3.140 \(\int \sin ^{-1}(a+b x)^3 \, dx\)

Optimal. Leaf size=82 \[ -\frac{6 \sqrt{1-(a+b x)^2}}{b}+\frac{(a+b x) \sin ^{-1}(a+b x)^3}{b}+\frac{3 \sqrt{1-(a+b x)^2} \sin ^{-1}(a+b x)^2}{b}-\frac{6 (a+b x) \sin ^{-1}(a+b x)}{b} \]

[Out]

(-6*Sqrt[1 - (a + b*x)^2])/b - (6*(a + b*x)*ArcSin[a + b*x])/b + (3*Sqrt[1 - (a + b*x)^2]*ArcSin[a + b*x]^2)/b
+ ((a + b*x)*ArcSin[a + b*x]^3)/b

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Rubi [A]  time = 0.081184, antiderivative size = 82, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 8, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {4803, 4619, 4677, 261} \[ -\frac{6 \sqrt{1-(a+b x)^2}}{b}+\frac{(a+b x) \sin ^{-1}(a+b x)^3}{b}+\frac{3 \sqrt{1-(a+b x)^2} \sin ^{-1}(a+b x)^2}{b}-\frac{6 (a+b x) \sin ^{-1}(a+b x)}{b} \]

Antiderivative was successfully verified.

[In]

Int[ArcSin[a + b*x]^3,x]

[Out]

(-6*Sqrt[1 - (a + b*x)^2])/b - (6*(a + b*x)*ArcSin[a + b*x])/b + (3*Sqrt[1 - (a + b*x)^2]*ArcSin[a + b*x]^2)/b
+ ((a + b*x)*ArcSin[a + b*x]^3)/b

Rule 4803

Int[((a_.) + ArcSin[(c_) + (d_.)*(x_)]*(b_.))^(n_.), x_Symbol] :> Dist[1/d, Subst[Int[(a + b*ArcSin[x])^n, x],
x, c + d*x], x] /; FreeQ[{a, b, c, d, n}, x]

Rule 4619

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.), x_Symbol] :> Simp[x*(a + b*ArcSin[c*x])^n, x] - Dist[b*c*n, Int[
(x*(a + b*ArcSin[c*x])^(n - 1))/Sqrt[1 - c^2*x^2], x], x] /; FreeQ[{a, b, c}, x] && GtQ[n, 0]

Rule 4677

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*(x_)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[((d + e*x^2)^
(p + 1)*(a + b*ArcSin[c*x])^n)/(2*e*(p + 1)), x] + Dist[(b*n*d^IntPart[p]*(d + e*x^2)^FracPart[p])/(2*c*(p + 1
)*(1 - c^2*x^2)^FracPart[p]), Int[(1 - c^2*x^2)^(p + 1/2)*(a + b*ArcSin[c*x])^(n - 1), x], x] /; FreeQ[{a, b,
c, d, e, p}, x] && EqQ[c^2*d + e, 0] && GtQ[n, 0] && NeQ[p, -1]

Rule 261

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a + b*x^n)^(p + 1)/(b*n*(p + 1)), x] /; FreeQ
[{a, b, m, n, p}, x] && EqQ[m, n - 1] && NeQ[p, -1]

Rubi steps

\begin{align*} \int \sin ^{-1}(a+b x)^3 \, dx &=\frac{\operatorname{Subst}\left (\int \sin ^{-1}(x)^3 \, dx,x,a+b x\right )}{b}\\ &=\frac{(a+b x) \sin ^{-1}(a+b x)^3}{b}-\frac{3 \operatorname{Subst}\left (\int \frac{x \sin ^{-1}(x)^2}{\sqrt{1-x^2}} \, dx,x,a+b x\right )}{b}\\ &=\frac{3 \sqrt{1-(a+b x)^2} \sin ^{-1}(a+b x)^2}{b}+\frac{(a+b x) \sin ^{-1}(a+b x)^3}{b}-\frac{6 \operatorname{Subst}\left (\int \sin ^{-1}(x) \, dx,x,a+b x\right )}{b}\\ &=-\frac{6 (a+b x) \sin ^{-1}(a+b x)}{b}+\frac{3 \sqrt{1-(a+b x)^2} \sin ^{-1}(a+b x)^2}{b}+\frac{(a+b x) \sin ^{-1}(a+b x)^3}{b}+\frac{6 \operatorname{Subst}\left (\int \frac{x}{\sqrt{1-x^2}} \, dx,x,a+b x\right )}{b}\\ &=-\frac{6 \sqrt{1-(a+b x)^2}}{b}-\frac{6 (a+b x) \sin ^{-1}(a+b x)}{b}+\frac{3 \sqrt{1-(a+b x)^2} \sin ^{-1}(a+b x)^2}{b}+\frac{(a+b x) \sin ^{-1}(a+b x)^3}{b}\\ \end{align*}

Mathematica [A]  time = 0.0320958, size = 74, normalized size = 0.9 \[ \frac{-6 \sqrt{1-(a+b x)^2}+(a+b x) \sin ^{-1}(a+b x)^3+3 \sqrt{1-(a+b x)^2} \sin ^{-1}(a+b x)^2-6 (a+b x) \sin ^{-1}(a+b x)}{b} \]

Antiderivative was successfully verified.

