3.14 \(\int \frac{(f+g x)^3 (a+b \cos ^{-1}(c x))}{\sqrt{d-c^2 d x^2}} \, dx\)

Optimal. Leaf size=450 \[ -\frac{3 f^2 g \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{c^2 \sqrt{d-c^2 d x^2}}-\frac{f^3 \sqrt{1-c^2 x^2} \left (a+b \cos ^{-1}(c x)\right )^2}{2 b c \sqrt{d-c^2 d x^2}}-\frac{3 f g^2 \sqrt{1-c^2 x^2} \left (a+b \cos ^{-1}(c x)\right )^2}{4 b c^3 \sqrt{d-c^2 d x^2}}-\frac{3 f g^2 x \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{2 c^2 \sqrt{d-c^2 d x^2}}-\frac{2 g^3 \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{3 c^4 \sqrt{d-c^2 d x^2}}-\frac{g^3 x^2 \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{3 c^2 \sqrt{d-c^2 d x^2}}-\frac{3 b f^2 g x \sqrt{1-c^2 x^2}}{c \sqrt{d-c^2 d x^2}}-\frac{3 b f g^2 x^2 \sqrt{1-c^2 x^2}}{4 c \sqrt{d-c^2 d x^2}}-\frac{b g^3 x^3 \sqrt{1-c^2 x^2}}{9 c \sqrt{d-c^2 d x^2}}-\frac{2 b g^3 x \sqrt{1-c^2 x^2}}{3 c^3 \sqrt{d-c^2 d x^2}} \]

[Out]

(-3*b*f^2*g*x*Sqrt[1 - c^2*x^2])/(c*Sqrt[d - c^2*d*x^2]) - (2*b*g^3*x*Sqrt[1 - c^2*x^2])/(3*c^3*Sqrt[d - c^2*d
*x^2]) - (3*b*f*g^2*x^2*Sqrt[1 - c^2*x^2])/(4*c*Sqrt[d - c^2*d*x^2]) - (b*g^3*x^3*Sqrt[1 - c^2*x^2])/(9*c*Sqrt
[d - c^2*d*x^2]) - (3*f^2*g*(1 - c^2*x^2)*(a + b*ArcCos[c*x]))/(c^2*Sqrt[d - c^2*d*x^2]) - (2*g^3*(1 - c^2*x^2
)*(a + b*ArcCos[c*x]))/(3*c^4*Sqrt[d - c^2*d*x^2]) - (3*f*g^2*x*(1 - c^2*x^2)*(a + b*ArcCos[c*x]))/(2*c^2*Sqrt
[d - c^2*d*x^2]) - (g^3*x^2*(1 - c^2*x^2)*(a + b*ArcCos[c*x]))/(3*c^2*Sqrt[d - c^2*d*x^2]) - (f^3*Sqrt[1 - c^2
*x^2]*(a + b*ArcCos[c*x])^2)/(2*b*c*Sqrt[d - c^2*d*x^2]) - (3*f*g^2*Sqrt[1 - c^2*x^2]*(a + b*ArcCos[c*x])^2)/(
4*b*c^3*Sqrt[d - c^2*d*x^2])

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Rubi [A]  time = 0.585273, antiderivative size = 450, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 7, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.226, Rules used = {4778, 4764, 4642, 4678, 8, 4708, 30} \[ -\frac{3 f^2 g \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{c^2 \sqrt{d-c^2 d x^2}}-\frac{f^3 \sqrt{1-c^2 x^2} \left (a+b \cos ^{-1}(c x)\right )^2}{2 b c \sqrt{d-c^2 d x^2}}-\frac{3 f g^2 \sqrt{1-c^2 x^2} \left (a+b \cos ^{-1}(c x)\right )^2}{4 b c^3 \sqrt{d-c^2 d x^2}}-\frac{3 f g^2 x \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{2 c^2 \sqrt{d-c^2 d x^2}}-\frac{2 g^3 \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{3 c^4 \sqrt{d-c^2 d x^2}}-\frac{g^3 x^2 \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{3 c^2 \sqrt{d-c^2 d x^2}}-\frac{3 b f^2 g x \sqrt{1-c^2 x^2}}{c \sqrt{d-c^2 d x^2}}-\frac{3 b f g^2 x^2 \sqrt{1-c^2 x^2}}{4 c \sqrt{d-c^2 d x^2}}-\frac{b g^3 x^3 \sqrt{1-c^2 x^2}}{9 c \sqrt{d-c^2 d x^2}}-\frac{2 b g^3 x \sqrt{1-c^2 x^2}}{3 c^3 \sqrt{d-c^2 d x^2}} \]

Antiderivative was successfully verified.

