Optimal. Leaf size=59 \[ -\frac{1}{18 x^{3/2}}+\frac{1}{30 x^{5/2}}-\frac{\pi }{12 x^3}+\frac{\tan ^{-1}\left (\sqrt{x}\right )}{6 x^3}+\frac{1}{6 \sqrt{x}}+\frac{1}{6} \tan ^{-1}\left (\sqrt{x}\right ) \]
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Rubi [A] time = 0.0245805, antiderivative size = 59, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {5159, 30, 5033, 51, 63, 203} \[ -\frac{1}{18 x^{3/2}}+\frac{1}{30 x^{5/2}}-\frac{\pi }{12 x^3}+\frac{\tan ^{-1}\left (\sqrt{x}\right )}{6 x^3}+\frac{1}{6 \sqrt{x}}+\frac{1}{6} \tan ^{-1}\left (\sqrt{x}\right ) \]
Antiderivative was successfully verified.
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Rule 5159
Rule 30
Rule 5033
Rule 51
Rule 63
Rule 203
Rubi steps
\begin{align*} \int -\frac{\tan ^{-1}\left (\sqrt{x}-\sqrt{1+x}\right )}{x^4} \, dx &=-\left (\frac{1}{2} \int \frac{\tan ^{-1}\left (\sqrt{x}\right )}{x^4} \, dx\right )+\frac{1}{4} \pi \int \frac{1}{x^4} \, dx\\ &=-\frac{\pi }{12 x^3}+\frac{\tan ^{-1}\left (\sqrt{x}\right )}{6 x^3}-\frac{1}{12} \int \frac{1}{x^{7/2} (1+x)} \, dx\\ &=-\frac{\pi }{12 x^3}+\frac{1}{30 x^{5/2}}+\frac{\tan ^{-1}\left (\sqrt{x}\right )}{6 x^3}+\frac{1}{12} \int \frac{1}{x^{5/2} (1+x)} \, dx\\ &=-\frac{\pi }{12 x^3}+\frac{1}{30 x^{5/2}}-\frac{1}{18 x^{3/2}}+\frac{\tan ^{-1}\left (\sqrt{x}\right )}{6 x^3}-\frac{1}{12} \int \frac{1}{x^{3/2} (1+x)} \, dx\\ &=-\frac{\pi }{12 x^3}+\frac{1}{30 x^{5/2}}-\frac{1}{18 x^{3/2}}+\frac{1}{6 \sqrt{x}}+\frac{\tan ^{-1}\left (\sqrt{x}\right )}{6 x^3}+\frac{1}{12} \int \frac{1}{\sqrt{x} (1+x)} \, dx\\ &=-\frac{\pi }{12 x^3}+\frac{1}{30 x^{5/2}}-\frac{1}{18 x^{3/2}}+\frac{1}{6 \sqrt{x}}+\frac{\tan ^{-1}\left (\sqrt{x}\right )}{6 x^3}+\frac{1}{6} \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\sqrt{x}\right )\\ &=-\frac{\pi }{12 x^3}+\frac{1}{30 x^{5/2}}-\frac{1}{18 x^{3/2}}+\frac{1}{6 \sqrt{x}}+\frac{1}{6} \tan ^{-1}\left (\sqrt{x}\right )+\frac{\tan ^{-1}\left (\sqrt{x}\right )}{6 x^3}\\ \end{align*}
Mathematica [A] time = 0.040509, size = 51, normalized size = 0.86 \[ \frac{1}{90} \left (-\frac{-15 x^2+5 x-3}{x^{5/2}}+\frac{30 \tan ^{-1}\left (\sqrt{x}-\sqrt{x+1}\right )}{x^3}+15 \tan ^{-1}\left (\sqrt{x}\right )\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.048, size = 40, normalized size = 0.7 \begin{align*}{\frac{1}{3\,{x}^{3}}\arctan \left ( \sqrt{x}-\sqrt{x+1} \right ) }+{\frac{1}{6}\arctan \left ( \sqrt{x} \right ) }+{\frac{1}{30}{x}^{-{\frac{5}{2}}}}+{\frac{1}{6}{\frac{1}{\sqrt{x}}}}-{\frac{1}{18}{x}^{-{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.62479, size = 53, normalized size = 0.9 \begin{align*} \frac{1}{6 \, \sqrt{x}} - \frac{1}{18 \, x^{\frac{3}{2}}} - \frac{\arctan \left (\sqrt{x + 1} - \sqrt{x}\right )}{3 \, x^{3}} + \frac{1}{30 \, x^{\frac{5}{2}}} + \frac{1}{6} \, \arctan \left (\sqrt{x}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.06878, size = 115, normalized size = 1.95 \begin{align*} -\frac{30 \,{\left (x^{3} + 1\right )} \arctan \left (\sqrt{x + 1} - \sqrt{x}\right ) -{\left (15 \, x^{2} - 5 \, x + 3\right )} \sqrt{x}}{90 \, x^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.13073, size = 53, normalized size = 0.9 \begin{align*} \frac{15 \, x^{2} - 5 \, x + 3}{90 \, x^{\frac{5}{2}}} + \frac{\arctan \left (-\sqrt{x + 1} + \sqrt{x}\right )}{3 \, x^{3}} + \frac{1}{6} \, \arctan \left (\sqrt{x}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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