Optimal. Leaf size=617 \[ -\frac{i b \left (3 d^2 i-2 d e h+e^2 g\right ) \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^4}-\frac{i b \left (3 d^2 i-2 d e h+e^2 g\right ) \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^4}-\frac{\left (a+b \sin ^{-1}(c x)\right ) \left (d^2 e h+d^3 (-i)-d e^2 g+e^3 f\right )}{e^4 (d+e x)}+\frac{\log (d+e x) \left (a+b \sin ^{-1}(c x)\right ) \left (3 d^2 i-2 d e h+e^2 g\right )}{e^4}+\frac{x (e h-2 d i) \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{i x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e^2}+\frac{b c \tan ^{-1}\left (\frac{c^2 d x+e}{\sqrt{1-c^2 x^2} \sqrt{c^2 d^2-e^2}}\right ) \left (d^2 e h+d^3 (-i)-d e^2 g+e^3 f\right )}{e^4 \sqrt{c^2 d^2-e^2}}+\frac{b \sin ^{-1}(c x) \left (3 d^2 i-2 d e h+e^2 g\right ) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^4}+\frac{b \sin ^{-1}(c x) \left (3 d^2 i-2 d e h+e^2 g\right ) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^4}+\frac{b \sqrt{1-c^2 x^2} (e h-2 d i)}{c e^3}+\frac{b i x \sqrt{1-c^2 x^2}}{4 c e^2}-\frac{b i \sin ^{-1}(c x)}{4 c^2 e^2}-\frac{i b \sin ^{-1}(c x)^2 \left (3 d^2 i-2 d e h+e^2 g\right )}{2 e^4}-\frac{b \sin ^{-1}(c x) \log (d+e x) \left (3 d^2 i-2 d e h+e^2 g\right )}{e^4} \]
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Rubi [A] time = 1.74197, antiderivative size = 617, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 15, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.484, Rules used = {1850, 4753, 12, 6742, 261, 321, 216, 725, 204, 2404, 4741, 4519, 2190, 2279, 2391} \[ -\frac{i b \left (3 d^2 i-2 d e h+e^2 g\right ) \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^4}-\frac{i b \left (3 d^2 i-2 d e h+e^2 g\right ) \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^4}-\frac{\left (a+b \sin ^{-1}(c x)\right ) \left (d^2 e h+d^3 (-i)-d e^2 g+e^3 f\right )}{e^4 (d+e x)}+\frac{\log (d+e x) \left (a+b \sin ^{-1}(c x)\right ) \left (3 d^2 i-2 d e h+e^2 g\right )}{e^4}+\frac{x (e h-2 d i) \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{i x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e^2}+\frac{b c \tan ^{-1}\left (\frac{c^2 d x+e}{\sqrt{1-c^2 x^2} \sqrt{c^2 d^2-e^2}}\right ) \left (d^2 e h+d^3 (-i)-d e^2 g+e^3 f\right )}{e^4 \sqrt{c^2 d^2-e^2}}+\frac{b \sin ^{-1}(c x) \left (3 d^2 i-2 d e h+e^2 g\right ) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^4}+\frac{b \sin ^{-1}(c x) \left (3 d^2 i-2 d e h+e^2 g\right ) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^4}+\frac{b \sqrt{1-c^2 x^2} (e h-2 d i)}{c e^3}+\frac{b i x \sqrt{1-c^2 x^2}}{4 c e^2}-\frac{b i \sin ^{-1}(c x)}{4 c^2 e^2}-\frac{i b \sin ^{-1}(c x)^2 \left (3 d^2 i-2 d e h+e^2 g\right )}{2 e^4}-\frac{b \sin ^{-1}(c x) \log (d+e x) \left (3 d^2 i-2 d e h+e^2 g\right )}{e^4} \]
Antiderivative was successfully verified.