[In]

Int[((f + g*x)^3*(a + b*ArcCos[c*x]))/Sqrt[d - c^2*d*x^2],x]

[Out]

(-3*b*f^2*g*x*Sqrt[1 - c^2*x^2])/(c*Sqrt[d - c^2*d*x^2]) - (2*b*g^3*x*Sqrt[1 - c^2*x^2])/(3*c^3*Sqrt[d - c^2*d
*x^2]) - (3*b*f*g^2*x^2*Sqrt[1 - c^2*x^2])/(4*c*Sqrt[d - c^2*d*x^2]) - (b*g^3*x^3*Sqrt[1 - c^2*x^2])/(9*c*Sqrt
[d - c^2*d*x^2]) - (3*f^2*g*(1 - c^2*x^2)*(a + b*ArcCos[c*x]))/(c^2*Sqrt[d - c^2*d*x^2]) - (2*g^3*(1 - c^2*x^2
)*(a + b*ArcCos[c*x]))/(3*c^4*Sqrt[d - c^2*d*x^2]) - (3*f*g^2*x*(1 - c^2*x^2)*(a + b*ArcCos[c*x]))/(2*c^2*Sqrt
[d - c^2*d*x^2]) - (g^3*x^2*(1 - c^2*x^2)*(a + b*ArcCos[c*x]))/(3*c^2*Sqrt[d - c^2*d*x^2]) - (f^3*Sqrt[1 - c^2
*x^2]*(a + b*ArcCos[c*x])^2)/(2*b*c*Sqrt[d - c^2*d*x^2]) - (3*f*g^2*Sqrt[1 - c^2*x^2]*(a + b*ArcCos[c*x])^2)/(
4*b*c^3*Sqrt[d - c^2*d*x^2])

Rule 4778

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)*((f_) + (g_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(p_), x_Symbol] :
> Dist[(d^IntPart[p]*(d + e*x^2)^FracPart[p])/(1 - c^2*x^2)^FracPart[p], Int[(f + g*x)^m*(1 - c^2*x^2)^p*(a +
b*ArcCos[c*x])^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && EqQ[c^2*d + e, 0] && IntegerQ[m] && IntegerQ
[p - 1/2] &&  !GtQ[d, 0]

Rule 4764

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)*((f_) + (g_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(p_), x_Symbol] :
> Int[ExpandIntegrand[(d + e*x^2)^p*(a + b*ArcCos[c*x])^n, (f + g*x)^m, x], x] /; FreeQ[{a, b, c, d, e, f, g},
x] && EqQ[c^2*d + e, 0] && IGtQ[m, 0] && IntegerQ[p + 1/2] && GtQ[d, 0] && IGtQ[n, 0] && (m == 1 || p > 0 ||
(n == 1 && p > -1) || (m == 2 && p < -2))

Rule 4642

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> -Simp[(a + b*ArcCos[c*x])
^(n + 1)/(b*c*Sqrt[d]*(n + 1)), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && GtQ[d, 0] && NeQ[n,
-1]

Rule 4678

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)*(x_)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[((d + e*x^2)^
(p + 1)*(a + b*ArcCos[c*x])^n)/(2*e*(p + 1)), x] - Dist[(b*n*d^IntPart[p]*(d + e*x^2)^FracPart[p])/(2*c*(p + 1
)*(1 - c^2*x^2)^FracPart[p]), Int[(1 - c^2*x^2)^(p + 1/2)*(a + b*ArcCos[c*x])^(n - 1), x], x] /; FreeQ[{a, b,
c, d, e, p}, x] && EqQ[c^2*d + e, 0] && GtQ[n, 0] && NeQ[p, -1]

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 4708

Int[(((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[
(f*(f*x)^(m - 1)*Sqrt[d + e*x^2]*(a + b*ArcCos[c*x])^n)/(e*m), x] + (Dist[(f^2*(m - 1))/(c^2*m), Int[((f*x)^(m
- 2)*(a + b*ArcCos[c*x])^n)/Sqrt[d + e*x^2], x], x] - Dist[(b*f*n*Sqrt[1 - c^2*x^2])/(c*m*Sqrt[d + e*x^2]), I
nt[(f*x)^(m - 1)*(a + b*ArcCos[c*x])^(n - 1), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[c^2*d + e, 0] &&
GtQ[n, 0] && GtQ[m, 1] && IntegerQ[m]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rubi steps

