Optimal. Leaf size=410 \[ \frac{\sqrt [4]{-i a-i b x+1} (i a+i b x+1)^{7/4}}{2 b^2}+\frac{(3-4 i a) \sqrt [4]{-i a-i b x+1} (i a+i b x+1)^{3/4}}{4 b^2}-\frac{3 (3-4 i a) \log \left (\frac{\sqrt{-i a-i b x+1}}{\sqrt{i a+i b x+1}}-\frac{\sqrt{2} \sqrt [4]{-i a-i b x+1}}{\sqrt [4]{i a+i b x+1}}+1\right )}{8 \sqrt{2} b^2}+\frac{3 (3-4 i a) \log \left (\frac{\sqrt{-i a-i b x+1}}{\sqrt{i a+i b x+1}}+\frac{\sqrt{2} \sqrt [4]{-i a-i b x+1}}{\sqrt [4]{i a+i b x+1}}+1\right )}{8 \sqrt{2} b^2}-\frac{3 (3-4 i a) \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{-i a-i b x+1}}{\sqrt [4]{i a+i b x+1}}\right )}{4 \sqrt{2} b^2}+\frac{3 (3-4 i a) \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt [4]{-i a-i b x+1}}{\sqrt [4]{i a+i b x+1}}\right )}{4 \sqrt{2} b^2} \]
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Rubi [A] time = 0.292121, antiderivative size = 410, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 11, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.688, Rules used = {5095, 80, 50, 63, 240, 211, 1165, 628, 1162, 617, 204} \[ \frac{\sqrt [4]{-i a-i b x+1} (i a+i b x+1)^{7/4}}{2 b^2}+\frac{(3-4 i a) \sqrt [4]{-i a-i b x+1} (i a+i b x+1)^{3/4}}{4 b^2}-\frac{3 (3-4 i a) \log \left (\frac{\sqrt{-i a-i b x+1}}{\sqrt{i a+i b x+1}}-\frac{\sqrt{2} \sqrt [4]{-i a-i b x+1}}{\sqrt [4]{i a+i b x+1}}+1\right )}{8 \sqrt{2} b^2}+\frac{3 (3-4 i a) \log \left (\frac{\sqrt{-i a-i b x+1}}{\sqrt{i a+i b x+1}}+\frac{\sqrt{2} \sqrt [4]{-i a-i b x+1}}{\sqrt [4]{i a+i b x+1}}+1\right )}{8 \sqrt{2} b^2}-\frac{3 (3-4 i a) \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{-i a-i b x+1}}{\sqrt [4]{i a+i b x+1}}\right )}{4 \sqrt{2} b^2}+\frac{3 (3-4 i a) \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt [4]{-i a-i b x+1}}{\sqrt [4]{i a+i b x+1}}\right )}{4 \sqrt{2} b^2} \]
Antiderivative was successfully verified.
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Rule 5095
Rule 80
Rule 50
Rule 63
Rule 240
Rule 211
Rule 1165
Rule 628
Rule 1162
Rule 617
Rule 204
Rubi steps
\begin{align*} \int e^{\frac{3}{2} i \tan ^{-1}(a+b x)} x \, dx &=\int \frac{x (1+i a+i b x)^{3/4}}{(1-i a-i b x)^{3/4}} \, dx\\ &=\frac{\sqrt [4]{1-i a-i b x} (1+i a+i b x)^{7/4}}{2 b^2}-\frac{(3 i+4 a) \int \frac{(1+i a+i b x)^{3/4}}{(1-i a-i b x)^{3/4}} \, dx}{4 b}\\ &=\frac{(3-4 i a) \sqrt [4]{1-i a-i b x} (1+i a+i b x)^{3/4}}{4 b^2}+\frac{\sqrt [4]{1-i a-i b x} (1+i a+i b x)^{7/4}}{2 b^2}-\frac{(3 (3 i+4 a)) \int \frac{1}{(1-i a-i b x)^{3/4} \sqrt [4]{1+i a+i b x}} \, dx}{8 b}\\ &=\frac{(3-4 i a) \sqrt [4]{1-i a-i b x} (1+i a+i b x)^{3/4}}{4 b^2}+\frac{\sqrt [4]{1-i a-i b x} (1+i a+i b x)^{7/4}}{2 b^2}+\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{1}{\sqrt [4]{2-x^4}} \, dx,x,\sqrt [4]{1-i a-i b x}\right )}{2 b^2}\\ &=\frac{(3-4 i a) \sqrt [4]{1-i a-i b x} (1+i a+i b x)^{3/4}}{4 b^2}+\frac{\sqrt [4]{1-i a-i b x} (1+i a+i b x)^{7/4}}{2 b^2}+\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{1}{1+x^4} \, dx,x,\frac{\sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{2 b^2}\\ &=\frac{(3-4 i a) \sqrt [4]{1-i a-i b x} (1+i a+i b x)^{3/4}}{4 b^2}+\frac{\sqrt [4]{1-i a-i b x} (1+i a+i b x)^{7/4}}{2 b^2}+\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,\frac{\sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{4 b^2}+\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,\frac{\sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{4 b^2}\\ &=\frac{(3-4 i a) \sqrt [4]{1-i a-i b x} (1+i a+i b x)^{3/4}}{4 b^2}+\frac{\sqrt [4]{1-i a-i b x} (1+i a+i b x)^{7/4}}{2 b^2}+\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,\frac{\sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{8 b^2}+\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,\frac{\sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{8 