3.245 \(\int (c e+d e x)^3 (a+b \sin ^{-1}(c+d x))^{3/2} \, dx\)

Optimal. Leaf size=380 \[ \frac{3 \sqrt{\pi } b^{3/2} e^3 \sin \left (\frac{2 a}{b}\right ) \text{FresnelC}\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{\pi } \sqrt{b}}\right )}{64 d}-\frac{3 \sqrt{\frac{\pi }{2}} b^{3/2} e^3 \sin \left (\frac{4 a}{b}\right ) \text{FresnelC}\left (\frac{2 \sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{512 d}+\frac{3 \sqrt{\frac{\pi }{2}} b^{3/2} e^3 \cos \left (\frac{4 a}{b}\right ) S\left (\frac{2 \sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{512 d}-\frac{3 \sqrt{\pi } b^{3/2} e^3 \cos \left (\frac{2 a}{b}\right ) S\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right )}{64 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{3 b e^3 \sqrt{1-(c+d x)^2} (c+d x)^3 \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}+\frac{9 b e^3 \sqrt{1-(c+d x)^2} (c+d x) \sqrt{a+b \sin ^{-1}(c+d x)}}{64 d}-\frac{3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d} \]

[Out]

(9*b*e^3*(c + d*x)*Sqrt[1 - (c + d*x)^2]*Sqrt[a + b*ArcSin[c + d*x]])/(64*d) + (3*b*e^3*(c + d*x)^3*Sqrt[1 - (
c + d*x)^2]*Sqrt[a + b*ArcSin[c + d*x]])/(32*d) - (3*e^3*(a + b*ArcSin[c + d*x])^(3/2))/(32*d) + (e^3*(c + d*x
)^4*(a + b*ArcSin[c + d*x])^(3/2))/(4*d) + (3*b^(3/2)*e^3*Sqrt[Pi/2]*Cos[(4*a)/b]*FresnelS[(2*Sqrt[2/Pi]*Sqrt[
a + b*ArcSin[c + d*x]])/Sqrt[b]])/(512*d) - (3*b^(3/2)*e^3*Sqrt[Pi]*Cos[(2*a)/b]*FresnelS[(2*Sqrt[a + b*ArcSin
[c + d*x]])/(Sqrt[b]*Sqrt[Pi])])/(64*d) + (3*b^(3/2)*e^3*Sqrt[Pi]*FresnelC[(2*Sqrt[a + b*ArcSin[c + d*x]])/(Sq
rt[b]*Sqrt[Pi])]*Sin[(2*a)/b])/(64*d) - (3*b^(3/2)*e^3*Sqrt[Pi/2]*FresnelC[(2*Sqrt[2/Pi]*Sqrt[a + b*ArcSin[c +
d*x]])/Sqrt[b]]*Sin[(4*a)/b])/(512*d)

________________________________________________________________________________________

Rubi [A]  time = 1.12443, antiderivative size = 380, normalized size of antiderivative = 1., number of steps used = 27, number of rules used = 12, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.48, Rules used = {4805, 12, 4629, 4707, 4641, 4635, 4406, 3306, 3305, 3351, 3304, 3352} \[ \frac{3 \sqrt{\pi } b^{3/2} e^3 \sin \left (\frac{2 a}{b}\right ) \text{FresnelC}\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{\pi } \sqrt{b}}\right )}{64 d}-\frac{3 \sqrt{\frac{\pi }{2}} b^{3/2} e^3 \sin \left (\frac{4 a}{b}\right ) \text{FresnelC}\left (\frac{2 \sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{512 d}+\frac{3 \sqrt{\frac{\pi }{2}} b^{3/2} e^3 \cos \left (\frac{4 a}{b}\right ) S\left (\frac{2 \sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{512 d}-\frac{3 \sqrt{\pi } b^{3/2} e^3 \cos \left (\frac{2 a}{b}\right ) S\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right )}{64 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{3 b e^3 \sqrt{1-(c+d x)^2} (c+d x)^3 \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}+\frac{9 b e^3 \sqrt{1-(c+d x)^2} (c+d x) \sqrt{a+b \sin ^{-1}(c+d x)}}{64 d}-\frac{3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d} \]

Antiderivative was successfully verified.

