Optimal. Leaf size=468 \[ \frac{8 \sqrt{2 \pi } c \sin \left (\frac{a}{b}\right ) \text{FresnelC}\left (\frac{\sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{15 b^{7/2} d^2}-\frac{32 \sqrt{\pi } \cos \left (\frac{2 a}{b}\right ) \text{FresnelC}\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{\pi } \sqrt{b}}\right )}{15 b^{7/2} d^2}-\frac{32 \sqrt{\pi } \sin \left (\frac{2 a}{b}\right ) S\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right )}{15 b^{7/2} d^2}-\frac{8 \sqrt{2 \pi } c \cos \left (\frac{a}{b}\right ) S\left (\frac{\sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{15 b^{7/2} d^2}+\frac{8 (c+d x)^2}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}+\frac{32 \sqrt{1-(c+d x)^2} (c+d x)}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}-\frac{4 c (c+d x)}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{8 c \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}-\frac{4}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{2 \sqrt{1-(c+d x)^2} (c+d x)}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}+\frac{2 c \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}} \]
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Rubi [A] time = 1.064, antiderivative size = 468, normalized size of antiderivative = 1., number of steps used = 21, number of rules used = 13, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.812, Rules used = {4805, 4745, 4621, 4719, 4723, 3306, 3305, 3351, 3304, 3352, 4633, 4631, 4641} \[ \frac{8 \sqrt{2 \pi } c \sin \left (\frac{a}{b}\right ) \text{FresnelC}\left (\frac{\sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{15 b^{7/2} d^2}-\frac{32 \sqrt{\pi } \cos \left (\frac{2 a}{b}\right ) \text{FresnelC}\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{\pi } \sqrt{b}}\right )}{15 b^{7/2} d^2}-\frac{32 \sqrt{\pi } \sin \left (\frac{2 a}{b}\right ) S\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right )}{15 b^{7/2} d^2}-\frac{8 \sqrt{2 \pi } c \cos \left (\frac{a}{b}\right ) S\left (\frac{\sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{15 b^{7/2} d^2}+\frac{8 (c+d x)^2}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}+\frac{32 \sqrt{1-(c+d x)^2} (c+d x)}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}-\frac{4 c (c+d x)}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{8 c \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}-\frac{4}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{2 \sqrt{1-(c+d x)^2} (c+d x)}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}+\frac{2 c \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}} \]
Antiderivative was successfully verified.
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Rule 4805
Rule 4745
Rule 4621
Rule 4719
Rule 4723
Rule 3306
Rule 3305
Rule 3351
Rule 3304
Rule 3352
Rule 4633
Rule 4631
Rule 4641
Rubi steps
\begin{align*} \int \frac{x}{\left (a+b \sin ^{-1}(c+d x)\right )^{7/2}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{-\frac{c}{d}+\frac{x}{d}}{\left (a+b \sin ^{-1}(x)\right )^{7/2}} \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \left (-\frac{c}{d \left (a+b \sin ^{-1}(x)\right )^{7/2}}+\frac{x}{d \left (a+b \sin ^{-1}(x)\right )^{7/2}}\right ) \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{x}{\left (a+b \sin ^{-1}(x)\right )^{7/2}} \, dx,x,c+d x\right )}{d^2}-\frac{c \operatorname{Subst}\left (\int \frac{1}{\left (a+b \sin ^{-1}(x)\right )^{7/2}} \, dx,x,c+d x\right )}{d^2}\\ &=\frac{2 c \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{2 (c+d x) \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}+\frac{2 \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x^2} \left (a+b \sin ^{-1}(x)\right )^{5/2}} \, dx,x,c+d x\right )}{5 b d^2}-\frac{4 \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1-x^2} \left (a+b \sin ^{-1}(x)\right )^{5/2}} \, dx,x,c+d x\right )}{5 b d^2}+\frac{(2 c) \operatorname{Subst}\left (\int \frac{x}{\sqrt{1-x^2} \left (a+b \sin ^{-1}(x)\right )^{5/2}} \, dx,x,c+d x\right )}{5 b d^2}\\ &=\frac{2 c \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{2 (c+d x) \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{4}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{4 c (c+d x)}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}+\frac{8 (c+d x)^2}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{16 \operatorname{Subst}\left (\int \frac{x}{\left (a+b \sin ^{-1}(x)\right )^{3/2}} \, dx,x,c+d x\right )}{15 b^2 d^2}+\frac{(4 c) \operatorname{Subst}\left (\int \frac{1}{\left (a+b \sin ^{-1}(x)\right )^{3/2}} \, dx,x,c+d x\right )}{15 b^2 d^2}\\ &=\frac{2 c \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{2 (c+d x) \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{4}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{4 c (c+d x)}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}+\frac{8 (c+d x)^2}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{8 c \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}+\frac{32 (c+d x) \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}-\frac{32 \operatorname{Subst}\left (\int \frac{\cos (2 x)}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{15 b^3 d^2}-\frac{(8 c) \operatorname{Subst}\left (\int \frac{x}{\sqrt{1-x^2} \sqrt{a+b \sin ^{-1}(x)}} \, dx,x,c+d x\right )}{15 b^3 d^2}\\ &=\frac{2 c \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{2 (c+d x) \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{4}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{4 c (c+d x)}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}+\frac{8 (c+d x)^2}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{8 c \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}+\frac{32 (c+d x) \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}-\frac{(8 c) \operatorname{Subst}\left (\int \frac{\sin (x)}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{15 b^3 