Optimal. Leaf size=488 \[ -\frac{i b h \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{i b h \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^3}-\frac{\left (a+b \sin ^{-1}(c x)\right ) \left (d^2 h-d e g+e^2 f\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}+\frac{h \log (d+e x) \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{b c \sqrt{1-c^2 x^2} \left (d^2 h-d e g+e^2 f\right )}{2 e^2 \left (c^2 d^2-e^2\right ) (d+e x)}-\frac{b c \tan ^{-1}\left (\frac{c^2 d x+e}{\sqrt{1-c^2 x^2} \sqrt{c^2 d^2-e^2}}\right ) \left (2 e^2 (e g-2 d h)-c^2 d \left (-3 d^2 h+d e g+e^2 f\right )\right )}{2 e^3 \left (c^2 d^2-e^2\right )^{3/2}}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^3}-\frac{b h \sin ^{-1}(c x) \log (d+e x)}{e^3}-\frac{i b h \sin ^{-1}(c x)^2}{2 e^3} \]
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Rubi [A] time = 1.26207, antiderivative size = 488, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 14, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.538, Rules used = {698, 4753, 12, 6742, 807, 725, 204, 216, 2404, 4741, 4519, 2190, 2279, 2391} \[ -\frac{i b h \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{i b h \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^3}-\frac{\left (a+b \sin ^{-1}(c x)\right ) \left (d^2 h-d e g+e^2 f\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}+\frac{h \log (d+e x) \left (a+b \sin ^{-1}(c x)\right )}{e^3}+\frac{b c \sqrt{1-c^2 x^2} \left (d^2 h-d e g+e^2 f\right )}{2 e^2 \left (c^2 d^2-e^2\right ) (d+e x)}-\frac{b c \tan ^{-1}\left (\frac{c^2 d x+e}{\sqrt{1-c^2 x^2} \sqrt{c^2 d^2-e^2}}\right ) \left (2 e^2 (e g-2 d h)-c^2 d \left (-3 d^2 h+d e g+e^2 f\right )\right )}{2 e^3 \left (c^2 d^2-e^2\right )^{3/2}}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^3}-\frac{b h \sin ^{-1}(c x) \log (d+e x)}{e^3}-\frac{i b h \sin ^{-1}(c x)^2}{2 e^3} \]
Antiderivative was successfully verified.
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Rule 698
Rule 4753
Rule 12
Rule 6742
Rule 807
Rule 725
Rule 204
Rule 216
Rule 2404
Rule 4741
Rule 4519
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\left (f+g x+h x^2\right ) \left (a+b \sin ^{-1}(c x)\right )}{(d+e x)^3} \, dx &=-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-(b c) \int \frac{3 d^2 h-e^2 (f+2 g x)-d e (g-4 h x)+2 h (d+e x)^2 \log (d+e x)}{2 e^3 (d+e x)^2 \sqrt{1-c^2 x^2}} \, dx\\ &=-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{(b c) \int \frac{3 d^2 h-e^2 (f+2 g x)-d e (g-4 h x)+2 h (d+e x)^2 \log (d+e x)}{(d+e x)^2 \sqrt{1-c^2 x^2}} \, dx}{2 e^3}\\ &=-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{(b c) \int \left (\frac{-e^2 f-d e g+3 d^2 h-2 e (e g-2 d h) x}{(d+e x)^2 \sqrt{1-c^2 x^2}}+\frac{2 h \log (d+e x)}{\sqrt{1-c^2 x^2}}\right ) \, dx}{2 e^3}\\ &=-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{(b c) \int \frac{-e^2 f-d e g+3 d^2 h-2 e (e g-2 d h) x}{(d+e x)^2 \sqrt{1-c^2 x^2}} \, dx}{2 e^3}-\frac{(b c h) \int \frac{\log (d+e x)}{\sqrt{1-c^2 x^2}} \, dx}{e^3}\\ &=\frac{b c \left (e^2 f-d e g+d^2 h\right ) \sqrt{1-c^2 x^2}}{2 e^2 \left (c^2 d^2-e^2\right ) (d+e x)}-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}-\frac{b h \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}+\frac{(b c h) \int \frac{\sin ^{-1}(c x)}{c d+c e x} \, dx}{e^2}-\frac{\left (b c \left (2 e^2 (e g-2 d h)-c^2 d \left (e^2 f+d e g-3 d^2 h\right )\right )\right ) \int \frac{1}{(d+e x) \sqrt{1-c^2 x^2}} \, dx}{2 e^3 \left (c^2 d^2-e^2\right )}\\ &=\frac{b c \left (e^2 f-d e g+d^2 h\right ) \sqrt{1-c^2 x^2}}{2 e^2 \left (c^2 d^2-e^2\right ) (d+e x)}-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}-\frac{b h \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}+\frac{(b c h) \operatorname{Subst}\left (\int \frac{x \cos (x)}{c^2 d+c e \sin (x)} \, dx,x,\sin ^{-1}(c x)\right )}{e^2}+\frac{\left (b c \left (2 e^2 (e g-2 d h)-c^2 d \left (e^2 f+d e g-3 d^2 h\right )\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-c^2 d^2+e^2-x^2} \, dx,x,\frac{e+c^2 d x}{\sqrt{1-c^2 x^2}}\right )}{2 e^3 \left (c^2 d^2-e^2\right )}\\ &=\frac{b c \left (e^2 f-d e g+d^2 h\right ) \sqrt{1-c^2 x^2}}{2 e^2 \left (c^2 d^2-e^2\right ) (d+e x)}-\frac{i b h \sin ^{-1}(c x)^2}{2 e^3}-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}-\frac{b c \left (2 e^2 (e g-2 d h)-c^2 d \left (e^2 f+d e g-3 d^2 h\right )\right ) \tan ^{-1}\left (\frac{e+c^2 d x}{\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}}\right )}{2 e^3 \left (c^2 d^2-e^2\right )^{3/2}}-\frac{b h \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}+\frac{(b c h) \operatorname{Subst}\left (\int \frac{e^{i x} x}{c^2 d-c \sqrt{c^2 d^2-e^2}-i c e e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{e^2}+\frac{(b c h) \operatorname{Subst}\left (\int \frac{e^{i x} x}{c^2 d+c \sqrt{c^2 d^2-e^2}-i c e e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{e^2}\\ &=\frac{b c \left (e^2 f-d e g+d^2 h\right ) \sqrt{1-c^2 x^2}}{2 e^2 \left (c^2 d^2-e^2\right ) (d+e x)}-\frac{i b h \sin ^{-1}(c x)^2}{2 e^3}-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}-\frac{b c \left (2 e^2 (e g-2 d h)-c^2 d \left (e^2 f+d e g-3 d^2 h\right )\right ) \tan ^{-1}\left (\frac{e+c^2 d x}{\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}}\right )}{2 e^3 \left (c^2 d^2-e^2\right )^{3/2}}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{b h \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{(b h) \operatorname{Subst}\left (\int \log \left (1-\frac{i c e e^{i x}}{c^2 d-c \sqrt{c^2 d^2-e^2}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{e^3}-\frac{(b h) \operatorname{Subst}\left (\int \log \left (1-\frac{i c e e^{i x}}{c^2 d+c \sqrt{c^2 d^2-e^2}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{e^3}\\ &=\frac{b c \left (e^2 f-d e g+d^2 h\right ) \sqrt{1-c^2 x^2}}{2 e^2 \left (c^2 d^2-e^2\right ) (d+e x)}-\frac{i b h \sin ^{-1}(c x)^2}{2 e^3}-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}-\frac{b c \left (2 e^2 (e g-2 d h)-c^2 d \left (e^2 f+d e g-3 d^2 h\right )\right ) \tan ^{-1}\left (\frac{e+c^2 d x}{\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}}\right )}{2 e^3 \left (c^2 d^2-e^2\right )^{3/2}}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{b h \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}+\frac{(i b h) \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{i c e x}{c^2 d-c \sqrt{c^2 d^2-e^2}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{e^3}+\frac{(i b h) \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{i c e x}{c^2 d+c \sqrt{c^2 d^2-e^2}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{e^3}\\ &=\frac{b c \left (e^2 f-d e g+d^2 h\right ) \sqrt{1-c^2 x^2}}{2 e^2 \left (c^2 d^2-e^2\right ) (d+e x)}-\frac{i b h \sin ^{-1}(c x)^2}{2 e^3}-\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right )}{2 e^3 (d+e