[In]

Int[(c*e + d*e*x)^3*(a + b*ArcSin[c + d*x])^(3/2),x]

[Out]

(9*b*e^3*(c + d*x)*Sqrt[1 - (c + d*x)^2]*Sqrt[a + b*ArcSin[c + d*x]])/(64*d) + (3*b*e^3*(c + d*x)^3*Sqrt[1 - (
c + d*x)^2]*Sqrt[a + b*ArcSin[c + d*x]])/(32*d) - (3*e^3*(a + b*ArcSin[c + d*x])^(3/2))/(32*d) + (e^3*(c + d*x
)^4*(a + b*ArcSin[c + d*x])^(3/2))/(4*d) + (3*b^(3/2)*e^3*Sqrt[Pi/2]*Cos[(4*a)/b]*FresnelS[(2*Sqrt[2/Pi]*Sqrt[
a + b*ArcSin[c + d*x]])/Sqrt[b]])/(512*d) - (3*b^(3/2)*e^3*Sqrt[Pi]*Cos[(2*a)/b]*FresnelS[(2*Sqrt[a + b*ArcSin
[c + d*x]])/(Sqrt[b]*Sqrt[Pi])])/(64*d) + (3*b^(3/2)*e^3*Sqrt[Pi]*FresnelC[(2*Sqrt[a + b*ArcSin[c + d*x]])/(Sq
rt[b]*Sqrt[Pi])]*Sin[(2*a)/b])/(64*d) - (3*b^(3/2)*e^3*Sqrt[Pi/2]*FresnelC[(2*Sqrt[2/Pi]*Sqrt[a + b*ArcSin[c +
d*x]])/Sqrt[b]]*Sin[(4*a)/b])/(512*d)

Rule 4805

Int[((a_.) + ArcSin[(c_) + (d_.)*(x_)]*(b_.))^(n_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Dist[1/d, Subst[I
nt[((d*e - c*f)/d + (f*x)/d)^m*(a + b*ArcSin[x])^n, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 4629

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(x^(m + 1)*(a + b*ArcSin[c*x])^n)/(m
+ 1), x] - Dist[(b*c*n)/(m + 1), Int[(x^(m + 1)*(a + b*ArcSin[c*x])^(n - 1))/Sqrt[1 - c^2*x^2], x], x] /; Fre
eQ[{a, b, c}, x] && IGtQ[m, 0] && GtQ[n, 0]

Rule 4707

Int[(((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[
(f*(f*x)^(m - 1)*Sqrt[d + e*x^2]*(a + b*ArcSin[c*x])^n)/(e*m), x] + (Dist[(f^2*(m - 1))/(c^2*m), Int[((f*x)^(m
- 2)*(a + b*ArcSin[c*x])^n)/Sqrt[d + e*x^2], x], x] + Dist[(b*f*n*Sqrt[1 - c^2*x^2])/(c*m*Sqrt[d + e*x^2]), I
nt[(f*x)^(m - 1)*(a + b*ArcSin[c*x])^(n - 1), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[c^2*d + e, 0] &&
GtQ[n, 0] && GtQ[m, 1] && IntegerQ[m]

Rule 4641

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(a + b*ArcSin[c*x])^
(n + 1)/(b*c*Sqrt[d]*(n + 1)), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && GtQ[d, 0] && NeQ[n,
-1]

Rule 4635

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Dist[1/c^(m + 1), Subst[Int[(a + b*x)^n*S
in[x]^m*Cos[x], x], x, ArcSin[c*x]], x] /; FreeQ[{a, b, c, n}, x] && IGtQ[m, 0]

Rule 4406

Int[Cos[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sin[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int[E
xpandTrigReduce[(c + d*x)^m, Sin[a + b*x]^n*Cos[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0]
&& IGtQ[p, 0]

Rule 3306

Int[sin[(e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[Cos[(d*e - c*f)/d], Int[Sin[(c*f)/d +
f*x]/Sqrt[c + d*x], x], x] + Dist[Sin[(d*e - c*f)/d], Int[Cos[(c*f)/d + f*x]/Sqrt[c + d*x], x], x] /; FreeQ[{c
, d, e, f}, x] && ComplexFreeQ[f] && NeQ[d*e - c*f, 0]

Rule 3305

Int[sin[(e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[Sin[(f*x^2)/d], x], x,
Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]

