Optimal. Leaf size=291 \[ \frac{i b^2 \text{PolyLog}\left (2,-e^{i \sin ^{-1}(c+d x)}\right ) \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4}-\frac{i b^2 \text{PolyLog}\left (2,e^{i \sin ^{-1}(c+d x)}\right ) \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4}-\frac{b^3 \text{PolyLog}\left (3,-e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}+\frac{b^3 \text{PolyLog}\left (3,e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{b^2 \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4 (c+d x)}-\frac{b \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d e^4 (c+d x)^2}-\frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{3 d e^4 (c+d x)^3}-\frac{b \tanh ^{-1}\left (e^{i \sin ^{-1}(c+d x)}\right ) \left (a+b \sin ^{-1}(c+d x)\right )^2}{d e^4}-\frac{b^3 \tanh ^{-1}\left (\sqrt{1-(c+d x)^2}\right )}{d e^4} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.39413, antiderivative size = 291, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 12, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.522, Rules used = {4805, 12, 4627, 4701, 4709, 4183, 2531, 2282, 6589, 266, 63, 206} \[ \frac{i b^2 \text{PolyLog}\left (2,-e^{i \sin ^{-1}(c+d x)}\right ) \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4}-\frac{i b^2 \text{PolyLog}\left (2,e^{i \sin ^{-1}(c+d x)}\right ) \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4}-\frac{b^3 \text{PolyLog}\left (3,-e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}+\frac{b^3 \text{PolyLog}\left (3,e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{b^2 \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4 (c+d x)}-\frac{b \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d e^4 (c+d x)^2}-\frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{3 d e^4 (c+d x)^3}-\frac{b \tanh ^{-1}\left (e^{i \sin ^{-1}(c+d x)}\right ) \left (a+b \sin ^{-1}(c+d x)\right )^2}{d e^4}-\frac{b^3 \tanh ^{-1}\left (\sqrt{1-(c+d x)^2}\right )}{d e^4} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 4805
Rule 12
Rule 4627
Rule 4701
Rule 4709
Rule 4183
Rule 2531
Rule 2282
Rule 6589
Rule 266
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{(c e+d e x)^4} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+b \sin ^{-1}(x)\right )^3}{e^4 x^4} \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+b \sin ^{-1}(x)\right )^3}{x^4} \, dx,x,c+d x\right )}{d e^4}\\ &=-\frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{3 d e^4 (c+d x)^3}+\frac{b \operatorname{Subst}\left (\int \frac{\left (a+b \sin ^{-1}(x)\right )^2}{x^3 \sqrt{1-x^2}} \, dx,x,c+d x\right )}{d e^4}\\ &=-\frac{b \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d e^4 (c+d x)^2}-\frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{3 d e^4 (c+d x)^3}+\frac{b \operatorname{Subst}\left (\int \frac{\left (a+b \sin ^{-1}(x)\right )^2}{x \sqrt{1-x^2}} \, dx,x,c+d x\right )}{2 d e^4}+\frac{b^2 \operatorname{Subst}\left (\int \frac{a+b \sin ^{-1}(x)}{x^2} \, dx,x,c+d x\right )}{d e^4}\\ &=-\frac{b^2 \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4 (c+d x)}-\frac{b \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d e^4 (c+d x)^2}-\frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{3 d e^4 (c+d x)^3}+\frac{b \operatorname{Subst}\left (\int (a+b x)^2 \csc (x) \, dx,x,\sin ^{-1}(c+d x)\right )}{2 d e^4}+\frac{b^3 \operatorname{Subst}\left (\int \frac{1}{x \sqrt{1-x^2}} \, dx,x,c+d x\right )}{d e^4}\\ &=-\frac{b^2 \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4 (c+d x)}-\frac{b \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d e^4 (c+d x)^2}-\frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{3 d e^4 (c+d x)^3}-\frac{b \left (a+b \sin ^{-1}(c+d x)\right )^2 \tanh ^{-1}\left (e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{b^2 \operatorname{Subst}\left (\int (a+b x) \log \left (1-e^{i x}\right ) \, dx,x,\sin ^{-1}(c+d x)\right )}{d e^4}+\frac{b^2 \operatorname{Subst}\left (\int (a+b x) \log \left (1+e^{i x}\right ) \, dx,x,\sin ^{-1}(c+d x)\right )}{d e^4}+\frac{b^3 \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} x} \, dx,x,(c+d x)^2\right )}{2 d e^4}\\ &=-\frac{b^2 \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4 (c+d x)}-\frac{b \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d e^4 (c+d x)^2}-\frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{3 d e^4 (c+d x)^3}-\frac{b \left (a+b \sin ^{-1}(c+d x)\right )^2 \tanh ^{-1}\left (e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}+\frac{i b^2 \left (a+b \sin ^{-1}(c+d x)\right ) \text{Li}_2\left (-e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{i b^2 \left (a+b \sin ^{-1}(c+d x)\right ) \text{Li}_2\left (e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{\left (i b^3\right ) \operatorname{Subst}\left (\int \text{Li}_2\left (-e^{i x}\right ) \, dx,x,\sin ^{-1}(c+d x)\right )}{d e^4}+\frac{\left (i b^3\right ) \operatorname{Subst}\left (\int \text{Li}_2\left (e^{i x}\right ) \, dx,x,\sin ^{-1}(c+d x)\right )}{d e^4}-\frac{b^3 \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sqrt{1-(c+d x)^2}\right )}{d e^4}\\ &=-\frac{b^2 \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4 (c+d x)}-\frac{b \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d e^4 (c+d x)^2}-\frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{3 d e^4 (c+d x)^3}-\frac{b \left (a+b \sin ^{-1}(c+d x)\right )^2 \tanh ^{-1}\left (e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{b^3 \tanh ^{-1}\left (\sqrt{1-(c+d x)^2}\right )}{d e^4}+\frac{i b^2 \left (a+b \sin ^{-1}(c+d x)\right ) \text{Li}_2\left (-e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{i b^2 \left (a+b \sin ^{-1}(c+d x)\right ) \text{Li}_2\left (e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{b^3 \operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}+\frac{b^3 \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}\\ &=-\frac{b^2 \left (a+b \sin ^{-1}(c+d x)\right )}{d e^4 (c+d x)}-\frac{b \sqrt{1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^2}{2 d e^4 (c+d x)^2}-\frac{\left (a+b \sin ^{-1}(c+d x)\right )^3}{3 d e^4 (c+d x)^3}-\frac{b \left (a+b \sin ^{-1}(c+d x)\right )^2 \tanh ^{-1}\left (e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{b^3 \tanh ^{-1}\left (\sqrt{1-(c+d x)^2}\right )}{d e^4}+\frac{i b^2 \left (a+b \sin ^{-1}(c+d x)\right ) \text{Li}_2\left (-e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{i b^2 \left (a+b \sin ^{-1}(c+d x)\right ) \text{Li}_2\left (e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}-\frac{b^3 \text{Li}_3\left (-e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}+\frac{b^3 \text{Li}_3\left (e^{i \sin ^{-1}(c+d x)}\right )}{d e^4}\\ \end{align*}