\begin{align*} \int \frac{(f+g x)^3 \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{d-c^2 d x^2}} \, dx &=\frac{\sqrt{1-c^2 x^2} \int \frac{(f+g x)^3 \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{1-c^2 x^2}} \, dx}{\sqrt{d-c^2 d x^2}}\\ &=\frac{\sqrt{1-c^2 x^2} \int \left (\frac{f^3 \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{1-c^2 x^2}}+\frac{3 f^2 g x \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{1-c^2 x^2}}+\frac{3 f g^2 x^2 \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{1-c^2 x^2}}+\frac{g^3 x^3 \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{1-c^2 x^2}}\right ) \, dx}{\sqrt{d-c^2 d x^2}}\\ &=\frac{\left (f^3 \sqrt{1-c^2 x^2}\right ) \int \frac{a+b \cos ^{-1}(c x)}{\sqrt{1-c^2 x^2}} \, dx}{\sqrt{d-c^2 d x^2}}+\frac{\left (3 f^2 g \sqrt{1-c^2 x^2}\right ) \int \frac{x \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{1-c^2 x^2}} \, dx}{\sqrt{d-c^2 d x^2}}+\frac{\left (3 f g^2 \sqrt{1-c^2 x^2}\right ) \int \frac{x^2 \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{1-c^2 x^2}} \, dx}{\sqrt{d-c^2 d x^2}}+\frac{\left (g^3 \sqrt{1-c^2 x^2}\right ) \int \frac{x^3 \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{1-c^2 x^2}} \, dx}{\sqrt{d-c^2 d x^2}}\\ &=-\frac{3 f^2 g \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{c^2 \sqrt{d-c^2 d x^2}}-\frac{3 f g^2 x \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{2 c^2 \sqrt{d-c^2 d x^2}}-\frac{g^3 x^2 \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{3 c^2 \sqrt{d-c^2 d x^2}}-\frac{f^3 \sqrt{1-c^2 x^2} \left (a+b \cos ^{-1}(c x)\right )^2}{2 b c \sqrt{d-c^2 d x^2}}-\frac{\left (3 b f^2 g \sqrt{1-c^2 x^2}\right ) \int 1 \, dx}{c \sqrt{d-c^2 d x^2}}+\frac{\left (3 f g^2 \sqrt{1-c^2 x^2}\right ) \int \frac{a+b \cos ^{-1}(c x)}{\sqrt{1-c^2 x^2}} \, dx}{2 c^2 \sqrt{d-c^2 d x^2}}-\frac{\left (3 b f g^2 \sqrt{1-c^2 x^2}\right ) \int x \, dx}{2 c \sqrt{d-c^2 d x^2}}+\frac{\left (2 g^3 \sqrt{1-c^2 x^2}\right ) \int \frac{x \left (a+b \cos ^{-1}(c x)\right )}{\sqrt{1-c^2 x^2}} \, dx}{3 c^2 \sqrt{d-c^2 d x^2}}-\frac{\left (b g^3 \sqrt{1-c^2 x^2}\right ) \int x^2 \, dx}{3 c \sqrt{d-c^2 d x^2}}\\ &=-\frac{3 b f^2 g x \sqrt{1-c^2 x^2}}{c \sqrt{d-c^2 d x^2}}-\frac{3 b f g^2 x^2 \sqrt{1-c^2 x^2}}{4 c \sqrt{d-c^2 d x^2}}-\frac{b g^3 x^3 \sqrt{1-c^2 x^2}}{9 c \sqrt{d-c^2 d x^2}}-\frac{3 f^2 g \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{c^2 \sqrt{d-c^2 d x^2}}-\frac{2 g^3 \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{3 c^4 \sqrt{d-c^2 d x^2}}-\frac{3 f g^2 x \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{2 c^2 \sqrt{d-c^2 d x^2}}-\frac{g^3 x^2 \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{3 c^2 \sqrt{d-c^2 d x^2}}-\frac{f^3 \sqrt{1-c^2 x^2} \left (a+b \cos ^{-1}(c x)\right )^2}{2 b c \sqrt{d-c^2 d x^2}}-\frac{3 f g^2 \sqrt{1-c^2 x^2} \left (a+b \cos ^{-1}(c x)\right )^2}{4 b c^3 \sqrt{d-c^2 d x^2}}-\frac{\left (2 b g^3 \sqrt{1-c^2 x^2}\right ) \int 1 \, dx}{3 c^3 \sqrt{d-c^2 d x^2}}\\ &=-\frac{3 b f^2 g x \sqrt{1-c^2 x^2}}{c \sqrt{d-c^2 d x^2}}-\frac{2 b g^3 x \sqrt{1-c^2 x^2}}{3 c^3 \sqrt{d-c^2 d x^2}}-\frac{3 b f g^2 x^2 \sqrt{1-c^2 x^2}}{4 c \sqrt{d-c^2 d x^2}}-\frac{b g^3 x^3 \sqrt{1-c^2 x^2}}{9 c \sqrt{d-c^2 d x^2}}-\frac{3 f^2 g \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{c^2 \sqrt{d-c^2 d x^2}}-\frac{2 g^3 \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{3 c^4 \sqrt{d-c^2 d x^2}}-\frac{3 f g^2 x \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{2 c^2 \sqrt{d-c^2 d x^2}}-\frac{g^3 x^2 \left (1-c^2 x^2\right ) \left (a+b \cos ^{-1}(c x)\right )}{3 c^2 \sqrt{d-c^2 d x^2}}-\frac{f^3 \sqrt{1-c^2 x^2} \left (a+b \cos ^{-1}(c x)\right )^2}{2 b c \sqrt{d-c^2 d x^2}}-\frac{3 f g^2 \sqrt{1-c^2 x^2} \left (a+b \cos ^{-1}(c x)\right )^2}{4 b c^3 \sqrt{d-c^2 d x^2}}\\ \end{align*}