Rule 3351

Int[Sin[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelS[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rule 3304

Int[sin[Pi/2 + (e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[Cos[(f*x^2)/d],
x], x, Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]

Rule 3352

Int[Cos[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelC[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rubi steps

\begin{align*} \int (c e+d e x)^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2} \, dx &=\frac{\operatorname{Subst}\left (\int e^3 x^3 \left (a+b \sin ^{-1}(x)\right )^{3/2} \, dx,x,c+d x\right )}{d}\\ &=\frac{e^3 \operatorname{Subst}\left (\int x^3 \left (a+b \sin ^{-1}(x)\right )^{3/2} \, dx,x,c+d x\right )}{d}\\ &=\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}-\frac{\left (3 b e^3\right ) \operatorname{Subst}\left (\int \frac{x^4 \sqrt{a+b \sin ^{-1}(x)}}{\sqrt{1-x^2}} \, dx,x,c+d x\right )}{8 d}\\ &=\frac{3 b e^3 (c+d x)^3 \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}-\frac{\left (9 b e^3\right ) \operatorname{Subst}\left (\int \frac{x^2 \sqrt{a+b \sin ^{-1}(x)}}{\sqrt{1-x^2}} \, dx,x,c+d x\right )}{32 d}-\frac{\left (3 b^2 e^3\right ) \operatorname{Subst}\left (\int \frac{x^3}{\sqrt{a+b \sin ^{-1}(x)}} \, dx,x,c+d x\right )}{64 d}\\ &=\frac{9 b e^3 (c+d x) \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{64 d}+\frac{3 b e^3 (c+d x)^3 \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}-\frac{\left (9 b e^3\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a+b \sin ^{-1}(x)}}{\sqrt{1-x^2}} \, dx,x,c+d x\right )}{64 d}-\frac{\left (3 b^2 e^3\right ) \operatorname{Subst}\left (\int \frac{\cos (x) \sin ^3(x)}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{64 d}-\frac{\left (9 b^2 e^3\right ) \operatorname{Subst}\left (\int \frac{x}{\sqrt{a+b \sin ^{-1}(x)}} \, dx,x,c+d x\right )}{128 d}\\ &=\frac{9 b e^3 (c+d x) \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{64 d}+\frac{3 b e^3 (c+d x)^3 \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}-\frac{3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}-\frac{\left (3 b^2 e^3\right ) \operatorname{Subst}\left (\int \left (\frac{\sin (2 x)}{4 \sqrt{a+b x}}-\frac{\sin (4 x)}{8 \sqrt{a+b x}}\right ) \, dx,x,\sin ^{-1}(c+d x)\right )}{64 d}-\frac{\left (9 b^2 e^3\right ) \operatorname{Subst}\left (\int \frac{\cos (x) \sin (x)}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{128 d}\\ &=\frac{9 b e^3 (c+d x) \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{64 d}+\frac{3 b e^3 (c+d x)^3 \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}-\frac{3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{\left (3 b^2 e^3\right ) \operatorname{Subst}\left (\int \frac{\sin (4 x)}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{512 d}-\frac{\left (3 b^2 e^3\right ) \operatorname{Subst}\left (\int \frac{\sin (2 x)}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{256 d}-\frac{\left (9 b^2 e^3\right ) \operatorname{Subst}\left (\int \frac{\sin (2 x)}{2 \sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{128 d}\\ &=\frac{9 b e^3 (c+d x) \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{64 d}+\frac{3 b e^3 (c+d x)^3 \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}-\frac{3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}-\frac{\left (9 b^2 e^3\right ) \operatorname{Subst}\left (\int \frac{\sin (2 x)}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{256 d}-\frac{\left (3 b^2 e^3 \cos \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sin \left (\frac{2 a}{b}+2 x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{256 d}+\frac{\left (3 b^2 e^3 \cos \left (\frac{4 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sin \left (\frac{4 a}{b}+4 x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{512 d}+\frac{\left (3 b^2 e^3 \sin \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cos \left (\frac{2 a}{b}+2 x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{256 d}-\frac{\left (3 b^2 e^3 \sin \left (\frac{4 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cos \left (\frac{4 a}{b}+4 x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{512 d}\\ &=\frac{9 b e^3 (c+d x) \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{64 d}+\frac{3 b e^3 (c+d x)^3 \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}-\frac{3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}-\frac{\left (3 b e^3 \cos \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \sin \left (\frac{2 x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{128 d}-\frac{\left (9 b^2 e^3 \cos \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sin \left (\frac{2 a}{b}+2 x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{256 d}+\frac{\left (3 b e^3 \cos \left (\frac{4 a}{b}\right )\right ) \operatorname{Subst}\left (\int \sin \left (\frac{4 x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{256 d}+\frac{\left (3 b e^3 \sin \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \cos \left (\frac{2 x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{128 d}+\frac{\left (9 b^2 e^3 \sin \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cos \left (\frac{2 a}{b}+2 x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{256 d}-\frac{\left (3 b e^3 \sin \left (\frac{4 a}{b}\right )\right ) \operatorname{Subst}\left (\int \cos \left (\frac{4 x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{256 d}\\ &=\frac{9 b e^3 (c+d x) \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{64 d}+\frac{3 b e^3 (c+d x)^3 \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}-\frac{3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{3 b^{3/2} e^3 \sqrt{\frac{\pi }{2}} \cos \left (\frac{4 a}{b}\right ) S\left (\frac{2 \sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{512 d}-\frac{3 b^{3/2} e^3 \sqrt{\pi } \cos \left (\frac{2 a}{b}\right ) S\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right )}{256 d}+\frac{3 b^{3/2} e^3 \sqrt{\pi } C\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right ) \sin \left (\frac{2 a}{b}\right )}{256 d}-\frac{3 b^{3/2} e^3 \sqrt{\frac{\pi }{2}} C\left (\frac{2 \sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right ) \sin \left (\frac{4 a}{b}\right )}{512 d}-\frac{\left (9 b e^3 \cos \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \sin \left (\frac{2 x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{128 d}+\frac{\left (9 b e^3 \sin \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \cos \left (\frac{2 x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{128 d}\\ &=\frac{9 b e^3 (c+d x) \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{64 d}+\frac{3 b e^3 (c+d x)^3 \sqrt{1-(c+d x)^2} \sqrt{a+b \sin ^{-1}(c+d x)}}{32 d}-\frac{3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac{e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{4 d}+\frac{3 b^{3/2} e^3 \sqrt{\frac{\pi }{2}} \cos \left (\frac{4 a}{b}\right ) S\left (\frac{2 \sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{512 d}-\frac{3 b^{3/2} e^3 \sqrt{\pi } \cos \left (\frac{2 a}{b}\right ) S\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right )}{64 d}+\frac{3 b^{3/2} e^3 \sqrt{\pi } C\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right ) \sin \left (\frac{2 a}{b}\right )}{64 d}-\frac{3 b^{3/2} e^3 \sqrt{\frac{\pi }{2}} C\left (\frac{2 \sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right ) \sin \left (\frac{4 a}{b}\right )}{512 d}\\ \end{align*}

