}+\frac{\tan ^{-1}\left (1-\sqrt{2} e^{a c+b c x}\right )}{\sqrt{2} b c}-\frac{\tan ^{-1}\left (\sqrt{2} e^{a c+b c x}+1\right )}{\sqrt{2} b c}+\frac{e^{a c+b c x} \tan ^{-1}(\tanh (c (a+b x)))}{b c} \]
Antiderivative was successfully verified.
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Rule 2194
Rule 5207
Rule 12
Rule 2249
Rule 297
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rubi steps
\begin{align*} \int e^{c (a+b x)} \tan ^{-1}(\tanh (a c+b c x)) \, dx &=\frac{\operatorname{Subst}\left (\int e^x \tan ^{-1}(\tanh (x)) \, dx,x,a c+b c x\right )}{b c}\\ &=\frac{e^{a c+b c x} \tan ^{-1}(\tanh (c (a+b x)))}{b c}-\frac{\operatorname{Subst}\left (\int \frac{2 e^{3 x}}{1+e^{4 x}} \, dx,x,a c+b c x\right )}{b c}\\ &=\frac{e^{a c+b c x} \tan ^{-1}(\tanh (c (a+b x)))}{b c}-\frac{2 \operatorname{Subst}\left (\int \frac{e^{3 x}}{1+e^{4 x}} \, dx,x,a c+b c x\right )}{b c}\\ &=\frac{e^{a c+b c x} \tan ^{-1}(\tanh (c (a+b x)))}{b c}-\frac{2 \operatorname{Subst}\left (\int \frac{x^2}{1+x^4} \, dx,x,e^{a c+b c x}\right )}{b c}\\ &=\frac{e^{a c+b c x} \tan ^{-1}(\tanh (c (a+b x)))}{b c}+\frac{\operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,e^{a c+b c x}\right )}{b c}-\frac{\operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,e^{a c+b c x}\right )}{b c}\\ &=\frac{e^{a c+b c x} \tan ^{-1}(\tanh (c (a+b x)))}{b c}-\frac{\operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,e^{a c+b c x}\right )}{2 b c}-\frac{\operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,e^{a c+b c x}\right )}{2 b c}-\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,e^{a c+b c x}\right )}{2 \sqrt{2} b c}-\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,e^{a c+b c x}\right )}{2 \sqrt{2} b c}\\ &=\frac{e^{a c+b c x} \tan ^{-1}(\tanh (c (a+b x)))}{b c}-\frac{\log \left (1-\sqrt{2} e^{a c+b c x}+e^{2 a c+2 b c x}\right )}{2 \sqrt{2} b c}+\frac{\log \left (1+\sqrt{2} e^{a c+b c x}+e^{2 a c+2 b c x}\right )}{2 \sqrt{2} b c}-\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\sqrt{2} e^{a c+b c x}\right )}{\sqrt{2} b c}+\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\sqrt{2} e^{a c+b c x}\right )}{\sqrt{2} b c}\\ &=\frac{\tan ^{-1}\left (1-\sqrt{2} e^{a c+b c x}\right )}{\sqrt{2} b c}-\frac{\tan ^{-1}\left (1+\sqrt{2} e^{a c+b c x}\right )}{\sqrt{2} b c}+\frac{e^{a c+b c x} \tan ^{-1}(\tanh (c (a+b x)))}{b c}-\frac{\log \left (1-\sqrt{2} e^{a c+b c x}+e^{2 a c+2 b c x}\right )}{2 \sqrt{2} b c}+\frac{\log \left (1+\sqrt{2} e^{a c+b c x}+e^{2 a c+2 b c x}\right )}{2 \sqrt{2} b c}\\ \end{align*}
Mathematica [C] time = 0.117015, size = 89, normalized size = 0.49 \[ \frac{\text{RootSum}\left [\text{$\#$1}^4+1\& ,\frac{-\log \left (e^{c (a+b x)}-\text{$\#$1}\right )+a c+b c x}{\text{$\#$1}}\& \right ]+2 e^{c (a+b x)} \tan ^{-1}\left (\frac{e^{2 c (a+b x)}-1}{e^{2 c (a+b x)}+1}\right )}{2 b c} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 0.73, size = 1355, normalized size = 7.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.52341, size = 225, normalized size = 1.25 \begin{align*} \frac{\arctan \left (\tanh \left (b c x + a c\right )\right ) e^{\left ({\left (b x + a\right )} c\right )}}{b c} - \frac{\sqrt{2} \arctan \left (\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} + 2 \, e^{\left (b c x + a c\right )}\right )}\right )}{2 \, b c} - \frac{\sqrt{2} \arctan \left (-\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} - 2 \, e^{\left (b c x + a c\right )}\right )}\right )}{2 \, b c} + \frac{\sqrt{2} \log \left (\sqrt{2} e^{\left (b c x + a c\right )} + e^{\left (2 \, b c x + 2 \, a c\right )} + 1\right )}{4 \, b c} - \frac{\sqrt{2} \log \left (-\sqrt{2} e^{\left (b c x + a c\right )} + e^{\left (2 \, b c x + 2 \, a c\right )} + 1\right )}{4 \, b c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.23642, size = 1152, normalized size = 6.4 \begin{align*} \frac{4 \, \sqrt{2} b c \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{1}{4}} \arctan \left (-\sqrt{2} b c \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{1}{4}} e^{\left (b c x + a c\right )} + \sqrt{2} \sqrt{\sqrt{2} b^{3} c^{3} \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{3}{4}} e^{\left (b c x + a c\right )} + b^{2} c^{2} \sqrt{\frac{1}{b^{4} c^{4}}} + e^{\left (2 \, b c x + 2 \, a c\right )}} b c \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{1}{4}} - 1\right ) + 4 \, \sqrt{2} b c \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{1}{4}} \arctan \left (-\sqrt{2} b c \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{1}{4}} e^{\left (b c x + a c\right )} + \sqrt{2} \sqrt{-\sqrt{2} b^{3} c^{3} \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{3}{4}} e^{\left (b c x + a c\right )} + b^{2} c^{2} \sqrt{\frac{1}{b^{4} c^{4}}} + e^{\left (2 \, b c x + 2 \, a c\right )}} b c \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{1}{4}} + 1\right ) + \sqrt{2} b c \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{1}{4}} \log \left (\sqrt{2} b^{3} c^{3} \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{3}{4}} e^{\left (b c x + a c\right )} + b^{2} c^{2} \sqrt{\frac{1}{b^{4} c^{4}}} + e^{\left (2 \, b c x + 2 \, a c\right )}\right ) - \sqrt{2} b c \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{1}{4}} \log \left (-\sqrt{2} b^{3} c^{3} \left (\frac{1}{b^{4} c^{4}}\right )^{\frac{3}{4}} e^{\left (b c x + a c\right )} + b^{2} c^{2} \sqrt{\frac{1}{b^{4} c^{4}}} + e^{\left (2 \, b c x + 2 \, a c\right )}\right ) + 4 \, \arctan \left (\frac{e^{\left (2 \, b c x + 2 \, a c\right )} - 1}{e^{\left (2 \, b c x + 2 \, a c\right )} + 1}\right ) e^{\left (b c x + a c\right )}}{4 \, b c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.41832, size = 344, normalized size = 1.91 \begin{align*} -\frac{1}{4} \,{\left (\frac{2 \, \sqrt{2} \arctan \left (\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} e^{\left (-a c\right )} + 2 \, e^{\left (b c x\right )}\right )} e^{\left (a c\right )}\right ) e^{\left (-11 \, a c\right )}}{b c} + \frac{2 \, \sqrt{2} \arctan \left (-\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} e^{\left (-a c\right )} - 2 \, e^{\left (b c x\right )}\right )} e^{\left (a c\right )}\right ) e^{\left (-11 \, a c\right )}}{b c} - \frac{\sqrt{2} e^{\left (-11 \, a c\right )} \log \left (\sqrt{2} e^{\left (b c x - a c\right )} + e^{\left (2 \, b c x\right )} + e^{\left (-2 \, a c\right )}\right )}{b c} + \frac{\sqrt{2} e^{\left (-11 \, a c\right )} \log \left (-\sqrt{2} e^{\left (b c x - a c\right )} + e^{\left (2 \, b c x\right )} + e^{\left (-2 \, a c\right )}\right )}{b c}\right )} e^{\left (11 \, a c\right )} - \frac{4 \, \pi e^{\left (b c x + a c\right )} \left \lfloor \frac{3 \, \pi - 4 \, \arctan \left (e^{\left (-2 \, a c\right )}\right )}{4 \, \pi } \right \rfloor - \pi e^{\left (b c x + a c\right )} + 4 \, \arctan \left (e^{\left (-2 \, b c x - 2 \, a c\right )}\right ) e^{\left (b c x + a c\right )}}{4 \, b c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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