Optimal. Leaf size=72 \[ \frac{\sqrt{e^2 \left (-x^2\right )-\frac{a e^2}{b}} \tan ^{-1}\left (\frac{e x}{\sqrt{e^2 \left (-x^2\right )-\frac{a e^2}{b}}}\right )^{m+1}}{e (m+1) \sqrt{a+b x^2}} \]
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Rubi [A] time = 0.107659, antiderivative size = 72, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.05, Rules used = {5157, 5155} \[ \frac{\sqrt{e^2 \left (-x^2\right )-\frac{a e^2}{b}} \tan ^{-1}\left (\frac{e x}{\sqrt{e^2 \left (-x^2\right )-\frac{a e^2}{b}}}\right )^{m+1}}{e (m+1) \sqrt{a+b x^2}} \]
Antiderivative was successfully verified.
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Rule 5157
Rule 5155
Rubi steps
\begin{align*} \int \frac{\tan ^{-1}\left (\frac{e x}{\sqrt{-\frac{a e^2}{b}-e^2 x^2}}\right )^m}{\sqrt{a+b x^2}} \, dx &=\frac{\sqrt{-\frac{a e^2}{b}-e^2 x^2} \int \frac{\tan ^{-1}\left (\frac{e x}{\sqrt{-\frac{a e^2}{b}-e^2 x^2}}\right )^m}{\sqrt{-\frac{a e^2}{b}-e^2 x^2}} \, dx}{\sqrt{a+b x^2}}\\ &=\frac{\sqrt{-\frac{a e^2}{b}-e^2 x^2} \tan ^{-1}\left (\frac{e x}{\sqrt{-\frac{a e^2}{b}-e^2 x^2}}\right )^{1+m}}{e (1+m) \sqrt{a+b x^2}}\\ \end{align*}
Mathematica [A] time = 0.221558, size = 66, normalized size = 0.92 \[ \frac{\sqrt{-\frac{e^2 \left (a+b x^2\right )}{b}} \tan ^{-1}\left (\frac{e x}{\sqrt{-\frac{e^2 \left (a+b x^2\right )}{b}}}\right )^{m+1}}{e (m+1) \sqrt{a+b x^2}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.9, size = 0, normalized size = 0. \begin{align*} \int{ \left ( \arctan \left ({ex{\frac{1}{\sqrt{-{\frac{a{e}^{2}}{b}}-{e}^{2}{x}^{2}}}}} \right ) \right ) ^{m}{\frac{1}{\sqrt{b{x}^{2}+a}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.13816, size = 270, normalized size = 3.75 \begin{align*} -\frac{\sqrt{b x^{2} + a} \left (-\arctan \left (\frac{b x \sqrt{-\frac{b e^{2} x^{2} + a e^{2}}{b}}}{b e x^{2} + a e}\right )\right )^{m} \sqrt{-\frac{b e^{2} x^{2} + a e^{2}}{b}} \arctan \left (\frac{b x \sqrt{-\frac{b e^{2} x^{2} + a e^{2}}{b}}}{b e x^{2} + a e}\right )}{a e m +{\left (b e m + b e\right )} x^{2} + a e} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{atan}^{m}{\left (\frac{e x}{\sqrt{- \frac{a e^{2}}{b} - e^{2} x^{2}}} \right )}}{\sqrt{a + b x^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\arctan \left (\frac{e x}{\sqrt{-e^{2} x^{2} - \frac{a e^{2}}{b}}}\right )^{m}}{\sqrt{b x^{2} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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