Optimal. Leaf size=198 \[ -\frac{3 b^3 e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )}{2 d}-\frac{3 b^2 e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d}+\frac{3 b^2 e \left (a+b \sin ^{-1}(c+d x)\right )^2}{4 d}+\frac{b e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^3}{d}+\frac{e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^4}{2 d}-\frac{e \left (a+b \sin ^{-1}(c+d x)\right )^4}{4 d}+\frac{3 b^4 e (c+d x)^2}{4 d} \]
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Rubi [A] time = 0.305862, antiderivative size = 198, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 6, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {4805, 12, 4627, 4707, 4641, 30} \[ -\frac{3 b^3 e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )}{2 d}-\frac{3 b^2 e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d}+\frac{3 b^2 e \left (a+b \sin ^{-1}(c+d x)\right )^2}{4 d}+\frac{b e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^3}{d}+\frac{e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^4}{2 d}-\frac{e \left (a+b \sin ^{-1}(c+d x)\right )^4}{4 d}+\frac{3 b^4 e (c+d x)^2}{4 d} \]
Antiderivative was successfully verified.
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Rule 4805
Rule 12
Rule 4627
Rule 4707
Rule 4641
Rule 30
Rubi steps
\begin{align*} \int (c e+d e x) \left (a+b \sin ^{-1}(c+d x)\right )^4 \, dx &=\frac{\operatorname{Subst}\left (\int e x \left (a+b \sin ^{-1}(x)\right )^4 \, dx,x,c+d x\right )}{d}\\ &=\frac{e \operatorname{Subst}\left (\int x \left (a+b \sin ^{-1}(x)\right )^4 \, dx,x,c+d x\right )}{d}\\ &=\frac{e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^4}{2 d}-\frac{(2 b e) \operatorname{Subst}\left (\int \frac{x^2 \left (a+b \sin ^{-1}(x)\right )^3}{\sqrt{1-x^2}} \, dx,x,c+d x\right )}{d}\\ &=\frac{b e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^3}{d}+\frac{e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^4}{2 d}-\frac{(b e) \operatorname{Subst}\left (\int \frac{\left (a+b \sin ^{-1}(x)\right )^3}{\sqrt{1-x^2}} \, dx,x,c+d x\right )}{d}-\frac{\left (3 b^2 e\right ) \operatorname{Subst}\left (\int x \left (a+b \sin ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{d}\\ &=-\frac{3 b^2 e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d}+\frac{b e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^3}{d}-\frac{e \left (a+b \sin ^{-1}(c+d x)\right )^4}{4 d}+\frac{e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^4}{2 d}+\frac{\left (3 b^3 e\right ) \operatorname{Subst}\left (\int \frac{x^2 \left (a+b \sin ^{-1}(x)\right )}{\sqrt{1-x^2}} \, dx,x,c+d x\right )}{d}\\ &=-\frac{3 b^3 e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )}{2 d}-\frac{3 b^2 e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d}+\frac{b e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^3}{d}-\frac{e \left (a+b \sin ^{-1}(c+d x)\right )^4}{4 d}+\frac{e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^4}{2 d}+\frac{\left (3 b^3 e\right ) \operatorname{Subst}\left (\int \frac{a+b \sin ^{-1}(x)}{\sqrt{1-x^2}} \, dx,x,c+d x\right )}{2 d}+\frac{\left (3 b^4 e\right ) \operatorname{Subst}(\int x \, dx,x,c+d x)}{2 d}\\ &=\frac{3 b^4 e (c+d x)^2}{4 d}-\frac{3 b^3 e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )}{2 d}+\frac{3 b^2 e \left (a+b \sin ^{-1}(c+d x)\right )^2}{4 d}-\frac{3 b^2 e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d}+\frac{b e (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^3}{d}-\frac{e \left (a+b \sin ^{-1}(c+d x)\right )^4}{4 d}+\frac{e (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^4}{2 d}\\ \end{align*}
