Optimal. Leaf size=191 \[ \frac{\cos \left (\frac{a}{b}\right ) \text{CosIntegral}\left (\frac{a+b \sin ^{-1}(c+d x)}{b}\right )}{24 b^5 d}+\frac{\sin \left (\frac{a}{b}\right ) \text{Si}\left (\frac{a+b \sin ^{-1}(c+d x)}{b}\right )}{24 b^5 d}-\frac{c+d x}{24 b^4 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac{c+d x}{12 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^3}+\frac{\sqrt{1-(c+d x)^2}}{24 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac{\sqrt{1-(c+d x)^2}}{4 b d \left (a+b \sin ^{-1}(c+d x)\right )^4} \]
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Rubi [A] time = 0.281997, antiderivative size = 191, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.583, Rules used = {4803, 4621, 4719, 4623, 3303, 3299, 3302} \[ \frac{\cos \left (\frac{a}{b}\right ) \text{CosIntegral}\left (\frac{a+b \sin ^{-1}(c+d x)}{b}\right )}{24 b^5 d}+\frac{\sin \left (\frac{a}{b}\right ) \text{Si}\left (\frac{a+b \sin ^{-1}(c+d x)}{b}\right )}{24 b^5 d}-\frac{c+d x}{24 b^4 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac{c+d x}{12 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^3}+\frac{\sqrt{1-(c+d x)^2}}{24 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac{\sqrt{1-(c+d x)^2}}{4 b d \left (a+b \sin ^{-1}(c+d x)\right )^4} \]
Antiderivative was successfully verified.
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Rule 4803
Rule 4621
Rule 4719
Rule 4623
Rule 3303
Rule 3299
Rule 3302
Rubi steps
\begin{align*} \int \frac{1}{\left (a+b \sin ^{-1}(c+d x)\right )^5} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{1}{\left (a+b \sin ^{-1}(x)\right )^5} \, dx,x,c+d x\right )}{d}\\ &=-\frac{\sqrt{1-(c+d x)^2}}{4 b d \left (a+b \sin ^{-1}(c+d x)\right )^4}-\frac{\operatorname{Subst}\left (\int \frac{x}{\sqrt{1-x^2} \left (a+b \sin ^{-1}(x)\right )^4} \, dx,x,c+d x\right )}{4 b d}\\ &=-\frac{\sqrt{1-(c+d x)^2}}{4 b d \left (a+b \sin ^{-1}(c+d x)\right )^4}+\frac{c+d x}{12 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^3}-\frac{\operatorname{Subst}\left (\int \frac{1}{\left (a+b \sin ^{-1}(x)\right )^3} \, dx,x,c+d x\right )}{12 b^2 d}\\ &=-\frac{\sqrt{1-(c+d x)^2}}{4 b d \left (a+b \sin ^{-1}(c+d x)\right )^4}+\frac{c+d x}{12 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^3}+\frac{\sqrt{1-(c+d x)^2}}{24 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )^2}+\frac{\operatorname{Subst}\left (\int \frac{x}{\sqrt{1-x^2} \left (a+b \sin ^{-1}(x)\right )^2} \, dx,x,c+d x\right )}{24 b^3 d}\\ &=-\frac{\sqrt{1-(c+d x)^2}}{4 b d \left (a+b \sin ^{-1}(c+d x)\right )^4}+\frac{c+d x}{12 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^3}+\frac{\sqrt{1-(c+d x)^2}}{24 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac{c+d x}{24 b^4 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac{\operatorname{Subst}\left (\int \frac{1}{a+b \sin ^{-1}(x)} \, dx,x,c+d x\right )}{24 b^4 d}\\ &=-\frac{\sqrt{1-(c+d x)^2}}{4 b d \left (a+b \sin ^{-1}(c+d x)\right )^4}+\frac{c+d x}{12 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^3}+\frac{\sqrt{1-(c+d x)^2}}{24 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac{c+d x}{24 b^4 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac{\operatorname{Subst}\left (\int \frac{\cos \left (\frac{a}{b}-\frac{x}{b}\right )}{x} \, dx,x,a+b \sin ^{-1}(c+d x)\right )}{24 b^5 d}\\ &=-\frac{\sqrt{1-(c+d x)^2}}{4 b d \left (a+b \sin ^{-1}(c+d x)\right )^4}+\frac{c+d x}{12 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^3}+\frac{\sqrt{1-(c+d x)^2}}{24 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac{c+d x}{24 b^4 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac{\cos \left (\frac{a}{b}\right ) \operatorname{Subst}\left (\int \frac{\cos \left (\frac{x}{b}\right )}{x} \, dx,x,a+b \sin ^{-1}(c+d x)\right )}{24 b^5 d}+\frac{\sin \left (\frac{a}{b}\right ) \operatorname{Subst}\left (\int \frac{\sin \left (\frac{x}{b}\right )}{x} \, dx,x,a+b \sin ^{-1}(c+d x)\right )}{24 b^5 d}\\ &=-\frac{\sqrt{1-(c+d x)^2}}{4 b d \left (a+b \sin ^{-1}(c+d x)\right )^4}+\frac{c+d x}{12 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^3}+\frac{\sqrt{1-(c+d x)^2}}{24 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac{c+d x}{24 b^4 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac{\cos \left (\frac{a}{b}\right ) \text{Ci}\left (\frac{a+b \sin ^{-1}(c+d x)}{b}\right )}{24 b^5 d}+\frac{\sin \left (\frac{a}{b}\right ) \text{Si}\left (\frac{a+b \sin ^{-1}(c+d x)}{b}\right )}{24 b^5 d}\\ \end{align*}
Mathematica [A] time = 0.413517, size = 156, normalized size = 0.82 \[ \frac{-\frac{6 b^4 \sqrt{1-(c+d x)^2}}{\left (a+b \sin ^{-1}(c+d x)\right )^4}+\frac{2 b^3 (c+d x)}{\left (a+b \sin ^{-1}(c+d x)\right )^3}+\frac{b^2 \sqrt{1-(c+d x)^2}}{\left (a+b \sin ^{-1}(c+d x)\right )^2}+\cos \left (\frac{a}{b}\right ) \text{CosIntegral}\left (\frac{a}{b}+\sin ^{-1}(c+d x)\right )+\sin \left (\frac{a}{b}\right ) \text{Si}\left (\frac{a}{b}+\sin ^{-1}(c+d x)\right )-\frac{b (c+d x)}{a+b \sin ^{-1}(c+d x)}}{24 b^5 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.075, size = 387, normalized size = 2. \begin{align*}{\frac{1}{d} \left ( -{\frac{1}{4\, \left ( a+b\arcsin \left ( dx+c \right ) \right ) ^{4}b}\sqrt{1- \left ( dx+c \right ) ^{2}}}+{\frac{1}{24\, \left ( a+b\arcsin \left ( dx+c \right ) \right ) ^{3}{b}^{5}} \left ( \left ( \arcsin \left ( dx+c \right ) \right ) ^{3}{\it Si} \left ( \arcsin \left ( dx+c \right ) +{\frac{a}{b}} \right ) \sin \left ({\frac{a}{b}} \right ){b}^{3}+ \left ( \arcsin \left ( dx+c \right ) \right ) ^{3}{\it Ci} \left ( \arcsin \left ( dx+c \right ) +{\frac{a}{b}} \right ) \cos \left ({\frac{a}{b}} \right ){b}^{3}+3\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{2}{\it Si} \left ( \arcsin \left ( dx+c \right ) +{\frac{a}{b}} \right ) \sin \left ({\frac{a}{b}} \right ) a{b}^{2}+3\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{2}{\it Ci} \left ( \arcsin \left ( dx+c \right ) +{\frac{a}{b}} \right ) \cos \left ({\frac{a}{b}} \right ) a{b}^{2}- \left ( \arcsin \left ( dx+c \right ) \right ) ^{2} \left ( dx+c \right ){b}^{3}+3\,\arcsin \left ( dx+c \right ){\it Si} \left ( \arcsin \left ( dx+c \right ) +{\frac{a}{b}} \right ) \sin \left ({\frac{a}{b}} \right ){a}^{2}b+3\,\arcsin \left ( dx+c \right ){\it Ci} \left ( \arcsin \left ( dx+c \right ) +{\frac{a}{b}} \right ) \cos \left ({\frac{a}{b}} \right ){a}^{2}b+\sqrt{1- \left ( dx+c \right ) ^{2}}\arcsin \left ( dx+c \right ){b}^{3}-2\,\arcsin \left ( dx+c \right ) \left ( dx+c \right ) a{b}^{2}+{\it Si} \left ( \arcsin \left ( dx+c \right ) +{\frac{a}{b}} \right ) \sin \left ({\frac{a}{b}} \right ){a}^{3}+{\it Ci} \left ( \arcsin \left ( dx+c \right ) +{\frac{a}{b}} \right ) \cos \left ({\frac{a}{b}} \right ){a}^{3}+\sqrt{1- \left ( dx+c \right ) ^{2}}a{b}^{2}- \left ( dx+c \right ){a}^{2}b+2\, \left ( dx+c \right ){b}^{3} \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{1}{b^{5} \arcsin \left (d x + c\right )^{5} + 5 \, a b^{4} \arcsin \left (d x + c\right )^{4} + 10 \, a^{2} b^{3} \arcsin \left (d x + c\right )^{3} + 10 \, a^{3} b^{2} \arcsin \left (d x + c\right )^{2} + 5 \, a^{4} b \arcsin \left (d x + c\right ) + a^{5}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.26283, size = 2585, normalized size = 13.53 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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