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Rule 1850
Rule 4753
Rule 12
Rule 6742
Rule 261
Rule 321
Rule 216
Rule 725
Rule 204
Rule 2404
Rule 4741
Rule 4519
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\left (f+g x+h x^2+110 x^3\right ) \left (a+b \sin ^{-1}(c x)\right )}{(d+e x)^2} \, dx &=-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}-(b c) \int \frac{110 d^3-d^2 e (h+220 x)+d e^2 (g+(h-165 x) x)+e^3 \left (-f+x^2 (h+55 x)\right )+\left (330 d^2+e^2 g-2 d e h\right ) (d+e x) \log (d+e x)}{e^4 (d+e x) \sqrt{1-c^2 x^2}} \, dx\\ &=-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}-\frac{(b c) \int \frac{110 d^3-d^2 e (h+220 x)+d e^2 (g+(h-165 x) x)+e^3 \left (-f+x^2 (h+55 x)\right )+\left (330 d^2+e^2 g-2 d e h\right ) (d+e x) \log (d+e x)}{(d+e x) \sqrt{1-c^2 x^2}} \, dx}{e^4}\\ &=-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}-\frac{(b c) \int \left (\frac{110 d^3-e^3 f+d e^2 g-d^2 e h-d e (220 d-e h) x-e^2 (165 d-e h) x^2+55 e^3 x^3}{(d+e x) \sqrt{1-c^2 x^2}}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \log (d+e x)}{\sqrt{1-c^2 x^2}}\right ) \, dx}{e^4}\\ &=-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}-\frac{(b c) \int \frac{110 d^3-e^3 f+d e^2 g-d^2 e h-d e (220 d-e h) x-e^2 (165 d-e h) x^2+55 e^3 x^3}{(d+e x) \sqrt{1-c^2 x^2}} \, dx}{e^4}-\frac{\left (b c \left (330 d^2+e^2 g-2 d e h\right )\right ) \int \frac{\log (d+e x)}{\sqrt{1-c^2 x^2}} \, dx}{e^4}\\ &=\frac{55 b (d+e x) \sqrt{1-c^2 x^2}}{2 c e^3}-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}-\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^4}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}+\frac{b \int \frac{-e^3 \left (55 d e^2+2 c^2 \left (110 d^3-e^3 f+d e^2 g-d^2 e h\right )\right )-e^4 \left (55 e^2-c^2 d (495 d-2 e h)\right ) x+c^2 e^5 (495 d-2 e h) x^2}{(d+e x) \sqrt{1-c^2 x^2}} \, dx}{2 c e^7}+\frac{\left (b c \left (330 d^2+e^2 g-2 d e h\right )\right ) \int \frac{\sin ^{-1}(c x)}{c d+c e x} \, dx}{e^3}\\ &=-\frac{b (495 d-2 e h) \sqrt{1-c^2 x^2}}{2 c e^3}+\frac{55 b (d+e x) \sqrt{1-c^2 x^2}}{2 c e^3}-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}-\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^4}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}-\frac{b \int \frac{c^2 e^5 \left (55 d e^2+2 c^2 \left (110 d^3-e^3 f+d e^2 g-d^2 e h\right )\right )+55 c^2 e^8 x}{(d+e x) \sqrt{1-c^2 x^2}} \, dx}{2 c^3 e^9}+\frac{\left (b c \left (330 d^2+e^2 g-2 d e h\right )\right ) \operatorname{Subst}\left (\int \frac{x \cos (x)}{c^2 d+c e \sin (x)} \, dx,x,\sin ^{-1}(c x)\right )}{e^3}\\ &=-\frac{b (495 d-2 e h) \sqrt{1-c^2 x^2}}{2 c e^3}+\frac{55 b (d+e x) \sqrt{1-c^2 x^2}}{2 c e^3}-\frac{i b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x)^2}{2 e^4}-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}-\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^4}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}-\frac{(55 b) \int \frac{1}{\sqrt{1-c^2 x^2}} \, dx}{2 c e^2}+\frac{\left (b c \left (330 d^2+e^2 g-2 d e h\right )\right ) \operatorname{Subst}\left (\int \frac{e^{i x} x}{c^2 d-c \sqrt{c^2 d^2-e^2}-i c e e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{e^3}+\frac{\left (b c \left (330 d^2+e^2 g-2 d e h\right )\right ) \operatorname{Subst}\left (\int \frac{e^{i x} x}{c^2 d+c \sqrt{c^2 d^2-e^2}-i c e e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{e^3}-\frac{\left (b c \left (110 d^3-e^3 f+d e^2 g-d^2 e h\right )\right ) \int \frac{1}{(d+e x) \sqrt{1-c^2 x^2}} \, dx}{e^4}\\ &=-\frac{b (495 d-2 e h) \sqrt{1-c^2 x^2}}{2 c e^3}+\frac{55 b (d+e x) \sqrt{1-c^2 x^2}}{2 c e^3}-\frac{55 b \sin ^{-1}(c x)}{2 c^2 e^2}-\frac{i b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x)^2}{2 e^4}-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}+\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^4}+\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^4}-\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^4}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}-\frac{\left (b \left (330 d^2+e^2 g-2 d e h\right )\right ) \operatorname{Subst}\left (\int \log \left (1-\frac{i c e e^{i x}}{c^2 d-c \sqrt{c^2 d^2-e^2}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{e^4}-\frac{\left (b \left (330 d^2+e^2 g-2 d e h\right )\right ) \operatorname{Subst}\left (\int \log \left (1-\frac{i c e e^{i x}}{c^2 d+c \sqrt{c^2 