Mathematica [C]  time = 0.186122, size = 273, normalized size = 0.72 \[ -\frac{i b e^3 e^{-\frac{4 i a}{b}} \sqrt{a+b \sin ^{-1}(c+d x)} \left (8 \sqrt{2} e^{\frac{2 i a}{b}} \sqrt{\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \text{Gamma}\left (\frac{5}{2},-\frac{2 i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )-8 \sqrt{2} e^{\frac{6 i a}{b}} \sqrt{-\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \text{Gamma}\left (\frac{5}{2},\frac{2 i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )-\sqrt{\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \text{Gamma}\left (\frac{5}{2},-\frac{4 i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )+e^{\frac{8 i a}{b}} \sqrt{-\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \text{Gamma}\left (\frac{5}{2},\frac{4 i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )\right )}{512 d \sqrt{\frac{\left (a+b \sin ^{-1}(c+d x)\right )^2}{b^2}}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(c*e + d*e*x)^3*(a + b*ArcSin[c + d*x])^(3/2),x]

[Out]

((-I/512)*b*e^3*Sqrt[a + b*ArcSin[c + d*x]]*(8*Sqrt[2]*E^(((2*I)*a)/b)*Sqrt[(I*(a + b*ArcSin[c + d*x]))/b]*Gam
ma[5/2, ((-2*I)*(a + b*ArcSin[c + d*x]))/b] - 8*Sqrt[2]*E^(((6*I)*a)/b)*Sqrt[((-I)*(a + b*ArcSin[c + d*x]))/b]
*Gamma[5/2, ((2*I)*(a + b*ArcSin[c + d*x]))/b] - Sqrt[(I*(a + b*ArcSin[c + d*x]))/b]*Gamma[5/2, ((-4*I)*(a + b
*ArcSin[c + d*x]))/b] + E^(((8*I)*a)/b)*Sqrt[((-I)*(a + b*ArcSin[c + d*x]))/b]*Gamma[5/2, ((4*I)*(a + b*ArcSin
[c + d*x]))/b]))/(d*E^(((4*I)*a)/b)*Sqrt[(a + b*ArcSin[c + d*x])^2/b^2])

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Maple [A]  time = 0.12, size = 582, normalized size = 1.5 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*e*x+c*e)^3*(a+b*arcsin(d*x+c))^(3/2),x)

[Out]

1/1024/d*e^3*(3*2^(1/2)*(a+b*arcsin(d*x+c))^(1/2)*cos(4*a/b)*FresnelS(2*2^(1/2)/Pi^(1/2)/(1/b)^(1/2)*(a+b*arcs
in(d*x+c))^(1/2)/b)*(1/b)^(1/2)*Pi^(1/2)*b^2-3*2^(1/2)*(a+b*arcsin(d*x+c))^(1/2)*sin(4*a/b)*FresnelC(2*2^(1/2)
/Pi^(1/2)/(1/b)^(1/2)*(a+b*arcsin(d*x+c))^(1/2)/b)*(1/b)^(1/2)*Pi^(1/2)*b^2-48*(1/b)^(1/2)*Pi^(1/2)*(a+b*arcsi
n(d*x+c))^(1/2)*cos(2*a/b)*FresnelS(2/Pi^(1/2)/(1/b)^(1/2)*(a+b*arcsin(d*x+c))^(1/2)/b)*b^2+48*(1/b)^(1/2)*Pi^
(1/2)*(a+b*arcsin(d*x+c))^(1/2)*sin(2*a/b)*FresnelC(2/Pi^(1/2)/(1/b)^(1/2)*(a+b*arcsin(d*x+c))^(1/2)/b)*b^2+32
*arcsin(d*x+c)^2*cos(4*(a+b*arcsin(d*x+c))/b-4*a/b)*b^2-128*arcsin(d*x+c)^2*cos(2*(a+b*arcsin(d*x+c))/b-2*a/b)
*b^2+64*arcsin(d*x+c)*cos(4*(a+b*arcsin(d*x+c))/b-4*a/b)*a*b-12*arcsin(d*x+c)*sin(4*(a+b*arcsin(d*x+c))/b-4*a/
b)*b^2-256*arcsin(d*x+c)*cos(2*(a+b*arcsin(d*x+c))/b-2*a/b)*a*b+96*arcsin(d*x+c)*sin(2*(a+b*arcsin(d*x+c))/b-2
*a/b)*b^2+32*cos(4*(a+b*arcsin(d*x+c))/b-4*a/b)*a^2-12*sin(4*(a+b*arcsin(d*x+c))/b-4*a/b)*a*b-128*cos(2*(a+b*a
rcsin(d*x+c))/b-2*a/b)*a^2+96*sin(2*(a+b*arcsin(d*x+c))/b-2*a/b)*a*b)/(a+b*arcsin(d*x+c))^(1/2)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d e x + c e\right )}^{3}{\left (b \arcsin \left (d x + c\right ) + a\right )}^{\frac{3}{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)^3*(a+b*arcsin(d*x+c))^(3/2),x, algorithm="maxima")

[Out]

integrate((d*e*x + c*e)^3*(b*arcsin(d*x + c) + a)^(3/2), x)

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Fricas [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)^3*(a+b*arcsin(d*x+c))^(3/2),x, algorithm="fricas")

[Out]

Exception raised: UnboundLocalError

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)**3*(a+b*asin(d*x+c))**(3/2),x)

[Out]

Timed out

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Giac [B]  time = 2.27437, size = 1890, normalized size = 4.97 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)^3*(a+b*arcsin(d*x+c))^(3/2),x, algorithm="giac")

