Optimal. Leaf size=51 \[ -\frac{x^2 \sqrt{1-a^2 x^4}}{8 a}+\frac{\sin ^{-1}\left (a x^2\right )}{8 a^2}+\frac{1}{4} x^4 \cos ^{-1}\left (a x^2\right ) \]
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Rubi [A] time = 0.0385854, antiderivative size = 51, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {4843, 12, 275, 321, 216} \[ -\frac{x^2 \sqrt{1-a^2 x^4}}{8 a}+\frac{\sin ^{-1}\left (a x^2\right )}{8 a^2}+\frac{1}{4} x^4 \cos ^{-1}\left (a x^2\right ) \]
Antiderivative was successfully verified.
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Rule 4843
Rule 12
Rule 275
Rule 321
Rule 216
Rubi steps
\begin{align*} \int x^3 \cos ^{-1}\left (a x^2\right ) \, dx &=\frac{1}{4} x^4 \cos ^{-1}\left (a x^2\right )+\frac{1}{4} \int \frac{2 a x^5}{\sqrt{1-a^2 x^4}} \, dx\\ &=\frac{1}{4} x^4 \cos ^{-1}\left (a x^2\right )+\frac{1}{2} a \int \frac{x^5}{\sqrt{1-a^2 x^4}} \, dx\\ &=\frac{1}{4} x^4 \cos ^{-1}\left (a x^2\right )+\frac{1}{4} a \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1-a^2 x^2}} \, dx,x,x^2\right )\\ &=-\frac{x^2 \sqrt{1-a^2 x^4}}{8 a}+\frac{1}{4} x^4 \cos ^{-1}\left (a x^2\right )+\frac{\operatorname{Subst}\left (\int \frac{1}{\sqrt{1-a^2 x^2}} \, dx,x,x^2\right )}{8 a}\\ &=-\frac{x^2 \sqrt{1-a^2 x^4}}{8 a}+\frac{1}{4} x^4 \cos ^{-1}\left (a x^2\right )+\frac{\sin ^{-1}\left (a x^2\right )}{8 a^2}\\ \end{align*}
Mathematica [A] time = 0.0275862, size = 48, normalized size = 0.94 \[ \frac{-a x^2 \sqrt{1-a^2 x^4}+2 a^2 x^4 \cos ^{-1}\left (a x^2\right )+\sin ^{-1}\left (a x^2\right )}{8 a^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.053, size = 65, normalized size = 1.3 \begin{align*}{\frac{{x}^{4}\arccos \left ( a{x}^{2} \right ) }{4}}-{\frac{{x}^{2}}{8\,a}\sqrt{-{a}^{2}{x}^{4}+1}}+{\frac{1}{8\,a}\arctan \left ({{x}^{2}\sqrt{{a}^{2}}{\frac{1}{\sqrt{-{a}^{2}{x}^{4}+1}}}} \right ){\frac{1}{\sqrt{{a}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.47624, size = 107, normalized size = 2.1 \begin{align*} \frac{1}{4} \, x^{4} \arccos \left (a x^{2}\right ) - \frac{1}{8} \, a{\left (\frac{\arctan \left (\frac{\sqrt{-a^{2} x^{4} + 1}}{a x^{2}}\right )}{a^{3}} + \frac{\sqrt{-a^{2} x^{4} + 1}}{{\left (a^{4} - \frac{{\left (a^{2} x^{4} - 1\right )} a^{2}}{x^{4}}\right )} x^{2}}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.52952, size = 93, normalized size = 1.82 \begin{align*} -\frac{\sqrt{-a^{2} x^{4} + 1} a x^{2} -{\left (2 \, a^{2} x^{4} - 1\right )} \arccos \left (a x^{2}\right )}{8 \, a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 1.03189, size = 48, normalized size = 0.94 \begin{align*} \begin{cases} \frac{x^{4} \operatorname{acos}{\left (a x^{2} \right )}}{4} - \frac{x^{2} \sqrt{- a^{2} x^{4} + 1}}{8 a} - \frac{\operatorname{acos}{\left (a x^{2} \right )}}{8 a^{2}} & \text{for}\: a \neq 0 \\\frac{\pi x^{4}}{8} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.34345, size = 62, normalized size = 1.22 \begin{align*} \frac{2 \, a^{2} x^{4} \arccos \left (a x^{2}\right ) - \sqrt{-a^{2} x^{4} + 1} a x^{2} - \arccos \left (a x^{2}\right )}{8 \, a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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