x)^2}-\frac{(e g-2 d h) \left (a+b \sin ^{-1}(c x)\right )}{e^3 (d+e x)}-\frac{b c \left (2 e^2 (e g-2 d h)-c^2 d \left (e^2 f+d e g-3 d^2 h\right )\right ) \tan ^{-1}\left (\frac{e+c^2 d x}{\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}}\right )}{2 e^3 \left (c^2 d^2-e^2\right )^{3/2}}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b h \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{b h \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{h \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{i b h \text{Li}_2\left (\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{i b h \text{Li}_2\left (\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^3}\\ \end{align*}
Mathematica [C] time = 6.64507, size = 996, normalized size = 2.04 \[ \frac{2 a d h-a e g}{e^3 (d+e x)}+b f \left (-\frac{c \sqrt{\frac{-d-\sqrt{\frac{1}{c^2}} e}{d+e x}+1} \sqrt{\frac{\sqrt{\frac{1}{c^2}} e-d}{d+e x}+1} F_1\left (2;\frac{1}{2},\frac{1}{2};3;-\frac{\sqrt{\frac{1}{c^2}} e-d}{d+e x},-\frac{-d-\sqrt{\frac{1}{c^2}} e}{d+e x}\right )}{4 e^2 (d+e x) \sqrt{1-c^2 x^2}}-\frac{\sin ^{-1}(c x)}{2 e (d+e x)^2}\right )+\frac{a h \log (d+e x)}{e^3}+b g \left (\frac{\frac{c \tan ^{-1}\left (\frac{d x c^2+e}{\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}}\right )}{\sqrt{c^2 d^2-e^2}}-\frac{\sin ^{-1}(c x)}{d+e x}}{e^2}-\frac{d \left (-\frac{i d \left (\log \left (\frac{e^2 \sqrt{c^2 d^2-e^2} \left (i d x c^2+i e+\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}\right )}{c^3 d (d+e x)}\right )+\log (4)\right ) c^3}{(c d-e) e (c d+e) \sqrt{c^2 d^2-e^2}}+\frac{\sqrt{1-c^2 x^2} c}{\left (c^2 d^2-e^2\right ) (d+e x)}-\frac{\sin ^{-1}(c x)}{e (d+e x)^2}\right )}{2 e}\right )+b h \left (\frac{\left (-\frac{i d \left (\log \left (\frac{e^2 \sqrt{c^2 d^2-e^2} \left (i d x c^2+i e+\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}\right )}{c^3 d (d+e x)}\right )+\log (4)\right ) c^3}{(c d-e) e (c d+e) \sqrt{c^2 d^2-e^2}}+\frac{\sqrt{1-c^2 x^2} c}{\left (c^2 d^2-e^2\right ) (d+e x)}-\frac{\sin ^{-1}(c x)}{e (d+e x)^2}\right ) d^2}{2 e^2}-\frac{2 \left (\frac{c \tan ^{-1}\left (\frac{d x c^2+e}{\sqrt{c^2 d^2-e^2} \sqrt{1-c^2 x^2}}\right )}{\sqrt{c^2 d^2-e^2}}-\frac{\sin ^{-1}(c x)}{d+e x}\right ) d}{e^3}+\frac{-\frac{i \sin ^{-1}(c x)^2}{2 e}+\frac{\log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right ) \sin ^{-1}(c x)}{e}+\frac{\log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right ) \sin ^{-1}(c x)}{e}-\frac{i \text{PolyLog}\left (2,-\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}-c d}\right )}{e}-\frac{i \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e}}{e^2}\right )+\frac{-a h d^2+a e g d-a e^2 f}{2 e^3 (d+e x)^2} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 1.641, size = 2706, normalized size = 5.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{a h x^{2} + a g x + a f +{\left (b h x^{2} + b g x + b f\right )} \arcsin \left (c x\right )}{e^{3} x^{3} + 3 \, d e^{2} x^{2} + 3 \, d^{2} e x + d^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b \operatorname{asin}{\left (c x \right )}\right ) \left (f + g x + h x^{2}\right )}{\left (d + e x\right )^{3}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (h x^{2} + g x + f\right )}{\left (b \arcsin \left (c x\right ) + a\right )}}{{\left (e x + d\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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