Optimal. Leaf size=88 \[ -\frac{a+b \sin ^{-1}(c+d x)}{3 d e^4 (c+d x)^3}-\frac{b \sqrt{1-(c+d x)^2}}{6 d e^4 (c+d x)^2}-\frac{b \tanh ^{-1}\left (\sqrt{1-(c+d x)^2}\right )}{6 d e^4} \]
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Rubi [A] time = 0.0727574, antiderivative size = 88, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {4805, 12, 4627, 266, 51, 63, 206} \[ -\frac{a+b \sin ^{-1}(c+d x)}{3 d e^4 (c+d x)^3}-\frac{b \sqrt{1-(c+d x)^2}}{6 d e^4 (c+d x)^2}-\frac{b \tanh ^{-1}\left (\sqrt{1-(c+d x)^2}\right )}{6 d e^4} \]
Antiderivative was successfully verified.
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Rule 4805
Rule 12
Rule 4627
Rule 266
Rule 51
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \frac{a+b \sin ^{-1}(c+d x)}{(c e+d e x)^4} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{a+b \sin ^{-1}(x)}{e^4 x^4} \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{a+b \sin ^{-1}(x)}{x^4} \, dx,x,c+d x\right )}{d e^4}\\ &=-\frac{a+b \sin ^{-1}(c+d x)}{3 d e^4 (c+d x)^3}+\frac{b \operatorname{Subst}\left (\int \frac{1}{x^3 \sqrt{1-x^2}} \, dx,x,c+d x\right )}{3 d e^4}\\ &=-\frac{a+b \sin ^{-1}(c+d x)}{3 d e^4 (c+d x)^3}+\frac{b \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} x^2} \, dx,x,(c+d x)^2\right )}{6 d e^4}\\ &=-\frac{b \sqrt{1-(c+d x)^2}}{6 d e^4 (c+d x)^2}-\frac{a+b \sin ^{-1}(c+d x)}{3 d e^4 (c+d x)^3}+\frac{b \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} x} \, dx,x,(c+d x)^2\right )}{12 d e^4}\\ &=-\frac{b \sqrt{1-(c+d x)^2}}{6 d e^4 (c+d x)^2}-\frac{a+b \sin ^{-1}(c+d x)}{3 d e^4 (c+d x)^3}-\frac{b \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sqrt{1-(c+d x)^2}\right )}{6 d e^4}\\ &=-\frac{b \sqrt{1-(c+d x)^2}}{6 d e^4 (c+d x)^2}-\frac{a+b \sin ^{-1}(c+d x)}{3 d e^4 (c+d x)^3}-\frac{b \tanh ^{-1}\left (\sqrt{1-(c+d x)^2}\right )}{6 d e^4}\\ \end{align*}
Mathematica [A] time = 0.0762458, size = 77, normalized size = 0.88 \[ -\frac{2 \left (a+b \sin ^{-1}(c+d x)\right )+b (c+d x) \left (\sqrt{1-(c+d x)^2}+(c+d x)^2 \tanh ^{-1}\left (\sqrt{1-(c+d x)^2}\right )\right )}{6 d e^4 (c+d x)^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.005, size = 78, normalized size = 0.9 \begin{align*}{\frac{1}{d} \left ( -{\frac{a}{3\,{e}^{4} \left ( dx+c \right ) ^{3}}}+{\frac{b}{{e}^{4}} \left ( -{\frac{\arcsin \left ( dx+c \right ) }{3\, \left ( dx+c \right ) ^{3}}}-{\frac{1}{6\, \left ( dx+c \right ) ^{2}}\sqrt{1- \left ( dx+c \right ) ^{2}}}-{\frac{1}{6}{\it Artanh} \left ({\frac{1}{\sqrt{1- \left ( dx+c \right ) ^{2}}}} \right ) } \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{{\left ({\left (d^{4} e^{4} x^{3} + 3 \, c d^{3} e^{4} x^{2} + 3 \, c^{2} d^{2} e^{4} x + c^{3} d e^{4}\right )} \int \frac{e^{\left (\frac{1}{2} \, \log \left (d x + c + 1\right ) + \frac{1}{2} \, \log \left (-d x - c + 1\right )\right )}}{d^{7} e^{4} x^{7} + 7 \, c d^{6} e^{4} x^{6} +{\left (21 \, c^{2} - 1\right )} d^{5} e^{4} x^{5} + 5 \,{\left (7 \, c^{3} - c\right )} d^{4} e^{4} x^{4} + 5 \,{\left (7 \, c^{4} - 2 \, c^{2}\right )} d^{3} e^{4} x^{3} +{\left (21 \, c^{5} - 10 \, c^{3}\right )} d^{2} e^{4} x^{2} +{\left (7 \, c^{6} - 5 \, c^{4}\right )} d e^{4} x +{\left (c^{7} - c^{5}\right )} e^{4} -{\left (d^{5} e^{4} x^{5} + 5 \, c d^{4} e^{4} x^{4} +{\left (10 \, c^{2} - 1\right )} d^{3} e^{4} x^{3} +{\left (10 \, c^{3} - 3 \, c\right )} d^{2} e^{4} x^{2} +{\left (5 \, c^{4} - 3 \, c^{2}\right )} d e^{4} x +{\left (c^{5} - c^{3}\right )} e^{4}\right )}{\left (d x + c + 1\right )}{\left (d x + c - 1\right )}}\,{d x} + \arctan \left (d x + c, \sqrt{d x + c + 1} \sqrt{-d x - c + 1}\right )\right )} b}{3 \,{\left (d^{4} e^{4} x^{3} + 3 \, c d^{3} e^{4} x^{2} + 3 \, c^{2} d^{2} e^{4} x + c^{3} d e^{4}\right )}} - \frac{a}{3 \,{\left (d^{4} e^{4} x^{3} + 3 \, c d^{3} e^{4} x^{2} + 3 \, c^{2} d^{2} e^{4} x + c^{3} d e^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.47081, size = 462, normalized size = 5.25 \begin{align*} -\frac{4 \, b \arcsin \left (d x + c\right ) +{\left (b d^{3} x^{3} + 3 \, b c d^{2} x^{2} + 3 \, b c^{2} d x + b c^{3}\right )} \log \left (\sqrt{-d^{2} x^{2} - 2 \, c d x - c^{2} + 1} + 1\right ) -{\left (b d^{3} x^{3} + 3 \, b c d^{2} x^{2} + 3 \, b c^{2} d x + b c^{3}\right )} \log \left (\sqrt{-d^{2} x^{2} - 2 \, c d x - c^{2} + 1} - 1\right ) + 2 \, \sqrt{-d^{2} x^{2} - 2 \, c d x - c^{2} + 1}{\left (b d x + b c\right )} + 4 \, a}{12 \,{\left (d^{4} e^{4} x^{3} + 3 \, c d^{3} e^{4} x^{2} + 3 \, c^{2} d^{2} e^{4} x + c^{3} d e^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx + \int \frac{b \operatorname{asin}{\left (c + d x \right )}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx}{e^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.67887, size = 508, normalized size = 5.77 \begin{align*} -\frac{{\left (d x + c\right )}^{3} b \arcsin \left (d x + c\right ) e^{\left (-4\right )}}{24 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{3}} - \frac{{\left (d x + c\right )} b \arcsin \left (d x + c\right ) e^{\left (-4\right )}}{8 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}} - \frac{b{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )} \arcsin \left (d x + c\right ) e^{\left (-4\right )}}{8 \,{\left (d x + c\right )} d} - \frac{b{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{3} \arcsin \left (d x + c\right ) e^{\left (-4\right )}}{24 \,{\left (d x + c\right )}^{3} d} - \frac{b e^{\left (-4\right )} \log \left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}{6 \, d} + \frac{b e^{\left (-4\right )} \log \left ({\left | d x + c \right |}\right )}{6 \, d} - \frac{{\left (d x + c\right )}^{3} a e^{\left (-4\right )}}{24 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{3}} + \frac{{\left (d x + c\right )}^{2} b e^{\left (-4\right )}}{24 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{2}} - \frac{{\left (d x + c\right )} a e^{\left (-4\right )}}{8 \, d{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}} - \frac{a{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )} e^{\left (-4\right )}}{8 \,{\left (d x + c\right )} d} - \frac{b{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{2} e^{\left (-4\right )}}{24 \,{\left (d x + c\right )}^{2} d} - \frac{a{\left (\sqrt{-{\left (d x + c\right )}^{2} + 1} + 1\right )}^{3} e^{\left (-4\right )}}{24 \,{\left (d x + c\right )}^{3} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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