Optimal. Leaf size=459 \[ -\frac{i b \left (d^2 h-d e g+e^2 f\right ) \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{i b \left (d^2 h-d e g+e^2 f\right ) \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^3}+\frac{\log (d+e x) \left (a+b \sin ^{-1}(c x)\right ) \left (d^2 h-d e g+e^2 f\right )}{e^3}+\frac{x (e g-d h) \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}+\frac{b \sin ^{-1}(c x) \left (d^2 h-d e g+e^2 f\right ) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b \sin ^{-1}(c x) \left (d^2 h-d e g+e^2 f\right ) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^3}+\frac{b \sqrt{1-c^2 x^2} (4 (e g-d h)+e h x)}{4 c e^2}-\frac{b h \sin ^{-1}(c x)}{4 c^2 e}-\frac{i b \sin ^{-1}(c x)^2 \left (d^2 h-d e g+e^2 f\right )}{2 e^3}-\frac{b \sin ^{-1}(c x) \log (d+e x) \left (d^2 h-d e g+e^2 f\right )}{e^3} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.786699, antiderivative size = 459, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 12, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.462, Rules used = {698, 4753, 12, 6742, 780, 216, 2404, 4741, 4519, 2190, 2279, 2391} \[ -\frac{i b \left (d^2 h-d e g+e^2 f\right ) \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{i b \left (d^2 h-d e g+e^2 f\right ) \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^3}+\frac{\log (d+e x) \left (a+b \sin ^{-1}(c x)\right ) \left (d^2 h-d e g+e^2 f\right )}{e^3}+\frac{x (e g-d h) \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}+\frac{b \sin ^{-1}(c x) \left (d^2 h-d e g+e^2 f\right ) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b \sin ^{-1}(c x) \left (d^2 h-d e g+e^2 f\right ) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )}{e^3}+\frac{b \sqrt{1-c^2 x^2} (4 (e g-d h)+e h x)}{4 c e^2}-\frac{b h \sin ^{-1}(c x)}{4 c^2 e}-\frac{i b \sin ^{-1}(c x)^2 \left (d^2 h-d e g+e^2 f\right )}{2 e^3}-\frac{b \sin ^{-1}(c x) \log (d+e x) \left (d^2 h-d e g+e^2 f\right )}{e^3} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 698
Rule 4753
Rule 12
Rule 6742
Rule 780
Rule 216
Rule 2404
Rule 4741
Rule 4519
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\left (f+g x+h x^2\right ) \left (a+b \sin ^{-1}(c x)\right )}{d+e x} \, dx &=\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-(b c) \int \frac{e x (2 e g-2 d h+e h x)+2 \left (e^2 f-d e g+d^2 h\right ) \log (d+e x)}{2 e^3 \sqrt{1-c^2 x^2}} \, dx\\ &=\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{(b c) \int \frac{e x (2 e g-2 d h+e h x)+2 \left (e^2 f-d e g+d^2 h\right ) \log (d+e x)}{\sqrt{1-c^2 x^2}} \, dx}{2 e^3}\\ &=\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{(b c) \int \left (\frac{e x (2 e g-2 d h+e h x)}{\sqrt{1-c^2 x^2}}+\frac{2 \left (e^2 f-d e g+d^2 h\right ) \log (d+e x)}{\sqrt{1-c^2 x^2}}\right ) \, dx}{2 e^3}\\ &=\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{(b c) \int \frac{x (2 e g-2 d h+e h x)}{\sqrt{1-c^2 x^2}} \, dx}{2 e^2}-\frac{\left (b c \left (e^2 f-d e g+d^2 h\right )\right ) \int \frac{\log (d+e x)}{\sqrt{1-c^2 x^2}} \, dx}{e^3}\\ &=\frac{b (4 (e g-d h)+e h x) \sqrt{1-c^2 x^2}}{4 c e^2}+\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}-\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{(b h) \int \frac{1}{\sqrt{1-c^2 x^2}} \, dx}{4 c e}+\frac{\left (b c \left (e^2 f-d e g+d^2 h\right )\right ) \int \frac{\sin ^{-1}(c x)}{c d+c e x} \, dx}{e^2}\\ &=\frac{b (4 (e g-d h)+e h x) \sqrt{1-c^2 x^2}}{4 c e^2}-\frac{b h \sin ^{-1}(c x)}{4 c^2 e}+\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}-\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}+\frac{\left (b c \left (e^2 f-d e g+d^2 h\right )\right ) \operatorname{Subst}\left (\int \frac{x \cos (x)}{c^2 d+c e \sin (x)} \, dx,x,\sin ^{-1}(c x)\right )}{e^2}\\ &=\frac{b (4 (e g-d h)+e h x) \sqrt{1-c^2 x^2}}{4 c e^2}-\frac{b h \sin ^{-1}(c x)}{4 c^2 e}-\frac{i b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x)^2}{2 e^3}+\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}-\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}+\frac{\left (b c \left (e^2 f-d e g+d^2 h\right )\right ) \operatorname{Subst}\left (\int \frac{e^{i x} x}{c^2 d-c \sqrt{c^2 d^2-e^2}-i c e e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{e^2}+\frac{\left (b c \left (e^2 f-d e g+d^2 h\right )\right ) \operatorname{Subst}\left (\int \frac{e^{i x} x}{c^2 d+c \sqrt{c^2 d^2-e^2}-i c e e^{i x}} \, dx,x,\sin ^{-1}(c x)\right )}{e^2}\\ &=\frac{b (4 (e g-d h)+e h x) \sqrt{1-c^2 x^2}}{4 c e^2}-\frac{b h \sin ^{-1}(c x)}{4 c^2 e}-\frac{i b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x)^2}{2 e^3}+\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}+\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{\left (b \left (e^2 f-d e g+d^2 h\right )\right ) \operatorname{Subst}\left (\int \log \left (1-\frac{i c e e^{i x}}{c^2 d-c \sqrt{c^2 d^2-e^2}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{e^3}-\frac{\left (b \left (e^2 f-d e g+d^2 h\right )\right ) \operatorname{Subst}\left (\int \log \left (1-\frac{i c e e^{i x}}{c^2 d+c \sqrt{c^2 d^2-e^2}}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{e^3}\\ &=\frac{b (4 (e g-d h)+e h x) \sqrt{1-c^2 x^2}}{4 c e^2}-\frac{b h \sin ^{-1}(c x)}{4 c^2 e}-\frac{i b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x)^2}{2 e^3}+\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}+\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}+\frac{\left (i b \left (e^2 f-d e g+d^2 h\right )\right ) \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{i c e x}{c^2 d-c \sqrt{c^2 d^2-e^2}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{e^3}+\frac{\left (i b \left (e^2 f-d e g+d^2 h\right )\right ) \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{i c e x}{c^2 d+c \sqrt{c^2 d^2-e^2}}\right )}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{e^3}\\ &=\frac{b (4 (e g-d h)+e h x) \sqrt{1-c^2 x^2}}{4 c e^2}-\frac{b h \sin ^{-1}(c x)}{4 c^2 e}-\frac{i b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x)^2}{2 e^3}+\frac{(e g-d h) x \left (a+b \sin ^{-1}(c x)\right )}{e^2}+\frac{h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e}+\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}+\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{b \left (e^2 f-d e g+d^2 h\right ) \sin ^{-1}(c x) \log (d+e x)}{e^3}+\frac{\left (e^2 f-d e g+d^2 h\right ) \left (a+b \sin ^{-1}(c x)\right ) \log (d+e x)}{e^3}-\frac{i b \left (e^2 f-d e g+d^2 h\right ) \text{Li}_2\left (\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )}{e^3}-\frac{i b \left (e^2 f-d e g+d^2 h\right ) \text{Li}_2\left (\frac{i e e^{i \sin ^{-1}(c x)}}{c d+\sqrt{c^2 d^2-e^2}}\right )}{e^3}\\ \end{align*}
Mathematica [A] time = 0.635477, size = 381, normalized size = 0.83 \[ \frac{\frac{b \left (-2 i c^2 \left (d^2 h-d e g+e^2 f\right ) \left (2 \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{c d-\sqrt{c^2 d^2-e^2}}\right )+2 \text{PolyLog}\left (2,\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )+\sin ^{-1}(c x) \left (\sin ^{-1}(c x)+2 i \left (\log \left (1+\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}-c d}\right )+\log \left (1-\frac{i e e^{i \sin ^{-1}(c x)}}{\sqrt{c^2 d^2-e^2}+c d}\right )\right )\right )\right )-4 c^2 \sin ^{-1}(c x) \log (d+e x) \left (d^2 h-d e g+e^2 f\right )+4 c e \sqrt{1-c^2 x^2} (e g-d h)+c e^2 h x \sqrt{1-c^2 x^2}-e^2 h \sin ^{-1}(c x)\right )}{2 c^2}+2 \log (d+e x) \left (a+b \sin ^{-1}(c x)\right ) \left (d^2 h-d e g+e^2 f\right )+2 e x (e g-d h) \left (a+b \sin ^{-1}(c x)\right )+e^2 h x^2 \left (a+b \sin ^{-1}(c x)\right )}{2 e^3} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.464, size = 2477, normalized size = 5.4 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} a g{\left (\frac{x}{e} - \frac{d \log \left (e x + d\right )}{e^{2}}\right )} + \frac{1}{2} \, a h{\left (\frac{2 \, d^{2} \log \left (e x + d\right )}{e^{3}} + \frac{e x^{2} - 2 \, d x}{e^{2}}\right )} + \frac{a f \log \left (e x + d\right )}{e} + \int \frac{{\left (b h x^{2} + b g x + b f\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{a h x^{2} + a g x + a f +{\left (b h x^{2} + b g x + b f\right )} \arcsin \left (c x\right )}{e x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b \operatorname{asin}{\left (c x \right )}\right ) \left (f + g x + h x^{2}\right )}{d + e x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (h x^{2} + g x + f\right )}{\left (b \arcsin \left (c x\right ) + a\right )}}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]