Mathematica [A]  time = 1.18172, size = 342, normalized size = 0.76 \[ \frac{\sqrt{d} g \left (c^2 x^2-1\right ) \left (12 a \sqrt{1-c^2 x^2} \left (c^2 \left (18 f^2+9 f g x+2 g^2 x^2\right )+4 g^2\right )+8 b c x \left (c^2 \left (27 f^2+g^2 x^2\right )+6 g^2\right )+27 b c f g \cos \left (2 \cos ^{-1}(c x)\right )\right )-36 a c f \sqrt{1-c^2 x^2} \sqrt{d-c^2 d x^2} \left (2 c^2 f^2+3 g^2\right ) \tan ^{-1}\left (\frac{c x \sqrt{d-c^2 d x^2}}{\sqrt{d} \left (c^2 x^2-1\right )}\right )+18 b c \sqrt{d} f \left (c^2 x^2-1\right ) \left (2 c^2 f^2+3 g^2\right ) \cos ^{-1}(c x)^2+6 b \sqrt{d} g \left (c^2 x^2-1\right ) \cos ^{-1}(c x) \left (4 \sqrt{1-c^2 x^2} \left (c^2 \left (9 f^2+g^2 x^2\right )+2 g^2\right )+9 c f g \sin \left (2 \cos ^{-1}(c x)\right )\right )}{72 c^4 \sqrt{d} \sqrt{1-c^2 x^2} \sqrt{d-c^2 d x^2}} \]

Antiderivative was successfully verified.

[In]

Integrate[((f + g*x)^3*(a + b*ArcCos[c*x]))/Sqrt[d - c^2*d*x^2],x]

[Out]

(18*b*c*Sqrt[d]*f*(2*c^2*f^2 + 3*g^2)*(-1 + c^2*x^2)*ArcCos[c*x]^2 - 36*a*c*f*(2*c^2*f^2 + 3*g^2)*Sqrt[1 - c^2
*x^2]*Sqrt[d - c^2*d*x^2]*ArcTan[(c*x*Sqrt[d - c^2*d*x^2])/(Sqrt[d]*(-1 + c^2*x^2))] + Sqrt[d]*g*(-1 + c^2*x^2
)*(8*b*c*x*(6*g^2 + c^2*(27*f^2 + g^2*x^2)) + 12*a*Sqrt[1 - c^2*x^2]*(4*g^2 + c^2*(18*f^2 + 9*f*g*x + 2*g^2*x^
2)) + 27*b*c*f*g*Cos[2*ArcCos[c*x]]) + 6*b*Sqrt[d]*g*(-1 + c^2*x^2)*ArcCos[c*x]*(4*Sqrt[1 - c^2*x^2]*(2*g^2 +
c^2*(9*f^2 + g^2*x^2)) + 9*c*f*g*Sin[2*ArcCos[c*x]]))/(72*c^4*Sqrt[d]*Sqrt[1 - c^2*x^2]*Sqrt[d - c^2*d*x^2])

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Maple [B]  time = 0.605, size = 845, normalized size = 1.9 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((g*x+f)^3*(a+b*arccos(c*x))/(-c^2*d*x^2+d)^(1/2),x)

[Out]

