Optimal. Leaf size=94 \[ -\frac{\left (11 a^2-5 a b x+4\right ) \sqrt{1-(a+b x)^2}}{18 b^3}-\frac{a \left (2 a^2+3\right ) \sin ^{-1}(a+b x)}{6 b^3}-\frac{x^2 \sqrt{1-(a+b x)^2}}{9 b}+\frac{1}{3} x^3 \cos ^{-1}(a+b x) \]
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Rubi [A] time = 0.114887, antiderivative size = 94, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {4806, 4744, 743, 780, 216} \[ -\frac{\left (11 a^2-5 a b x+4\right ) \sqrt{1-(a+b x)^2}}{18 b^3}-\frac{a \left (2 a^2+3\right ) \sin ^{-1}(a+b x)}{6 b^3}-\frac{x^2 \sqrt{1-(a+b x)^2}}{9 b}+\frac{1}{3} x^3 \cos ^{-1}(a+b x) \]
Antiderivative was successfully verified.
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Rule 4806
Rule 4744
Rule 743
Rule 780
Rule 216
Rubi steps
\begin{align*} \int x^2 \cos ^{-1}(a+b x) \, dx &=\frac{\operatorname{Subst}\left (\int \left (-\frac{a}{b}+\frac{x}{b}\right )^2 \cos ^{-1}(x) \, dx,x,a+b x\right )}{b}\\ &=\frac{1}{3} x^3 \cos ^{-1}(a+b x)+\frac{1}{3} \operatorname{Subst}\left (\int \frac{\left (-\frac{a}{b}+\frac{x}{b}\right )^3}{\sqrt{1-x^2}} \, dx,x,a+b x\right )\\ &=-\frac{x^2 \sqrt{1-(a+b x)^2}}{9 b}+\frac{1}{3} x^3 \cos ^{-1}(a+b x)-\frac{1}{9} \operatorname{Subst}\left (\int \frac{\left (-\frac{2+3 a^2}{b^2}+\frac{5 a x}{b^2}\right ) \left (-\frac{a}{b}+\frac{x}{b}\right )}{\sqrt{1-x^2}} \, dx,x,a+b x\right )\\ &=-\frac{x^2 \sqrt{1-(a+b x)^2}}{9 b}-\frac{\left (4+11 a^2-5 a b x\right ) \sqrt{1-(a+b x)^2}}{18 b^3}+\frac{1}{3} x^3 \cos ^{-1}(a+b x)-\frac{\left (a \left (3+2 a^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x^2}} \, dx,x,a+b x\right )}{6 b^3}\\ &=-\frac{x^2 \sqrt{1-(a+b x)^2}}{9 b}-\frac{\left (4+11 a^2-5 a b x\right ) \sqrt{1-(a+b x)^2}}{18 b^3}+\frac{1}{3} x^3 \cos ^{-1}(a+b x)-\frac{a \left (3+2 a^2\right ) \sin ^{-1}(a+b x)}{6 b^3}\\ \end{align*}
Mathematica [A] time = 0.0828341, size = 83, normalized size = 0.88 \[ -\frac{\sqrt{-a^2-2 a b x-b^2 x^2+1} \left (11 a^2-5 a b x+2 b^2 x^2+4\right )+3 a \left (2 a^2+3\right ) \sin ^{-1}(a+b x)-6 b^3 x^3 \cos ^{-1}(a+b x)}{18 b^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.003, size = 161, normalized size = 1.7 \begin{align*}{\frac{1}{{b}^{3}} \left ({\frac{\arccos \left ( bx+a \right ) \left ( bx+a \right ) ^{3}}{3}}-\arccos \left ( bx+a \right ) \left ( bx+a \right ) ^{2}a+\arccos \left ( bx+a \right ) \left ( bx+a \right ){a}^{2}-{\frac{\arccos \left ( bx+a \right ){a}^{3}}{3}}-{\frac{ \left ( bx+a \right ) ^{2}}{9}\sqrt{1- \left ( bx+a \right ) ^{2}}}-{\frac{2}{9}\sqrt{1- \left ( bx+a \right ) ^{2}}}-a \left ( -{\frac{bx+a}{2}\sqrt{1- \left ( bx+a \right ) ^{2}}}+{\frac{\arcsin \left ( bx+a \right ) }{2}} \right ) -{a}^{2}\sqrt{1- \left ( bx+a \right ) ^{2}}-{\frac{\arcsin \left ( bx+a \right ){a}^{3}}{3}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.42065, size = 173, normalized size = 1.84 \begin{align*} \frac{3 \,{\left (2 \, b^{3} x^{3} + 2 \, a^{3} + 3 \, a\right )} \arccos \left (b x + a\right ) -{\left (2 \, b^{2} x^{2} - 5 \, a b x + 11 \, a^{2} + 4\right )} \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{18 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.819965, size = 170, normalized size = 1.81 \begin{align*} \begin{cases} \frac{a^{3} \operatorname{acos}{\left (a + b x \right )}}{3 b^{3}} - \frac{11 a^{2} \sqrt{- a^{2} - 2 a b x - b^{2} x^{2} + 1}}{18 b^{3}} + \frac{5 a x \sqrt{- a^{2} - 2 a b x - b^{2} x^{2} + 1}}{18 b^{2}} + \frac{a \operatorname{acos}{\left (a + b x \right )}}{2 b^{3}} + \frac{x^{3} \operatorname{acos}{\left (a + b x \right )}}{3} - \frac{x^{2} \sqrt{- a^{2} - 2 a b x - b^{2} x^{2} + 1}}{9 b} - \frac{2 \sqrt{- a^{2} - 2 a b x - b^{2} x^{2} + 1}}{9 b^{3}} & \text{for}\: b \neq 0 \\\frac{x^{3} \operatorname{acos}{\left (a \right )}}{3} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.30621, size = 211, normalized size = 2.24 \begin{align*} \frac{{\left (b x + a\right )}^{3} \arccos \left (b x + a\right )}{3 \, b^{3}} - \frac{{\left (b x + a\right )}^{2} a \arccos \left (b x + a\right )}{b^{3}} + \frac{{\left (b x + a\right )} a^{2} \arccos \left (b x + a\right )}{b^{3}} - \frac{\sqrt{-{\left (b x + a\right )}^{2} + 1}{\left (b x + a\right )}^{2}}{9 \, b^{3}} + \frac{\sqrt{-{\left (b x + a\right )}^{2} + 1}{\left (b x + a\right )} a}{2 \, b^{3}} - \frac{\sqrt{-{\left (b x + a\right )}^{2} + 1} a^{2}}{b^{3}} + \frac{a \arccos \left (b x + a\right )}{2 \, b^{3}} - \frac{2 \, \sqrt{-{\left (b x + a\right )}^{2} + 1}}{9 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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