b^2}-\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,\frac{\sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{8 \sqrt{2} b^2}-\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,\frac{\sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{8 \sqrt{2} b^2}\\ &=\frac{(3-4 i a) \sqrt [4]{1-i a-i b x} (1+i a+i b x)^{3/4}}{4 b^2}+\frac{\sqrt [4]{1-i a-i b x} (1+i a+i b x)^{7/4}}{2 b^2}-\frac{3 (3-4 i a) \log \left (1+\frac{\sqrt{1-i a-i b x}}{\sqrt{1+i a+i b x}}-\frac{\sqrt{2} \sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{8 \sqrt{2} b^2}+\frac{3 (3-4 i a) \log \left (1+\frac{\sqrt{1-i a-i b x}}{\sqrt{1+i a+i b x}}+\frac{\sqrt{2} \sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{8 \sqrt{2} b^2}+\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{4 \sqrt{2} b^2}-\frac{(3 (3-4 i a)) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{4 \sqrt{2} b^2}\\ &=\frac{(3-4 i a) \sqrt [4]{1-i a-i b x} (1+i a+i b x)^{3/4}}{4 b^2}+\frac{\sqrt [4]{1-i a-i b x} (1+i a+i b x)^{7/4}}{2 b^2}-\frac{3 (3-4 i a) \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{4 \sqrt{2} b^2}+\frac{3 (3-4 i a) \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{4 \sqrt{2} b^2}-\frac{3 (3-4 i a) \log \left (1+\frac{\sqrt{1-i a-i b x}}{\sqrt{1+i a+i b x}}-\frac{\sqrt{2} \sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{8 \sqrt{2} b^2}+\frac{3 (3-4 i a) \log \left (1+\frac{\sqrt{1-i a-i b x}}{\sqrt{1+i a+i b x}}+\frac{\sqrt{2} \sqrt [4]{1-i a-i b x}}{\sqrt [4]{1+i a+i b x}}\right )}{8 \sqrt{2} b^2}\\ \end{align*}
Mathematica [C] time = 0.0419517, size = 79, normalized size = 0.19 \[ \frac{\sqrt [4]{-i (a+b x+i)} \left (2\ 2^{3/4} (3-4 i a) \, _2F_1\left (-\frac{3}{4},\frac{1}{4};\frac{5}{4};-\frac{1}{2} i (a+b x+i)\right )+(i a+i b x+1)^{7/4}\right )}{2 b^2} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.22, size = 0, normalized size = 0. \begin{align*} \int \left ({(1+i \left ( bx+a \right ) ){\frac{1}{\sqrt{1+ \left ( bx+a \right ) ^{2}}}}} \right ) ^{{\frac{3}{2}}}x\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \left (\frac{i \, b x + i \, a + 1}{\sqrt{{\left (b x + a\right )}^{2} + 1}}\right )^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.316, size = 1123, normalized size = 2.74 \begin{align*} -\frac{b^{2} \sqrt{\frac{144 i \, a^{2} - 216 \, a - 81 i}{b^{4}}} \log \left (\frac{b^{2} \sqrt{\frac{144 i \, a^{2} - 216 \, a - 81 i}{b^{4}}} +{\left (12 \, a + 9 i\right )} \sqrt{\frac{i \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}}}{12 \, a + 9 i}\right ) - b^{2} \sqrt{\frac{144 i \, a^{2} - 216 \, a - 81 i}{b^{4}}} \log \left (-\frac{b^{2} \sqrt{\frac{144 i \, a^{2} - 216 \, a - 81 i}{b^{4}}} -{\left (12 \, a + 9 i\right )} \sqrt{\frac{i \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}}}{12 \, a + 9 i}\right ) - b^{2} \sqrt{\frac{-144 i \, a^{2} + 216 \, a + 81 i}{b^{4}}} \log \left (\frac{b^{2} \sqrt{\frac{-144 i \, a^{2} + 216 \, a + 81 i}{b^{4}}} +{\left (12 \, a + 9 i\right )} \sqrt{\frac{i \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}}}{12 \, a + 9 i}\right ) + b^{2} \sqrt{\frac{-144 i \, a^{2} + 216 \, a + 81 i}{b^{4}}} \log \left (-\frac{b^{2} \sqrt{\frac{-144 i \, a^{2} + 216 \, a + 81 i}{b^{4}}} -{\left (12 \, a + 9 i\right )} \sqrt{\frac{i \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}}}{12 \, a + 9 i}\right ) - 2 \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}{\left (2 i \, b x - 2 i \, a + 5\right )} \sqrt{\frac{i \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}}}{8 \, b^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \left (\frac{i \, b x + i \, a + 1}{\sqrt{{\left (b x + a\right )}^{2} + 1}}\right )^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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