Optimal. Leaf size=91 \[ \frac{1}{2} i x^2 \text{PolyLog}\left (2,-i e^x\right )-\frac{1}{2} i x^2 \text{PolyLog}\left (2,i e^x\right )-i x \text{PolyLog}\left (3,-i e^x\right )+i x \text{PolyLog}\left (3,i e^x\right )+i \text{PolyLog}\left (4,-i e^x\right )-i \text{PolyLog}\left (4,i e^x\right ) \]
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Rubi [A] time = 0.0661729, antiderivative size = 91, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 5, integrand size = 8, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.625, Rules used = {5143, 2531, 6609, 2282, 6589} \[ \frac{1}{2} i x^2 \text{PolyLog}\left (2,-i e^x\right )-\frac{1}{2} i x^2 \text{PolyLog}\left (2,i e^x\right )-i x \text{PolyLog}\left (3,-i e^x\right )+i x \text{PolyLog}\left (3,i e^x\right )+i \text{PolyLog}\left (4,-i e^x\right )-i \text{PolyLog}\left (4,i e^x\right ) \]
Antiderivative was successfully verified.
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Rule 5143
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int x^2 \tan ^{-1}\left (e^x\right ) \, dx &=\frac{1}{2} i \int x^2 \log \left (1-i e^x\right ) \, dx-\frac{1}{2} i \int x^2 \log \left (1+i e^x\right ) \, dx\\ &=\frac{1}{2} i x^2 \text{Li}_2\left (-i e^x\right )-\frac{1}{2} i x^2 \text{Li}_2\left (i e^x\right )-i \int x \text{Li}_2\left (-i e^x\right ) \, dx+i \int x \text{Li}_2\left (i e^x\right ) \, dx\\ &=\frac{1}{2} i x^2 \text{Li}_2\left (-i e^x\right )-\frac{1}{2} i x^2 \text{Li}_2\left (i e^x\right )-i x \text{Li}_3\left (-i e^x\right )+i x \text{Li}_3\left (i e^x\right )+i \int \text{Li}_3\left (-i e^x\right ) \, dx-i \int \text{Li}_3\left (i e^x\right ) \, dx\\ &=\frac{1}{2} i x^2 \text{Li}_2\left (-i e^x\right )-\frac{1}{2} i x^2 \text{Li}_2\left (i e^x\right )-i x \text{Li}_3\left (-i e^x\right )+i x \text{Li}_3\left (i e^x\right )+i \operatorname{Subst}\left (\int \frac{\text{Li}_3(-i x)}{x} \, dx,x,e^x\right )-i \operatorname{Subst}\left (\int \frac{\text{Li}_3(i x)}{x} \, dx,x,e^x\right )\\ &=\frac{1}{2} i x^2 \text{Li}_2\left (-i e^x\right )-\frac{1}{2} i x^2 \text{Li}_2\left (i e^x\right )-i x \text{Li}_3\left (-i e^x\right )+i x \text{Li}_3\left (i e^x\right )+i \text{Li}_4\left (-i e^x\right )-i \text{Li}_4\left (i e^x\right )\\ \end{align*}
Mathematica [A] time = 0.0080973, size = 91, normalized size = 1. \[ \frac{1}{2} i x^2 \text{PolyLog}\left (2,-i e^x\right )-\frac{1}{2} i x^2 \text{PolyLog}\left (2,i e^x\right )-i x \text{PolyLog}\left (3,-i e^x\right )+i x \text{PolyLog}\left (3,i e^x\right )+i \text{PolyLog}\left (4,-i e^x\right )-i \text{PolyLog}\left (4,i e^x\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.079, size = 70, normalized size = 0.8 \begin{align*}{\frac{i}{2}}{x}^{2}{\it polylog} \left ( 2,-i{{\rm e}^{x}} \right ) -{\frac{i}{2}}{x}^{2}{\it polylog} \left ( 2,i{{\rm e}^{x}} \right ) -ix{\it polylog} \left ( 3,-i{{\rm e}^{x}} \right ) +ix{\it polylog} \left ( 3,i{{\rm e}^{x}} \right ) +i{\it polylog} \left ( 4,-i{{\rm e}^{x}} \right ) -i{\it polylog} \left ( 4,i{{\rm e}^{x}} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{3} \, x^{3} \arctan \left (e^{x}\right ) - \int \frac{x^{3} e^{x}}{3 \,{\left (e^{\left (2 \, x\right )} + 1\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 2.28235, size = 298, normalized size = 3.27 \begin{align*} \frac{1}{3} \, x^{3} \arctan \left (e^{x}\right ) + \frac{1}{6} i \, x^{3} \log \left (i \, e^{x} + 1\right ) - \frac{1}{6} i \, x^{3} \log \left (-i \, e^{x} + 1\right ) - \frac{1}{2} i \, x^{2}{\rm Li}_2\left (i \, e^{x}\right ) + \frac{1}{2} i \, x^{2}{\rm Li}_2\left (-i \, e^{x}\right ) + i \, x{\rm polylog}\left (3, i \, e^{x}\right ) - i \, x{\rm polylog}\left (3, -i \, e^{x}\right ) - i \,{\rm polylog}\left (4, i \, e^{x}\right ) + i \,{\rm polylog}\left (4, -i \, e^{x}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{2} \operatorname{atan}{\left (e^{x} \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{2} \arctan \left (e^{x}\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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