[Out]

-3/1024*sqrt(pi)*b^4*i*erf(sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x +
c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/((sqrt(2)*b^(7/2)*i/abs(b) - sqrt(2)*b^(5/2))*d) - 3/1024*sqrt(pi)*b^(7/2)*i
*erf(-sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4
*a*i/b + 3)/((sqrt(2)*b^3*i/abs(b) + sqrt(2)*b^2)*d) + 3/128*sqrt(pi)*b^(7/2)*i*erf(-sqrt(b*arcsin(d*x + c) +
a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(2*a*i/b + 3)/((b^3*i/abs(b) + b^2)*d) + 3/128*sq
rt(pi)*b^(7/2)*i*erf(sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-2
*a*i/b + 3)/((b^3*i/abs(b) - b^2)*d) - 1/128*sqrt(pi)*a*b^3*erf(-sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i
/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4*a*i/b + 3)/((sqrt(2)*b^(7/2)*i/abs(b) + sqrt(2)*b^
(5/2))*d) + 1/128*sqrt(pi)*a*b^3*erf(sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arc
sin(d*x + c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/((sqrt(2)*b^(7/2)*i/abs(b) - sqrt(2)*b^(5/2))*d) + 1/32*sqrt(pi)*a
*b^(5/2)*erf(-sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(2*a*i/b +
3)/((b^3*i/abs(b) + b^2)*d) - 1/32*sqrt(pi)*a*b^(5/2)*erf(sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt
(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-2*a*i/b + 3)/((b^3*i/abs(b) - b^2)*d) - 1/128*sqrt(pi)*a*b^2*erf(sqrt(2)*
sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/(
(sqrt(2)*b^(5/2)*i/abs(b) - sqrt(2)*b^(3/2))*d) + 1/128*sqrt(pi)*a*b^(3/2)*erf(-sqrt(2)*sqrt(b*arcsin(d*x + c)
+ a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4*a*i/b + 3)/((sqrt(2)*b^2*i/abs(b) +
sqrt(2)*b)*d) - 1/32*sqrt(pi)*a*b^(3/2)*erf(-sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x
+ c) + a)/sqrt(b))*e^(2*a*i/b + 3)/((b^2*i/abs(b) + b)*d) + 1/32*sqrt(pi)*a*b^(3/2)*erf(sqrt(b*arcsin(d*x + c
) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-2*a*i/b + 3)/((b^2*i/abs(b) - b)*d) + 3/512
*sqrt(b*arcsin(d*x + c) + a)*b*i*e^(4*i*arcsin(d*x + c) + 3)/d + 1/64*sqrt(b*arcsin(d*x + c) + a)*b*arcsin(d*x
+ c)*e^(4*i*arcsin(d*x + c) + 3)/d - 3/64*sqrt(b*arcsin(d*x + c) + a)*b*i*e^(2*i*arcsin(d*x + c) + 3)/d - 1/1
6*sqrt(b*arcsin(d*x + c) + a)*b*arcsin(d*x + c)*e^(2*i*arcsin(d*x + c) + 3)/d + 3/64*sqrt(b*arcsin(d*x + c) +
a)*b*i*e^(-2*i*arcsin(d*x + c) + 3)/d - 1/16*sqrt(b*arcsin(d*x + c) + a)*b*arcsin(d*x + c)*e^(-2*i*arcsin(d*x
+ c) + 3)/d - 3/512*sqrt(b*arcsin(d*x + c) + a)*b*i*e^(-4*i*arcsin(d*x + c) + 3)/d + 1/64*sqrt(b*arcsin(d*x +
c) + a)*b*arcsin(d*x + c)*e^(-4*i*arcsin(d*x + c) + 3)/d + 1/64*sqrt(b*arcsin(d*x + c) + a)*a*e^(4*i*arcsin(d*
x + c) + 3)/d - 1/16*sqrt(b*arcsin(d*x + c) + a)*a*e^(2*i*arcsin(d*x + c) + 3)/d - 1/16*sqrt(b*arcsin(d*x + c)
+ a)*a*e^(-2*i*arcsin(d*x + c) + 3)/d + 1/64*sqrt(b*arcsin(d*x + c) + a)*a*e^(-4*i*arcsin(d*x + c) + 3)/d