Optimal. Leaf size=79 \[ \frac{x^{m+1} \, _2F_1\left (\frac{1}{2},\frac{m+1}{2};\frac{m+3}{2};-a^2 x^2\right )}{m+1}+\frac{i a x^{m+2} \, _2F_1\left (\frac{1}{2},\frac{m+2}{2};\frac{m+4}{2};-a^2 x^2\right )}{m+2} \]
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Rubi [A] time = 0.0407399, antiderivative size = 79, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.214, Rules used = {5060, 808, 364} \[ \frac{x^{m+1} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{m+1}{2},\frac{m+3}{2},-a^2 x^2\right )}{m+1}+\frac{i a x^{m+2} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{m+2}{2},\frac{m+4}{2},-a^2 x^2\right )}{m+2} \]
Antiderivative was successfully verified.
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Rule 5060
Rule 808
Rule 364
Rubi steps
\begin{align*} \int e^{i \tan ^{-1}(a x)} x^m \, dx &=\int \frac{x^m (1+i a x)}{\sqrt{1+a^2 x^2}} \, dx\\ &=(i a) \int \frac{x^{1+m}}{\sqrt{1+a^2 x^2}} \, dx+\int \frac{x^m}{\sqrt{1+a^2 x^2}} \, dx\\ &=\frac{x^{1+m} \, _2F_1\left (\frac{1}{2},\frac{1+m}{2};\frac{3+m}{2};-a^2 x^2\right )}{1+m}+\frac{i a x^{2+m} \, _2F_1\left (\frac{1}{2},\frac{2+m}{2};\frac{4+m}{2};-a^2 x^2\right )}{2+m}\\ \end{align*}
Mathematica [C] time = 0.0369974, size = 85, normalized size = 1.08 \[ \frac{i \sqrt{1-i a x} \sqrt{a x-i} x^{m+1} F_1\left (m+1;-\frac{1}{2},\frac{1}{2};m+2;-i a x,i a x\right )}{(m+1) \sqrt{1+i a x} \sqrt{a x+i}} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.293, size = 71, normalized size = 0.9 \begin{align*}{\frac{{x}^{1+m}}{1+m}{\mbox{$_2$F$_1$}({\frac{1}{2}},{\frac{1}{2}}+{\frac{m}{2}};\,{\frac{3}{2}}+{\frac{m}{2}};\,-{a}^{2}{x}^{2})}}+{\frac{ia{x}^{2+m}}{2+m}{\mbox{$_2$F$_1$}({\frac{1}{2}},1+{\frac{m}{2}};\,2+{\frac{m}{2}};\,-{a}^{2}{x}^{2})}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (i \, a x + 1\right )} x^{m}}{\sqrt{a^{2} x^{2} + 1}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{i \, \sqrt{a^{2} x^{2} + 1} x^{m}}{a x + i}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 3.36593, size = 95, normalized size = 1.2 \begin{align*} \frac{i a x^{2} x^{m} \Gamma \left (\frac{m}{2} + 1\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, \frac{m}{2} + 1 \\ \frac{m}{2} + 2 \end{matrix}\middle |{a^{2} x^{2} e^{i \pi }} \right )}}{2 \Gamma \left (\frac{m}{2} + 2\right )} + \frac{x x^{m} \Gamma \left (\frac{m}{2} + \frac{1}{2}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, \frac{m}{2} + \frac{1}{2} \\ \frac{m}{2} + \frac{3}{2} \end{matrix}\middle |{a^{2} x^{2} e^{i \pi }} \right )}}{2 \Gamma \left (\frac{m}{2} + \frac{3}{2}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (i \, a x + 1\right )} x^{m}}{\sqrt{a^{2} x^{2} + 1}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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