Mathematica [B] time = 7.69102, size = 732, normalized size = 2.52 \[ \frac{a b^2 \left (8 i \text{PolyLog}\left (2,-e^{i \sin ^{-1}(c+d x)}\right )-\frac{2 \left (4 i (c+d x)^3 \text{PolyLog}\left (2,e^{i \sin ^{-1}(c+d x)}\right )+4 \sin ^{-1}(c+d x)^2+2 \sin ^{-1}(c+d x) \sin \left (2 \sin ^{-1}(c+d x)\right )-3 (c+d x) \sin ^{-1}(c+d x) \log \left (1-e^{i \sin ^{-1}(c+d x)}\right )+3 (c+d x) \sin ^{-1}(c+d x) \log \left (1+e^{i \sin ^{-1}(c+d x)}\right )+\sin ^{-1}(c+d x) \sin \left (3 \sin ^{-1}(c+d x)\right ) \log \left (1-e^{i \sin ^{-1}(c+d x)}\right )-\sin ^{-1}(c+d x) \sin \left (3 \sin ^{-1}(c+d x)\right ) \log \left (1+e^{i \sin ^{-1}(c+d x)}\right )-2 \cos \left (2 \sin ^{-1}(c+d x)\right )+2\right )}{(c+d x)^3}\right )}{8 d e^4}+\frac{b^3 \left (48 i \sin ^{-1}(c+d x) \text{PolyLog}\left (2,-e^{i \sin ^{-1}(c+d x)}\right )-48 i \sin ^{-1}(c+d x) \text{PolyLog}\left (2,e^{i \sin ^{-1}(c+d x)}\right )-48 \text{PolyLog}\left (3,-e^{i \sin ^{-1}(c+d x)}\right )+48 \text{PolyLog}\left (3,e^{i \sin ^{-1}(c+d x)}\right )-\frac{16 \sin ^{-1}(c+d x)^3 \sin ^4\left (\frac{1}{2} \sin ^{-1}(c+d x)\right )}{(c+d x)^3}+24 \sin ^{-1}(c+d x)^2 \log \left (1-e^{i \sin ^{-1}(c+d x)}\right )-24 \sin ^{-1}(c+d x)^2 \log \left (1+e^{i \sin ^{-1}(c+d x)}\right )-4 \sin ^{-1}(c+d x)^3 \tan \left (\frac{1}{2} \sin ^{-1}(c+d x)\right )-24 \sin ^{-1}(c+d x) \tan \left (\frac{1}{2} \sin ^{-1}(c+d x)\right )-4 \sin ^{-1}(c+d x)^3 \cot \left (\frac{1}{2} \sin ^{-1}(c+d x)\right )-24 \sin ^{-1}(c+d x) \cot \left (\frac{1}{2} \sin ^{-1}(c+d x)\right )-(c+d x) \sin ^{-1}(c+d x)^3 \csc ^4\left (\frac{1}{2} \sin ^{-1}(c+d x)\right )-6 \sin ^{-1}(c+d x)^2 \csc ^2\left (\frac{1}{2} \sin ^{-1}(c+d x)\right )+6 \sin ^{-1}(c+d x)^2 \sec ^2\left (\frac{1}{2} \sin ^{-1}(c+d x)\right )+48 \log \left (\tan \left (\frac{1}{2} \sin ^{-1}(c+d x)\right )\right )\right )}{48 d e^4}-\frac{a^2 b \sqrt{-c^2-2 c d x-d^2 x^2+1}}{2 d e^4 (c+d x)^2}-\frac{a^2 b \log \left (\sqrt{-c^2-2 c d x-d^2 x^2+1}+1\right )}{2 d e^4}+\frac{a^2 b \log (c+d x)}{2 d e^4}-\frac{a^2 b \sin ^{-1}(c+d x)}{d e^4 (c+d x)^3}-\frac{a^3}{3 d e^4 (c+d x)^3} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.124, size = 716, normalized size = 2.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{3} \arcsin \left (d x + c\right )^{3} + 3 \, a b^{2} \arcsin \left (d x + c\right )^{2} + 3 \, a^{2} b \arcsin \left (d x + c\right ) + a^{3}}{d^{4} e^{4} x^{4} + 4 \, c d^{3} e^{4} x^{3} + 6 \, c^{2} d^{2} e^{4} x^{2} + 4 \, c^{3} d e^{4} x + c^{4} e^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a^{3}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx + \int \frac{b^{3} \operatorname{asin}^{3}{\left (c + d x \right )}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx + \int \frac{3 a b^{2} \operatorname{asin}^{2}{\left (c + d x \right )}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx + \int \frac{3 a^{2} b \operatorname{asin}{\left (c + d x \right )}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx}{e^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \arcsin \left (d x + c\right ) + a\right )}^{3}}{{\left (d e x + c e\right )}^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]