d^2-e^2}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{e^4}+\frac{\left (b c \left (110 d^3-e^3 f+d e^2 g-d^2 e h\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-c^2 d^2+e^2-x^2} \, dx,x,\frac{e+c^2 d x}{\sqrt{1-c^2 x^2}}\right )}{e^4}\\ &=-\frac{b (495 d-2 e h) \sqrt{1-c^2 x^2}}{2 c e^3}+\frac{55 b (d+e x) \sqrt{1-c^2 x^2}}{2 c e^3}-\frac{55 b \sin ^{-1}(c x)}{2 c^2 e^2}-\frac{i b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x)^2}{2 e^4}-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}-\frac{b c \left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \tan ^{-1}\left (\frac{e+c^2 d x}{\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}}\right )}{e^4 \sqrt{c^2 d^2-e^2}}+\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^4}+\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^4}-\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^4}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}+\frac{\left (i b \left (330 d^2+e^2 g-2 d e h\right )\right ) \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{i c e x}{c^2 d-c \sqrt{c^2 d^2-e^2}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{e^4}+\frac{\left (i b \left (330 d^2+e^2 g-2 d e h\right )\right ) \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{i c e x}{c^2 d+c \sqrt{c^2 d^2-e^2}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{e^4}\\ &=-\frac{b (495 d-2 e h) \sqrt{1-c^2 x^2}}{2 c e^3}+\frac{55 b (d+e x) \sqrt{1-c^2 x^2}}{2 c e^3}-\frac{55 b \sin ^{-1}(c x)}{2 c^2 e^2}-\frac{i b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x)^2}{2 e^4}-\frac{(220 d-e h) x \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{55 x^2 \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{\left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \left (a+b \sin ^{-1}(c x)\right )}{e^4 (d+e x)}-\frac{b c \left (110 d^3-e^3 f+d e^2 g-d^2 e h\right ) \tan ^{-1}\left (\frac{e+c^2 d x}{\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}}\right )}{e^4 \sqrt{c^2 d^2-e^2}}+\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^4}+\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^4}-\frac{b \left (330 d^2+e^2 g-2 d e h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^4}+\frac{\left (330 d^2+e^2 g-2 d e h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^4}-\frac{i b \left (330 d^2+e^2 g-2 d e h\right ) \text{Li}_2\left (\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^4}-\frac{i b \left (330 d^2+e^2 g-2 d e h\right ) \text{Li}_2\left (\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^4}\\ \end{align*}
Mathematica [A] time = 1.43079, size = 515, normalized size = 0.83 \[ \frac{-i b \left (3 d^2 i-2 d e h+e^2 g\right ) \left (2 \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )+2 \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )+\sin ^{-1}(c x) \left (\sin ^{-1}(c x)+2 i \left (\log \left (1+\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}-c d}\right )+\log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )\right )\right )\right )-\frac{2 \left (a+b \sin ^{-1}(c x)\right ) \left (d^2 e h+d^3 (-i)-d e^2 g+e^3 f\right )}{d+e x}+2 \log (d+e x) \left (a+b \sin ^{-1}(c x)\right ) \left (3 d^2 i-2 d e h+e^2 g\right )+2 e x (e h-2 d i) \left (a+b \sin ^{-1}(c x)\right )+e^2 i x^2 \left (a+b \sin ^{-1}(c x)\right )+\frac{2 b c \tan ^{-1}\left (\frac{c^2 d x+e}{\sqrt{1-c^2 x^2} \sqrt{c^2 d^2-e^2}}\right ) \left (d^2 e h+d^3 (-i)-d e^2 g+e^3 f\right )}{\sqrt{c^2 d^2-e^2}}+\frac{2 b e \sqrt{1-c^2 x^2} (e h-2 d i)}{c}+\frac{b e^2 i x \sqrt{1-c^2 x^2}}{2 c}-\frac{b e^2 i \sin ^{-1}(c x)}{2 c^2}-2 b \sin ^{-1}(c x) \log (d+e x) \left (3 d^2 i-2 d e h+e^2 g\right )}{2 e^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 1.714, size = 2939, normalized size = 4.8 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{a i x^{3} + a h x^{2} + a g x + a f +{\left (b i x^{3} + b h x^{2} + b g x + b f\right )} \arcsin \left (c x\right )}{e^{2} x^{2} + 2 \, d e x + d^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b \operatorname{asin}{\left (c x \right )}\right ) \left (f + g x + h x^{2} + i x^{3}\right )}{\left (d + e x\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (i x^{3} + h x^{2} + g x + f\right )}{\left (b \arcsin \left (c x\right ) + a\right )}}{{\left (e x + d\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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