d^2}-\frac{\left (32 \cos \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cos \left (\frac{2 a}{b}+2 x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{15 b^3 d^2}-\frac{\left (32 \sin \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sin \left (\frac{2 a}{b}+2 x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{15 b^3 d^2}\\ &=\frac{2 c \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{2 (c+d x) \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{4}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{4 c (c+d x)}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}+\frac{8 (c+d x)^2}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{8 c \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}+\frac{32 (c+d x) \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}-\frac{\left (8 c \cos \left (\frac{a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\sin \left (\frac{a}{b}+x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{15 b^3 d^2}-\frac{\left (64 \cos \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \cos \left (\frac{2 x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{15 b^4 d^2}+\frac{\left (8 c \sin \left (\frac{a}{b}\right )\right ) \operatorname{Subst}\left (\int \frac{\cos \left (\frac{a}{b}+x\right )}{\sqrt{a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{15 b^3 d^2}-\frac{\left (64 \sin \left (\frac{2 a}{b}\right )\right ) \operatorname{Subst}\left (\int \sin \left (\frac{2 x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{15 b^4 d^2}\\ &=\frac{2 c \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{2 (c+d x) \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{4}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{4 c (c+d x)}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}+\frac{8 (c+d x)^2}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{8 c \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}+\frac{32 (c+d x) \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}-\frac{32 \sqrt{\pi } \cos \left (\frac{2 a}{b}\right ) C\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right )}{15 b^{7/2} d^2}-\frac{32 \sqrt{\pi } S\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right ) \sin \left (\frac{2 a}{b}\right )}{15 b^{7/2} d^2}-\frac{\left (16 c \cos \left (\frac{a}{b}\right )\right ) \operatorname{Subst}\left (\int \sin \left (\frac{x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{15 b^4 d^2}+\frac{\left (16 c \sin \left (\frac{a}{b}\right )\right ) \operatorname{Subst}\left (\int \cos \left (\frac{x^2}{b}\right ) \, dx,x,\sqrt{a+b \sin ^{-1}(c+d x)}\right )}{15 b^4 d^2}\\ &=\frac{2 c \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{2 (c+d x) \sqrt{1-(c+d x)^2}}{5 b d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}-\frac{4}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{4 c (c+d x)}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}+\frac{8 (c+d x)^2}{15 b^2 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}-\frac{8 c \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}+\frac{32 (c+d x) \sqrt{1-(c+d x)^2}}{15 b^3 d^2 \sqrt{a+b \sin ^{-1}(c+d x)}}-\frac{32 \sqrt{\pi } \cos \left (\frac{2 a}{b}\right ) C\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right )}{15 b^{7/2} d^2}-\frac{8 c \sqrt{2 \pi } \cos \left (\frac{a}{b}\right ) S\left (\frac{\sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right )}{15 b^{7/2} d^2}+\frac{8 c \sqrt{2 \pi } C\left (\frac{\sqrt{\frac{2}{\pi }} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b}}\right ) \sin \left (\frac{a}{b}\right )}{15 b^{7/2} d^2}-\frac{32 \sqrt{\pi } S\left (\frac{2 \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{b} \sqrt{\pi }}\right ) \sin \left (\frac{2 a}{b}\right )}{15 b^{7/2} d^2}\\ \end{align*}
Mathematica [C] time = 1.8565, size = 524, normalized size = 1.12 \[ \frac{-2 \left (-16 a^2 \sin \left (2 \sin ^{-1}(c+d x)\right )+32 \sqrt{\pi } \sqrt{\frac{1}{b}} \cos \left (\frac{2 a}{b}\right ) \left (a+b \sin ^{-1}(c+d x)\right )^{5/2} \text{FresnelC}\left (\frac{2 \sqrt{\frac{1}{b}} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{\pi }}\right )+32 \sqrt{\pi } \sqrt{\frac{1}{b}} \sin \left (\frac{2 a}{b}\right ) \left (a+b \sin ^{-1}(c+d x)\right )^{5/2} S\left (\frac{2 \sqrt{\frac{1}{b}} \sqrt{a+b \sin ^{-1}(c+d x)}}{\sqrt{\pi }}\right )-32 a b \sin ^{-1}(c+d x) \sin \left (2 \sin ^{-1}(c+d x)\right )+4 a b \cos \left (2 \sin ^{-1}(c+d x)\right )+3 b^2 \sin \left (2 \sin ^{-1}(c+d x)\right )-16 b^2 \sin ^{-1}(c+d x)^2 \sin \left (2 \sin ^{-1}(c+d x)\right )+4 b^2 \sin ^{-1}(c+d x) \cos \left (2 \sin ^{-1}(c+d x)\right )\right )-c \left (e^{-i \sin ^{-1}(c+d x)} \left (-8 e^{\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \left (a+b \sin ^{-1}(c+d x)\right )^2 \sqrt{\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \text{Gamma}\left (\frac{1}{2},\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )+8 a^2+4 a b \left (4 \sin ^{-1}(c+d x)+i\right )+2 b^2 \left (4 \sin ^{-1}(c+d x)^2+2 i \sin ^{-1}(c+d x)-3\right )\right )+4 e^{-\frac{i a}{b}} \left (a+b \sin ^{-1}(c+d x)\right ) \left (e^{\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \left (2 a+2 b \sin ^{-1}(c+d x)-i b\right )-2 i b \left (-\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )^{3/2} \text{Gamma}\left (\frac{1}{2},-\frac{i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )\right )-6 b^2 e^{i \sin ^{-1}(c+d x)}\right )}{30 b^3 d^2 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.167, size = 1172, normalized size = 2.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{{\left (b \arcsin \left (d x + c\right ) + a\right )}^{\frac{7}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{{\left (b \arcsin \left (d x + c\right ) + a\right )}^{\frac{7}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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