Optimal. Leaf size=56 \[ -i \text{PolyLog}\left (2,-e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right )-i \cos ^{-1}\left (\sqrt{x}\right )^2+2 \cos ^{-1}\left (\sqrt{x}\right ) \log \left (1+e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right ) \]
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Rubi [A] time = 0.0558409, antiderivative size = 56, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {4831, 3719, 2190, 2279, 2391} \[ -i \text{PolyLog}\left (2,-e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right )-i \cos ^{-1}\left (\sqrt{x}\right )^2+2 \cos ^{-1}\left (\sqrt{x}\right ) \log \left (1+e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right ) \]
Antiderivative was successfully verified.
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Rule 4831
Rule 3719
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\cos ^{-1}\left (\sqrt{x}\right )}{x} \, dx &=-\left (2 \operatorname{Subst}\left (\int x \tan (x) \, dx,x,\cos ^{-1}\left (\sqrt{x}\right )\right )\right )\\ &=-i \cos ^{-1}\left (\sqrt{x}\right )^2+4 i \operatorname{Subst}\left (\int \frac{e^{2 i x} x}{1+e^{2 i x}} \, dx,x,\cos ^{-1}\left (\sqrt{x}\right )\right )\\ &=-i \cos ^{-1}\left (\sqrt{x}\right )^2+2 \cos ^{-1}\left (\sqrt{x}\right ) \log \left (1+e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right )-2 \operatorname{Subst}\left (\int \log \left (1+e^{2 i x}\right ) \, dx,x,\cos ^{-1}\left (\sqrt{x}\right )\right )\\ &=-i \cos ^{-1}\left (\sqrt{x}\right )^2+2 \cos ^{-1}\left (\sqrt{x}\right ) \log \left (1+e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right )+i \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right )\\ &=-i \cos ^{-1}\left (\sqrt{x}\right )^2+2 \cos ^{-1}\left (\sqrt{x}\right ) \log \left (1+e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right )-i \text{Li}_2\left (-e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right )\\ \end{align*}
Mathematica [A] time = 0.0260489, size = 54, normalized size = 0.96 \[ -i \left (\text{PolyLog}\left (2,-e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right )+\cos ^{-1}\left (\sqrt{x}\right ) \left (\cos ^{-1}\left (\sqrt{x}\right )+2 i \log \left (1+e^{2 i \cos ^{-1}\left (\sqrt{x}\right )}\right )\right )\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.002, size = 59, normalized size = 1.1 \begin{align*} -i \left ( \arccos \left ( \sqrt{x} \right ) \right ) ^{2}+2\,\arccos \left ( \sqrt{x} \right ) \ln \left ( 1+ \left ( \sqrt{x}+i\sqrt{1-x} \right ) ^{2} \right ) -i{\it polylog} \left ( 2,- \left ( \sqrt{x}+i\sqrt{1-x} \right ) ^{2} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\arccos \left (\sqrt{x}\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\arccos \left (\sqrt{x}\right )}{x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{acos}{\left (\sqrt{x} \right )}}{x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\arccos \left (\sqrt{x}\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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