Optimal. Leaf size=65 \[ \frac{\text{Si}\left (\cos ^{-1}(a+b x)\right )}{2 b}+\frac{a+b x}{2 b \cos ^{-1}(a+b x)}+\frac{\sqrt{1-(a+b x)^2}}{2 b \cos ^{-1}(a+b x)^2} \]
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Rubi [A] time = 0.08065, antiderivative size = 65, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 8, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.625, Rules used = {4804, 4622, 4720, 4624, 3299} \[ \frac{\text{Si}\left (\cos ^{-1}(a+b x)\right )}{2 b}+\frac{a+b x}{2 b \cos ^{-1}(a+b x)}+\frac{\sqrt{1-(a+b x)^2}}{2 b \cos ^{-1}(a+b x)^2} \]
Antiderivative was successfully verified.
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Rule 4804
Rule 4622
Rule 4720
Rule 4624
Rule 3299
Rubi steps
\begin{align*} \int \frac{1}{\cos ^{-1}(a+b x)^3} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{1}{\cos ^{-1}(x)^3} \, dx,x,a+b x\right )}{b}\\ &=\frac{\sqrt{1-(a+b x)^2}}{2 b \cos ^{-1}(a+b x)^2}+\frac{\operatorname{Subst}\left (\int \frac{x}{\sqrt{1-x^2} \cos ^{-1}(x)^2} \, dx,x,a+b x\right )}{2 b}\\ &=\frac{\sqrt{1-(a+b x)^2}}{2 b \cos ^{-1}(a+b x)^2}+\frac{a+b x}{2 b \cos ^{-1}(a+b x)}-\frac{\operatorname{Subst}\left (\int \frac{1}{\cos ^{-1}(x)} \, dx,x,a+b x\right )}{2 b}\\ &=\frac{\sqrt{1-(a+b x)^2}}{2 b \cos ^{-1}(a+b x)^2}+\frac{a+b x}{2 b \cos ^{-1}(a+b x)}+\frac{\operatorname{Subst}\left (\int \frac{\sin (x)}{x} \, dx,x,\cos ^{-1}(a+b x)\right )}{2 b}\\ &=\frac{\sqrt{1-(a+b x)^2}}{2 b \cos ^{-1}(a+b x)^2}+\frac{a+b x}{2 b \cos ^{-1}(a+b x)}+\frac{\text{Si}\left (\cos ^{-1}(a+b x)\right )}{2 b}\\ \end{align*}
Mathematica [A] time = 0.0501086, size = 65, normalized size = 1. \[ \frac{\text{Si}\left (\cos ^{-1}(a+b x)\right )}{2 b}+\frac{a+b x}{2 b \cos ^{-1}(a+b x)}+\frac{\sqrt{1-(a+b x)^2}}{2 b \cos ^{-1}(a+b x)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.051, size = 53, normalized size = 0.8 \begin{align*}{\frac{1}{b} \left ({\frac{1}{2\, \left ( \arccos \left ( bx+a \right ) \right ) ^{2}}\sqrt{1- \left ( bx+a \right ) ^{2}}}+{\frac{bx+a}{2\,\arccos \left ( bx+a \right ) }}+{\frac{{\it Si} \left ( \arccos \left ( bx+a \right ) \right ) }{2}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{1}{\arccos \left (b x + a\right )^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\operatorname{acos}^{3}{\left (a + b x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.29833, size = 77, normalized size = 1.18 \begin{align*} \frac{\operatorname{Si}\left (\arccos \left (b x + a\right )\right )}{2 \, b} + \frac{b x + a}{2 \, b \arccos \left (b x + a\right )} + \frac{\sqrt{-{\left (b x + a\right )}^{2} + 1}}{2 \, b \arccos \left (b x + a\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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