[In]

Integrate[ArcSin[a + b*x]^3,x]

[Out]

(-6*Sqrt[1 - (a + b*x)^2] - 6*(a + b*x)*ArcSin[a + b*x] + 3*Sqrt[1 - (a + b*x)^2]*ArcSin[a + b*x]^2 + (a + b*x
)*ArcSin[a + b*x]^3)/b

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Maple [A]  time = 0.032, size = 71, normalized size = 0.9 \begin{align*}{\frac{1}{b} \left ( \left ( \arcsin \left ( bx+a \right ) \right ) ^{3} \left ( bx+a \right ) +3\, \left ( \arcsin \left ( bx+a \right ) \right ) ^{2}\sqrt{1- \left ( bx+a \right ) ^{2}}-6\,\sqrt{1- \left ( bx+a \right ) ^{2}}-6\, \left ( bx+a \right ) \arcsin \left ( bx+a \right ) \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(arcsin(b*x+a)^3,x)

[Out]

1/b*(arcsin(b*x+a)^3*(b*x+a)+3*arcsin(b*x+a)^2*(1-(b*x+a)^2)^(1/2)-6*(1-(b*x+a)^2)^(1/2)-6*(b*x+a)*arcsin(b*x+
a))

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arcsin(b*x+a)^3,x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 2.79887, size = 170, normalized size = 2.07 \begin{align*} \frac{{\left (b x + a\right )} \arcsin \left (b x + a\right )^{3} - 6 \,{\left (b x + a\right )} \arcsin \left (b x + a\right ) + 3 \, \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (\arcsin \left (b x + a\right )^{2} - 2\right )}}{b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arcsin(b*x+a)^3,x, algorithm="fricas")

[Out]

((b*x + a)*arcsin(b*x + a)^3 - 6*(b*x + a)*arcsin(b*x + a) + 3*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*(arcsin(b*x
+ a)^2 - 2))/b

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Sympy [A]  time = 0.735238, size = 109, normalized size = 1.33 \begin{align*} \begin{cases} \frac{a \operatorname{asin}^{3}{\left (a + b x \right )}}{b} - \frac{6 a \operatorname{asin}{\left (a + b x \right )}}{b} + x \operatorname{asin}^{3}{\left (a + b x \right )} - 6 x \operatorname{asin}{\left (a + b x \right )} + \frac{3 \sqrt{- a^{2} - 2 a b x - b^{2} x^{2} + 1} \operatorname{asin}^{2}{\left (a + b x \right )}}{b} - \frac{6 \sqrt{- a^{2} - 2 a b x - b^{2} x^{2} + 1}}{b} & \text{for}\: b \neq 0 \\x \operatorname{asin}^{3}{\left (a \right )} & \text{otherwise} \end{cases} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(asin(b*x+a)**3,x)

[Out]

Piecewise((a*asin(a + b*x)**3/b - 6*a*asin(a + b*x)/b + x*asin(a + b*x)**3 - 6*x*asin(a + b*x) + 3*sqrt(-a**2
- 2*a*b*x - b**2*x**2 + 1)*asin(a + b*x)**2/b - 6*sqrt(-a**2 - 2*a*b*x - b**2*x**2 + 1)/b, Ne(b, 0)), (x*asin(
a)**3, True))

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Giac [A]  time = 1.19109, size = 105, normalized size = 1.28 \begin{align*} \frac{{\left (b x + a\right )} \arcsin \left (b x + a\right )^{3}}{b} + \frac{3 \, \sqrt{-{\left (b x + a\right )}^{2} + 1} \arcsin \left (b x + a\right )^{2}}{b} - \frac{6 \,{\left (b x + a\right )} \arcsin \left (b x + a\right )}{b} - \frac{6 \, \sqrt{-{\left (b x + a\right )}^{2} + 1}}{b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arcsin(b*x+a)^3,x, algorithm="giac")

[Out]

(b*x + a)*arcsin(b*x + a)^3/b + 3*sqrt(-(b*x + a)^2 + 1)*arcsin(b*x + a)^2/b - 6*(b*x + a)*arcsin(b*x + a)/b -
6*sqrt(-(b*x + a)^2 + 1)/b