Mathematica [A] time = 0.263336, size = 163, normalized size = 0.82 \[ -\frac{e \left (3 b^2 \left (2 (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^2+2 b \sqrt{1-(c+d x)^2} (c+d x) \left (a+b \sin ^{-1}(c+d x)\right )-\left (a+b \sin ^{-1}(c+d x)\right )^2-b^2 (c+d x)^2\right )-2 (c+d x)^2 \left (a+b \sin ^{-1}(c+d x)\right )^4+\left (a+b \sin ^{-1}(c+d x)\right )^4-4 b (c+d x) \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^3\right )}{4 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.04, size = 412, normalized size = 2.1 \begin{align*}{\frac{1}{d} \left ({\frac{e \left ( dx+c \right ) ^{2}{a}^{4}}{2}}+e{b}^{4} \left ({\frac{ \left ( \left ( dx+c \right ) ^{2}-1 \right ) \left ( \arcsin \left ( dx+c \right ) \right ) ^{4}}{2}}+ \left ( \arcsin \left ( dx+c \right ) \right ) ^{3} \left ( \left ( dx+c \right ) \sqrt{1- \left ( dx+c \right ) ^{2}}+\arcsin \left ( dx+c \right ) \right ) -{\frac{3\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{2} \left ( \left ( dx+c \right ) ^{2}-1 \right ) }{2}}-{\frac{3\,\arcsin \left ( dx+c \right ) }{2} \left ( \left ( dx+c \right ) \sqrt{1- \left ( dx+c \right ) ^{2}}+\arcsin \left ( dx+c \right ) \right ) }+{\frac{3\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{2}}{4}}+{\frac{3\, \left ( dx+c \right ) ^{2}}{4}}-{\frac{3\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{4}}{4}} \right ) +4\,ea{b}^{3} \left ( 1/2\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{3} \left ( \left ( dx+c \right ) ^{2}-1 \right ) +3/4\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{2} \left ( \left ( dx+c \right ) \sqrt{1- \left ( dx+c \right ) ^{2}}+\arcsin \left ( dx+c \right ) \right ) -3/4\,\arcsin \left ( dx+c \right ) \left ( \left ( dx+c \right ) ^{2}-1 \right ) -3/8\, \left ( dx+c \right ) \sqrt{1- \left ( dx+c \right ) ^{2}}-3/8\,\arcsin \left ( dx+c \right ) -1/2\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{3} \right ) +6\,e{a}^{2}{b}^{2} \left ( 1/2\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{2} \left ( \left ( dx+c \right ) ^{2}-1 \right ) +1/2\,\arcsin \left ( dx+c \right ) \left ( \left ( dx+c \right ) \sqrt{1- \left ( dx+c \right ) ^{2}}+\arcsin \left ( dx+c \right ) \right ) -1/4\, \left ( \arcsin \left ( dx+c \right ) \right ) ^{2}-1/4\, \left ( dx+c \right ) ^{2} \right ) +4\,e{a}^{3}b \left ( 1/2\,\arcsin \left ( dx+c \right ) \left ( dx+c \right ) ^{2}+1/4\, \left ( dx+c \right ) \sqrt{1- \left ( dx+c \right ) ^{2}}-1/4\,\arcsin \left ( dx+c \right ) \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.58579, size = 1045, normalized size = 5.28 \begin{align*} \frac{{\left (2 \, a^{4} - 6 \, a^{2} b^{2} + 3 \, b^{4}\right )} d^{2} e x^{2} + 2 \,{\left (2 \, a^{4} - 6 \, a^{2} b^{2} + 3 \, b^{4}\right )} c d e x +{\left (2 \, b^{4} d^{2} e x^{2} + 4 \, b^{4} c d e x +{\left (2 \, b^{4} c^{2} - b^{4}\right )} e\right )} \arcsin \left (d x + c\right )^{4} + 4 \,{\left (2 \, a b^{3} d^{2} e x^{2} + 4 \, a b^{3} c d e x +{\left (2 \, a b^{3} c^{2} - a b^{3}\right )} e\right )} \arcsin \left (d x + c\right )^{3} + 3 \,{\left (2 \,{\left (2 \, a^{2} b^{2} - b^{4}\right )} d^{2} e x^{2} + 4 \,{\left (2 \, a^{2} b^{2} - b^{4}\right )} c d e x -{\left (2 \, a^{2} b^{2} - b^{4} - 2 \,{\left (2 \, a^{2} b^{2} - b^{4}\right )} c^{2}\right )} e\right )} \arcsin \left (d x + c\right )^{2} + 2 \,{\left (2 \,{\left (2 \, a^{3} b - 3 \, a b^{3}\right )} d^{2} e x^{2} + 4 \,{\left (2 \, a^{3} b - 3 \, a b^{3}\right )} c d e x -{\left (2 \, a^{3} b - 3 \, a b^{3} - 2 \,{\left (2 \, a^{3} b - 3 \, a b^{3}\right )} c^{2}\right )} e\right )} \arcsin \left (d x + c\right ) + 2 \,{\left ({\left (2 \, a^{3} b - 3 \, a b^{3}\right )} d e x + 2 \,{\left (b^{4} d e x + b^{4} c e\right )} \arcsin \left (d x + c\right )^{3} +{\left (2 \, a^{3} b - 3 \, a b^{3}\right )} c e + 6 \,{\left (a b^{3} d e x + a b^{3} c e\right )} \arcsin \left (d x + c\right )^{2} + 3 \,{\left ({\left (2 \, a^{2} b^{2} - b^{4}\right )} d e x +{\left (2 \, a^{2} b^{2} - b^{4}\right )} c e\right )} \arcsin \left (d x + c\right )\right )} \sqrt{-d^{2} x^{2} - 2 \, c d x - c^{2} + 1}}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 6.88189, size = 1027, normalized size = 5.19 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.34008, size = 751, normalized size = 3.79 \begin{align*} \frac{{\left ({\left (d x + c\right )}^{2} - 1\right )} b^{4} \arcsin \left (d x + c\right )^{4} e}{2 \, d} + \frac{\sqrt{-{\left (d x + c\right )}^{2} + 1}{\left (d x + c\right )} b^{4} \arcsin \left (d x + c\right )^{3} e}{d} + \frac{2 \,{\left ({\left (d x + c\right )}^{2} - 1\right )} a b^{3} \arcsin \left (d x + c\right )^{3} e}{d} + \frac{b^{4} \arcsin \left (d x + c\right )^{4} e}{4 \, d} + \frac{3 \, \sqrt{-{\left (d x + c\right )}^{2} + 1}{\left (d x + c\right )} a b^{3} \arcsin \left (d x + c\right )^{2} e}{d} + \frac{3 \,{\left ({\left (d x + c\right )}^{2} - 1\right )} a^{2} b^{2} \arcsin \left (d x + c\right )^{2} e}{d} - \frac{3 \,{\left ({\left (d x + c\right )}^{2} - 1\right )} b^{4} \arcsin \left (d x + c\right )^{2} e}{2 \, d} + \frac{a b^{3} \arcsin \left (d x + c\right )^{3} e}{d} + \frac{3 \, \sqrt{-{\left (d x + c\right )}^{2} + 1}{\left (d x + c\right )} a^{2} b^{2} \arcsin \left (d x + c\right ) e}{d} - \frac{3 \, \sqrt{-{\left (d x + c\right )}^{2} + 1}{\left (d x + c\right )} b^{4} \arcsin \left (d x + c\right ) e}{2 \, d} + \frac{2 \,{\left ({\left (d x + c\right )}^{2} - 1\right )} a^{3} b \arcsin \left (d x + c\right ) e}{d} - \frac{3 \,{\left ({\left (d x + c\right )}^{2} - 1\right )} a b^{3} \arcsin \left (d x + c\right ) e}{d} + \frac{3 \, a^{2} b^{2} \arcsin \left (d x + c\right )^{2} e}{2 \, d} - \frac{3 \, b^{4} \arcsin \left (d x + c\right )^{2} e}{4 \, d} + \frac{\sqrt{-{\left (d x + c\right )}^{2} + 1}{\left (d x + c\right )} a^{3} b e}{d} - \frac{3 \, \sqrt{-{\left (d x + c\right )}^{2} + 1}{\left (d x + c\right )} a b^{3} e}{2 \, d} + \frac{{\left ({\left (d x + c\right )}^{2} - 1\right )} a^{4} e}{2 \, d} - \frac{3 \,{\left ({\left (d x + c\right )}^{2} - 1\right )} a^{2} b^{2} e}{2 \, d} + \frac{3 \,{\left ({\left (d x + c\right )}^{2} - 1\right )} b^{4} e}{4 \, d} + \frac{a^{3} b \arcsin \left (d x + c\right ) e}{d} - \frac{3 \, a b^{3} \arcsin \left (d x + c\right ) e}{2 \, d} - \frac{3 \, a^{2} b^{2} e}{4 \, d} + \frac{3 \, b^{4} e}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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