-1/3*a*g^3*x^2/c^2/d*(-c^2*d*x^2+d)^(1/2)-2/3*a*g^3/d/c^4*(-c^2*d*x^2+d)^(1/2)-3/2*a*f*g^2*x/c^2/d*(-c^2*d*x^2
+d)^(1/2)+3/2*a*f*g^2/c^2/(c^2*d)^(1/2)*arctan((c^2*d)^(1/2)*x/(-c^2*d*x^2+d)^(1/2))-3*a*f^2*g/c^2/d*(-c^2*d*x
^2+d)^(1/2)+a*f^3/(c^2*d)^(1/2)*arctan((c^2*d)^(1/2)*x/(-c^2*d*x^2+d)^(1/2))+1/2*b*(-d*(c^2*x^2-1))^(1/2)*(-c^
2*x^2+1)^(1/2)/c/d/(c^2*x^2-1)*arccos(c*x)^2*f^3-1/3*b*(-d*(c^2*x^2-1))^(1/2)*g^3/d/(c^2*x^2-1)*arccos(c*x)*x^
4-1/3*b*(-d*(c^2*x^2-1))^(1/2)*g^3/c^2/d/(c^2*x^2-1)*arccos(c*x)*x^2+3*b*(-d*(c^2*x^2-1))^(1/2)*g/c^2/d/(c^2*x
^2-1)*arccos(c*x)*f^2+1/9*b*(-d*(c^2*x^2-1))^(1/2)*g^3/c/d/(c^2*x^2-1)*(-c^2*x^2+1)^(1/2)*x^3+2/3*b*(-d*(c^2*x
^2-1))^(1/2)*g^3/c^3/d/(c^2*x^2-1)*(-c^2*x^2+1)^(1/2)*x-3/2*b*(-d*(c^2*x^2-1))^(1/2)*f*g^2/d/(c^2*x^2-1)*arcco
s(c*x)*x^3+3/2*b*(-d*(c^2*x^2-1))^(1/2)*f*g^2/c^2/d/(c^2*x^2-1)*arccos(c*x)*x-3/8*b*(-d*(c^2*x^2-1))^(1/2)*f*g
^2/c^3/d/(c^2*x^2-1)*(-c^2*x^2+1)^(1/2)-3*b*(-d*(c^2*x^2-1))^(1/2)*g/d/(c^2*x^2-1)*arccos(c*x)*x^2*f^2+3/4*b*(
-d*(c^2*x^2-1))^(1/2)*(-c^2*x^2+1)^(1/2)/c^3/d/(c^2*x^2-1)*arccos(c*x)^2*f*g^2+3/4*b*(-d*(c^2*x^2-1))^(1/2)*f*
g^2/c/d/(c^2*x^2-1)*(-c^2*x^2+1)^(1/2)*x^2+3*b*(-d*(c^2*x^2-1))^(1/2)*g/c/d/(c^2*x^2-1)*(-c^2*x^2+1)^(1/2)*x*f
^2+2/3*b*(-d*(c^2*x^2-1))^(1/2)*g^3/c^4/d/(c^2*x^2-1)*arccos(c*x)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^3*(a+b*arccos(c*x))/(-c^2*d*x^2+d)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{{\left (a g^{3} x^{3} + 3 \, a f g^{2} x^{2} + 3 \, a f^{2} g x + a f^{3} +{\left (b g^{3} x^{3} + 3 \, b f g^{2} x^{2} + 3 \, b f^{2} g x + b f^{3}\right )} \arccos \left (c x\right )\right )} \sqrt{-c^{2} d x^{2} + d}}{c^{2} d x^{2} - d}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^3*(a+b*arccos(c*x))/(-c^2*d*x^2+d)^(1/2),x, algorithm="fricas")

[Out]

integral(-(a*g^3*x^3 + 3*a*f*g^2*x^2 + 3*a*f^2*g*x + a*f^3 + (b*g^3*x^3 + 3*b*f*g^2*x^2 + 3*b*f^2*g*x + b*f^3)
*arccos(c*x))*sqrt(-c^2*d*x^2 + d)/(c^2*d*x^2 - d), x)

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Sympy [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)**3*(a+b*acos(c*x))/(-c**2*d*x**2+d)**(1/2),x)

[Out]

Exception raised: TypeError

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (g x + f\right )}^{3}{\left (b \arccos \left (c x\right ) + a\right )}}{\sqrt{-c^{2} d x^{2} + d}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^3*(a+b*arccos(c*x))/(-c^2*d*x^2+d)^(1/2),x, algorithm="giac")

[Out]

integrate((g*x + f)^3*(b*arccos(c*x) + a)/sqrt(-c^2*d*x^2 + d), x)